I have a UIImageView that is undergoing a simple translation animation, and I am trying to get the coordinates of the view while it is moving via the imageview.frame.origin.x property. However, it is giving me the coordinates that the imageview will be at after the animation. Is there any way to get the current coordinates?
Yes, you need to check the coordinates of the presenationLayer. You can read a detailed description about it in my blog post about tapping moving layers.
Related
Here is the view I got, I got a layer view, detect user touch, and a image view, which showing the image. The layer view is cover on top of the image view. The image view's image is aspect fit. So, it won't lost the ratio. If in my layer view touch on 100, 240, it is a layer view coordinate, but not the image's coordinate. I would like to know how to convert the layer view's coordinate to a image's coordinate. In this example, the image size may be 180*180, so, the coordinate in layer view in the image is 60, 90.
Thanks.
If I'm understanding this question correctly, you want to take a point, which is currently in relation to the layer's coordinate system, and convert it to the image view's coordinate system?
In that case, there are a couple of ways to do this.
Easiest is to use convertPoint:fromView: or convertPoint:toView:
CGPoint imageViewTouchPoint = [layerView convertPoint:touchPoint fromView:imageView];
CGPoint imageViewTouchPoint = [imageView convertPoint:touchPoint toView:layerView];
Either one should work.
EDIT - I realize now that this is only if the UIImageView has the same frame as the UIImage, which you said it might not, due to the UIViewContentModeScaleAspectFit property.
In this case, unless I'm mistaken, the image frame is calculated inside the UIImageView drawRect: method and isn't a property that gets set. This means you'll have to calculate this on your own.
Definitely get the imageViewTouchPoint from one of the methods above (just in case you want to use the same logic on a UIImageView which isn't the full screen size).
You will then need to calculate the scaled image frame. There are a couple of ways to do this. Some people go brute force and manually calculate based on which side of the image is longer, then determining which side should be scaled. Then they calculate the origin by by centering the image and subtracting the image and image view's sides and dividing by two.
I like to write as little code as possible if it's unnecessary, even if it means importing a framework. If you import AVFoundation you get a method AVMakeRectWithAspectRatioInsideRect which you can use to actually calculate the scaled rectangle in one line of code.
CGRect imageRect = AVMakeRectWithAspectRatioInsideRect(image.size, imageView.frame);
Whichever method you use, you will then simply translate your touched point with the scaled image origin:
CGPoint imageTouchPoint = CGPointMake(imageViewTouchPoint.x - imageRect.origin.x, imageViewTouchPoint.y - imageRect.origin.y);
You have to do the math yourself. Calculate the aspect ratio of your image and compare with the aspect ratio of the image view's bounds.
Look at this question: How to Get Image position in ImageView
After searching more, got a hack:
CGSize imageInViewSize = [photo resizedImageWithContentMode:UIViewContentModeScaleAspectFit bounds:imageView.size interpolationQuality:kCGInterpolationNone].size;
CGRect overlayRect = CGRectMake((imageView.frame.size.width - imageInViewSize.width) / 2,
(imageView.frame.size.height - imageInViewSize.height) / 2,
imageInViewSize.width,
imageInViewSize.height);
NSLog(#"Frame of Image inside UIImageView: Left:%f Top:%f Width:%f Height:%f \n", overlayRect.origin.x, overlayRect.origin.y, overlayRect.size.width, overlayRect.size.height);
I have two CIImages. I'm trying to apply a CGAffineTransformation to the top image, and then pass it through along with the background image to the CIFilter for blending, but my resulting image seems to show the top image moving around (I just want it rotated on the spot).
I'm also having the same problem when scaling (the position of the top image seems to change).
What am I missing?
So after lots of digging, turns out my problem was due to the rotation point. This question/answer helped a lot.
CGContext rotation
I've created a canvas within which I display an image that is clipped when it goes over the edges. I can do this fine with a square shaped frame, however the frame I want to use is the one below. Is there any way I can clip the image inside the frame without having to add a non transparent square border around the image, i.e. just using the black line that I've already drawn? (on iPad)
You'll need to use Core Graphics and Quartz to handle this sort of clipping/graphics manipulation.
http://developer.apple.com/library/ios/#documentation/GraphicsImaging/Conceptual/drawingwithquartz2d/Introduction/Introduction.html#//apple_ref/doc/uid/TP30001066
If you're using UIBezierPath, you may be able to achieve the clipping you're after using the following process
http://developer.apple.com/library/ios/#documentation/GraphicsImaging/Conceptual/drawingwithquartz2d/dq_paths/dq_paths.html#//apple_ref/doc/uid/TP30001066-CH211-TPXREF101
Convert your UIBezierPath to a CGPath
Get your image into a CGContext
Add your CGPath to the context via CGContextAddPath
Clip your context using CGContextClip
Alternatively, if you don't want to be messing with paths (and depending on whether this technique is suitable for your situation, your description of the issue makes it hard to tell), it might be worth using image masking to achieve the effect you're after. See the first link and look under "Bitmap Images and Image Masks".
