suppose I have following sql table
objid firstname lastname active
1 test test 0
2 test test 1
3 test1 test1 1
4 test2 test2 0
5 test2 test2 0
6 test3 test3 1
Now, the result I am interested in is as follows:
objid firstname lastname active
1 test test 0
2 test test 1
4 test2 test2 0
5 test2 test2 0
How can I achieve this?
I have tried the following query,
select firstname,lastname from table
group by firstname,lastname
having count(*) > 1
But this query gives results like
firstname lastname
test test
test2 test2
You've found your duplicated records but you're interested in getting all the information attached to them. You need to join your duplicates to your main table to get that information.
select *
from my_table a
join ( select firstname, lastname
from my_table
group by firstname, lastname
having count(*) > 1 ) b
on a.firstname = b.firstname
and a.lastname = b.lastname
This is the same as an inner join and means that for every record in your sub-query, that found the duplicate records you find everything from your main table that has the same firstseen and lastseen combination.
You can also do this with in, though you should test the difference:
select *
from my_table a
where ( firstname, lastname ) in
( select firstname, lastname
from my_table
group by firstname, lastname
having count(*) > 1 )
Further Reading:
A visual representation of joins from Coding Horror
Join explanation from Wikipedia
SELECT DISTINCT t1.*
FROM myTable AS t1
INNER JOIN myTable AS t2
ON t1.firstname = t2.firstname
AND t1.lastname = t2.lastname
AND t1.objid <> t2.objid
This will output every row which has a duplicate, basing on firstname and lastname.
Here's a little more legible way to do Ben's first answer:
WITH duplicates AS (
select firstname, lastname
from my_table
group by firstname, lastname
having count(*) > 1
)
SELECT a.*
FROM my_table a
JOIN duplicates b ON (a.firstname = b.firstname and a.lastname = b.lastname)
SELECT user_name,email_ID
FROM User_Master WHERE
email_ID
in (SELECT email_ID
FROM User_Master GROUP BY
email_ID HAVING COUNT(*)>1)
nice option get all duplicated value from tables
select * from Employee where Name in (select Name from Employee group by Name having COUNT(*)>1)
This is the easiest way:
SELECT * FROM yourtable a WHERE EXISTS (SELECT * FROM yourtable b WHERE a.firstname = b.firstname AND a.secondname = b.secondname AND a.objid <> b.objid)
If you want to print all duplicate IDs from the table:
select * from table where id in (select id from table group By id having count(id)>1)
I'm surprised that there is no answer using Window function. I just came across this use case and this helped me.
select t.objid, t.firstname, t.lastname, t.active
from
(
select t.*, count(*) over (partition by firstname, lastname) as cnt
from my_table t
) t
where t.cnt > 1;
Fiddle - https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=c0cc3b679df63c4d7d632cbb83a9ef13
The format goes like
select
tbl.relevantColumns
from
(
select t.*, count(*) over (partition by key_columns) as cnt
from desiredTable t
) as tbl
where tbl.cnt > 1;
This format selects whatever columns you require from the table (sometimes all columns) where the count > 1 for the key_columns being used to identify the duplicate rows. key_columns can be any number of columns.
This answer may not be great one, but I think it is simple to understand.
SELECT * FROM table1 WHERE (firstname, lastname) IN ( SELECT firstname, lastname FROM table1 GROUP BY firstname, lastname having count() > 1);
This Query returns dupliacates
SELECT * FROM (
SELECT a.*
FROM table a
WHERE (`firstname`,`lastname`) IN (
SELECT `firstname`,`lastname` FROM table
GROUP BY `firstname`,`lastname` HAVING COUNT(*)>1
)
)z WHERE z.`objid` NOT IN (
SELECT MIN(`objid`) FROM table
GROUP BY `firstname`,`lastname` HAVING COUNT(*)>1
)
Please try
WITH cteTemp AS (
SELECT EmployeeID, JoinDT,
row_number() OVER(PARTITION BY EmployeeID, JoinDT ORDER BY EmployeeID) AS [RowFound]
FROM dbo.Employee
)
SELECT * FROM cteTemp WHERE [RowFound] > 1 ORDER BY JoinDT
Related
I have a table like this:
ID Name Family Phone_Number
1 A B 123456
2 c d 321456
3 A B
4 A B 456789
I want to delete records 3 and 4.
