I've read through a lot of examples, but the problem I'm facing is the date I'm getting doesn't have leading 0's and all the objective-c stuff I've found has them. So I need to take the date:
4/9/2012 1:30 PM
And determine if it is today. My place was to either grab today's date and compare it to the first part of that string, but as I said before I can't find anyway to make a date in objective c without leading 0's. I'm hoping to avoid parsing that string manually to add leading 0's.
Use an NSDateFormatter object
[dateFormatter setDateFormat:#"h:mm a"];
if you want 0's
[dateFormatter setDateFormat:#"hh:mm a"];
I think that using the single M option for your date format string will allow it to parse a single digit month value:
The possible date formats are specified here
#ynistersix answer is correct. In Data Formatting Guide, they said that NSDateFormatter follows http://unicode.org/reports/tr35/tr35-dates.html
h 1..2 11 Hour [1-12]. When used in skeleton data or in a skeleton
passed in an API for flexible date pattern generation, it should match
the 12-hour-cycle format preferred by the locale (h or K); it should
not match a 24-hour-cycle format (H or k). Use hh for zero padding.
This is consistent with most other languages. Like .NET
"h" The hour, using a 12-hour clock from 1 to 12.
2009-06-15T01:45:30 -> 1
2009-06-15T13:45:30 -> 1
"hh" The hour, using a 12-hour clock from 01 to 12.
2009-06-15T01:45:30 -> 01
2009-06-15T13:45:30 -> 01
Related
I am using jqwidgets-datetimeinput to display and input formatted date. It is working fine for most of the use cases but for the format d MMMM yyyy it is not behaving correctly.
it is showing as 6/11/2020 June 2020 instead of 11 June 2020
Interesting. I think you just found one of the many bugs/"features" that plague jqWidgets.
Upon further investigation, this seems to happen when d is the end of the format string, or is followed by a space character. To get around this, you can use a non-breaking space:
'd\u00a0MMMM yyyy'
If you're on Windows, you can also do Alt+0160 to type it out, but this may be unwise, as the two characters look identical.
I have inherited some code and am very new to VB.
The code is basically being fed decimal values, these are being converted into the Hex equivalent and (I think) the Format function is being used to make sure only 2 characters (i.e. a byte) are being used in another string.
The problem is this, when the Format function encounters a Hex value that Ends in an 'A', it seems to convert the string into a time format of some sort.
Example:
"4A" converts to 04:00:00
"7A" converts to 07:00:00
Here's the relevant code snippet:
Format("4A")
In the actual code I'd get a "00", as the function has the following optional additions:
Format("0A","00")
I'm assuming the "A" is some special character.
Anybody have an idea around this quirk? Thanks in advance!
A is being interpreted as AM just as P would be PM and output 16:00.
Format() is likely not the correct thing to use here, it would only pad as you want it to if the input were a number.
Better to pad after you convert the base:
hexa = Hex$(i)
If (i < 16) Then hexa = "0" & hexa
I have an excel created from a comma-delimited text file originally from a .sql file with an SQL INSERT query.
In one of the columns I have: "Cast(0x123456AB...) As TIME
Obviously this is NOT the jsondate format... so no help from that question...
I replaced the Cast( and replaced the ") As TIME" with empty strings.
So now I have the time values in hexadecimal.
How do I convert them into Excel Time or Datetime?
OK Playing around with it showed me that it's exactly the same as the jquery date answer. You take the numeric portion starting with 0x.
Take the 10 digits AFTER the 0x. e.g. in A2: =MID(A1, 3, 10)
Turn it into hexadecimal e.g. in A3: = HEX2DEC(A2)
Divide by 86400 e.g. A4: =A3/86400
And add the result to 1/1/1970 date. e.g. = A5: =A4 + Date(1970, 1, 1)
Or in short:
=(hex2dec(mid(a1,numstart,10))/86400) + date(1970,1,1)
Replace numstart with the 1-starting index of the number.
e.g. 3 if you have a 12 or 13 digit number like 0x12345678AB and you'll get 12345678AB
This is similar to the Convert JSON Date /Date(1388624400000)/ to Date in Excel
Except that:
a. The question was answered wrong and wouldn't work. (I edited it)
b. The .sql file was retrieved in a stored procedure from the database via SQL. While in the question they were using jquery returned ajax data, which seemed to differ. Turns out they're the same number with a different format.
As an added remark, I had a space mark at the beginning of my hex number. Until I did the MID on it, I didn't see that.
Note: When using ajax returned formatted dates like /date:0x12345678ab/ you'll set numstart to 8. If hex2dec fails, try turning the hex string into uppercase
before calling hex2dec. To debug just put each formula in a separate cell, so you see what works and what doesn't.
I am having an issue trying to parse an Atom RFC 3339 date coming from a feed. Is is coming in is form: #"2014-07-21T11:36:05-05:00" and the following formats fail to parse it... any help?
[dateFormatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ssZZZ"];
[dateFormatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ss.SSSZZZ"];
[dateFormatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ss"];
[dateFormatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ss.ZZZZ"];
The format you need is
yyyy-MM-dd'T'HH:mm:ssZZZZZ
The five Z pattern is a recent-ish addition to the formatting library that handles exactly this time zone format.
(Despite Apple's Technical Q&A 1480 on this topic (and the identical code in the date formatting guide), the only item in the format string that needs to be escaped with apostrophes is the T -- Unicode Technical Standard #35, which governs the format strings, says that only ASCII letters, a-z and A-Z, are reserved. It also says, however, that punctuation may be used in the future, so you can quote the colons and hyphens if you like.)
I have banged my head against this for too long now!
I have a string: 2012-09-27T18:00:00.000-04:00
I have a format: [dateFormatter setDateFormat:#"yyyy-MM-dd'T'HH:mm:ss'Z'"];
I get a null result converting the string.
Can someone help with the correct date format?
According to the documentation for NSDateFormatter:
The format string uses the format patterns from the Unicode Technical Standard #35. The version of the standard varies with release of the operating system:
Formatters in OS X v10.8 and iOS 6.0 use [version tr35-25].
Following that link:
s 1..2 12 Second. Use one or two for zero padding.
In other words, s for seconds means only the integral part.
But right underneath that, there's:
S 1..n 3456 Fractional Second - truncates (like other time fields) to the count of letters. (example shows display using pattern SSSS for seconds value 12.34567)
Then, the reason you aren't matching the timezone is that you're quoting the Z, so it matches a literal Z rather than a timezone format.
To match the ISO8601 timezone format you're seeing, the same documentation says you want ZZZZZ.
So, it looks like, at least for 10.8/iOS 6, you want:
[dateFormatter setDateFormat:#"yyyy-MM-dd'T'HH:mm:ss'.'SSSZZZZZ"]
For earlier versions, you've got the links to the docs; you should be able to figure it out now.
Testing this (in Python, to save a few lines of code):
>>> import Cocoa
>>> df = Cocoa.NSDateFormatter.alloc().init()
>>> df.setDateFormat_("yyyy-MM-dd'T'HH:mm:ss'.'SSSZZZZZ")
>>> print df.dateFromString_(2012-09-27T18:00:00.000-04:00')
2012-09-27 22:00:00 +0000