Covert a column of string dates - sql
I have 2 columns in access that are saved as string dates yyyymmdd. I am linking the table to a oracle database and need to coveret the columns on insert to look like yyyy/mm/dd.
I am trying:
INSERT INTO TEST
(DATE) Values (20110818, To_DATE("YYYY/MM/DD"))
FROM TEST_DATE
I want to convert the entire column on insert from access into oracle
Try like this
INSERT INTO TEST
(DATE)
SELECT TO_DATE('20110818','YYYYMMDD')
FROM TEST_DATE
Related
How to convert a string column into a date column
Imported a date column from a CSV file where there are string values are shown as date 44705 44704 44703 I want to convert the entire column into a date format as date "2022-05-22" "2022-05-21" "2022-05-20" I have used this script which allowed me to generate the result. SELECT dateadd(d,44703,'1899-12-30') as date The question is, how could I apply this script for a range of values (there are 700 rows in the table). e.g 44000 to 44705. I would like all string values to be converted as a date format.
select cast (44705-1 as smalldatetime) gives 2022-05-25 00:00 So you could just update the column using the above. See https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=dc24abb3025e0f3796e7d978ba406be3 New fiddle with update statement, this line will update all rows, as per test. update #test set pdate = cast(dateadd(d,tdate-2,'1899-12-30') as smalldatetime)
To convert a string to date we can add temporary date column and fill it and delete old column and rename new one to old one alter table TableName add NewColumnName date null; --create temporary column update TableName set NewColumnName =dateadd(d,cast(cast([date] as float) as int)-2,'1899-12-30') --fill it alter table TableName drop column [date]--delete old column EXEC sp_RENAME 'TableName.NewColumnName' , 'date', 'COLUMN'--rename new one to old one
Dates inserting incorrectly - SQL
Dates are not inserting correctly to table, any explanation / solution? create table test ( ID bigint, MarketOpen datetime ); insert into test (ID, MarketOpen) values (1, 2019-01-19-11-40-00); select * from test; Fiddle
Thats totally the wrong way to enter a date. SQL Server is treating your current syntax as a calculation e.g. 2019-01-19-11-40-00=1948 and then converting the number 1948 to a datetime. You need to use a formatted string e.g. insert into #test (ID, EventId, MarketId, RaceDate, MarketOpen, HorseID) values (1, 123, 153722767, '2019-01-19 11:40:00', '2019-01-18 11:40:00', 34434); Note: As mentioned by seanb its best practice to use a non-ambiguous format when specifying dates and the ISO format (yyyymmdd) is probably the best of these.
How to convert two types of dates format into one date format in SQL?
I have three table in the database two of them contain dates however the dates are in two format, first 20-02-2011 and second is 25/09/2018. Let say each table have 10000 records and mixed with these two types of dates format. This why I why I create the column like --- (Transaction_Date, Varchar(10) Not Null) I tried convert (Varchar(10),Transaction_Date,105) and also tried replace(convert(varchar(10),Transaction_Date,105),'/','-') However date and year functions are still not working. Please suggest a possible way.
How about this? select replace(date, replace(Transaction_Date, '/', '-'), 105) That is: (1) convert to a date and (2) replace the slash before converting.
You need to remember about your culture. Saved format vs server culture. But this is very possible select Cast('2-22-2011' as datetime) f1, Cast('2/22/2011' as datetime) f2 I other words just use Cast select cast(Transaction_Date as datetime) . . . But you should as soon as possible get rid of columns that saves date as string and create new date/time column, and insert your date values there alter table tbl add column temp datetime update tbl set temp = Cast(Transaction_Date as datetime) alter table tbl drop column Transaction_Date alter table tbl add column Transaction_Date datetime update tbl set Transaction_Date = temp alter table tbl drop column temp
Postgres Data type conversion
