Objective c - SQLite selecting random row with another value - objective-c

Basically I have a database of words,
This database contains a rowID(primary key), the word and word length as table columns.
I want to select a random row where length = x and get the word at that row.
This is for an iPhone game project and it is high priority that the queries are as fast as possible (the searches are made in a game).
For instance:
SELECT * FROM WordsDB WHERE >= (abs(random()) %% (SELECT max(rowid) FROM WordsDB)) LIMIT 1;
This query is really fast at selecting a random row a lot faster than ORDER BY RANDOM() LIMIT 1, however, if I add the word length to the query I get issues:
SELECT * FROM WordsDB WHERE length = 9 AND rowid >= (abs(random()) %% (SELECT max(rowid) FROM WordsDB)) LIMIT 1
Presumably because the random row will not always have a length of 9.
I was just wondering what would be the fastest / most efficient way of doing this.
Thanks for your time
Note: the 2 % symbols are because it is in objective c and the query is set as a string.

This one seems to work ok for me:
select * from WordsDB
where length = 9
limit (abs(random()) % (select count(rowid) from WordsDB
where length = 9)), 1;
note that length = 9 appears in both where clauses.
Add index on length if it appears to be slow.

Add an index to the WordsDB.length
create index if not exists WordsDBLengthIndex on WordsDB (length);
should make selection on this field much faster

Related

How to permutate an SQL table using a seed?

Background
I have a front-end with a list of items with infinite scrolling, and I fetch pages of items by specifying the page limit and offset.
Problem
Apart from simply ordering the result by some of the columns, I would like to add a "random" option. The thing is, I don't want repetitions, so I need to have the entire dataset permutated before doing the limit and offset, and I need to be able to get the same permutation as long as I supply the same seed.
What I tried
A naive approach was to write a table-valued function that takes an int seed and uses it in the ORDER BY clause like so:
SELECT *
FROM dbo.Entities e
ORDER BY HASHBYTES('MD2', e.Title) ^ #seed
OFFSET 0 ROWS
FETCH NEXT (SELECT COUNT(*) FROM dbo.Entities) ROWS ONLY
This seemed to work well at a first glance, but it turned out it's not very "volatile" for the lack of better word - it becomes more visible with sparse result sets, where most seeds (chosen randomly from between 0 and 2147483647) yield the same order.
I thought I would get better results by hashing the seed as well, but SQL Server doesn't allow me to XOR two varbinary variables. Am I even looking in the right direction? Are there any performance considerations that I should be making and I might not be aware of?
The best way is to create a tally table with two columns: first a sequential integer, (between 1 and 1,000,000), second a random integer number. Then generate a random number to get the first value and then make a join with a computed ROW_NUMBER().
CREATE TABLE T_NUM (SEQUENTIAL INT, RANDOM INT);
GO
WITH
N AS(SELECT 0 AS I
UNION ALL
SELECT I + 1
FROM N
WHERE I < 9)
INSERT INTO T_NUM (SEQUENTIAL)
SELECT N1.I + N2.I * 10 + N3.I * 100 + N4.I * 1000 + N5.I * 10000 + N6.I * 100000
FROM N AS N1
CROSS JOIN N AS N2
CROSS JOIN N AS N3
CROSS JOIN N AS N4
CROSS JOIN N AS N5
CROSS JOIN N AS N6;
GO
WITH T AS
(
SELECT SEQUENTIAL, ROW_NUMBER() OVER (ORDER BY CHECKSUM(NEWID())) AS ALEA
FROM T_NUM
)
UPDATE N
SET RANDOM = ALEA
FROM T_NUM AS N
JOIN T ON T.SEQUENTIAL = N.SEQUENTIAL;
GO
DECLARE #SEED INT = FLOOR(1 + RAND() * 1000000);
Now you have your seed to enter in the alea sequence then join your table on sequential order
ORDER BY HASHBYTES('MD2', e.Title + convert(nvarchar(max), #seed))
should work, but performance-wise it would be a disaster. You would calculate MD2 for all records every time. I would not do this on server side at all. You can generate random sequence on client and then just pick from server rows with row number 158, 7, 1027 and 9. But it has still two problems
if item is deleted, row number of all consecutive records shifts. It would just break the whole sequence and you would get duplicities and missing records
row number over millions of records is not that fast either
I see two options. You can query all ids from the table and use them for generating of random order. But that would be a lot of numbers. Or you have to ensure the id space is dense enough. Then you can query 20 random ids and hope at least 10 of them exist. If you are unlucky, you would have to query again.

