I want to convert a varchar(max) column to decimal(10,4).
When I try to use cast or convert I am getting an arithmetic overflow exception. The issue is that the data stored in the varchar column may contain different precisions and different scales. For example, 123456789.1234567', 1.12345678 or 123456.1234.
For values like 123456.1234 it is converting with out any issue but for other values I am having some problems.
After testing I found that it was not the decimal place that was causing the problem, it was the precision (10)
This doesn't work: Arithmetic overflow error converting varchar to data type numeric.
DECLARE #TestConvert VARCHAR(MAX) = '123456789.12343594'
SELECT CAST(#TestConvert AS DECIMAL(10, 4))
This worked
DECLARE #TestConvert VARCHAR(MAX) = '123456789.12343594'
SELECT CAST(#TestConvert AS DECIMAL(13, 4))
Should be like 9 int + 4 floating = 13 chars
My explanation is in the code. :)
DECLARE #TestConvert VARCHAR(MAX) = '123456789.1234567'
BEGIN TRY
SELECT CAST(#TestConvert AS DECIMAL(10, 4))
END TRY
BEGIN CATCH
SELECT 'The reason you get the message "' + ERROR_MESSAGE() + '" is because DECIMAL(10, 4) only allows for 4 numbers after the decimal.'
END CATCH
-- Here's one way to truncate the string to a castable value.
SELECT CAST(LEFT(#TestConvert, (CHARINDEX('.', #TestConvert, 1) + 4)) AS DECIMAL(14, 4))
-- If you noticed, I changed it to DECIMAL(14, 4) instead of DECIMAL(10, 4) That's because this number has 14 digits, as proven below.
-- Read this for a better explanation as to what precision, scale and length mean: http://msdn.microsoft.com/en-us/library/ms190476(v=sql.105).aspx
SELECT LEN(LEFT(#TestConvert, (CHARINDEX('.', #TestConvert, 1) + 4)))
I came up with the following solution:
SELECT [Str], DecimalParsed = CASE
WHEN ISNUMERIC([Str]) = 1 AND CHARINDEX('.', [Str])=0 AND LEN(REPLACE(REPLACE([Str], '-', ''), '+', '')) < 29 THEN CONVERT(decimal(38,10), [Str])
WHEN ISNUMERIC([Str]) = 1 AND (CHARINDEX('.', [Str])!=0 AND CHARINDEX('.', REPLACE(REPLACE([Str], '-', ''), '+', ''))<=29) THEN
CONVERT(decimal(38,10),
CASE WHEN LEN([Str]) - LEN(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE([Str], '0', ''), '1', ''), '2', ''), '3', ''), '4', ''), '5', ''), '6', ''), '7', ''), '8', ''), '9', '')) <= 38
THEN [Str]
ELSE SUBSTRING([Str], 1, 38 + LEN(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE([Str], '0', ''), '1', ''), '2', ''), '3', ''), '4', ''), '5', ''), '6', ''), '7', ''), '8', ''), '9', ''))) END)
ELSE NULL END
FROM TestStrToDecimal
I know it looks like an overkill and probably it is, but it works for me (checked both positive, negative, big and small numbers of different precision and scale - everything is converted to decimal(38,10) or NULL).
It is hard-coded to decimal(38,10) type, so if you need different precision, change the constants in the code (38, 10, 29).
How it works? The result is:
if conversion is simple without overflow or precision loss (e.g. 123 or 123.456), then it just convert it.
if number is not too big, but has too many digits after decimal point (e.g. 123.1234567890123456789012345678901234567890), then it trims the exceeding digits at the end keeping only 38 first digits.
if number is too big and can't be converted to decimal without an overflow (e.g. 9876543210987654321098765432109876543210), then NULL is returned
each case is separate WHEN statement inthe code above.
