Compare SQL groups against eachother - sql

How can one filter a grouped resultset for only those groups that meet some criterion compared against the other groups? For example, only those groups that have the maximum number of constituent records?
I had thought that a subquery as follows should do the trick:
SELECT * FROM (
SELECT *, COUNT(*) AS Records
FROM T
GROUP BY X
) t HAVING Records = MAX(Records);
However the addition of the final HAVING clause results in an empty recordset... what's going on?

In MySQL (Which I assume you are using since you have posted SELECT *, COUNT(*) FROM T GROUP BY X Which would fail in all RDBMS that I know of). You can use:
SELECT T.*
FROM T
INNER JOIN
( SELECT X, COUNT(*) AS Records
FROM T
GROUP BY X
ORDER BY Records DESC
LIMIT 1
) T2
ON T2.X = T.X
This has been tested in MySQL and removes the implicit grouping/aggregation.
If you can use windowed functions and one of TOP/LIMIT with Ties or Common Table expressions it becomes even shorter:
Windowed function + CTE: (MS SQL-Server & PostgreSQL Tested)
WITH CTE AS
( SELECT *, COUNT(*) OVER(PARTITION BY X) AS Records
FROM T
)
SELECT *
FROM CTE
WHERE Records = (SELECT MAX(Records) FROM CTE)
Windowed Function with TOP (MS SQL-Server Tested)
SELECT TOP 1 WITH TIES *
FROM ( SELECT *, COUNT(*) OVER(PARTITION BY X) [Records]
FROM T
)
ORDER BY Records DESC
Lastly, I have never used oracle so apolgies for not adding a solution that works on oracle...
EDIT
My Solution for MySQL did not take into account ties, and my suggestion for a solution to this kind of steps on the toes of what you have said you want to avoid (duplicate subqueries) so I am not sure I can help after all, however just in case it is preferable here is a version that will work as required on your fiddle:
SELECT T.*
FROM T
INNER JOIN
( SELECT X
FROM T
GROUP BY X
HAVING COUNT(*) =
( SELECT COUNT(*) AS Records
FROM T
GROUP BY X
ORDER BY Records DESC
LIMIT 1
)
) T2
ON T2.X = T.X

For the exact question you give, one way to look at it is that you want the group of records where there is no other group that has more records. So if you say
SELECT taxid, COUNT(*) as howMany
GROUP by taxid
You get all counties and their counts
Then you can treat that expressions as a table by making it a subquery, and give it an alias. Below I assign two "copies" of the query the names X and Y and ask for taxids that don't have any more in one table. If there are two with the same number I'd get two or more. Different databases have proprietary syntax, notably TOP and LIMIT, that make this kind of query simpler, easier to understand.
SELECT taxid FROM
(select taxid, count(*) as HowMany from flats
GROUP by taxid) as X
WHERE NOT EXISTS
(
SELECT * from
(
SELECT taxid, count(*) as HowMany FROM
flats
GROUP by taxid
) AS Y
WHERE Y.howmany > X.howmany
)

Try this:
SELECT * FROM (
SELECT *, MAX(Records) as max_records FROM (
SELECT *, COUNT(*) AS Records
FROM T
GROUP BY X
) t
) WHERE Records = max_records
I'm sorry that I can't test the validity of this query right now.