Select 15 elements from 1 million row data in database [duplicate]

I've got a SQL Server table with about 50,000 rows in it. I want to select about 5,000 of those rows at random. I've thought of a complicated way, creating a temp table with a "random number" column, copying my table into that, looping through the temp table and updating each row with RAND(), and then selecting from that table where the random number column < 0.1. I'm looking for a simpler way to do it, in a single statement if possible.
This article suggest using the NEWID() function. That looks promising, but I can't see how I could reliably select a certain percentage of rows.
Anybody ever do this before? Any ideas?
select top 10 percent * from [yourtable] order by newid()
In response to the "pure trash" comment concerning large tables: you could do it like this to improve performance.
select * from [yourtable] where [yourPk] in
(select top 10 percent [yourPk] from [yourtable] order by newid())
The cost of this will be the key scan of values plus the join cost, which on a large table with a small percentage selection should be reasonable.
Depending on your needs, TABLESAMPLE will get you nearly as random and better performance.
this is available on MS SQL server 2005 and later.
TABLESAMPLE will return data from random pages instead of random rows and therefore deos not even retrieve data that it will not return.
On a very large table I tested
select top 1 percent * from [tablename] order by newid()
took more than 20 minutes.
select * from [tablename] tablesample(1 percent)
took 2 minutes.
Performance will also improve on smaller samples in TABLESAMPLE whereas it will not with newid().
Please keep in mind that this is not as random as the newid() method but will give you a decent sampling.
See the MSDN page.
newid()/order by will work, but will be very expensive for large result sets because it has to generate an id for every row, and then sort them.
TABLESAMPLE() is good from a performance standpoint, but you will get clumping of results (all rows on a page will be returned).
For a better performing true random sample, the best way is to filter out rows randomly. I found the following code sample in the SQL Server Books Online article Limiting Results Sets by Using TABLESAMPLE:
If you really want a random sample of
individual rows, modify your query to
filter out rows randomly, instead of
using TABLESAMPLE. For example, the
following query uses the NEWID
function to return approximately one
percent of the rows of the
Sales.SalesOrderDetail table:
SELECT * FROM Sales.SalesOrderDetail
WHERE 0.01 >= CAST(CHECKSUM(NEWID(),SalesOrderID) & 0x7fffffff AS float)
/ CAST (0x7fffffff AS int)
The SalesOrderID column is included in
the CHECKSUM expression so that
NEWID() evaluates once per row to
achieve sampling on a per-row basis.
The expression CAST(CHECKSUM(NEWID(),
SalesOrderID) & 0x7fffffff AS float /
CAST (0x7fffffff AS int) evaluates to
a random float value between 0 and 1.
When run against a table with 1,000,000 rows, here are my results:
SET STATISTICS TIME ON
SET STATISTICS IO ON
/* newid()
rows returned: 10000
logical reads: 3359
CPU time: 3312 ms
elapsed time = 3359 ms
*/
SELECT TOP 1 PERCENT Number
FROM Numbers
ORDER BY newid()
/* TABLESAMPLE
rows returned: 9269 (varies)
logical reads: 32
CPU time: 0 ms
elapsed time: 5 ms
*/
SELECT Number
FROM Numbers
TABLESAMPLE (1 PERCENT)
/* Filter
rows returned: 9994 (varies)
logical reads: 3359
CPU time: 641 ms
elapsed time: 627 ms
*/
SELECT Number
FROM Numbers
WHERE 0.01 >= CAST(CHECKSUM(NEWID(), Number) & 0x7fffffff AS float)
/ CAST (0x7fffffff AS int)
SET STATISTICS IO OFF
SET STATISTICS TIME OFF
If you can get away with using TABLESAMPLE, it will give you the best performance. Otherwise use the newid()/filter method. newid()/order by should be last resort if you have a large result set.