Here are few examples of conversion:
You still haven't explained why you can't use a Float data type, so here is an example:
DECLARE #StringVal varchar(50)
SET #StringVal = '123456789.1234567'
SELECT #StringVal, CAST(#StringVal AS FLOAT)
SET #StringVal = '1.12345678'
SELECT #StringVal, CAST(#StringVal AS FLOAT)
SET #StringVal = '123456.1234'
SELECT #StringVal, CAST(#StringVal AS FLOAT)
You are missing the fact that 6.999,50 is not a valid decimal. You can't have a comma and a decimal point in a decimal value surely? What number is it supposed to be?
Assuming your locale specifies . as grouping and , as decimal separator: To remove the grouping digits:
SELECT CONVERT(decimal(11,2), REPLACE('6.999,50', '.', ''))
will yield 6999,50 as a decimal
You are going to have to truncate the values yourself as strings before you put them into that column.
Otherwise, if you want more decimal places, you will need to change your declaration of the decimal column.
Your major problem is not the stuff to the right of the decimal, it is the stuff to the left. The two values in your type declaration are precision and scale.
From MSDN: "Precision is the number of digits in a number. Scale is
the number of digits to the right of the decimal point in a number.
For example, the number 123.45 has a precision of 5 and a scale of 2."
If you specify (10, 4), that means you can only store 6 digits to the left of the decimal, or a max number of 999999.9999. Anything bigger than that will cause an overflow.
Implemented using Custom Function.
This will check whether the string value can be converted to Decimal safely
CREATE FUNCTION [dbo].[TryParseAsDecimal]
(
#Value NVARCHAR(4000)
,#Precision INT
,#Scale INT
)
RETURNS BIT
AS
BEGIN
IF(ISNUMERIC(#Value) =0) BEGIN
RETURN CAST(0 AS BIT)
END
SELECT #Value = REPLACE(#Value,',','') --Removes the comma
--This function validates only the first part eg '1234567.8901111111'
--It validates only the values before the '.' ie '1234567.'
DECLARE #Index INT
DECLARE #Part1Length INT
DECLARE #Part1 VARCHAR(4000)
SELECT #Index = CHARINDEX('.', #Value, 0)
IF (#Index>0) BEGIN
--If decimal places, extract the left part only and cast it to avoid leading zeros (eg.'0000000001' => '1')
SELECT #Part1 =LEFT(#Value, #Index-1);
SELECT #Part1=SUBSTRING(#Part1, PATINDEX('%[^0]%', #Part1+'.'), LEN(#Part1));
SELECT #Part1Length = LEN(#Part1);
END
ELSE BEGIN
SELECT #Part1 =CAST(#Value AS DECIMAL);
SELECT #Part1Length= LEN(#Part1)
END
IF (#Part1Length > (#Precision-#Scale)) BEGIN
RETURN CAST(0 AS BIT)
END
RETURN CAST(1 AS BIT)
END
I know this is an old question, but Bill seems to be the only one that has actually "Explained" the issue. Everyone else seems to be coming up with complex solutions to a misuse of a declaration.
"The two values in your type declaration are precision and scale."
...
"If you specify (10, 4), that means you can only store 6 digits to the
left of the decimal, or a max number of 999999.9999. Anything bigger
than that will cause an overflow."
So if you declare DECIMAL(10,4) you can have a total of 10 numbers, with 4 of them coming AFTER the decimal point.
so 123456.1234 has 10 digits, 4 after the decimal point. That will fit into the parameters of DECIMAL(10,4).
1234567.1234 will throw an error. there are 11 digits to fit into a 10 digit space, and 4 digits MUST be used AFTER the decimal point. Trimming a digit off the left side of the decimal is not an option.
If your 11 characters were 123456.12345, this would not throw an error as trimming(Rounding) from the end of a decimal value is acceptable.
When declaring decimals, always try to declare the maximum that your column will realistically use and the maximum number of decimal places you want to see.
So if your column would only ever show values with a maximum of 1 million and you only care about the first two decimal places, declare as DECIMAL(9,2).
