I'm trying to set some values to my NSMutableDictionary inside a loop and assigning the dictionary values to an NSMutableArray each time like below,
for(int i=0;i<=lastObj;i++){
[mutableDict setValue:[valuesArray objectAtIndex:i] forKey:#"Name"];
[mutableDict setValue:[uniqueArray objectAtIndex:i] forKey:#"SSN"];
//......then
**[mutableArray addObject:mutableDict];**/*not working perfectly all values s replaced by final mutableDict values (duplicate values)*/
but
**[mutableArray addObject:[mutableDict copy]];**/* Working Correctly !!! */
}
inside loop in each iteration new values is assigned to mutableDictionary and whenever i say just addObject my mutableArray is getting all duplicate values but whenever i say addObject:[mutableDict copy], array is getting correct unique values without any duplicates, i don't know what the difference the compiler feels when i say copy, can anybody tell me the difference in this.
Thanks in advance.
[mutableArray addObject:mutableDict];
keeps on adding mutableDict to mutableArray. adding the object doesnt create a new memory location, it points to the same memory. so when u set the values of mutableDict, it gets reflected in all added objects as they refer to same memory location.
copy creates a new memory location and adds the object removing the above scenario.
to avoid this u can add
for(int i=0;i<=lastObj;i++){
NSMutableDictionary * mutableDict = [NSMutableDictionary new]; //create new memory location
[mutableDict setValue:[valuesArray objectAtIndex:i] forKey:#"Name"];
[mutableDict setValue:[uniqueArray objectAtIndex:i] forKey:#"SSN"];
[mutableArray addObject:mutableDict];
[mutableDict release]; //release
}
hope this helps u. happy coding :)
Looking at your code block, its clear you are allocating mutableDict outside your for loop. Hence When you say below statement inside the for loop, basically you are passing the same object for addition to mutalbeArray.
[mutableArray addObject:mutableDict];
addObject doesnt allocate any memory for objects, but it uses the same object passed and just sends "retain" message to increase the reference count. Since you are passing the same object within the for loop, mutalbeArray would contain the references to same object.
In case of copy say,
[mutableArray addObject:[mutableDict copy]];
the copy message sent to mutableDict returns a new copy which is then passed addObject. Hence every iteration in the forloop passes a new object(due to copy) to addObject.
Also note these following
Copy creates a new object, it should be later released, but your code is not releasing it. This will lead to memory leak.
Copy creates immutable object, hence you should probably use mutableCopy instead if you want objects added to mutableArray to be modified.
Related
What happens if I call [alloc] init] on an object which already was initialized and alloc'ed?
In my particular case I have an NSMutableArray which I initialize in superclass Parent using NSMutableArray* someArray = [NSMutableArray alloc] init];
In subclass Child I need to insert an object in someArray but at a specific index, for example 3.
So if the array has no items, or if it has less items than the index I'm trying to insert at (array has 4 items, and I want to insert at index 10) it will crash.
What would happen if I initialized someArray again in Child class? Would the pointer stored in someArray be replaced with the new one I'm initializing and the "old" one would just leak?
EDIT:
Sorry, my terminology was a bit off. I don't mean doing [someObject alloc], but doing someObject = [SomeClass alloc] init]; where someObject had previoulsy been initialized with an instance of SomeClass
Just for clarity when you say "What happens if I call [alloc] init] on an object..." your terminology is wrong.
The following line:
NSMutableArray* someArray = [[NSMutableArray alloc] init];
Reads in English:
"Send the alloc message to the NSMutableArray class object, then send the init message to the object returned from the first message, then store the object returned from init into the pointer variable named someArray."
I say that to emphasize the fact that you're not "calling alloc/init" on an existing object, you're making a new object, and storing a reference to this new object over the reference you had to the previous object. Since you no longer have a reference to that previous object, you've lost the ability to properly release its memory, so yes, you'll leak it.
correct, it will leak. Use NSMutableArray insertObject:atIndex:
There are a couple of ways that come to mind to do what I think you want. A sort of clumsy one is to put as many [NSNull null] objects into the array as you need so that it's filled up to the spot where you need to add the new object. Then you would replace an existing NSNull if you were storing your own object.
Probably a better approach is to use a dictionary instead of an array and turn your index value into a key.
I wrote a class, which acts as a filter. I pass three objects:
An NSArray, which holds objects to filter (these objects have a timestamp property)
An NSMutableArray (which will hold the section names for a tableView, the periods based on timestamps). I need this array, because I have to sort the periods.
An NSMutableDictionary, in which the keys will be the section names, the values are NSMutableArrays, which hold the items for a given period.