Related

Listing multiple columns in a single row in SQL

(select ID,EXTERNAL_TRANSACTION_ID,EXTERNAL_TRANSACTION_TYPE,ROW_NUMBER() OVER(PARTITION BY EXTERNAL_TRANSACTION_ID ORDER BY ID ) AS SEQNUM
from AC_POS_TRANSACTION_TRK aptt WHERE [RESULT] ='Success'
GROUP BY ID, EXTERNAL_TRANSACTION_ID,EXTERNAL_TRANSACTION_TYPE )
Hello,
On above query, I want to get rows of transaction id's which has seqnum=1 and seqnum=2
But if that transaction id has no second row (seqnum=2), I dont want to get any row for that transaction id.
Thanks!!
Something like this
Not 100% sure if this is correct without you table definition, but my understanding is that you want to EXCLUDE records if that record has an entry with seqnum=2 -- you can't use a where clause alone because that would still return seqnum = 1.
You can use an exists /not exists or in/not in clause like this
(select ID,EXTERNAL_TRANSACTION_ID,EXTERNAL_TRANSACTION_TYPE,ROW_NUMBER() OVER(PARTITION BY EXTERNAL_TRANSACTION_ID ORDER BY ID ) AS SEQNUM
from AC_POS_TRANSACTION_TRK aptt WHERE [RESULT] ='Success'
and not exists ( select 1 from AC_POS_TRANSACTION_TRK a where a.id = aptt.id
and a.seqnum = 2)
GROUP BY ID, EXTERNAL_TRANSACTION_ID,EXTERNAL_TRANSACTION_TYPE )
basically what this does is it excludes records if a record exists as specified in the NOT EXISTS query.
One option you can try is to add a count of rows per group using the same partioning critera and then filter accordingly. Not entirely sure about your query without seeing it in context and with sample data - there's no aggregation so why use group by?
However can you try something along these lines
select * from (
select ID,EXTERNAL_TRANSACTION_ID,EXTERNAL_TRANSACTION_TYPE,
Row_Number() over(partition by EXTERNAL_TRANSACTION_ID order by ID) as SEQNUM,
Count(*) over(partition by EXTERNAL_TRANSACTION_ID) Qty
from AC_POS_TRANSACTION_TRK
where [RESULT] ='Success'
)x
where SEQNUM in (1,2) and Qty>1
This should do the job.
With Qry As (
-- Your original query goes here
),
Select Qry.*
From Qry
Where Exists (
Select *
From Qry Qry1
Where Qry1.EXTERNAL_TRANSACTION_ID = Qry.EXTERNAL_TRANSACTION_ID
And Qry1.SEQNUM = 1
)
And Exists (
Select *
From Qry Qry2
Where Qry2.EXTERNAL_TRANSACTION_ID = Qry.EXTERNAL_TRANSACTION_ID
And Qry2.SEQNUM = 2
)
BTW, your original query looks problematic to me, specifically I think that instead of a GROUP BY columns those columns should be in the PARTITION BY clause of the OVER statement, but without knowing more about the table structures and what you're trying to achieve, I could not say for sure.

SQL Server view inside CTE causing poor performance

When I use a view inside of a CTE, each subquery that references the CTE seems to re-query the view. There are large chunks of the execution plan that are repeated for each subquery. This isn't the case when selecting from a table. Is this expected? Is there any way to get around it?
WITH cte AS (
SELECT v.id
FROM test_view AS v
)
SELECT TOP 25 *,
(SELECT COUNT(*) FROM cte) AS subquery
FROM cte
I'm working with SQL Server 2005
EDIT:
I'm trying to get data from a view in pages with the query below. I need the total number of rows in the view, the number of rows that match a search, and a subset of the matching rows. This works well when selecting from tables, but using a view causes repeated execution of the CTE. I attempted to force intermediate materialization a variety of different ways from the link in Martin's answer, but didn't have any luck.
WITH tableRecords AS (
SELECT *
FROM example_view
),
filteredTableRecords AS (
SELECT *, ROW_NUMBER() OVER (ORDER BY id ASC) AS tableRecordNumber
FROM tableRecords
WHERE 1 = 1
)
SELECT *,
(SELECT COUNT(*) FROM tableRecords) AS totalRecords,
(SELECT COUNT(*) FROM filteredTableRecords) AS totalDisplayRecords
FROM filteredTableRecords
WHERE tableRecordNumber BETWEEN 1 AND 25
ORDER BY tableRecordNumber ASC
Yes it is largely expected.
See Provide a hint to force intermediate materialization of CTEs or derived tables
For the query in your question you can do this though
WITH CTE AS
(
SELECT v.id,
count(*) OVER () AS Cnt
FROM test_view AS v
)
SELECT TOP 25 *
FROM CTE
ORDER BY v.id
I suggest you re-write your query as below
There are a few improvements I did over your query
removal of where 1=1, it is unnecessary as it is always true.
the sub-query in select clause will be called everytime you execute the sql script, so instead of that you can actually use the cross apply to increase the performance.
;WITH tableRecords AS(
SELECT *
FROM example_view
),
filteredTableRecords AS (
SELECT *, ROW_NUMBER() OVER (ORDER BY id ASC) AS tableRecordNumber
FROM tableRecords
),TotalNumber
(
SELECT (SELECT COUNT(1) FROM tableRecords) AS totalRecords,
(SELECT COUNT(1) FROM filteredTableRecords) AS totalDisplayRecords
)
SELECT *
FROM filteredTableRecords F
CROSS APPLY TotalNumber AS T
WHERE tableRecordNumber BETWEEN 1 AND 25
ORDER BY tableRecordNumber ASC