This will give you a maximum number of 9,999,999.99 before an error is thrown.
Understanding the issue before you try to fix it, will ensure you choose the right fix for your situation, and help you to understand the reason why the fix is needed / works.
Again, i know i'm five years late to the party.
However, my two cents on a solution for this, (judging by your comments that the column is already set as DECIMAL(10,4) and cant be changed)
Easiest way to do it would be two steps.
Check that your decimal is not further than 10 points away, then trim to 10 digits.
CASE WHEN CHARINDEX('.',CONVERT(VARCHAR(50),[columnName]))>10 THEN 'DealWithIt'
ELSE LEFT(CONVERT(VARCHAR(50),[columnName]),10)
END AS [10PointDecimalString]
The reason i left this as a string is so you can deal with the values that are over 10 digits long on the left of the decimal.
But its a start.
create function [Sistema].[fParseDecimal]
(
#Valor nvarchar(4000)
)
returns decimal(18, 4) as begin
declare #Valores table (Valor varchar(50));
insert into #Valores values (#Valor);
declare #Resultado decimal(18, 4) = (select top 1
cast('' as xml).value('sql:column("Valor") cast as xs:decimal ?', 'decimal(18, 4)')
from #Valores);
return #Resultado;
END
In case you need to ROUND the result, not truncate, can use this:
select convert(decimal(38,4), round(convert(decimal(38,10), '123456789.1234567'),4))
This will return the following:
'123456789.1235' for '123456789.1234567'
'123456789.1234' for '123456789.1234467'
In MySQL
select convert( if( listPrice REGEXP '^[0-9]+$', listPrice, '0' ), DECIMAL(15, 3) ) from MyProduct WHERE 1
Related
I've been trying to remove the trailing zeros from a column of a table. It works well when I try to remove the zeros from the column. However, when I use it with a case statement (to remove the zeros when a flag is turned on, and to keep them when a flag is turned off) it doesn't work properly. It doesn't recognize the flag. For example, I've hard coded the column as a constant value; while 1=0 (false), it is retrieving the value removing the zeros. It should be true in the else statement.
SELECT CASE WHEN 1=0 THEN cast(CAST(123.45000 AS decimal(6,2)) as float)
ELSE
'123.456700'
END
SELECT CASE WHEN 1=0 THEN CONVERT(DOUBLE PRECISION, 123.456700)
ELSE
'123.456700'
END
Why is this happening? Can anyone help me with this?
The above is well explained by #Tim below.
However, it doesn't remove the zeros at all in a table. It doesn't recognize the flag at all. Here is an example:
CREATE TABLE #tablea
(item CHAR(2), name VARCHAR(10), amount DECIMAL(9,2))
INSERT INTO #tablea
VALUES ('AB', 'D1', 1.10),
('AB', 'D2', 1.00),
('AB', 'D3', 0.90),
('AB', 'D4', 0.09)
DECLARE #flag INT = 1
SELECT CASE WHEN #flag = 1
THEN CAST(CAST(amount AS DECIMAL(6,2)) AS VARCHAR(max))
ELSE amount END
FROM #tablea
As #JNevill commented, what is happening here is that an implicit conversion is happening in the ELSE branch of your CASE expression, converting the string literal into a float, thereby removing the trailing zeroes when it gets printed. One option would be to cast the IF portion to VARCHAR:
SELECT
CASE WHEN 1=0
THEN CAST(CAST(123.45000 AS decimal(6,2)) AS varchar(max)) -- a string
ELSE '123.456700' END -- also a string
Demo
Note that in certain versions of SQL (other than yours) your CASE expression would not even run without error. It just so happens that a silent conversion is taking place here.
You can't remove trailing zeroes from a decimal data type. The decimal/numeric data types are fixed point data type:
Numeric data types that have fixed precision and scale. Decimal and numeric are synonyms and can be used interchangeably.
