Selecting all levels in a hierarchy as a tuple in MDX - mdx

Question

I made my first cube yesterday. I'm still new to this, so please forgive any misuse of terminology. One of my dimensions, let's call it MyDimension1 has a hierarchy, let's call it MyHierarchy, with two levels, let's call them Level1 and Level2.
I seem to be able to do something like:
SELECT
{ [Measures].[Whatever] } ON 0,
{ ([MyDimension1].[Level1].[Level1], [MyDimension1].[Level2].[Level2]) } ON 1
FROM MyCube
Which gives me the result I want. If I understand correctly, the set defining axis 1 contains a tuple with two components(?). I've read that each component(?) of a tuple is supposed to be from a different dimension, but I seem to be able to specify components of the same dimension, as demonstrated by the above query. I'd like to be able to just specify the hierarchy by name and then have the server create the tuples for me, though. So something like:
SELECT
{ [Measures].[Whatever] } ON 0,
{ AllLevelsToTuple([MyDimension1].[MyHierarchy]) } ON 1
FROM MyCube
But I can't seem to figure out how to do this. Thanks in advance!
EDIT (My example, as requested by an answerer):
This does what I want, functionally, but isn't the syntax I'd like:
SELECT [Measures].[Original] ON 0,
([Customer].[Customer].[Customer], [Customer].[Account ID].[Account ID]) ON 1
Results (In SSMS):
Original
--------- -- --------
CustomerA 15 306.03
CustomerA 16 754.20
...
CustomerB 17 524.43
...
CustomerC 22 760.42
...
When I expand the dimension, it looks like:
- Customer
- Hierarchy
+ Members
+ Customer
+ Account ID
When I do something like (I'd like to do something similar syntactically):
SELECT [Measures].[Original] ON 0,
([Customer].[Hierarchy].Members) ON 1
I get the following results:
Original
---------- --------
All 17638.15
CustomerA 2624.76
15
16
...
CustomerB 3113.67
17 524.43
...
CustomerC 3427.01
22 760.42
...
I want there to be 3 columns, not 2, basically.

Answer 1

You might want to read this MDX gentle introduction.
I've read that each component(?) of a tuple is supposed to be from a
different dimension
From different hierarchy instead. In AS, I guess that for each level, you have as well a corresponding flat hierarchy; so the following looks like you're accessing levels of two different hierarchies:
{ ([MyDimension1].[Level1].[Level1], [MyDimension1].[Level2].[Level2]) } ON 1
I'm not a specialist of AS but I guess the following statement :
SELECT [Measures].[Original] ON 0,
([Customer].[Customer].[Customer], [Customer].[Account ID].[Account ID]) ON 1
is actually interpreted as a crossjoin of level members from 2 different hierarchies; it is more likely that the () notation is interpreted as the () operator instead of tuple notation and then {},{} is a crossjoin in MDX :
SELECT [Measures].[Original] ON 0,
[Customer].[Customer].[Customer].members * [Customer].[Account ID].[Account ID].members ON 1
hence the two columns in front of your measures in the result.
I want there to be 3 columns, not 2, basically.
You'll need to use calculated measures; something like :
with
MEMBER Measures.HN as [Customer].Currentmember.Hierarchy.Name
MEMBER Measures.LN as [Customer].Currentmember.Level.Name
MEMBER Measures.MN as [Customer].Currentmember.Name
SELECT { Measures.HN, Measures.LN, Measures.MN, [Measures].[Original] } ON 0,
([Customer].[Hierarchy].Members) ON 1

Answer 2

Yes, you can create a tuple from different dimensions, and you do so by placing members between parentheses and separated by commas.
But in this case, you don't need a tuple, simply a set. A set contains members from a single dimension, separated by commas and placed between curly braces: {}.
Have a look at the descendants function. You can create a set from your hierarchy using this function.