SQL query to select distinct row with minimum value

I want an SQL statement to get the row with a minimum value.
Consider this table:
id game point
1 x 5
1 z 4
2 y 6
3 x 2
3 y 5
3 z 8
How do I select the ids that have the minimum value in the point column, grouped by game? Like the following:
id game point
1 z 4
2 y 5
3 x 2
Use:
SELECT tbl.*
FROM TableName tbl
INNER JOIN
(
SELECT Id, MIN(Point) MinPoint
FROM TableName
GROUP BY Id
) tbl1
ON tbl1.id = tbl.id
WHERE tbl1.MinPoint = tbl.Point
This is another way of doing the same thing, which would allow you to do interesting things like select the top 5 winning games, etc.
SELECT *
FROM
(
SELECT ROW_NUMBER() OVER (PARTITION BY ID ORDER BY Point) as RowNum, *
FROM Table
) X
WHERE RowNum = 1
You can now correctly get the actual row that was identified as the one with the lowest score and you can modify the ordering function to use multiple criteria, such as "Show me the earliest game which had the smallest score", etc.
This will work
select * from table
where (id,point) IN (select id,min(point) from table group by id);
As this is tagged with sql only, the following is using ANSI SQL and a window function:
select id, game, point
from (
select id, game, point,
row_number() over (partition by game order by point) as rn
from games
) t
where rn = 1;
Ken Clark's answer didn't work in my case. It might not work in yours either. If not, try this:
SELECT *
from table T
INNER JOIN
(
select id, MIN(point) MinPoint
from table T
group by AccountId
) NewT on T.id = NewT.id and T.point = NewT.MinPoint
ORDER BY game desc
SELECT DISTINCT
FIRST_VALUE(ID) OVER (Partition by Game ORDER BY Point) AS ID,
Game,
FIRST_VALUE(Point) OVER (Partition by Game ORDER BY Point) AS Point
FROM #T
SELECT * from room
INNER JOIN
(
select DISTINCT hotelNo, MIN(price) MinPrice
from room
Group by hotelNo
) NewT
on room.hotelNo = NewT.hotelNo and room.price = NewT.MinPrice;
This alternative approach uses SQL Server's OUTER APPLY clause. This way, it
creates the distinct list of games, and
fetches and outputs the record with the lowest point number for that game.
The OUTER APPLY clause can be imagined as a LEFT JOIN, but with the advantage that you can use values of the main query as parameters in the subquery (here: game).
SELECT colMinPointID
FROM (
SELECT game
FROM table
GROUP BY game
) As rstOuter
OUTER APPLY (
SELECT TOP 1 id As colMinPointID
FROM table As rstInner
WHERE rstInner.game = rstOuter.game
ORDER BY points
) AS rstMinPoints
This is portable - at least between ORACLE and PostgreSQL:
select t.* from table t
where not exists(select 1 from table ti where ti.attr > t.attr);
Most of the answers use an inner query. I am wondering why the following isn't suggested.
select
*
from
table
order by
point
fetch next 1 row only // ... or the appropriate syntax for the particular DB
This query is very simple to write with JPAQueryFactory (a Java Query DSL class).
return new JPAQueryFactory(manager).
selectFrom(QTable.table).
setLockMode(LockModeType.OPTIMISTIC).
orderBy(QTable.table.point.asc()).
fetchFirst();
Try:
select id, game, min(point) from t
group by id