This means that the decimal point is in a fixed position within the stored number, unlike float and read which are floating point data types - so for a decimal(9,2) there will always be two digits to the right of the decimal point - and for numeric(5,3) where will always be three digits to the left of the decimal point.
If precision is not very important, you can convert to float - but you should be aware that unlike decimal, float is an approximate data type.
Please note that you would still have to convert both branches of the case statement to a varhcar otherwise SQL Server will implicitly convert both branches to float and it will look like the flag is being ignored.
DECLARE #flag INT = 1
SELECT
CASE WHEN #flag = 1
THEN CAST(CAST(amount AS float) as varchar(30))
ELSE CAST(amount as varchar(30))
END As [Remove trailing zeros],
-- This is to show the opposite branch
CASE WHEN #flag = 0
THEN CAST(CAST(amount AS float) as varchar(30))
ELSE CAST(amount as varchar(30))
END As [Include trailing zeros]
FROM #tablea
Results:
Remove trailing zeros Include trailing zeros
1.1 1.10
1 1.00
0.9 0.90
0.09 0.09
#Tim, thanks. It works in the demo you showed. But it doesn't remove the zeros at all in a table. It doesn't recognize the flag at all. Here is an example:
CREATE TABLE #tablea
(item CHAR(2), name VARCHAR(10), amount DECIMAL(9,2))
INSERT INTO #tablea
VALUES ('AB', 'D1', 1.10),
('AB', 'D2', 1.00),
('AB', 'D3', 0.90),
('AB', 'D4', 0.09)
DECLARE #flag INT = 1
SELECT CASE WHEN #flag = 1
THEN CAST(CAST(amount AS DECIMAL(6,2)) AS VARCHAR(max))
ELSE amount END
FROM #tablea
So if I have a data (varchar) like say 10.1
I need the value as 0000101000000.
means (000010) whole number and (1000000) decimal value.
Its a 13 character string ,numbers coming before decimal point should be in first 6 characters and numbers coming after decimal point should be in last 7 characters
Maybe..?
DECLARE #d decimal(13,7) = 10.1;
SELECT RIGHT('0000000000000' + CONVERT(varchar(13),CONVERT(bigint,(#d * 10000000))),13);
Using my crystal ball here though.
Edit: As, for some reason, the OP is storing a decimal as a varchar (this is a really bad bad idea on it's own), I have added further logic to attempt to convert the value to a decimal first.
As experience has taught many of us, give a user a non-numeric column to store a numeric value in and they're more than happily store a non-numeric value in it, so i have used TRY_CONVERT and assumed you are using SQL Server 2012+:
DECLARE #d varchar(13) = 10.1;
SELECT RIGHT('0000000000000' + CONVERT(varchar(13),CONVERT(bigint,(TRY_CONVERT(decimal(13,7),#d) * 10000000))),13);
SELECT REPLICATE('0',6-LEN(SUBSTRING(CAST([data] AS VARCHAR), 1,
CHARINDEX('.',CAST([data] AS VARCHAR)) -1)))+SUBSTRING(CAST([data] AS VARCHAR), 1,
CHARINDEX('.',CAST([data] AS VARCHAR)) -1)+
SUBSTRING(CAST([data] AS VARCHAR), CHARINDEX('.',CAST([data] AS VARCHAR)) + 1,
LEN(CAST([data] AS VARCHAR)))+REPLICATE('0',7-LEN(SUBSTRING(CAST([data] AS VARCHAR), CHARINDEX('.',CAST([data] AS VARCHAR)) + 1,
LEN(CAST([data] AS VARCHAR))))) AS Whole
FROM Table1
Output
Whole
0000101000000
Demo
http://sqlfiddle.com/#!18/8649d/16
You can use some math and string operations to do it like below
see live demo
declare #var decimal(10,4)
set #var=10.1
select #var,
right(cast(cast(( floor(#var)+ power(10,7)) as int) as varchar(13)),6)
+
cast(cast(((#var- floor(#var)) * power(10,7)) as int) as varchar(13))
There's a fair amount of string manipulation to be done here. I'll step through what I did.
