How to remove the carriage space using SQL query. I tried the replace (..) idea but its not working at all ? The duplicate idea is not working
I guess you should go with below code -
REPLACE(REPLACE( col_name, CHR(10)), CHR(13))
This will replace the spaces and carriage both and might solve your problem.
I generally use the test1 option:
select replace(replace('teste
return test', chr (13), ''), chr (10), ' ') test1,
translate('teste
return test', chr(10) || chr(13) || chr(09), ' ') test2
from dual;
I am using
substr( item_name, instr(item_name," ",1,1)-1 )
to get the name of an item before space.
What is the correct way to do it?
Try using single quote
substr( item_name, instr(item_name, ' ' ,1,1)-1 )
Your problem is with the string character, which should be a single quote.
This is often handled using regexp_substr():
select regexp_substr(item_name, '^([^ ]*)[ ]', 1, 1)
I have an issue with a file that's created from data (in format of bytes) returned from the database.
the problem is that there is a few newlines in the file.
i would like to know if there is a way to write a where clause to check if some record has a newline character?
Using the CHR function to look for the ASCII value:
select *
from your_table
where instr(your_text_col, chr(10)) > 0;
If you want to search for carriage returns, that would be chr(13).
You can write something like:
SELECT id
FROM table_name
WHERE field_name LIKE '%'||CHR(10)||'%'
;
(|| is the concatenation operator; CHR(10) is the tenth ASCII character, i.e. a newline.)
Depending on the platform, a newline will generally either be a CHR(10) (Unix) or a CHR(13) followed by a CHR(10) (Windows). There are other options for other more esoteric platforms, but 99.999% of the time, it will be one of these two.
You can search the data in a column looking for one or both characters
SELECT instr( column_name, CHR(10) ) position_of_first_lf,
instr( column_name, CHR(13) || CHR(10) ) position_of_first_cr_lf
FROM table_name
WHERE instr( column_name, CHR(10) ) > 0
This worked the best for me.
select * from label_master where regexp_like (text, chr(10));
I need to trim New Line (Chr(13) and Chr(10) and Tab space from the beginning and end of a String) in an Oracle query. I learnt that there is no easy way to trim multiple characters in Oracle. "trim" function trims only single character. It would be a performance degradation if i call trim function recursivelly in a loop using a function. I heard regexp_replace can match the whitespaces and remove them.
Can you guide of a reliable way to use regexp_replace to trim multiple tabspaces or new lines or combinations of them in beginning and end of a String. If there is any other way, Please guide me.
If you have Oracle 10g, REGEXP_REPLACE is pretty flexible.
Using the following string as a test:
chr(9) || 'Q qwer' || chr(9) || chr(10) ||
chr(13) || 'qwerqwer qwerty' || chr(9) ||
chr(10) || chr(13)
The [[:space:]] will remove all whitespace, and the ([[:cntrl:]])|(^\t) regexp will remove non-printing characters and tabs.
select
tester,
regexp_replace(tester, '(^[[:space:]]+)|([[:space:]]+$)',null)
regexp_tester_1,
regexp_replace(tester, '(^[[:cntrl:]^\t]+)|([[:cntrl:]^\t]+$)',null)
regexp_tester_2
from
(
select
chr(9) || 'Q qwer' || chr(9) || chr(10) ||
chr(13) || 'qwerqwer qwerty' || chr(9) ||
chr(10) || chr(13) tester
from
dual
)
Returning:
REGEXP_TESTER_1: "Qqwerqwerqwerqwerty"
REGEXP_TESTER_2: "Q qwerqwerqwer qwerty"
Hope this is of some use.
This how I would implement it:
REGEXP_REPLACE(text,'(^[[:space:]]*|[[:space:]]*$)')
How about the quick and dirty translate function?
This will remove all occurrences of each character in string1:
SELECT translate(
translate(
translate(string1, CHR(10), '')
, CHR(13), '')
, CHR(09), '') as massaged
FROM BLAH;
Regexp_replace is an option, but you may see a performance hit depending on how complex your expression is.