Try to figure out duplicates and then delete the duplicate rows:
WITH cte AS (
SELECT
FirstName
, LastName
, row_number() OVER(PARTITION BY FirstName, LastName ORDER BY FirstName) AS RN
FROM YourTABLE
)
DELETE cte WHERE RN > 1
An example:
DECLARE #table TABLE
(
ID INT,
FirstName VARCHAR(10),
LastName VARCHAR(10)
);
INSERT INTO #table
(
ID,
FirstName,
LastName
)
VALUES
(1, 'A' , 'B')
, (2, 'c' , 'd')
, (3, 'A' , 'B')
, (4, 'A' , 'B')
Query to delete:
;WITH cte AS (
SELECT
FirstName
, LastName
, row_number() OVER(PARTITION BY FirstName, LastName ORDER BY FirstName) AS RN
FROM #table
)
DELETE cte WHERE RN > 1
SELECT * FROM #table
OUTPUT:
ID FirstName LastName
1 A B
2 c d
Write sql and execute
; WITH TableBWithRowID AS
(
SELECT ROW_NUMBER() OVER (ORDER BY Name, Family) AS RowID, Name, Family
FROM TABLE1
)
DELETE o
FROM TableBWithRowID o
WHERE RowID < (SELECT MAX(rowID) FROM TableBWithRowID i WHERE i.Name =o.Name and i.Family=o.Family GROUP BY Name, Family)
replace TABLE1 with your table name
The below query will delete all the duplicates records based on the first and last name column. Assuming there is no null in the first and last name column.
You just need to provide/change at two places in below query
DELETE FROM <YourTableName>
where Id not in (
SELECT MIN(ID) as RowId
FROM <YourTableName>
GROUP BY FirstName, LastName
)
With EXISTS:
delete t from tablename t
where exists (
select 1 from tablename
where name = t.name and family = t.family and id < t.id
)
See the demo
#SQL Experts,
I am trying to fetch duplicate records from SQL table where 1st Column and 2nd Column values are same but 3rd column values should be different.
Below is my table
ID NAME DEPT
--------------------
1 VRK CSE
1 VRK ECE
2 AME MEC
3 BMS CVL
From the above table , i am trying to fetch first 2 rows, below is the Query, suggest me why isn't give correct results.
SELECT A.ID, A.NAME, A.DEPT
FROM TBL A
INNER JOIN TBL B ON A.ID = B.ID
AND A.NAME = B.NAME
AND A.DEPT <> B.DEPT
Somehow I am not getting the expected results.
Your sample data does not make it completely clear what you want here. Assuming you want to target groups of records having duplicate first/second columns with all third column values being unique, then we may try:
SELECT ID, NAME, DEPT
FROM
(
SELECT ID, NAME, DEPT,
COUNT(*) OVER (PARTITION BY ID, NAME) cnt,
MIN(DEPT) OVER (PARTITION BY ID, NAME) min_dept,
MAX(DEPT) OVER (PARTITION BY ID, NAME) max_dept
FROM yourTable
) t
WHERE cnt > 1 AND min_dept = max_dept;
UPDATE
select *
from
(
select *,
COUNT(*) over (partition by id, [name]) cnt1,
COUNT(*) over (partition by id, [name], dept) cnt2
from dbo.T
) x
where x.cnt1 > 1 and x.cnt2 < x.cnt1;
For find duplicate column
select x.id, x.name, count(*)
from
(select distinct a.id, a.name, a.dept
from tab a) x
group by x.id, x.name
having count(*) > 1
If you want the original rows, I would just go for exists:
select t.*
from tbl t
where exists (select 1
from tbl t
where t2.id = t.id and t2.name = t.name and
t2.dept <> t.dept
);
If you just want the id/name pairs:
select t.id, t.name
from tbl t
group by t.id, t.name
having min(t.dept) <> max(t.dept);
Empid----Name
1 aa
2 bb
3 cc
4 aa
5 bb
I need to get output to print EmpId number for which names are repeated
output Required:
1,2,4,5.
