iOS Cell Label link - objective-c

Question

Hi I am new to iOS programming and I need a little help.
I have a table view cell which is populated by data from a .plist file. I need to be able to make a link within one of the cells. How could I do this?
Here is the code which is loading the data into the cells:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *CellIdentifier = #"CustomTableCell";
static NSString *CellNib = #"DetailViewCell";
DetailViewCell *cell = (DetailViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
NSArray *nib = [[NSBundle mainBundle] loadNibNamed:CellNib owner:self options:nil];
cell = (DetailViewCell *)[nib objectAtIndex:0];
}
cell.accessoryType = UITableViewCellAccessoryNone;
cell.cellTitleLabel.textColor = [UIColor blackColor];
cell.cellTitleLabel.font = [UIFont systemFontOfSize:20.0];
cell.cellSubtitleLabel.textColor = [UIColor darkGrayColor];
informations = [[NSArray alloc] initWithObjects:#"City", #"Country", #"State", #"History", #"Link", nil];
subtitles = [[NSArray alloc] initWithObjects:titleString, subtitleString, stateString, populationString, #"Link", nil];
cell.cellTitleLabel.text = [informations objectAtIndex:indexPath.row];
cell.cellSubtitleLabel.text = [subtitles objectAtIndex:indexPath.row];
return (DetailViewCell *) cell;
}
For the cell "Link" I need it to open a url which is stored in the .plist file. How could i do this?
Many thanks
Ryan
PS: I'm a newbie at this stuff, so be descriptive. Thanks

Answer 1

Firs of all, move the following to viewDidLoad
informations = [[NSArray alloc] initWithObjects:#"City", #"Country", #"State", #"History", #"Link", nil];
subtitles = [[NSArray alloc] initWithObjects:titleString, subtitleString, stateString, populationString, #"Link", nil];
Second, for the cell that has a value of #"Link"
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
DetailViewCell *cell = [tableView cellForRowAtIndexPath:indexPath];
if(cell.cellTitleLabel.text == #"Link")
{
//Open in safari
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:cell.cellSubtitleLabel.text]];
}
}

Answer 2

Make the two arrays properties of your viewController.
#property (nonatomic, retain) NSArray *informationArray, *subtitlesArray;
Initialise them in your -viewDidLoad method:
self.informationArray = [NSArray arrayWithObjects:#"City", #"Country", #"State", #"History", #"Link", nil];
self.subtitlesArray = [NSArray arrayWithObjects:titleString, subtitleString, stateString, populationString, #"Link", nil];
and then check to see if the retrieved data is a link, then open it in safari.
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
id title = [self.informationArray objectAtIndex:indexPath.row];
NSURL *link = [NSURL URLWithString:[self.subtitlesArray objectAtIndex:indexPath.row]];
//or to get the link out of a .plist
NSDictionary *plist = [NSData dataWithContentsOfFile:filePathForPlist];
NSURL *link = [NSURL URLWithString:[[plist objectForKey:title] objectForKey:#"Link"];
// you may need to get a different object from the .plist depending on the structure of the file.
//Check to see if the indexPath matches a cell with a title of "Link" and that the URL can be opened.
if([title isEqualToString:#"Link"] && [[UIApplication sharedApplication] canOpenURL:link]) {
[[UIApplication sharedApplication] openURL:link];
}
}