I have the following example code:
$dataProvider = new CActiveDataProvider('firstTable',
array('criteria' => array(
'select' => 't.firstfield,secondTable.secondfield',
'join' => 'join secondTable on secondTable.id=t.secondTable_id',
),
'pagination' => array(
'pageSize' => 10,
),
));
$results=$dataProvider->getData();
After running the code above, firstField (from the model table - firstTable) is available in the object, but secondField (from the joined table - secondTable) is not.
Can anyone provide assistance on what is wrong with the code or why the "select" option is not picking up the secondField?
it would be better if you use CDbCriteria, that has a better solution to join table with the help of relations. I can show the example with CDbCriteria.
$criteria = new CDbCriteria;
$criteria->select = 'firstfield';
$criteria->with = array('secondTable_relation'=>array('select'=>'secondfield'));
$dataProvider = new CActiveDataProvider('firstTable',
array('criteria' => $criteria,
'pagination' => array(
'pageSize' => 10,
),
));
$results=$dataProvider->getData();
secondTable_relation is a relation name with secondTable.
Can anyone provide assistance on what is wrong with the code or why the "select" option is not picking up the secondField?
Answer:
That is happening because you have not selected the field which relates the two tables, i.e the foreign key in firstTable : secondTable_id. So if you do:
'select' => 't.firstfield,t.secondTable_id,secondTable.secondfield',
you will be able to access the secondField of secondTable:
$singleresultrow->secondTableRelationName['secondField'];// a single result row can be obtained by foreach iteration over $results
However there will still be another query (Lazy Loading) when you access the secondField. And the initial(before lazy) object returned will not have the secondTable object filled.
The problem i think lies in the fact that by default yii accesses the related fields by lazy loading, and for that to happen the related foreign_key should be present in the model you are trying to make a dataprovider of, here it is firstTable, and the foreign_key secondTable_id.
Related
i am newbii in yii development and have an issue while displaying data using cgridview as it is showing only first record
Motel,Hotel,Roomcategory and halls are models in which PK and FK are passing ...
Code is here
$sponsorm = Motel::model()->find('MotelId=:MotelId', array(':MotelId'=>Yii::app()->user->id));
$sponsorhotel = Hotel::model()->find('hotelId=:hotelId', array(':hotelId'=>$sponsorm->MotelId));
$room = Roomcategory::model()->find('hotelId=:hotelId', array(':hotelId'=>$sponsorhotel->hotelId));
$halls = Halls::model()->find('hotelId=:hotelId', array(':hotelId'=>$sponsorhotel->hotelId));
echo CHtml::image(Yii::app()->request->baseUrl.'/img/4.png');
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'businessowner-grid',
'dataProvider'=>$room->search(),
//'filter'=>$sponsore,
'columns'=>array(
'roomCategoryNames',
'noOfRooms',
'price',
),
));
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'businessowner-grid',
'dataProvider'=>$halls->search(),
//'filter'=>$sponsore,
'columns'=>array(
'Type',
//'noOfHalls',
'seats',
'price',
),
));
Right now you are finding only one record because you use find to get one specific record. So you assign this record data to model variables and then you do
$model->search();
This searches from specific table multiple values but you have set the attributes so, that it matches only one record.
To get Motel gridview data use following code:
$sponsorm = $dataProvider=new CActiveDataProvider('Motel', array(
'criteria'=>array(
'condition'=>'MotelId = :MotelId',
'params' => array(':MotelId'=>Yii::app()->user->id)
),
));
It is doing the same as search() but the difference is that searching criteria is different. You can use also code below.
$motelModel = new Model();
$motelModel->MotelId = Yii::app()->user->id;
Now there is only one attribute assigned an is setting a criteria to match all rows what has this user id in MotelId field.
$modelModel->search();
Also, I see that you echo something between logic. Please do not do that. Output data only in views and keep the logic out of views. :)
lets say i have a table named
cars{
'id','name','brand_id',
}
and another table
brand{
'id','brand_name',
}
I have a situation that i want to generate an Excel report with the following attributes.