I used a variable for the base number so I could verify different results:
declare #n decimal(9,3) = 10.1
You need 6 spaces left of the decimal and 7 spaces to the right, so I'm doing all the manipulation on a VARCHAR(13). I didn't create a new variable as a VARCHAR because I'm assuming you want to be able to do this conversion in line on the fly, so I'm using that CAST over and over again.
Start by finding the decimal place.
SELECT CHARINDEX('.',CAST(#n as VARCHAR(13)))
In the sample number, that's a 3, but it could obviously change.
Now, get the portion of the number to the left of the decimal place.
SELECT SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1)
Then get the portion to the right of the decimal.
SELECT SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13))))
Pad the leading zeroes. Put 6 on, concatenate, and take a RIGHT 6. Accounts for no digits to the left of the decimal.
SELECT RIGHT(REPLICATE(0,6) + SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1), 6)
Pad the trailing zeroes. Same idea, but in the other direction.
SELECT LEFT(SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13)))) + REPLICATE(0,7),7)
Then put it all together.
SELECT RIGHT(REPLICATE(0,6) + SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1), 6)
+
LEFT(SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13)))) + REPLICATE(0,7),7)
Results.
0000101000000
declare #var varchar(20) = '10000.112'
SELECT FORMAT (FLOOR(#var), '000000') + left((PARSENAME(#var,1)) + replicate('0',7),7)
I want to convert data from Varchar column to Numeric data type -
so before conversion I am calling ISNUMERIC function to check whether data is numeric and if yes convert it to numeric data type. But I am facing an issue -
IsNumeric function is not behaving as expected -
- IsNumeric(x) returns true - when varchar value has both comma and a tab character (Char(9)),
- IsNumeric(x) returns false - when varchar value has only tab character and no comma
It is explained with the help of below SQL -
DECLARE #propValue AS VARCHAR(50)
SET #propValue = '1,592 ' -- contains comma + tab (Char(9))
SELECT ISNUMERIC(#propValue) -- Returns 1
--If ISNUMERIC func returns true for this value, lets convert this Varchar value to Numeric
SELECT CAST(#propValue AS Numeric(19, 4)) -- :-( Error converting data type varchar to numeric.
I Googled and found various solutions to tackle this problem -
--Solution 1: use 'e0'
SELECT ISNUMERIC(#propValue + 'e0') -- Returns 0
--Solution 2: remove comma before calling IsNumeric()
SELECT ISNUMERIC(REPLACE(#propValue, ',', '')) -- Returns 0
--Solution 3
--Call CLR function to parse Varchar value
What is the recommended solution in above scenario and why?
Also, I would really appreciate if anyone can explain why IsNumeric(x) returns false - when varchar value has only tab character and no comma?
Thank you!
Keep in mind that ISNUMERIC() = 1 does not mean "can be converted to every numeric type" but rather "can be converted to at least one numeric type." This comes up a lot where the value can be converted to at least one numeric type, but not the one you want. A much more basic example:
IF ISNUMERIC(256) = 1
SELECT CONVERT(TINYINT, 256);
If you have strings that have known violations (such as tabs), then why not also replace tabs? Why not prevent garbage data from getting into this value in the first place?
