How do I print a triangle of stars using SQL - sql

Question

Is it practically possible to create a triangle of stars like this as below in SQL.I know that this could be done easily in any other programming language like C,C++,Java but want to know whether it is really possible with just SQL or PL/SQL.I tried working on it with dual table in Oracle but couldn't get through it.
* *
* * * *
* * * or * * *
Can someone please shed somelight if anyone knows about it.

Answer 1

The simplest approach would be something like this. You can get more sophisticated particularly if you want to build the equilateral triangle rather than the right triangle.
SQL> ed
Wrote file afiedt.buf
1 select rpad( '* ', level*2, '* ' )
2 from dual
3* connect by level <= 3
SQL> /
RPAD('*',LEVEL*2,'*')
--------------------------------------------------------------------------------
*
* *
* * *

Answer 2

select rpad('* ', level * 2, '* ')
from dual connect by
level <= 10
*
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *
* * * * * * * *
* * * * * * * * *
* * * * * * * * * *
select rpad(' ',r*2,' ')||rpad('* ',l*2,'* ') k
from ( select level l,row_number() over(order by null) r
from dual
connect by level<=10
order by l desc)
* * * * * * * * * *
* * * * * * * * *
* * * * * * * *
* * * * * * *
* * * * * *
* * * * *
* * * *
* * *
* *
*
select rpad(' ',l*2,' ')||rpad('* ',r*2,'* ') k
from ( select level l,row_number() over(order by null) r
from dual
connect by level<=10
order by l desc)
*
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *
* * * * * * * *
* * * * * * * * *
* * * * * * * * * *
select rpad(' ',l,' ')||rpad('* ',r*2,'* ') k
from ( select level l,row_number() over(order by null) r
from dual
connect by level<=10
order by l desc)
*
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *

Answer 3

Not sure what you are looking for exactly. Perhaps this?
select '*' from dual
union all select '**' from dual
union all select '***' from dual
Example

Answer 4

Here is the script to Get a perfect triangle or Pyramid in sql (tested in Microsoft Sql 2008)
declare #x int,#y int
select #x=5,#y=0
while #x>0
begin
print space(#x)+replicate('*',#y)+replicate('*',#y+1)
set #y=#y+1
set #x=#x-1
end
*
***
*****
*******
*********
you can get many more scripts and help at this link... it was helpful to me
Link:- sqlquerynscript

Answer 5

Try this..
declare #x int,#y int,#diff int
select #x=0,#y=10,#diff=2--diferrence between consecutive rows
while #x<#y
begin
if #x=0 and #diff<>1
print space((#y-#x)*#diff-1)+replicate('*',1)
else if(#diff%2=0)
print space((#y-#x)*#diff)+replicate('* ',#x+(#x*(#diff-1)))
else
print space((#y-#x)*#diff)+replicate('* ',#x+(#x*(#diff-1)))
select #x=#x+1
end

Answer 6

If all you want is the simple triangle, then you can do this:
SELECT '*' FROM table
UNION
SELECT '**' FROM table
UNION
SELECT '***' FROM table

Answer 7

declare #count int,#num int,#num1 int, #space int, #str varchar(50)
set #count = 5 set #num = 1
while(#num<=#count)
begin
set #num1 = 0 set #space = #count-#num
while (#num1<#num)
begin
if #str is null
set #str = '* '
else
set #str = #str+'* ' set #num1 = #num1+1
end
print (space(#space)+#str)
set #num = #num+1 set #str = null
end

Answer 8

[Equilateral Traingle] We can make a pyramid with Oracle SQL as follows.
select rpad(' ',5 -level) || rpad( '* ', level*2, '* ' )
from dual
connect by level <= 5;
** Here 5 is the number of lines.
Let us reverse it,
select rpad(' ',level) || rpad( '* ', 2*(5-level+1), '* ' )
from dual
connect by level <= 5;

Answer 9

declare #row int = 5,
#index int = 0,
#string nvarchar(5) =''
while #row > 0
begin
set #index = #row
while #index > 0
begin
set #string = '*' + #string
set #index = #index - 1
end
print #string
set #string = ''
set #row = #row - 1
end
*****
****
***
**
*

Answer 10

DECLARE #lclMaxLevel INT=5
DECLARE #lclPrintCount INT =0
WHILE #lclMaxLevel > 0
BEGIN
PRINT Space(#lclMaxLevel)
+ Replicate('*', #lclPrintCount+1)
SET #lclMaxLevel=#lclMaxLevel - 1
SET #lclPrintCount=#lclPrintCount + 1
END