I have been looking for the solution on the web for a long time. Most tutorials are fairly simple about adding shadow to a UIView. I also noticed that if we add a shadow to an UIImageView. The shadow shape could perfectly fit the shape of the content image if the image itself has alpha channel in it. Say for example, if the image is an animal with transparent background, the shadow shape is also the same as that animal (not a rectangle shadow as same as UIImageView frame).
But these are not enough. What I need to do is to add some changes to the shadow so it may have some rotation angle and compressed (squeezed or shift) effect so that looks like the sunlight comes from a certain spot.
To demonstrate what I need, I upload 2 images below, which I captured from the Google Map App created by Apple. You can imagine the Annotation Pin is an image which has the Pin shape, so the shadow is also "pin shaped", but it is not simply "offset" with a CGSize, you can see the top of the shadow is shifted right about 35 degrees and slightly squeezed the height.
When we tap and hold and pin, the shadow is also animated away from the pin, so I believe that such shadow can be made programmably.
The best shadow tutorial I can found so far is http://nachbaur.com/blog/fun-shadow-effects-using-custom-calayer-shadowpaths But unfortunately, that cannot make this effect.
If anyone know the answer or know any better words to search for, please let me know. Thank you.
(Please note that the shape of the image is dynamic in the App, so using any tool like Photoshop to pre-render the shadow is not an option.)
In order to create dynamic effects like this, you have to use Core Graphics. It's incredibly powerful once you know how to use it. Basically you need to set a skew transform on the context, set up a shadow and draw the image. You will probably have to use transparency layers as well.
It doesn't sound like you can use CALayer shadows, since that is meant to solve a specific use-case. The approach Apple takes with the pin marks on the map is to have two separate images that are created ahead of time (e.g. in Photoshop) and they position them within the map relative to a reference point.
If you really do need to do this at run-time, it should still be possible by using either Core Graphics or ImageKit. To get a blurred shadow appearance, you can use the kCICategoryBlur CIFilter. You can then convert the image to grayscale. And to get that compressed look you just need to resize and skew the image.
Once you have two separate images, you can either take the CGImageRef for the shadow image and can set that as the content of another sublayer, or you can add it as a separate view.
If you know what all the shapes are, you could just render a shadow image in Photoshop or something.
I would like to know how I can get the diameter (or radius) of an expanding circle animation at a at any point in time during the animation. I will end up stoping the animation right after I get the size as well, but figure I couldn't stop and remove it form the layer until I get the size of the circle.
For an example of how the expanding circle animation is implemented, it is a variation on the implementation shown in the addGrowingCircleAtPoint:(CGPoint)point method in the answer in the iPhone Quartz2D render expanding circle question.
I have tried to check various values on the layers, animation, etc but can't seem to find anything. I figure worse case I can attempt to make a best guess by taking the current time it is into its animation and use that to figure where it "should" be at based on its to and from size states. This seems like overkill for what I would assume is a value that is incrementing someplace I can just get easily.
Update:
I have tried several properties on the Presentation Layer including the Transform which never seems to change all the values are always the same regardless of what size the circle is at the time checked.
Okay here is how you get the current state of the an animation while it is animating.
While Rob was close he left out two pieces of key information.
First from the layer.presentationLayer.subLayers you have to get the layer you are animating on, which for me is the only sub layer available.
Second, from this sub layer you cannot just access the transform directly you have to do it by valueForKeyPath to get transform.scale.x. I used x because its a circle and x and y are the same.
I then use this to calculate the size of the circle at the time of the based on the values used to create the Arc.
I assume what you're trying to get to is the current CATransform3D, and that from that, you can get to your circle size.
What you want is the layer.presentationLayer.transform. See the CALayer docs for details on the presentationLayer. Also see the Core Animation Rendering Architecture.