In the class from which I pass these objects, there is a tableView, in which I display the items.
This class has it own NSMutableArray and NSMutableDictionary, I not initialize them, only retain the corresponding return values of the filter class. In the delloc method I release them. There is a method in the filter class:
+ (void)insertItem:(id)item forPeriod:(NSString *)period toContainer:(NSMutableDictionary *)container {
if ( ![[container allKeys] containsObject:period] ) {
// the period isn't stored, create and store it
NSMutableArray *periodArray = [[NSMutableArray alloc] init];
[container setObject:periodArray forKey:period];
[periodArray release];
periodArray = nil;
}
// store the item
NSMutableArray *arrayForPeriod = [container objectForKey:period];
[arrayForPeriod addObject:item];
arrayForPeriod = nil;
}
The instruments shows me leak when I set the newly allocated array as an object of the dictionary. At this point this is definitely true, because the dictionary retains again the array, so after the release, it retain count remains 1. But I think in the caller class when I release the dictionary, the array will be released too. Am I wrong?
Yes it is considered as a leak because your var is a local variable. Then you still have an object in memory but no reference to it. Remember the init makes a retain + the retain made by the dictionary = 2 retains. Just create your array using
NSMutableArray *periodArray = [[[NSMutableArray alloc] init]
autorelease]
Is it clear ?
You could switch to ARC. Alternatively, check what the static analyser thinks of your code. It is pretty good at finding memory leaks, better than most humans.
Once you have a few hundred objects in your dictionary, you waste an awful lot of time and memory. A dictionary doesn't have an array of all keys stashed away somewhere, it has to create it every time you call your method. That's copying a few hundred pointers (cheap) and retaining them (expensive). containsObject for an array compares the object with every object in the array calling isEqual: That's expensive. It's an NSString compare each time. The array is autoreleased, and when it finally goes away, all the keys in it get released. Again expensive.
NSDictionary uses a hash table, so [objectForKey ] will immediately go to the right object. One operation instead of possibly hundreds.
Let's say I've got an array with strings.
NSArray *names = [NSArray arrayWithObjects: #"One", #"Two", #"Three", nil];
What I want is to initiate objects of some custom class and them add them to a mutable array. I'm using a custom init method that takes a string argument.
To be more specific, I want to [SomeClass alloc] initWithName: aName] and add the resulting object to a NSMutableArray.
I'm thinking of using Objective-C fast enumeration. So what I get is:
NSMutableArray *objects = [NSMutableArray arrayWithCapacity: [names count];
for (NSString *name in names) {
[objects addObject: [[[SomeClass alloc] initWithName: name] autorelease]];
}
The problem is that I can't add nil to the array and I don't like exception handling. However, my initiation method may return nil. So I decide to check first before adding (prevention). My new for-in-loop is:
SomeClass *someObject;
for (NSString *name in names) {
someObject = [[[SomeClass alloc] initWithName: name] autorelease];
if (someObject) {
[objects addObject: someObject];
}
}
Now, instead of immediately passing the new object to the array, I'm setting up a pointer someObject first and then passing the pointer to the array instead.
This example raises a question to me. When I someObject = [[[SomeClass alloc] initWithName: name] autorelease] in the loop, do the existing objects (which are added using the same pointer) in the array change too?
To put it in other words: does the addObject: (id)someObject method make a new internal copy of the pointer I pass or do I have to create a copy of the pointer — I don't know how — and pass the copy myself?
Thanks a lot! :-)
It's fine to reuse someObject; if you think about it, you're already reusing name each time you go through the loop.
-addObject: may or may not copy the object that you pass in. (It doesn't -- it retains the object rather than copying it, but it's conceivable that some NSMutableArray subclass could copy instead.) The important thing is that this code really shouldn't care about what -addObject: does.
Also, don't lose sight of the distinction between a pointer and the object that it points to. Pointers are just references, and a pointer is copied each time you pass it into a method or function. (Like C, Objective-C passes parameters by value, so passing a pointer into a method results in putting the value of the pointer on the stack.) The object itself isn't copied, however.
Short answer: no, you don't have to worry about reusing someObject.
Slightly longer answer: the assignment—someObject = ... assigns a new pointer value to the someObject variable; addObject: is then getting that value, not the address of someObject itself.
I think you're getting confused in the concept of pointer here. When you say someObject = [[[SomeClass alloc] init... you are basically pointing the someObject pointer to a new object. So to answer your question- your current code is fine.
As for whether arrays maintain copies of the objects added to them - NO, the array retains the object you add to it. However, that doesn't matter to your code above.
