I have a requirement to create a xaml page with Semantic Zoom where the zoomed in view contains both GridViews and ListViews. I have started out with the basic Grid Application template.
In order to try to achieve this, I have made the Semantic Zoom control's zoomed in view show a list view, and the list view contains the ListView and GridView controls I need to actually show the data as ListViewItems. This works, up to a point - the issue is that the mouse-down or tap animations happen on the whole child control of the parent ListView instead of the child's elements. This sort of layout would be simple if I didn't need to support semantic zoom.
So, my question is is this the best way to achieve this sort of layout, or am I missing something. If this is the best way, is it possible to control the behaviour so that the child item elements have the correct animation effect on selection?
Additional Info
The choice of GridView or ListView is based on the type of the items in the collections. In this example, grp 1, 3 and 4 (to be shown in grids) are all collections of type NewsFull and the remainder (to show in Lists) are of type HeadlineOnly, both types inherit from NewsBase.
The page layout (zoomed in) should be something like this...
Title
grp 1 grp 2 grp 3 grp 4 grp 5
[g][g][g][g] [_list item_] [g][g][g][g][g] [g][g][g] [_list_item_]
[g][g][g][g] [_list item_] [g][g][g][g][g] [g][g][g] [_list_item_]
[g][g][g][g] [_list item_] [g][g][g][g] [g][g] [_list_item_]
[g][g][g] [_list item_] [g][g][g][g] [g][g]
where [g] is a grid view item, and [_list_item_] is a list view item.
Zoomd out view is like this...
Title
grp 1 grp 2 grp 3 grp 4 grp 5
[summary] [summary] [summary] [summary] [summary]
Perhaps you can try using the ItemContainerStyleSelector to swap out the container of the items based on the item type or similar? This way, may be you can set one group to have a wrapping layout container and another can just be a stackpanel?
the design looks reasonable to me. the issue you have is merely " is it possible to control the behaviour so that the child item elements have the correct animation effect on selection?"
the problem here is that you probably lack abstraction here regarding different levels of UI object. I would assume you wrote this big control simply using one xaml object and then messed up with the style setup. In my opinion, you will need to break your UI to these levels of components:
ZoomPage // which is essentially a list
GroupElement // which could be GRID object or list object depending on the DATACONTEXT
GroupElement // which also has a summary state.
what you specified definitely can be achieved, looks to me just the styles are not deployed properly, if indeed your control is too complex, break it down, and test them separately.
hope this helps
Related
I have a table (and model) with the following properties in an asp.net MVC 4 application:
TV Table
height
width
depth
type
brand
cost
When the user answes a question about the space that they have for the TV I then do an ajax call to determine which types are possible to fit into the space they have specified. Which type of TV type they want is the following question, so some options may need to be disabled. The SQL for what types fit in the space is "select distinct type from TV where height < #height and width < #width and depth < #depth".
Should I:
1. create a new model that I call from the TV controller just to return the distinct types
2. add a method to the TV model that I call from the TV controller that just returns a list of string with the types that fit
Depends on what you want to display to the user based on her selection' e. g.
If you want to display TV name + its description then returning a list of TV model will make sense.
If you are just going to display a list of TV names in combo box, then returning a list of string will suffice.
Calling a new action make sense in both cases IMHO.
EDIT:
For 2 - I want to return a list of string - should I create a new data model for this, or add a method in the existing TV data model that returns a list of string?
To expand on above query, since its not clear (at least I do not visualize it) from your question i will assume few things.
Case 1: You are displaying a view say "TVSelection" to the user that does not contain list of TVModels. In this view you are expecting user to enter three values i.e. Width, Height, Depth. Now when user enter these values, she can submit the form or you can fetch the TV Brand name list on Lost Focus event as well. In any case, the question would be are you updating existing view by populating the combo box or you are displaying a new view. I am assuming you are updating existing "TVSelection" view by the means of making an AJAX call. In that case you can just call a method on your controller (which displayed the "TVSelection" view) that returns a list of TV Brand names.
Case 2: You are displaying "TVSelection" view that already has a list of TVModel objects and you update it dynamically on selection of required field (filtering). In this case you can add a method in the TVModel itself to filter names only that matches the user selection.
I found these links relevant 1 & 2.
Hope that make sense.
Please add more details to your question if this does not answer your question.
I have a scrollableView with several views inside and I'd like to add item to some of these view if they meet a certain criteria, like if they have data attached or not. Also I'm using Alloy, here's my markup
<ScrollableView id="scrollableView">
<View id="view" class='coolView'></View>
...
