Select Max Date in Year Month Day Format - sql

I have a table that I drew the following sample from:
Item <other columns> year month day
---- -- ------------ ---- ----- ---
VX4O GL 630.5938 2012 7 20
BX2T GL 0 2012 7 13
MWB806I GL 92004.72 2012 6 15
4XU GL 17.125 2012 7 20
VL4O GL 130.5 2012 7 20
MWB806I GL 92004 2012 10 26
MWB806I GL 92005 2012 11 30
3PU GL 25 2012 7 20
VC4O GL 630.6094 2012 7 20
MWB806I GL 92005 2012 11 2
The first column is Item, the last three columns are year, month, day.
How do I select the max date per item?

SELECT Item, MAX(CONVERT(DATETIME, RTRIM([year])
+ RIGHT('0'+RTRIM([month]), 2)
+ RIGHT('0'+RTRIM([day], 2)
)
FROM dbo.table
GROUP BY Item;
Now you really should consider fixing this schema. Why are you storing year/month/day separately? All it does is make calculations like this one much more difficult, and prevents any proper validation (you can have check constraints for basic stuff, but these are much more complex for things like leap years). And it doesn't save you any space (in fact you lose space if month/day are int, or if you can use smalldatetime).

Related

MS Access SQL – How can I count the occurrence of a number from one table in strings of another table

In MS Access 365 I have 2 tables and I want to count the occurrence of a year from the first table in part of a string of the second table, purely with SQL (so far I used VBA, but I want to simplify).
The first table (tDistinctYears) contains all the years, in which one of our members paid:
ID
PaymentYear
1
2015
2
2016
3
2017
3
2018
4
2019
5
2020
6
2021
7
2022
The second table (tPayments) has all payments from members with one column containing a membership number and the other one containing payment years. Sometimes a member pays for one year, sometime for several years. The table therefore looks like that:
MembershipNr
YearPayment
11
2016
11
2017
11
2018
26
2017
26
2018;2019
26
2020;2021;2022
38
2016
38
2017
38
2018;2019;2020;2021
I want a query which tells me how many members paid in which year:
PaymentYear
Count
2015
0
2016
2
2017
3
2018
3
2019
2
2020
2
2021
2
I used the following SQL query, which I found using various answers on stackoverflow:
SELECT tDistinctYears.PaymentYear, (COUNT(tPayments.YearPayment)) AS [Count]
FROM tDistinctYears
LEFT JOIN tPayments ON tDistinctYears.PaymentYear like "*" & tPayments.YearPayment & "*"
WHERE (tDistinctYears.PaymentYear > 0 AND tDistinctYears.PaymentYear <= YEAR(NOW()))
GROUP BY tDistinctYears.PaymentYear;
But what I get is this:
PaymentYear
Count
2015
0
2016
2
2017
3
2018
1
2019
0
2020
0
2021
0
It seems as if the above query does not use the “like” expression in the JOIN ON section.
Can someone help me, please?
I think you are close just alter column in where condition tPayments.YearPayment should be first and tDistinctYears.PaymentYear should be inside like operator.
SELECT tDistinctYears.PaymentYear, (COUNT(tPayments.YearPayment)) AS [Count]
FROM tDistinctYears
LEFT JOIN tPayments ON tPayments.YearPayment like "*" &
tDistinctYears.PaymentYear
& "*" WHERE (tDistinctYears.PaymentYear > 0 AND tDistinctYears.PaymentYear <=
YEAR(NOW()))
GROUP BY tDistinctYears.PaymentYear;

Count by unique values in other fields in Oracle SQL

I have table like this:
Year Month Type
2013 4 31
2013 3 31
2014 5 40
2014 6 41
2015 5 31
2015 7 40
2013 4 31
2013 3 31
2014 5 40
2014 6 41
2015 5 31
2015 7 40
2013 4 31
2013 3 31
I would like to count number of appearance of each combination. So output should be something like this:
Year Month Type Count_of_appearance
2013 3 31 3
2013 4 31 3
etc..
I've been using something like:
SELECT Year,
Month,
Type,
(SELECT COUNT (*)
FROM myTable
WHERE (...im lost in defining a condition in order to make this work...)
AS Count_of_appearance
FROM employee;
I'm lost at defining functional WHERE clause.
Problem is I a have a lot of fields like this and a lot of unique values. Table is 8Gb big.
You are looking for GROUP BY:
SELECT Year, Month, Type, COUNT(*) AS Count_of_appearance
FROM employee
GROUP BY Year, Month, Type
ORDER BY Year, Month, Type;
To ensure that the results are in the right order, you should include an ORDER BY as well.