Selecting Rows Randomly from a Large Table on MSDN has a simple, well-articulated solution that addresses the large-scale performance concerns.
SELECT * FROM Table1
WHERE (ABS(CAST(
(BINARY_CHECKSUM(*) *
RAND()) as int)) % 100) < 10
This link have a interesting comparison between Orderby(NEWID()) and other methods for tables with 1, 7, and 13 millions of rows.
Often, when questions about how to select random rows are asked in discussion groups, the NEWID query is proposed; it is simple and works very well for small tables.
SELECT TOP 10 PERCENT *
FROM Table1
ORDER BY NEWID()
However, the NEWID query has a big drawback when you use it for large tables. The ORDER BY clause causes all of the rows in the table to be copied into the tempdb database, where they are sorted. This causes two problems:
The sorting operation usually has a high cost associated with it.
Sorting can use a lot of disk I/O and can run for a long time.
In the worst-case scenario, tempdb can run out of space. In the
best-case scenario, tempdb can take up a large amount of disk space
that never will be reclaimed without a manual shrink command.
What you need is a way to select rows randomly that will not use tempdb and will not get much slower as the table gets larger. Here is a new idea on how to do that:
SELECT * FROM Table1
WHERE (ABS(CAST(
(BINARY_CHECKSUM(*) *
RAND()) as int)) % 100) < 10
The basic idea behind this query is that we want to generate a random number between 0 and 99 for each row in the table, and then choose all of those rows whose random number is less than the value of the specified percent. In this example, we want approximately 10 percent of the rows selected randomly; therefore, we choose all of the rows whose random number is less than 10.
Please read the full article in MSDN.
Just order the table by a random number and obtain the first 5,000 rows using TOP.
SELECT TOP 5000 * FROM [Table] ORDER BY newid();
UPDATE
Just tried it and a newid() call is sufficent - no need for all the casts and all the math.
If you (unlike the OP) need a specific number of records (which makes the CHECKSUM approach difficult) and desire a more random sample than TABLESAMPLE provides by itself, and also want better speed than CHECKSUM, you may make do with a merger of the TABLESAMPLE and NEWID() methods, like this:
DECLARE #sampleCount int = 50
SET STATISTICS TIME ON
SELECT TOP (#sampleCount) *
FROM [yourtable] TABLESAMPLE(10 PERCENT)
ORDER BY NEWID()
SET STATISTICS TIME OFF
In my case this is the most straightforward compromise between randomness (it's not really, I know) and speed. Vary the TABLESAMPLE percentage (or rows) as appropriate - the higher the percentage, the more random the sample, but expect a linear drop off in speed. (Note that TABLESAMPLE will not accept a variable)
This is a combination of the initial seed idea and a checksum, which looks to me to give properly random results without the cost of NEWID():
SELECT TOP [number]
FROM table_name
ORDER BY RAND(CHECKSUM(*) * RAND())
In MySQL you can do this:
SELECT `PRIMARY_KEY`, rand() FROM table ORDER BY rand() LIMIT 5000;
Didn't quite see this variation in the answers yet. I had an additional constraint where I needed, given an initial seed, to select the same set of rows each time.
For MS SQL:
Minimum example:
select top 10 percent *
from table_name
order by rand(checksum(*))
Normalized execution time: 1.00
NewId() example:
select top 10 percent *
from table_name
order by newid()
Normalized execution time: 1.02
NewId() is insignificantly slower than rand(checksum(*)), so you may not want to use it against large record sets.
Selection with Initial Seed:
declare #seed int
set #seed = Year(getdate()) * month(getdate()) /* any other initial seed here */
select top 10 percent *
from table_name