I have this dataset that's in a SQL format. However the DATE type needs to be converted into a different format because I get the following error CREATE TABLE INSERT 0 1 INSERT 0 1 INSERT 0 1 INSERT 0 1 ERROR: date/time field value out of range: "28-10-96" LINE 58: ...040','2','10','','P13-00206','','','','','1-3-95','28-10-96'... ^ HINT: Perhaps you need a different "datestyle" setting. I've definitely read the documentation on date format http://www.postgresql.org/docs/current/static/datatype-datetime.html But my question is how do I convert all of the dates in a proper format without going through all the 500 or so data rows and making sure each one is correct before inserting into a DB. Backend is handle by rails, but I figured going through SQL to cleaning it up will be best here. I have a CREATE TABLE statement above this dataset, and mind you the data set was given to be via a DBF converter/external source Here's part of my dataset INSERT INTO winery_attributes (ID,NAME,STATUS,BLDSZ_ORIG,BLDSZ_CURR,HAS_CAVE,CAVESIZE,PROD_ORIG,PROD_CURR,TOUR_TASTG,VISIT_DAY,VISIT_WEEK,VISIT_YR,VISIT_MKTG,VISIT_NMEV,VISIT_ALL,EMPLYEENUM,PARKINGNUM,WDO,LAST_UP,IN_CITYBDY,IN_AIASP,NOTES,SMLWNRYEXM,APPRV_DATE,ESTAB_DATE,TOTAL_SIZE,SUBJ_TO_75,GPY_AT_75,AVA,SUP_DIST) VALUES (1,'ACACIA WINERY','PROD','8000','34436','','0','50000','250000','APPT','75','525','27375','3612','63','30987','22','97','x','001_02169-MOD_AcaciaWinery','','','','','1-11-79','1-9-82','34436','x','125000','Los Carneros','1'); INSERT INTO winery_attributes (ID,NAME,STATUS,BLDSZ_ORIG,BLDSZ_CURR,HAS_CAVE,CAVESIZE,PROD_ORIG,PROD_CURR,TOUR_TASTG,VISIT_DAY,VISIT_WEEK,VISIT_YR,VISIT_MKTG,VISIT_NMEV,VISIT_ALL,EMPLYEENUM,PARKINGNUM,WDO,LAST_UP,IN_CITYBDY,IN_AIASP,NOTES,SMLWNRYEXM,APPRV_DATE,ESTAB_DATE,TOTAL_SIZE,SUBJ_TO_75,GPY_AT_75,AVA,SUP_DIST) VALUES ('2','AETNA SPRING CELLARS','PROD','2500','2500','','0','2000','20000','TST APPT','0','3','156','0','0','156','1','10','x','','','','','x','1-4-86','1-6-86','2500','','0','Napa Valley','3'); INSERT INTO winery_attributes (ID,NAME,STATUS,BLDSZ_ORIG,BLDSZ_CURR,HAS_CAVE,CAVESIZE,PROD_ORIG,PROD_CURR,TOUR_TASTG,VISIT_DAY,VISIT_WEEK,VISIT_YR,VISIT_MKTG,VISIT_NMEV,VISIT_ALL,EMPLYEENUM,PARKINGNUM,WDO,LAST_UP,IN_CITYBDY,IN_AIASP,NOTES,SMLWNRYEXM,APPRV_DATE,ESTAB_DATE,TOTAL_SIZE,SUBJ_TO_75,GPY_AT_75,AVA,SUP_DIST) VALUES ('3','ALTA VINEYARD CELLAR','PROD','480','480','','0','5000','5000','NO','0','4','208','0','0','208','4','6','x','003_U-387879','','','','','2-5-79','1-9-80','480','','0','Diamond Mountain District','3'); INSERT INTO winery_attributes (ID,NAME,STATUS,BLDSZ_ORIG,BLDSZ_CURR,HAS_CAVE,CAVESIZE,PROD_ORIG,PROD_CURR,TOUR_TASTG,VISIT_DAY,VISIT_WEEK,VISIT_YR,VISIT_MKTG,VISIT_NMEV,VISIT_ALL,EMPLYEENUM,PARKINGNUM,WDO,LAST_UP,IN_CITYBDY,IN_AIASP,NOTES,SMLWNRYEXM,APPRV_DATE,ESTAB_DATE,TOTAL_SIZE,SUBJ_TO_75,GPY_AT_75,AVA,SUP_DIST) VALUES ('4','BLACK STALLION','PROD','43600','43600','','0','100000','100000','PUB','50','350','18200','0','0','18200','2','45','x','P13-00391','','','','','1-5-80','1-9-85','43600','','0','Oak Knoll District of Napa Valley','3'); INSERT INTO winery_attributes (ID,NAME,STATUS,BLDSZ_ORIG,BLDSZ_CURR,HAS_CAVE,CAVESIZE,PROD_ORIG,PROD_CURR,TOUR_TASTG,VISIT_DAY,VISIT_WEEK,VISIT_YR,VISIT_MKTG,VISIT_NMEV,VISIT_ALL,EMPLYEENUM,PARKINGNUM,WDO,LAST_UP,IN_CITYBDY,IN_AIASP,NOTES,SMLWNRYEXM,APPRV_DATE,ESTAB_DATE,TOTAL_SIZE,SUBJ_TO_75,GPY_AT_75,AVA,SUP_DIST) VALUES ('5','ALTAMURA WINERY','PROD','11800','11800','x','3115','50000','50000','APPT','0','20','1040','0','0','1040','2','10','','P13-00206','','','','','1-3-95','28-10-96','14915','x','50000','Napa Valley','4');
The dates in your data set are in the form of a string. Since they are not in the default datestyle (which is YYYY-MM-DD) you should explicitly convert them to a date as follows: to_date('1-5-80', 'DD-MM-YY') If you store the data in a timestamp instead, use to_timestamp('1-5-80', 'DD-MM-YY') If you are given the data set in the form of the INSERT statements that you show, then first load all the data as simple strings into varchar columns, then add date columns and do an UPDATE (and similarly for integer and boolean columns): UPDATE my_table SET estab = to_date(ESTAB_DATE, 'DD-MM-YY'), -- column estab of type date apprv = to_date(APPRV_DATE, 'DD-MM-YY'), -- etc ... When the update is done you can ALTER TABLE to drop the text columns with dates (integers, booleans).
INSERT INTO SELECT FROM ACCESS TO ORACLE
I have a table in Access named TEST_DATE1 with the column TEST_DATE that is a String datatype and the records look like 20080130. yyyymmdd I have a table in Oracle named TEST with the column TEST_DATE that is a DATE datatype and I want the records to look like 2008/01/30 yyyy/mm/dd. I have the two tables linked and when I usually update tables between Access and Oracle I usually do a INSERT INTO TEST SELECT * FROM TEST_DATE1; How would you convert the string to a DATE using the INSERT INTO SELECT I have tried INSERT INTO TEST (SELECT TO_DATE(TEST_DATE, 'yyyy/mm/dd')) FROM TEST_DATE1; Thanks!
To move the records to Oracle, converting a string to a date: INSERT INTO test (test_date) SELECT TO_DATE(test_date, 'YYYYMMDD') FROM test_date1 Once it's in Oracle stored as a date, you can retrieve it in any format you like: SELECT TO_CHAR(test_date, 'YYYY/MM/DD') as test_date FROM test;