MSSQL 2008 SP pagination and count number of total records

In my SP I have the following:
with Paging(RowNo, ID, Name, TotalOccurrences) as
(
ROW_NUMBER() over (order by TotalOccurrences desc) as RowNo, V.ID, V.Name, R.TotalOccurrences FROM dbo.Videos V INNER JOIN ....
)
SELECT * FROM Paging WHERE RowNo BETWEEN 1 and 50
SELECT COUNT(*) FROM Paging
The result is that I get the error: invalid object name 'Paging'.
Can I query again the Paging table? I don't want to include the count for all results as a new column ... I would prefer to return as another data set. Is that possible?
Thanks, Radu
After more research I fond another way of doing this:
with Paging(RowNo, ID, Name, TotalOccurrences) AS
(
ROW_NUMBER() over (order by TotalOccurrences desc) as RowNo, V.ID, V.Name, R.TotalOccurrences FROM dbo.Videos V INNER JOIN ....
)
select RowNo, ID, Name, TotalOccurrences, (select COUNT(*) from Paging) as TotalResults from Paging where RowNo between (#PageNumber - 1 )* #PageSize + 1 and #PageNumber * #PageSize;
I think that this has better performance than calling two times the query.
You can't do that because the CTE you are defining will only be available to the FIRST query that appears after it's been defined. So when you run the COUNT(*) query, the CTE is no longer available to reference. That's just a limitation of CTEs.
So to do the COUNT as a separate step, you'd need to not use the CTE and instead use the full query to COUNT on.
Or, you could wrap the CTE up in an inline table valued function and use that instead, to save repeating the main query, something like this:
CREATE FUNCTION dbo.ufnExample()
RETURNS TABLE
AS
RETURN
(
with Paging(RowNo, ID, Name, TotalOccurrences) as
(
ROW_NUMBER() over (order by TotalOccurrences desc) as RowNo, V.ID, V.Name, R.TotalOccurrences FROM dbo.Videos V INNER JOIN ....
)
SELECT * FROM Paging
)
SELECT * FROM dbo.ufnExample() x WHERE RowNo BETWEEN 1 AND 50
SELECT COUNT(*) FROM dbo.ufnExample() x
Please be aware that Radu D's solution's query plan shows double hits to those tables. It is doing two executions under the covers. However, this still may be the best way as I haven't found a truly scalable 1-query design.
A less scalable 1-query design is to dump a completed ordered list into a #tablevariable , SELECT ##ROWCOUNT to get the full count, and select from #tablevariable where row number between X and Y. This works well for <10000 rows, but with results in the millions of rows, populating that #tablevariable gets expensive.
A hybrid approach is to populate this temp/variable up to 10000 rows. If not all 10000 rows are filled up, you're set. If 10000 rows are filled up, you'll need to rerun the search to get the full count. This works well if most of your queries return well under 10000 rows. The 10000 limit is a rough approximation, you can play around with this threshold for your case.
Write "AS" after the CTE table name Paging as below:
with Paging AS (RowNo, ID, Name, TotalOccurrences) as
(
ROW_NUMBER() over (order by TotalOccurrences desc) as RowNo, V.ID, V.Name, R.TotalOccurrences FROM dbo.Videos V INNER JOIN ....
)
SELECT * FROM Paging WHERE RowNo BETWEEN 1 and 50
SELECT COUNT(*) FROM Paging

adding count( ) column on each row

I'm not sure if this is even a good question or not.
I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book.
There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn.
I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a separate query. Is it possible to add a count() column to the resultset that counts every result found?
the output would look like this:
ID Title Author Count(...)
1 book_1 auth_1 23
2 book_2 auth_2 23
4 book_4 auth_.. 23
...
Thanks!
This won't add the count to each row, but one way to get the total count without running a second query is to run your first query using the SQL_CALC_FOUND_ROWS option and then select FOUND_ROWS(). This is sometimes useful if you want to know how many total results there are so you can calculate the page count.
Example:
select SQL_CALC_FOUND_ROWS ID, Title, Author
from yourtable
limit 0, 10;
SELECT FOUND_ROWS();
From the manual:
http://dev.mysql.com/doc/refman/5.1/en/information-functions.html#function_found-rows
The usual way of counting in a query is to group on the fields that are returned:
select ID, Title, Author, count(*) as Cnt
from ...
group by ID, Title, Author
order by Title
limit 1, 10
The Cnt column will contain the number of records in each group, i.e. for each title.
Regarding second query:
select tbl.id, tbl.title, tbl.author, x.cnt
from tbl
cross join (select count(*) as cnt from tbl) as x
If you will not join to other table(s):
select tbl.id, tbl.title, tbl.author, x.cnt
from tbl, (select count(*) as cnt from tbl) as x
My Solution:
SELECT COUNT(1) over(partition BY text) totalRecordNumber
FROM (SELECT 'a' text, id_consult_req
FROM consult_req cr);
If your problem is simply the speed/cost of doing a second (complex) query I would suggest you simply select the resultset into a hash-table and then count the rows from there while returning, or even more efficiently use the rowcount of the previous resultset, then you do not even have to recount
This will add the total count on each row:
select count(*) over (order by (select 1)) as Cnt,*
from yourtable
Here is your answare:
SELECT *, #cnt count_rows FROM (
SELECT *, (#cnt := #cnt + 1) row_number FROM your_table
CROSS JOIN (SELECT #cnt := 0 AS variable) t
) t;
You simply cannot do this, you'll have to use a second query.