order by rand(checksum(*) % #seed) /* any other math function here */
If you need to select the same set given a seed, this seems to work.
Try this:
SELECT TOP 10 Field1, ..., FieldN
FROM Table1
ORDER BY NEWID()
Here is an updated and improved form of sampling. It is based on the same concept of some other answers that use CHECKSUM / BINARY_CHECKSUM and modulus.
Reasons to use an implementation similar to this one, as opposed to other answers:
It is relatively fast over huge data sets and can be efficiently used in/with derived queries. Millions of pre-filtered rows can be sampled in seconds with no tempdb usage and, if aligned with the rest of the query, the overhead is often minimal.
Does not suffer from CHECKSUM(*) / BINARY_CHECKSUM(*) issues with runs of data. When using the CHECKSUM(*) approach, the rows can be selected in "chunks" and not "random" at all! This is because CHECKSUM prefers speed over distribution.
Results in a stable/repeatable row selection and can be trivially changed to produce different rows on subsequent query executions. Approaches that use NEWID(), such as CHECKSUM(NEWID()) % 100, can never be stable/repeatable.
Allows for increased sample precision and reduces introduced statistical errors. The sampling precision can also be tweaked. CHECKSUM only returns an int value.
Does not use ORDER BY NEWID(), as ordering can become a significant bottleneck with large input sets. Avoiding the sorting also reduces memory and tempdb usage.
Does not use TABLESAMPLE and thus works with a WHERE pre-filter.
Cons / limitations:
Slightly slower execution times and using CHECKSUM(*). Using hashbytes, as shown below, adds about 3/4 of a second of overhead per million lines. This is with my data, on my database instance: YMMV. This overhead can be eliminated if using a persisted computed column of the resulting 'well distributed' bigint value from HASHBYTES.
Unlike the basic SELECT TOP n .. ORDER BY NEWID(), this is not guaranteed to return "exactly N" rows. Instead, it returns a percentage row rows where such a value is pre-determined. For very small sample sizes this could result in 0 rows selected. This limitation is shared with the CHECKSUM(*) approaches.
Here is the gist:
-- Allow a sampling precision [0, 100.0000].
declare #sample_percent decimal(7, 4) = 12.3456
select
t.*
from t
where 1=1
and t.Name = 'Mr. No Questionable Checksum Usages'
and ( -- sample
#sample_percent = 100
or abs(
-- Choose appropriate identity column(s) for hashbytes input.
-- For demonstration it is assumed to be a UNIQUEIDENTIFIER rowguid column.
convert(bigint, hashbytes('SHA1', convert(varbinary(32), t.rowguid)))
) % (1000 * 100) < (1000 * #sample_percent)
)
Notes:
While SHA1 is technically deprecated since SQL Server 2016, it is both sufficient for the task and is slightly faster than either MD5 or SHA2_256. Use a different hashing function as relevant. If the table already contains a hashed column (with a good distribution), that could potentially be used as well.
Conversion of bigint is critical as it allows 2^63 bits of 'random space' to which to apply the modulus operator; this is much more than the 2^31 range from the CHECKSUM result. This reduces the modulus error at the limit, especially as the precision is increased.
The sampling precision can be changed as long as the modulus operand and sample percent are multiplied appropriately. In this case, that is 1000 * to account for the 4 digits of precision allowed in #sample_percent.
Can multiply the bigint value by RAND() to return a different row sample each run. This effectively changes the permutation of the fixed hash values.
If #sample_percent is 100 the query planner can eliminate the slower calculation code entirely. Remember 'parameter sniffing' rules. This allows the code to be left in the query regardless of enabling sampling.