'name','brand_name' i.e. SELECT cars.name, brand.brand_name FROM cars INNER JOIN on brand WHERE cars.brand_id = brand.id
So i created a dataprovider like this:
$sql = "SELECT cars.name, brand.brand_name FROM cars INNER JOIN brand on cars.brand_id = brand.id";
$result = Yii::app()->db->createCommand($sql)->queryAll();
$this->render('doc', array('dataprovider' => $result));
Now i want to generate Excel file with result as a dataProvider so i write the following code:
// lets say i am doing this in view page named doc.php
$factory = new CWidgetFactory();
Yii::import('ext.eexcelview.EExcelView',true);
$widget = $factory->createWidget($this,'EExcelView', array(
'dataProvider'=>$dataprovider->search(),
'grid_mode'=>'export',
'title'=>'Title',
'creator'=>'TNC',
'autoWidth'=>false,
'filename'=>'Report.xlsx',
'stream'=>false,
'disablePaging'=>false,
'exportType'=>'Excel2007',
'columns'=>array(
'name',
'brand_name',),
'showTableOnEmpty' => false,
));
$widget->init();
$widget->run();
I have included all the extensions that i have to.. This code is working when i fed the dataProvider field with a single table entry .
But the situation arises when i include multiple tables.
These lines don't actually make a dataprovider:
$result = Yii::app()->db->createCommand($sql)->queryAll();
$this->render('doc', array('dataprovider' => $result));
You'll want to do something like the following:
$dataprovider = new CSqlDataProvider($sql, array(
'pagination'=>false,
);
$this->render('doc', array('dataprovider' => $dataprover);
More info here: http://www.yiiframework.com/doc/api/1.1/CSqlDataProvider
This works for 2 tables, dont know works for more than 2 or not.
$dataProvider = new CArrayDataProvider($dataprovider, array('id' => 'brand', 'sort' => array('attributes' => array('brand_name', ), ), 'pagination' => false));
$this -> render('doc', array('dataprovider' => $dataProvider,));
I have two tables: user and asset and there is user_asset table that makes many_many relation
Now I want to show only the assets related with logged-in user in CGridView (user_id comes from Yii::app()->user->id)
How to write a criteria that makes it possible?
1) You need to define your relations in both of the model
user:
'assets' => array(self::MANY_MANY, 'Asset', 'user_asset(user_id, asset_id)'),
asset:
'users' => array(self::MANY_MANY, 'Asset', 'user_asset(asset_id, user_id)'),
2) You Create a dataProvider that will fetch only the recquired datas (define it in a model (best) or a controller bu not in a view):
$dataProvider=new CActiveDataProvider('Asset', array(
'criteria'=>array(
'with'=>array(
'users'=>array(
'condition' => 'id = ' . Yii::app()->user->id
),
),
),
...
));
3) You give to your CGridView the good provider:
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
...
));
The code is given as example, you should adapt it to your need!
I got it work, adding this inside the Model class's search method:
$criteria->with=array(
'users'
);
$criteria->together = true;
$criteria->condition = "users_users.user_id='".Yii::app()->user->id."'";
... and inside CActiveDataProvider declaration:
'criteria'=>array(
'with' => 'users',
'together'=>true,
'condition'=>'users_users.user_id = '.Yii::app()->user->id,
),
Maybe not the best way but does what needed. users_users is sql table alias by Yii, I got a hint from error message :)
My title will look like naive but I have to say I read/searched/tested everything possible, but my find() method don't implement the JOIN to related tables in the SQL query. I used it several times in other projects without problems but here...
Here my 2 models (nothing special but the manual definition of the related model) :
class Pflanzen extends AppModel {
public $useTable = 'pflanzen';
public $hasAndBelongsToMany = array(
'Herbar' => array(
'order'=>'Herbar.order ASC',
'joinTable' => 'herbar_pflanzen',
'foreignKey' => 'pflanzen_id',
'associationForeignKey' => 'herbar_id')
);
}
class Herbar extends AppModel {
public $useTable = 'herbar';
public $hasAndBelongsToMany = array(
'Pflanzen' => array('joinTable' => 'herbar_pflanzen',
'foreignKey' => 'herbar_id',
'associationForeignKey' => 'pflanzen_id')
)
}
Here my query in the "Herbar" controller (can't be more normal...) :
$pflanzen = $this->Herbar->Pflanzen->find('all',array(
'fields'=>array('Herbar.name','Pflanzen.linkplatter'),
'conditions' => array('Pflanzen.linkplatter' => true),
'order' => 'Herbar.name',
'limit' => 10,
'recursive'=>2)
);
$this->set('pflanzen',$pflanzen);
and the resulting error in the view :
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Herbar.name' in 'field list'
SQL Query: SELECT `Herbar`.`name`, `Pflanzen`.`linkplatter`, `Pflanzen`.`id` FROM `burgerbib`.`platter_pflanzen` AS `Pflanzen` WHERE `Pflanzen`.`linkplatter` = '1' ORDER BY `Herbar`.`name` ASC LIMIT 10
You can see that their is no JOIN in the SQL. Why ?? What do I wrong ?