Three20 provides the answer!
I have just started to jump into the realm of Objective-C and am slowly getting it all. I have been working on unarchiving a file that was a NSMutableArray and then initializing in my model with that array. The array is filled with various NSMutableDicationary's. From what I have seen it will add those dictionaries as non-mutable, so I went ahead and copied the regular and put them in a mutable and remove the old one. This solution seems to work for every instance except the very first.
I am at a loss as to why it would work for all but the first.
Here is how I am initializing it all
-(id) initWithList:(NSMutableArray *)savedList
{
self = [super init];
if (self)
{
int size=0;
serverList=[[NSMutableArray alloc] initWithArray:savedList copyItems:YES];
size=[serverList count];
for(int i=0;i<size;i++)
{
loginList=[NSMutableDictionary dictionaryWithDictionary:[serverList objectAtIndex:i]];
[serverList addObject:loginList];
[serverList removeObjectAtIndex:i];
}
}
return self;
}
Here is the code that is throwing the error, The value is being read off of a checkbox in a tableview and passed here to change the value.
-(void)setMount:(int)row value:(NSNumber*)boolAsNumber
{
[[serverList objectAtIndex:row] setObject:boolAsNumber forKey:#"mountshare"];
}
Here is the error that it shows when I try and change the first element
2010-12-01 13:38:54.445 Network Share[35992:a0f] *** -[NSCFDictionary setObject:forKey:]: mutating method sent to immutable object
Thanks for your help. If there is a better way please let me know.
This loop code is wrong:
size=[serverList count];
for(int i=0;i<size;i++)
{
loginList=[NSMutableDictionary dictionaryWithDictionary:[serverList objectAtIndex:i]];
[serverList addObject:loginList];
[serverList removeObjectAtIndex:i];
}
When you remove an object, the array is renumbered. After you've processed the 1st object at index 0, the original 2nd object is becoming the 1st object at index 0, but i is now set to index 1, which is where the original 3rd object is! This means you're only processing alternate items from the original array, and the 2nd, 4th, etc items never get swapped, and that's why you get the errors you're seeing.
One way to solve this would be to replace the "i" in the objectAtIndex: and removeObjectAtIndex: calls with "0", so you're always taking items off the front of the array.
The alternate solution would be to create a separate newServerList array and insert your new objects into that. At the end of the loop, release the old serverList and set the variable to point to newServerList.
Your indexes are messed up. As soon as you remove the object at index 0, the next one will take it's place and you will never replace that, because you then carry on with index 1.
{immutable0, immutable1}
i = 0:
addObject:
{immutable0, immutable1, mutable0}
removeObjectAtIndex:
{immutable1, mutable0}
i = 1:
addObject:
{immutable0, mutable0, mutable02}
removeObjectAtIndex:
{immutable0, mutable02}
--> still got the immutable there. Remember to never remove objects from a mutable array you are looping through at the same time.
You could condense the code a bit:
NSMutableArray *serverList = [NSMutableArray arrayWithCapacity:[savedList count]];
for (NSDictionary *dictionary in savedList)
{
mutable = [dictionary mutableCopy];
[serverList addObject:mutable];
[mutable release];
}
Unrelated to your problem: the argument is obviously wrong (NSMutableArray), if you expect an immutable array there; and if you create your serverList that way, there is no need for a deep copy (copyItems:YES).
sorry for my stupid question (beginner)
I got the demo program Accelerometergraph the apple site and would like to use
NSMutableArray in the values of acceleration x.
but my NSMutableArray contains only one object, there being several passage
NSMutableArray routine and should contain the same number of objects that the counter
show, how code below
if(!isPaused)
{
array = [[NSMutableArray alloc] init];
[filter addAcceleration:acceleration];
[unfiltered addX:acceleration.x y:acceleration.y z:acceleration.z];
NSNumber *number = [[NSNumber alloc] initWithDouble:acceleration.x];
[array addObject:number];
++a;
if (a == 30) // only check the # objs of mutablearray
{
sleep(2);
}
[filtered addX:filter.x y:filter.y z:filter.z];
}
It looks like you're missing a loop of some kind. The code you list above:
Makes sure something isn't paused.
Creates a new (empty) mutable array.
Adds a value to the new array.
And does some other work.
My guess is that this whole if{} block sits inside some kind of loop. You need to alloc and init the mutable array outside of the loop instead.
You create a new array each time the if block is entered, so the addObject: will only add the object to the most recently created array.
Furthermore, you are leaking the array and number objects. Each time you allocate an object, you are responsible for releasing it. Make sure you're familiar with the guidelines set out in the memory management programming guide.