</ScrollableView>
To know if there are data attached I check the currentPage attribute like so:
function updateCurrentView(e) {
currentView = e.currentPage;
}
But I have no idea how to add an item to the current View.
Edit: To add some clarification, I have a label which when clicked allow me to choose two currencies, when chosen these currency pairs are saved in the database and should be displayed instead of the label. So my guess was to check whether the current view has currency pair saved.
There are 2 things to take care of here:
1.Whenever a currency is selected,immediately label on that particular view will change.
2.Whenever the scrollableView is loaded,it must always refer to the database if a currency is selected.
First one can be done as:
1.Get the instance of scrollableView using the getView method of alloy controller.Pass the id of the scrollableView to it.Lets call it myScrollableView.Refer this for more info.
http://docs.appcelerator.com/titanium/latest/#!/api/Alloy.Controller
2.Use var currentView=myScrollableView.getCurrentPage() to the get the current page which will be a number.
3.Now use the scrollableView instance to get all the views.
var viewArray=myScrollableView.getViews();
4.viewArray[currentView] will give you the view of current page.After you have got the view you can change the desired label using:
viewArray[currentView].children[positionOfTheView]
The "positionOfTheView" can be obtained by printing the viewArray[i].children array using Ti.API.info.
Second thing can be accomplished as follows:
1.Get the instance of scrollableView using the getView method of alloy controller.Pass the id of the scrollableView to it.Lets call it myScrollableView.Refer this for more info.
http://docs.appcelerator.com/titanium/latest/#!/api/Alloy.Controller
2.Now use the scrollableView instance to get all the views.
var viewArray=myScrollableView.getViews();
3.This is a JavaScript array of all the views in the scrollableView. Now iterate through this array and according to the data in the database,change the concerned view using:
viewArray[i].children[positionOfTheView]
The "positionOfTheView" can be obtained by printing the viewArray[i].children array using Ti.API.info.
Can I add an item to the container as the first one rather than appending all existing ones.
From what I understand this.add([item]) will add item as the last one, however I would like it to apper it on the top of the screen before anything else has been added.
You can use insert method of container like this:
this.insert(0 , item);
where it would appear depends on your layout.
I'm using boostrap library on Yii via yii-booster
I've created a relation table view
The related view is a TbGriView itself
Vhen in a row i click on the link on the 'related' column, the row expands itself, and render a TbGridview inside it.
The problem is that the internal gridview cannot be sorte, paged or filtered, because each action on it causes that the entire container grid will empty
Note
- external grid as a id of 'extenalgrid'
- each internal grid has as id like 'internalgrid-$rowId' , so every internal grid as differnt id on div, table and table row elements.
- the action called from "render related tabel" link is using renderPartial without the postProcess option. If i use potProcess, the row will be empty
So is it not possible to rendere a full working gridview/tbgridview into a related table ?
Use different css classes for the filters, buttons and headers for the different tables. From the jquery.yiigridview.js file events are bound to selectors as $('#table-id .selector-class') so elements in your internal gridView still trigger the events bound to the external gridView. You also have to specify a different url for the internal gridView by setting it's ajaxUrl.
I'm on ExtJS 4 and using an MVC approach. I've created a simple grid view class, and have added a componentquery type 'ref' to that view in my controller. Within the initial grid view itself I set several columns to be hidden and some to be visible by default. The rendering of the grid with those settings is all working fine.
Then I have a button that, when clicked and based on some other conditions, will make some of the initially hidden grid columns visible. This works as well.
But what I need is a way to later 'reset' the grid to its initial view (with the correct columns hidden/visible, as they were initially).
I've tried various permutations of the following with no effect:
var theGrid = this.getTheGrid();
theGrid.reconfigure(store, theGrid.initialConfig.columns);
theGrid.getView().refresh();
I suppose I could loop through every column and reset its 'hidden' state, but would think there's a way to just 'reset' back to what's set in the class? Advice?
SOLUTION UPDATE
Appreciate the pointer from tuespetre. For anyone coming along in the future looking for specifics, here is what was needed (at least for my implementation):
Within the view, moved the column defs into a variable
Within the view, columns ref within the class becomes:
columns: myColumns,
Within the view, the following function created within the class:
resetGrid: function(){
this.reconfigure(null, myColumns);
},
Within the controller:
var theGrid = this.getTheGrid();
theGrid.resetGrid();
You will just need to create a function on your view class to encapsulate that functionality.