Oracle SQL -- find the values NOT in a table - sql

Question

Take this table WORDS
WORD
Hello
Aardvark
Potato
Dog
Cat
And this list:
('Hello', 'Goodbye', 'Greetings', 'Dog')
How do I return a list of words that AREN'T in the words table, but are in my list?
If I have a table that "contains all possible words", I can do:
SELECT * from ALL_WORDS_TABLE
where word in ('Hello', 'Goodbye', 'Greetings', 'Dog')
and word not in
(SELECT word from WORDS
where word in ('Hello', 'Goodbye', 'Greetings', 'Dog')
);
However I do not have such a table. How else can this be done?
Also, constructing a new table is not an option because I do not have that level of access.

Answer 1

Instead of hard coding the list values into rows, use DBMS_DEBUG_VC2COLL to dynamically convert your delimited list into rows, then use the MINUS operator to eliminate rows in the second query that are not in the first query:
select column_value
from table(sys.dbms_debug_vc2coll('Hello', 'Goodbye', 'Greetings', 'Dog'))
minus
select word
from words;

Answer 2

Try this solution :
SELECT
a.word
FROM
(
SELECT 'Hello' word FROM DUAL UNION
SELECT 'Goodbye' word FROM DUAL UNION
SELECT 'Greetings' word FROM DUAL UNION
SELECT 'Dog' word FROM DUAL
) a
LEFT JOIN ALL_WORDS_TABLE t ON t.word = a.word
WHERE
t.word IS NULL

Answer 3

You can turn your list into a view like this:
select 'Hello' as word from dual
union all
select 'Goodbye' from dual
union all
select 'Greetings' from dual
union all
select 'Dog' from dual
Then you can select from that:
select * from
(
select 'Hello' as word from dual
union all
select 'Goodbye' from dual
union all
select 'Greetings' from dual
union all
select 'Dog' from dual
)
where word not in (select word from words);
Possibly not as neat a solution as you might have hoped for...
You say you don't have sufficient privileges to create tables, so presumably you can't create types either - but if you can find a suitable type "lying around" in your database you can do this:
select * from table (table_of_varchar2_type('Hello','Goodbye','Greetings','Dog'))
where column_value not in (select word from words);
Here table_of_varchar2_type is imagined to be the name of a type that is defined like:
create type table_of_varchar2_type as table of varchar2(100);
One such type you are likely to be able to find is SYS.KU$_VCNT which is a TABLE OF VARCHAR2(4000).