SSRS: Horizontal alignment on a group

On my dataset I select information from four different years sorted by date and how many subscriptions I had on said date, which looks something like this:
Date Year Subs Day
15/09/2014 2015 57 1
16/09/2014 2015 18 2
17/09/2014 2015 16 3
14/09/2015 2016 10 1
15/09/2015 2016 45 2
16/09/2015 2016 28 3
12/09/2016 2017 32 1
13/09/2016 2017 11 2
14/09/2016 2017 68 3
24/08/2017 2018 23 1
25/08/2017 2018 53 2
26/08/2017 2018 13 3
What I'm trying to do is create an 'Year' Column Group to align them horizontally, but when I do that, this is the result:
result
Expected result:
expected result
Is this achievable in SSRS? I've tried removing the group =(Details), which gives me the desired result, except it only returns one line of information.
Any insight aprreciated.
By default, the Details group causes you to get one row per row in the dataset. In your case, I would suggest grouping the Rows by the Day column and create a column group by Year.
First, create the two groups and add columns inside the column group.
Then, add a row outside and above the Day row group. Place the headings here and then delete the top row. It should look like this:
Now these 4 columns will repeat to the right for each year and you will get rows based on the number of days in your dataset.

sql running total math current quarter

Im trying to figure out the total for the quarter when the only data shown is a running total for the year:
Id Amount Periods Year Type Date
-------------------------------------------------------------
1 65 2 2014 G 4-1-12
2 75 3 2014 G 7-1-12
3 25 1 2014 G 1-1-12
4 60 1 2014 H 1-1-12
5 75 1 2014 Y 1-1-12
6 120 3 2014 I 7-1-12
7 30 1 2014 I 1-1-12
8 90 2 2014 I 4-1-12
In the data shown above. The items in type G and I are running totals for the period (in qtrs). If my query returns period 3, is there a sql way to get the data for the qtr? The math would involve retrieving the data for the 3rd period - 2nd period.
Right now my sql is something like:
SELECT * FROM data WHERE Date='4-1-12';
In this query, it will return row #1, which is a total for 2 periods. I would like it to return just the total for the 2nd period. Im looking to make this happen with SQLite.
Any help would be appreciated.
Thank alot
You want to subtract the running total of the previous quarter:
SELECT Id,
Year,
Type,
Date,
Amount - IFNULL((SELECT Amount
FROM data AS previousQuarter
WHERE previousQuarter.Year = data.year
AND previousQuarter.Type = data.Type
AND previousQuarter.Periods = data.Periods - 1
), 0) AS Amount
FROM data
The IFNULL is needed to handle a quarter that has no previous quarter.

SQL count ocurrences within time periods

I recently started up working with Access database in a project at my work (hospital) and got lots of useful tips from this site. However, I have now a problem that I can't figure out how to solve.
I have a table containing treatment dates (as well as other data) for lots of patients. My task is to count the number of treatments given within each week (and possibly month/quarter/year as well). The treatment dates are located in the column 'TreatDate' in the table 'Data'.
I have used DatePart to separate out year and week number as:
SELECT
DatePart('yyyy',[TreatStart]) AS Year, DatePart('ww',[TreatStart]) AS Week
FROM Data
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
Which gives me:
Year Week
2006 16
2006 16
2006 16
2006 17
2006 17
2006 18
2006 19
2006 19
2006 19
... ...
How do I count the number of occurances in each week in order to get something like:
Year Week N
2006 16 3
2006 17 2
2006 18 1
2006 19 3
... ... ...
Best regards,
Mattias
Just add the group by on the same values by which you want count and add the count aggregate function to get the total count of the appointments at that given group.
SELECT DatePart('yyyy',[TreatStart]) AS Year, DatePart('ww',[TreatStart]) AS Week , COUNT(*) As N
FROM Data
GROUP BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart])
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
Use GROUP BY and COUNT:
SELECT DatePart('yyyy',[TreatStart]) AS Year,
DatePart('ww',[TreatStart]) AS Week,
COUNT(*) as N
FROM Data
GROUP BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart])
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
The output will be:
Year Week N
2006 16 3
2006 17 2
2006 18 1
2006 19 3