If you are using sql server,use the below script.
;WITH CTE_1 AS
(
SELECT *,COUNT(1)OVER(PARTITION BY Name ORDER BY Name) CNT
FROM [YourTable]
)
SELECT ID
FROM [CTE_1]
WHERE CNT > 1
Try this
select empid from table
where name in (select name from table group by name having count(*)>1)
SELECT *
FROM table AS parent
WHERE EXISTS(
SELECT *
FROM table AS sub
WHERE sub.Name == parent.Name && parent.Empid <> sub.Empid
)
Try this.
select distinct t.Empid from
#Your_Table t inner join
(
select Name, COUNT (Name) as count
from #Your_Table
group by Name
having COUNT (Name) > 1
)a on a.Name=t.Name
order by t.Empid
SELECT * FROM (
SELECT ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Name) RowNo,*
From Your_Table
) a
WHERE RowNo > 1
Is there a way to union two tables, but keep the rows from the first table appearing first in the result set? However orderby column is not in select query
For example:
Table 1
name surname
-------------------
John Doe
Bob Marley
Ras Tafari
Table 2
name surname
------------------
Lucky Dube
Abby Arnold
Result
Expected Result:
name surname
-------------------
John Doe
Bob Marley
Ras Tafari
Lucky Dube
Abby Arnold
I am bringing Data by following query
SELECT name,surname FROM TABLE 1 ORDER BY ID
UNION
SELECT name,surname FROM TABLE 2
The above query is not keeping track of order by after union.
P.S - I dont want to show ID in my select query
I am getting ORDER BY Column by joining tables. Following is my real query
SELECT tbl_Event_Type_Sort_Orders.Appraisal_Event_Type_ID AS Appraisal_Event_Type_ID , ISNULL(tbl_Appraisal_Event_Types.Appraisal_Event_Type_Display_Name, 'UnCategorized') AS Appraisal_Event_Type_Display_Name
INTO #temptbl
FROM tbl_Event_Type_Sort_Orders
INNER JOIN tbl_Appraisal_Event_Types
ON tbl_Event_Type_Sort_Orders.Appraisal_Event_Type_ID = tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID
WHERE 1=1
AND User_Name='abc'
ORDER BY tbl_Event_Type_Sort_Orders.Sort_Order
SELECT * FROM #temptbl
UNION
SELECT DISTINCT (tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID) AS Appraisal_Event_Type_ID , ISNULL(tbl_Appraisal_Event_Types.Appraisal_Event_Type_Display_Name, 'UnCategorized') AS Appraisal_Event_Type_Display_Name
FROM tbl_Appraisal_Event_Types
INNER JOIN tbl_Appraisal_Events
ON tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID = tbl_Appraisal_Events.Event_Type_ID
INNER JOIN tbl_Appraisals
ON tbl_Appraisal_Events.Appraisal_ID = tbl_Appraisal_Events.Appraisal_ID
WHERE 1=1
AND ((tbl_Appraisals.Assigned_To_Staff_User) = 'abc' OR (tbl_Appraisals.Assigned_To_Staff_User2) = 'abc' OR (tbl_Appraisals.Assigned_To_Staff_User3) = 'abc')
Put a UNION ALL in a derived table. To keep duplicate elimination, do select distinct and also add a NOT EXISTS to second select to avoid returning same person twice if found in both tables:
select name, surname
from
(
select distinct name, surname, 1 as tno
from table1
union all
select distinct name, surname, 2 as tno
from table2 t2
where not exists (select * from table1 t1
where t2.name = t1.name
and t2.surname = t1.surname)
) dt
order by tno, surname, name
You can use a column for the table and one for the ID to order by:
SELECT x.name, x.surname FROM (
SELECT ID, TableID = 1, name, surname
FROM table1
UNION ALL
SELECT ID = -1, TableID = 2, name, surname
FROM table2
) x
ORDER BY x.TableID, x.ID
You can write as below, if you are ok with duplicate data then please use UNION ALL it will be faster:
SELECT NAME, surname FROM (
SELECT ID,name,surname FROM TABLE 1
UNION
SELECT ID,name,surname FROM TABLE 2 ) t ORDER BY ID
this will order the first row sets first then by anything you need
(haven't tested the code)
;with cte_1
as
(SELECT ID,name,surname,1 as table_id FROM TABLE 1
UNION
SELECT ID,name,surname,2 as table_id FROM TABLE 2 )
SELECT name, surname
FROM cte_1
ORDER BY table_id,ID
simply use a UNION clause with out order by.