I would really appreciate your help as I'm searching for hours and do no more see any solutions and didn't find nothing using google. Thanks in advance !!
HABTM doesn't make joined queries, it makes a query for all base records and more queries as needed for each relationship to fill the array. Your condition assumes a join, hence the error.
You can force a join using the 'joins' parameter. http://book.cakephp.org/1.2/en/view/872/Joining-tables
In the End, the better way of doing this is using the containable behaviour. Force Join is only useful when the containable behavior don't respond to the need :
http://book.cakephp.org/2.0/fr/core-libraries/behaviors/containable.html#using-containable
I have two tables:
Contestant and Votes
Contestant hasMany Votes
I've tried doing a count(Vote.id) as Votes so I can place it on the
recordset and just paginate them but I have no idea where to place it.
I did it on the fields array but it gave me the total count of votes
regardless of the contestant they belong to.
The votes are linked together in the Contestant recordset so what I
did was on my view I did a count($contestant[Vote]) but this can't be
paginated and my client wants to be able to sort the contestants by
votes.
Is there a way I can do something like this on my view?:
sort('Votes', 'count(Vote)'); ?>
Or do I have to create a query which does a count for all the votes
where Contestant.id = Votes.contestant_id ?
Controller Contestant:
function index() {
$page = 'Contestants';
$this->set('page', $page);
$this->paginate =
array(
'order' => 'id ASC',
'contain' => array(
'Vote' => array(
'fields' => array("Vote.contestant_id",'Vote.id')
)
)
$conditions ["Contestant.active"] = 1;
$this->set('contestants', $this->paginate('Contestant',
$conditions));
}
Check out deceze's response in this question: CakePHP mathematic-calculation field?
Essentially you want to do something like this I'm guessing:
'contain' => array(
'Vote' => array(
'fields' => array('SUM(Vote.id) AS Contestant__votes'),
'group' => array('Vote.contestant_id'),
)
)
Since cakephp doesn't support group by in containable behavior I tried a different approach. Create the paginate var for the vote model instead (All of this is done in the Contestants Controller):
var $paginate = array(
'Vote'=>array(
'limit'=>5,
'fields' => array(
'Contestant.*, count(Vote.contestant_id) as Contestant_votes, Vote.id'
),
'group' => array(
'Vote.contestant_id'
),
'order' => array(
'Contestant_votes Desc'
)
),
'Contestant'=>array(
'limit'=>5,
'order' => array(
'Contestant.id Desc'
)
)
);
And now in my controller I do the following:
function index() {
$page = 'Contestants';
$this->set('page', $page);
$conditions ["Contestant.active"] = 1;
$this->set('contestants', $this->paginate($this->Contestant->Vote,$conditions));
}
Now the contestants are ordered by their total vote tally, although I still can't figure how to place the Contestant_votes as a paginator variable since in the record set it's in a array of it's own and not in any of the model arrays used to paginate.
Thanks Matt Huggins your approach was the one that led me to this solution.
Addition: Do you also want to sort by Votes (total votes) ascending or descending? If yes, you can not do it easily by the default pagination method of cakephp.
For that you need a little tweak. Here is the details about this trick: CakePHP Advanced Pagination – sort by derived field
Hope you'd find it helpful.
Thanks
Adnan
For the specific relationship you define, your needs are well-served by counter-caching.
You will need to define a new field in your contestants table: vote_count. Then, in your Votes model, you'll need to update the $belongsTo definition slightly:
class Votes extends AppModel
{
var $belongsTo = array(
'Contestant' => array( 'counterCache' => true )
);
}
Now, anytime a Vote record is saved, the vote_count field of the parent Contestant will be updated. Now you can simply sort by Contestant.vote_count as you would any other Contestant field:
class ContestantsController extends AppController
{
// Controller stuff that comes before...
function index()
{
$this->paginate = array( 'Contestant' => array(
'conditions' => array( 'Contestant.active' => 1 ),
'order' => array( 'Contestant.vote_count' => 'DESC' ),
));
$contestants = $this->paginate('Contestants');
$this->set( compact('contestants'));
}
// Controller stuff that comes after...
}