I read data from a excel file.
The cols of internal table all are char128, there are 2 cols contain only digital with decimal point. So I need to check the fields only contain digital or digital with decimal point.
The function module NUMERIC_CHECK, just can check only digital, if the digital with decimal point it will be useless.
You may use CO (contains only):
IF value CO '1234567890.'.
"OK
ELSE.
"Error"
ENDIF.
Maybe you need also a space in your IF _ CO-statement.
This check does not detect multiple decimals points (e.g. 123.45.67.89).
Newer versions of ABAP support regular expressions.
If you have also spaces in your string, you may add them into the CO-value:: IF value CO '1234567890 .'.
You might try to use REGEX. The report DEMO_REGEX_TOY lets you input strings and test regular expressions against them.
Someone more experienced with REGEX in general might be able to make this a little more versatile but here's what I came up with:
-?[0-9]+(\.[0-9]*)?
-? Optionally match the '-' character (allows for negatives or non-negatives
[0-9]+ matches digits (the + makes it match 1 or more)
\.? optionally matches the '.' character (the \ is needed as '.' is an operator)
([0-9]+)? optionally matches any digits after the decimal
if you want to check if the string is a valid decimal, you could use the following module function : 'HRCM_STRING_TO_AMOUNT_CONVERT', which allow you to convert a string to its numeric counterpart, given the string, the decimal separator and the thousand separator.
regards
Another way to check for number:
data: float_value type f.
try.
float_value = <your string value here>.
catch cx_sy_conversion_no_number.
" not a valid number
endtry.
Related
I'm currently trying to read from a CSV files ( separated with semicolon ';') with decimal numbers formatted with a comma(,) as a decimal separator instead of a dot (.).
i.e: the number 12356.12 is stored as 12356,12.
In the source's projection, what would be the correct format to read the value correctly?
The format should in Java Decimal Format
If your CSV file's columnDelimiter is a comma (','), your first concern is how to avoid your number data won't be treated as different columns. Since your number data is stored as 12356,12, so my suggests as below :
Change the columnDelimiter as | or other special characters.
2.Set escape char. Please see this description:
In addition, 12356,12 can't be identified as Decimal format in ADF automatically. And no such mechanism o turn , into .. So I think you need to transfer data as string temporary. Then convert it into Decimal in your destination with java code.
True answer is in the comments: In the copy job the culture can be defined, which influences the decimal separator. Go to "mapping" > "Type conversion settings" > "culture" and chose en-us, de-de or whatever works for you. Be aware that this will also influence other types like dates.
I'm trying to figure out the base regex to capture the middle of a google url out of a sql database.
For example, a few links:
https://www.google.com/cars/?year=2016&model=dodge+durango&id=1234
https://www.google.com/cars/?year=2014&model=jeep+cherokee+crossover&id=6789
What would be the regex to capture the text to get dodge+durango , or jeep+cherokee+crossover ? (It's alright that the + still be in there.)
My Attempts:
1)
\b[=.]\W\b\w{5}\b[+.]?\w{7}
, but this clearly does not work as this is a hard coded scenario that would only work like something for the dodge durango example. (would extract "dodge+durango)
2) Using positive lookback ,
[^+]( ?=&id )
but I am not fully sure how to use this, as this only grabs one character behind the & symbol.
How can I extract a string of (potentially) any length with any amount of + delimeters between the "model=" and "&id" boundaries?
seems like you could use regexp_replace and access match groups:
regexp_replace(input, 'model=(.*?)([&\\s]|$)', E'\\1')
from here:
The regexp_replace function provides substitution of new text for
substrings that match POSIX regular expression patterns. It has the
syntax regexp_replace(source, pattern, replacement [, flags ]). The
source string is returned unchanged if there is no match to the
pattern. If there is a match, the source string is returned with the
replacement string substituted for the matching substring. The
replacement string can contain \n, where n is 1 through 9, to indicate
that the source substring matching the n'th parenthesized
subexpression of the pattern should be inserted, and it can contain \&
to indicate that the substring matching the entire pattern should be
inserted. Write \ if you need to put a literal backslash in the
replacement text. The flags parameter is an optional text string
containing zero or more single-letter flags that change the function's
behavior. Flag i specifies case-insensitive matching, while flag g
specifies replacement of each matching substring rather than only the
first one
I may be misunderstanding, but if you want to get the model, just select everything between model= and the ampersand (&).
regexp_matches(input, 'model=([^&]*)')
model=: Match literally
([^&]*): Capture
[^&]*: Anything that isn't an ampersand
*: Unlimited times
I want to check if an email address fits a pattern:
-Only letters, numbers, and '.' or '_' symbols.