This works but it is quite ugly:
DECLARE #x TABLE (propValue VARCHAR(50));
INSERT #x SELECT '1,592' + CHAR(9)
UNION ALL SELECT '55' + CHAR(9) + '32'
UNION ALL SELECT CHAR(9) + '7,452.32 '
UNION ALL SELECT 'foo'
UNION ALL SELECT '74';
SELECT CONVERT(NUMERIC(19,4),
LTRIM(RTRIM(REPLACE(REPLACE(propValue, CHAR(9), ''), ',', '')))
)
FROM #x
WHERE ISNUMERIC(LTRIM(RTRIM(REPLACE(REPLACE(propValue,
CHAR(9), ''), ',', ''))) + 'e0') = 1;
While not applicable to your exact question, I wrote a FAQ about this 10 years ago: http://classicasp.aspfaq.com/general/what-is-wrong-with-isnumeric.html
ISNUMERIC(RTRIM(LTRIM(x))) = 1
I have a one database table field called Amount which type is decimal(18,6). so it is stored in database up to 6 decimal points like 9.786534 But while retrieving that field using select query i have to take care like following
Remove trialling zero e.g if number is 9.230000 then result is only 9.23
If decimal points are all zero then only remove only four trialling zero e.g If number is 9.000000 then result is 9.00
Result is up to 2 decimal point if there are trialling zero.
If we write simple query like
select TOP 1 Amount From EmployeeMaster
then it gives 9.230000
but my intension is to remove trailing zero..
Please help me..
It works for removing trailing zeros, but I am still not able to convert 9 to 9.00 in this method.
Declare #myvalue varchar(50),
#Price Varchar(50)
Set #Price = '9.230000'
set #Myvalue = reverse(substring(#Price,patindex('%.%',#Price)+1,len(#Price)))
SELECT
case
When patindex('%.%[1-9]%',#price) = 0 Then
substring(#price,1,patindex('%.%',#price)-1)
else
substring(#price,1,patindex('%.%',#price)-1) + '.' + Reverse(substring(#Myvalue,patindex('%[1-9]%',#Myvalue),len(#Myvalue)))
END
Coming from decimal(18,6) you could do...
select cast(Amount as decimal(18,2))
Most databases that support the CAST function will round the number while converting it. On SQLServer this is what I would do if I wanted rounding.
If what you actually want is a string with only two digits after the decimal then you could
select cast((Amount as decimal(18,2)) as nvarchar)
nvarchar is SQLServer's variable length unicode type. Databases do not agree much on string types. Your database may have a different one. The rest of that sql is ANSI standard. Not all dbs support that either but many do.
This should work
SELECT CAST(REPLACE(RTRIM(REPLACE(CAST(CAST(33.9082976 AS DECIMAL(38,8)) AS NVARCHAR(256)),'0',' ')),' ','0') AS FLOAT)
Does this work?
select TOP 1 ROUND(Amount, 2) From EmployeeMaster
TRY below mentioned code.
SELECT TOP 1 CONVERT(DECIMAL(10,2),Amount) From EmployeeMaster
Hope it will work as expected.
An alternative approach:
1) convert the decimal to a string;
2) split the string into 2 parts, separating the last 4 characters from the rest of the string;
3) remove trailing zeros from the last 4 characters;
4) concatenate the two parts back.
WITH data (V) AS (SELECT CAST(9.786534 AS decimal(18,6))
UNION ALL
SELECT CAST(9.78653 AS decimal(18,6))
UNION ALL
SELECT CAST(9.7800 AS decimal(18,6))
UNION ALL
SELECT CAST(9.7 AS decimal(18,6))
UNION ALL
SELECT CAST(9.00000 AS decimal(18,6))
)
, AsString (V) AS (SELECT CAST(V AS varchar) FROM data)
, Split (L, R) AS (SELECT LEFT(V, LEN(V) - 4), RIGHT(V, 4) FROM AsString)
, Adjusted AS (SELECT L,
REPLACE(RTRIM(REPLACE(R, '0', ' ')), ' ', '0') AS R
FROM Split)
SELECT Result = L + R FROM Adjusted
The output of the above script is:
Result
--------
9.786534
9.78653
9.78
9.70
9.00
I guess using patindex in your case:
CASE WHEN FLOOR(Amount) <> CEILING(Amount) THEN
LTRIM(SUBSTRING(STR(Amount, 18, 6), 1, LEN(STR(Amount, 18, 6)) - PATINDEX('%[^0]%', REVERSE(str(Amount, 18, 6))) + 1))
ELSE STR(Amount,18,2)
END
for a decimal(18,6) field this should work:
select trim(to_char(Amount, '999999999999999999.99')) from EmployeeMaster
(at least for Oracle, not sure about other types)
I need to select from one column of datatype float and insert it in another column as nvarchar.
