Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()
Related
I'm trying to SELECT all the rows from a SQL database which are between an hour interval, for every day.
The datetime column is called "Dt" and has the following datetime format: 2019-10-17 16:03:43
I'd like to extract all the rows from this table where the Dt was between 22:00:00 and 02:00:00, for everyday.
SELECT *
FROM MY_TABLE
WHERE "Dt" BETWEEN '*-*- 22:00:00' AND '*-*- 02:00:00';
where * should be any...
Thanks for your support!
EDIT: I forgot to mention: I'm using the integrated SQL interpreter from DB Browser for SQLite
You need to extract the time part of the date and compare that it is within the range. Since midnight is between 22 and 2, you will need to split it to two comparisons, time between 22 and 0 and between 0 and 2.
To see how to extract the time take a look at this question.
With Postgres, assuming dt is defined as timestamp you can do the following:
SELECT *
FROM MY_TABLE
WHERE "Dt" BETWEEN "Dt"::date + time '22:00:00' and ("Dt"::date + 1) + time '02:00:00'
Or if you want to exclude timestamps at precisely 02:00:00
SELECT *
FROM MY_TABLE
WHERE "Dt" >= "Dt"::date + time '22:00:00'
and "Dt" < ("Dt"::date + 1) + time '02:00:00'
select DT_time from (
select cast (substr(to_char(Dt,'dd-mm-yyyy HH:MM:SS'),12,2) as integer ) as DT_time from MY_TABLE )
where DT_time between 2 and 22;
between 22:00:00 and 02:00:00
means:
SELECT *
FROM MY_TABLE
WHERE
substr(Dt, 12) BETWEEN '22:00:00' AND '23:59:59'
OR
substr(Dt, 12) BETWEEN '00:00:00' AND '02:00:00'
This will work ::
SELECT *
FROM MY_TABLE
WHERE DATEPART(HOUR, Dt)>22
AND DATEPART(HOUR, Dt)<2
Update :
SELECT *
FROM MY_TABLE
WHERE Dt Between DATEADD (hour,22,DATEADD(day, DATEDIFF(day, 0, Dt), 0)) AND DATEADD (hour,2,DATEADD(day, DATEDIFF(day, -1, Dt), 0))
SELECT *
FROM MY_TABLE
WHERE DATEPART(HOUR, Dt)>22
OR DATEPART(HOUR, Dt)<2
Above query work for you..
1st one will check only for particular date and consecutive next date along with your time range.
But If you don't care about dates and only looking for time interval in particular hours then 2nd one is for you.
For SQLite :
SELECT *
FROM MY_TABLE
WHERE strftime('%H','Dt')>22
OR strftime('%H','Dt')<2
I am trying to use my query as the current day for my SQL query.
What I am trying below returns 0 records:
select *
from [TEST].[dbo].LIMIT
where endOfDay = GETDATE()
select *
from [TEST].[dbo].LIMIT
where endOfDay = dateadd(dd, datediff(dd, 0, getdate()), 0)
where endOfDay >= getdate() and endOfDay < getdate() + 1
An example date would be 2019-07-09 00:00:00.0
Also if there is no given date for today's date can I get a range of dates?
Any help would be appreciated, thanks.
First, you need to omit the quotes or else 'GETDATE()' is just a string.
Second, to match by "day", you need to strip the time part from the result of GETDATE(), which you can do by using CAST(GETDATE() as DATE) instead:
select *
from [TEST].[dbo].LIMIT
where endOfDay = CAST(GETDATE() as DATE)
For this to work best, the endOfDay column also needs to be of type DATE. If it is something else, you need to also CAST or CONVERT endOfDay to a DATE.
Using quotes makes it looking for a meaningless literal 'GETDATE()' to find nothing
You can use
with LIMIT(today, EndOfDay) as
(
select CONVERT(DATETIME, CONVERT(date, GETDATE())), GETDATE()
)
select EndOfDay
from LIMIT
where EndOfDay >= today and EndOfDay < today + 1;
Demo
Try this:
select *
from [TEST].[dbo].LIMIT
where cast(endOfDay as date) = cast(GETDATE() as date)
SQL Fiddle to see what the date will be compared with.
GETDATE() returns the server's current date and time. Unless you have any records that match that exactly, it doesn't make sense to use GETDATE. It doesn't look like you do based on the endOfDay column name.
The other criteria you show,
dateadd(dd,datediff(dd,0,getdate()),0) is essentially stripping the time off and returning midnight of the current date.
select getdate() 2019-07-11 15:10:09.287
select dateadd(dd,datediff(dd,0,getdate()),0) 2019-07-11 00:00:00.000
Assuming you don't care about time, convert both EndofDay and Getdate to a simple date for comparison.
select * from [TEST].[dbo].LIMIT where convert(date,EndOfDay) = convert(date,getdate())
I have a problem that is I am unable to resolve as of now.
I need to get the data of
this day, this week and this month
I have a table reminder where I want to select reminders according to
following parameters.
1. Today
2. This Week
3. This Month
The column rdate having the date format in dd-mm-yyyy which is stored as nvarchar
For example
If I execute this weeks query I should get data starting from this week i.e.
If it is Friday I should get data from starting from Sunday to Saturday of that week
How can I get the data as mentioned above. I have searched a lot on internet but I didn't get the solution?