-The last part (ex: .com) must contain between 2 and 4 letters.
This is my Reg Exp: '[a-zA-Z0-9._]+#[a-zA-Z0-9._]+.[a-zA-Z]{2,4}'
The problem is that it accepts symbols like %, and .commmm is accepted as the last part. How could I solve it?
The main problems are actually two here:
You are using an unescaped . outside the character class that may match any symbol (but a newline)
You are not using anchors ^ and $, and thus you may match substring inside a larger string.
Use
'^[a-zA-Z0-9._]+#[a-zA-Z0-9._]+[.][a-zA-Z]{2,4}$'
^ ^^^ ^
When you place a . into a pair of square brackets, you match a literal period.
I think you just need ^ and $ to specify the beginning and end of the string:
'^[a-zA-Z0-9.]+#[a-zA-Z0-9.]+.[a-zA-Z]{2,4}$'
You might want to slightly adjust the rules so the email and domain cannot start with a period:
'^\w[a-zA-Z0-9.]*#\w[a-zA-Z0-9.]*.[a-zA-Z]{2,4}$'
I would like a regular expression to find the %s in the source string that don't form the start of a valid two-hex-digit escaped character (defined as a % followed by exactly two hexadecimal digits, upper or lower case) that can be used to replace only these % symbols with %25.
(The motivation is to make the best guess attempt to create legally escaped strings from strings of various origins that may be legally percent escaped and may not, and may even be a mixture of the two, without damaging the data intent if the original string was already correctly encoded, e.g. by blanket re-encoding).
Here's an example input string.
He%20has%20a%2050%%20chance%20of%20living%2C%20but%20there%27s%20only%20a%2025%%20chance%20of%20that.
This doesn't conform to any encoding standard because it is a mix of valid escaped characters eg. %20 and two loose percentage symbols. I'd like to convert those %s to %25s.
My progress so far is to identify a regex %[0-9a-z]{2} that finds the % symbols that are legal but I can't work out how to modify it to find the ones that aren't legal.
%(?![0-9a-fA-F]{2})
Should do the trick. Use a look-ahead to find a % NOT followed by a valid two-digit hexadecimal value then replace the found % symbol with your %25 replacement.
(Hopefully this works with (presumably) NSRegularExpression, or whatever you're using)
%(?![a-fA-F0-9]{2})
That's a percent followed by a negative lookahead for two hex digits.
I have a Sql statament using special character (ex: ('), (/), (&)) and I don't know how to write them in my VB.NET code. Please help me. Thanks.
Find out the Unicode code point for the character (from http://www.unicode.org) and then use ChrW to convert from the code point to the character. (To put this in another string, use concatenation. I'm somewhat surprised that VB doesn't have an escape sequence, but there we go.)
For example, for the Euro sign (U+20AC) you'd write:
Dim euro as Char = ChrW(&H20AC)
The advantage of this over putting the character directly into source code is that your source code stays "just pure ASCII" - which means you won't have any strange issues with any other program trying to read it, diff it, etc. The disadvantage is that it's harder to see the symbol in the code, of course.
The most common way seems to be to append a character of the form Chr(34)... 34 represents a double quote character. The character codes can be found from the windows program "charmap"... just windows/Run... and type charmap
If you are passing strings to be processed as SQL statement try doubling the characters for example.
"SELECT * FROM MyRecords WHERE MyRecords.MyKeyField = ""With a "" Quote"" "
The '' double works with the other special characters as well.
The ' character can be doubled up to allow it into a string e.g
lSQLSTatement = "Select * from temp where name = 'fred''s'"
Will search for all records where name = fred's
Three points:
1) The example characters you've given are not special characters. They're directly available on your keyboard. Just press the corresponding key.
2) To type characters that don't have a corresponding key on the keyboard, use this:
Alt + (the ASCII code number of the special character)
For example, to type ¿, press Alt and key in 168, which is the ASCII code for that special character.
You can use this method to type a special character in practically any program not just a VB.Net text editor.
3) What you probably looking for is what is called 'escaping' characters in a string. In your SQL query string, just place a \ before each of those characters. That should do.
Chr() is probably the most popular.
ChrW() can be used if you want to generate unicode characters
The ControlChars class contains some special and 'invisible' characters, plus the quote - for example, ControlChars.Quote