SELECT name,surname FROM TABLE 1
UNION
SELECT name,surname FROM TABLE 2
if you wanted to order first table use the below query.
;WITH cte_1
AS
(SELECT name,surname,ROW_NUMBER()OVER(ORDER BY Id)b FROM TABLE 1 )
SELECT name,surname
FROM cte_1
UNION
SELECT name,surname
FROM TABLE 2
I have a SQL query question.
I have a table with first name, last name and mobile numbers of clients.
Thor Prestby 98726364
Thor Prestby 98726364
Lars Testrud 12938485
Lise Robol 12938485
I want to find rows with the same mobile number, that have different names. As you see above Thor has 2 rows, and that's right. Lars and Lise have the same mobile number and that is what I want to find.
You pretty much outlined yourself the actions needed to take in your question.
In a nutshell
use a subselect to get all the distinct rows
group on mobilenumber from this unique resultset from the subselect
retain only those mobilenumbers that occur at least twice
SQL Statement
SELECT mobilenumber, COUNT(*)
FROM (
SELECT DISTINCT mobilenumber, firstname, lastname
FROM YourTable
) AS q
GROUP BY
mobilenumber
HAVING COUNT(*) > 1
I am assuming that you are using MS SQL Server here but you could use:
Declare #t table
(
FirstName varchar(100),
LastName varchar(100),
Mobile bigint
)
Insert Into #t
values ('Thor','Prestby',98726364),
('Thor','Prestby', 98726364),
('Lars','Testrud',12938485),
('Lise','Robol', 12938485),
('AN','Other', 12345868)
Select Mobile
From #t
Group By Mobile
Having Count(*) > 1
EXCEPT
Select Mobile
From #t
Group By FirstName, LastName, Mobile
Having Count(*) > 1
SELECT * FROM the_table tt
WHERE EXISTS (
SELECT * FROM the_table xx
WHERE xx.mobineno = tt.mobileno
AND (xx.fname <> tt.fname OR xx.lname <> tt.lname)
);
For this records:
Thor Prestby 98726364
Thor Prestby 98726364
Lars Testrud 12938485
Lise Robol 12938485
AN Other 12345868
Try it:
select t.mobile, count(*) from new_table t
where t.mobile in
(select t1.mobile from new_table t1
where t1.mobile=t.mobile
group by t1.firstname, t1.lastname, t1.mobile
having count(*)=1)
group by t.mobile
having count(*)>1
You will get this result:
12938485 2
SELECT t1.phone, count(t1.phone) CountNo
FROM (SELECT distinct * FROM YourTable) t1
Left Outer Join YourTable t2 ON t1.phone = t2.phone AND ( t1.FirstName <> t2.FirstName OR t1.LastName <> t2.LastName)
WHERE t2.FirstName IS NOT NULL
GROUP BY t1.phone
HAVING count(t1.phone) > 1
ORDER BY CountNo desc
I am using standard SQL syntax and joins to achieve the results
Setup:
create table dummy
(
firstname varchar2(20),
lastname varchar2(20),
phone number
);
insert into dummy values('Thor','Prestby',98726364);
insert into dummy values('Thor','Prestby',98726364);
insert into dummy values('Lars','Testrud',12938485);
insert into dummy values('Lise','Robol',12938485);
Query:
select a.firstname,a.lastname,a.phone from dummy a inner join dummy b
on a.phone=b.phone and a.firstname != b.firstname and a.lastname != b.lastname;
Result
FIRSTNAME LASTNAME PHONE
-------------------- -------------------- ----------------------
Lise Robol 12938485
Lars Testrud 12938485