This is the query I have been trying
SELECT
*
FROM
reminder
WHERE
date > DATE_SUB(GETDATE(), INTERVAL 1 DAY)
ORDER BY
rdate DESC;
Where I'm converting nvarchar to date format.
If it's not possible to change the [date] column's data type to DATE, then you will incur a massive performance penalty when trying to filter by date.
Add computed column to table
We can add a computed column that will store the date in the correct format, and then index it for quick searchiing:
ALTER TABLE reminder
ADD Date_Value AS (CONVERT(DATE, '12-05-2016', 105)) PERSISTED;
-- This should yield superior performance
CREATE NONCLUSTERED INDEX IX_Date_Value ON reminder (Date_Value);
Table-valued function to calculate date range
Now, let's create an inline table-valued function to generate the date range for specific period types:
CREATE FUNCTION [dbo].[tvfn_Get_Date_Range](
#Period_Type VARCHAR(100)
)
RETURNS
TABLE
AS RETURN
(
WITH date_range AS(
SELECT CAST(GETDATE() AS DATE) d
-- This line works correctly if your week starts on Sunday
,CAST(DATEADD(WEEK, DATEDIFF(WEEK, '19050101', GETDATE()), '19050101') AS DATE) AS week_start
,CAST(DATEADD(DAY, - DAY(GETDATE()) + 1, GETDATE()) AS DATE) AS month_start
,CAST(DATEADD(MONTH, 1, DATEADD(DAY, - DAY(GETDATE()), GETDATE())) AS DATE) AS month_end
)
SELECT d AS From_Date
,d AS To_Date
FROM date_range
WHERE #Period_Type = 'DAY'
UNION ALL
SELECT week_start
,DATEADD(DAY, 7, week_start)
FROM date_range
WHERE #Period_Type = 'WEEK'
UNION ALL
SELECT month_start
,month_end
FROM date_range
WHERE #Period_Type = 'MONTH'
)
In the above function, week starts on Sunday. If you need this to be configurable, then take a look at the answer to SET DATEFIRST in FUNCTION.
Fast, simple querying now possible
You can now use the two together using a simple query:
SET #Range VARCHAR(100) = 'WEEK'
SELECT *
FROM reminder
CROSS APPLY [dbo].[tvfn_Get_Date_Range](#Range) dr
WHERE Date_Value BETWEEN dr.Date_From AND dr.Date_To
If you can't change the columns data type to Date (or DateTime), you must convert it to date in the query.
Here is one way to get the data for today, this week and this month:
Get records from today:
SELECT *
FROM reminder
WHERE CONVERT(Date, [date], 105) = CAST(GETDATE() as date)
ORDER BY rdate DESC;
Get records from this week:
SELECT *
FROM reminder
WHERE DATEPART(WEEK, CONVERT(Date, [date], 105)) = DATEPART(WEEK, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
Get records from this Month:
SELECT *
FROM reminder
WHERE DATEPART(MONTH, CONVERT(Date, [date], 105)) = DATEPART(MONTH, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
To my knowledge, SQL server internally deals with date format as MM/dd/yyyy.
Usually I prefer to save date as string in SQL table since it's easier for inserting and retrieving.
For example, suppose that the column rdate is defined as follows in your table reminder:
[rdate] nvarchar NULL
Then you can customize the select statement for a week as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/11/2011'"
And for 10 days as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/14/2011'"
And so on. If this is not what you want, please provide more details about your requirements.
I have a select, and I need to limit data only for two last days. So today is 24th Aug 2016 so I need to get data for 24th Aug 2016, 23th Aug 2016 and 22th Aug 2016. How can I do that? I suppose I should use DATEADD function, or something similar. It needs to be done dynamicaly.
I need to get something like this:
SELECT * FROM TABLE_NAME WHERE
DATE = '2016-08-22'
The date must be updated each day
DateAdd, exactly
SELECT * FROM TABLE_NAME
WHERE DATE BETWEEN dateadd(d,-2,cast(getDate() as date)) AND cast(getDate() as date)
SELECT *
FROM TABLE_NAME
WHERE cast(DATE as date) BETWEEN cast(DATEADD(D, -2, GETDATE()) as date) AND cast(GETDATE() as date)
SELECT * FROM TABLE_NAME WHERE
cast(DATE as date) >= cast(GETDATE()-2 as date)
or
--For limiting future dates
SELECT * FROM TABLE_NAME
WHERE
cast(DATE as date) in (cast(GETDATE()-2 as date),cast(GETDATE()-1 as date), cast(GETDATE() as date))
Use GETDATE() function
If there are future dates in this table you can perhaps use this
select * from table_name
where date <= getdate()
and date >= dateadd(day,-2,getdate())
SELECT * FROM TABLE_NAME WHERE
DATE >=cast(getdate()-2 as date)--so this will be rounded off to midnight and it is sargable
First you have to make today's date in absolute by converting it in float then floor and then convert it into small date time. And then using dateadd subtract 2 days from today's absolute date.
SELECT * FROM
TABLE_NAME
WHERE
DATE >= (SELECT DATEADD(dd,-2,CAST(FLOOR(CAST(GETDATE() as FLOAT)) as SMALLDATETIME)))
I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)