You could use both LTRIM and RTRIM.
select rtrim(ltrim('abcdab','ab'),'ab') from dual;
If you want to trim CHR(13) only when it comes with a CHR(10) it gets more complicated. Firstly, translated the combined string to a single character. Then LTRIM/RTRIM that character, then replace the single character back to the combined string.
select replace(rtrim(ltrim(replace('abccccabcccaab','ab','#'),'#'),'#'),'#','ab') from dual;
TRANSLATE (column_name, 'd'||CHR(10)||CHR(13), 'd')
The 'd' is a dummy character, because translate does not work if the 3rd parameter is null.
For what version of Oracle? 10g+ supports regexes - see this thread on the OTN Discussion forum for how to use REGEXP_REPLACE to change non-printable characters into ''.
I know this is not a strict answer for this question, but I've been working in several scenarios where you need to transform text data following these rules:
No spaces or ctrl chars at the beginning of the string
No spaces or ctrl chars at the end of the string
Multiple ocurrencies of spaces or ctrl chars will be replaced to a single space
Code below follow the rules detailed above:
WITH test_view AS (
SELECT CHR(9) || 'Q qwer' || CHR(9) || CHR(10) ||
CHR(13) || ' qwerqwer qwerty ' || CHR(9) ||
CHR(10) || CHR(13) str
FROM DUAL
) SELECT
str original
,TRIM(REGEXP_REPLACE(str, '([[:space:]]{2,}|[[:cntrl:]])', ' ')) fixed
FROM test_view;
ORIGINAL FIXED
---------------------- ----------------------
Q qwer Q qwer qwerqwer qwerty
qwerqwer qwerty
1 row selected.
If at all anyone is looking to convert data in 1 variable that lies in 2 or 3 different lines like below
'Data1
Data2'
And you want to display data as 'Data1 Data2' then use below
select TRANSLATE ('Data1
Data2', ''||CHR(10), ' ') from dual;
it took me hrs to get the right output. Thanks to me I just saved you 1 or 2 hrs :)
In cases where the Oracle solution seems overly convoluted, I create a java class with static methods and then install it as a package in Oracle. This might not be as performant, but you will eventually find other cases (date conversion to milliseconds for example) where you will find the java fallback helpful.
Below code can be used to Remove New Line and Table Space in text column
Select replace(replace(TEXT,char(10),''),char(13),'')
Try the code below.
It will work if you enter multiple lines in a single column.
create table products (prod_id number , prod_desc varchar2(50));
insert into products values(1,'test first
test second
test third');
select replace(replace(prod_desc,chr(10),' '),chr(13),' ') from products where prod_id=2;
Output :test first test second test third
TRIM(BOTH chr(13)||chr(10)||' ' FROM str)
Instead of using regexp_replace multiple time use (\s) as given below;
SELECT regexp_replace('TEXT','(\s)','')
FROM dual;
Fowloing code remove newline from both side of string:
select ltrim(rtrim('asbda'||CHR(10)||CHR(13) ,''||CHR(10)||CHR(13)),''||CHR(10)||CHR(13)) from dual
but in most cases this one is just enought :
select rtrim('asbda'||CHR(10)||CHR(13) ,''||CHR(10)||CHR(13))) from dual
UPDATE My_Table
SET Mycolumn1 =
TRIM (
TRANSLATE (Mycolumn1,
CHR (10) || CHR (11) || CHR (13),
' '))
WHERE ( INSTR (Mucolumn1, CHR (13)) > 0
OR INSTR (Mucolumn1, CHR (10)) > 0
OR INSTR (Mucolumn1, CHR (11)) > 0);
How can I replace single-quote (') with double-quote (") in sql query - oracle 10g?
This should work:
UPDATE myTable
SET myField = REPLACE(myField, '''', '"');
You can use Ansi-codes as well, to make it more crystal what is happening:
SELECT someString
,replace(someString, Chr(39), Chr(34)) as replacedString
FROM (SELECT ' abc ' || Chr(39) || ' def ' as someString
FROM Dual)
39 is a single quote, 34 a double quote
If you have a variable in single quotes with an apostrophe e.g. 'John's Book', simply insert 2 apostrophes. i.e. 'John''s Book'. NOTE: Do NOT use a double quotation "
This should work:
UPDATE myTable
SET field = replace(your_string,Chr(39),Chr(39)||Chr(39));
Ten bucks says this thing is wide-open to SQL injection and the correct answer is to use parameterization.