I tried to cast it: cast([Column_Name] as nvarchar(50))
The result was 9.07235e+009 instead of a 10 digit number (phone number).
Does any one know how to cast or convert this data properly?
Check STR. You need something like SELECT STR([Column_Name],10,0) ** This is SQL Server solution, for other servers check their docs.
If you're storing phone numbers in a float typed column (which is a bad idea) then they are presumably all integers and could be cast to int before casting to nvarchar.
So instead of:
select cast(cast(1234567890 as float) as nvarchar(50))
1.23457e+009
You would use:
select cast(cast(cast(1234567890 as float) as int) as nvarchar(50))
1234567890
In these examples the innermost cast(1234567890 as float) is used in place of selecting a value from the appropriate column.
I really recommend that you not store phone numbers in floats though!
What if the phone number starts with a zero?
select cast(0100884555 as float)
100884555
Whoops! We just stored an incorrect phone number...
Do not use floats to store fixed-point, accuracy-required data.
This example shows how to convert a float to NVARCHAR(50) properly, while also showing why it is a bad idea to use floats for precision data.
create table #f ([Column_Name] float)
insert #f select 9072351234
insert #f select 907235123400000000000
select
cast([Column_Name] as nvarchar(50)),
--cast([Column_Name] as int), Arithmetic overflow
--cast([Column_Name] as bigint), Arithmetic overflow
CAST(LTRIM(STR([Column_Name],50)) AS NVARCHAR(50))
from #f
Output
9.07235e+009 9072351234
9.07235e+020 907235123400000010000
You may notice that the 2nd output ends with '10000' even though the data we tried to store in the table ends with '00000'. It is because float datatype has a fixed number of significant figures supported, which doesn't extend that far.
For anyone willing to try a different method, they can use this:
select FORMAT([Column_Name], '') from YourTable
This will easily change any float value to nvarchar.
Float won't convert into NVARCHAR directly, first we need to convert float into money datatype and then convert into NVARCHAR, see the examples below.
Example1
SELECT CAST(CAST(1234567890.1234 AS FLOAT) AS NVARCHAR(100))
output
1.23457e+009
Example2
SELECT CAST(CAST(CAST(1234567890.1234 AS FLOAT) AS MONEY) AS NVARCHAR(100))
output
1234567890.12
In Example2 value is converted into float to NVARCHAR
You can also do something:
SELECT CAST(CAST(34512367.392 AS decimal(30,9)) AS NVARCHAR(100))
Output:
34512367.392000000
I had same problem and i saw your solution.
Good solution, its worked, thank you...
I created a function with your codes. Now i use it.
My function is here:
create function dbo.fnc_BigNumbertoNvarchar (#MyFloat float)
returns NVARCHAR(50)
AS
BEGIN
RETURN REPLACE (RTRIM (REPLACE (REPLACE (RTRIM ((REPLACE (CAST (CAST (#MyFloat AS DECIMAL (38 ,18 )) AS VARCHAR( max)), '0' , ' '))), ' ' , '0'), '.', ' ')), ' ','.')
END
Continuing a1ex07's answer - to use STR function (SQL SERVER),
and Ronen Festinger's comment - that he gets asterisks instead of digits,
I wanted to point out that the default length of STR is 10,
therefore, for large numbers, don't forget to use the length argument
For example: STR(1234567890123, 14)
DECLARE #MyFloat [float]
SET #MyFloat = 1000109360.050
SELECT REPLACE (RTRIM (REPLACE (REPLACE (RTRIM ((REPLACE (CAST (CAST (#MyFloat AS DECIMAL (38 ,18 )) AS VARCHAR( max)), '0' , ' '))), ' ' , '0'), '.', ' ')), ' ','.')