Computing #sample_percent, with lower/upper limits, and adding a TOP "hint" in the query as might be useful when the sample is used in a derived table context.
-- Approximate max-sample and min-sample ranges.
-- The minimum sample percent should be non-zero within the precision.
declare #max_sample_size int = 3333333
declare #min_sample_percent decimal(7,4) = 0.3333
declare #sample_percent decimal(7,4) -- [0, 100.0000]
declare #sample_size int
-- Get initial count for determining sample percentages.
-- Remember to match the filter conditions with the usage site!
declare #rows int
select #rows = count(1)
from t
where 1=1
and t.Name = 'Mr. No Questionable Checksum Usages'
-- Calculate sample percent and back-calculate actual sample size.
if #rows <= #max_sample_size begin
set #sample_percent = 100
end else begin
set #sample_percent = convert(float, 100) * #max_sample_size / #rows
if #sample_percent < #min_sample_percent
set #sample_percent = #min_sample_percent
end
set #sample_size = ceiling(#rows * #sample_percent / 100)
select *
from ..
join (
-- Not a precise value: if limiting exactly at, can introduce more bias.
-- Using 'option optimize for' avoids this while requiring dynamic SQL.
select top (#sample_size + convert(int, #sample_percent + 5))
from t
where 1=1
and t.Name = 'Mr. No Questionable Checksum Usages'
and ( -- sample
#sample_percent = 100
or abs(
convert(bigint, hashbytes('SHA1', convert(varbinary(32), t.rowguid)))
) % (1000 * 100) < (1000 * #sample_percent)
)
) sampled
on ..
It appears newid() can't be used in where clause, so this solution requires an inner query:
SELECT *
FROM (
SELECT *, ABS(CHECKSUM(NEWID())) AS Rnd
FROM MyTable
) vw
WHERE Rnd % 100 < 10 --10%
I was using it in subquery and it returned me same rows in subquery
SELECT ID ,
( SELECT TOP 1
ImageURL
FROM SubTable
ORDER BY NEWID()
) AS ImageURL,
GETUTCDATE() ,
1
FROM Mytable
then i solved with including parent table variable in where
SELECT ID ,
( SELECT TOP 1
ImageURL
FROM SubTable
Where Mytable.ID>0
ORDER BY NEWID()
) AS ImageURL,
GETUTCDATE() ,
1
FROM Mytable
Note the where condtition
The server-side processing language in use (eg PHP, .net, etc) isn't specified, but if it's PHP, grab the required number (or all the records) and instead of randomising in the query use PHP's shuffle function. I don't know if .net has an equivalent function but if it does then use that if you're using .net
ORDER BY RAND() can have quite a performance penalty, depending on how many records are involved.
select * from table
where id in (
select id from table
order by random()
limit ((select count(*) from table)*55/100))
// to select 55 percent of rows randomly
If you know you have approximately N rows and you want approximately K random rows, you just need to pull any given row with a chance K/N. Using the RAND() function which gives you a fair distribution between 0 and 1, you could just do the following where PROB = K/N. Worked very quickly for me.
SELECT * FROM some_table WHERE RAND() < PROB
This works for me:
SELECT * FROM table_name
ORDER BY RANDOM()
LIMIT [number]

Build Semi-Random String From Table in PostgreSQL

I have a table called fragments which hold a bunch of words, and sentence fragments. I want to create a random "sentence" by selecting a random fragment appending it to the string I'm building (separated by a delimiter). I want to keep doing this until I reach a specified length and then return the resulting string. What is the best way to do this in PostgreSQL?
id | text
----------------
1 | hello
2 | world
Given the example table above and a desired length of 20 I would expect to get back something like:
world hello hello world
http://sqlfiddle.com/#!15/0a88ca/1
You could use a recursive CTE for this:
WITH RECURSIVE recCte (sentence, length) AS
(
--recursive seed
SELECT
CAST("text" AS VARCHAR(200)) as sentence,
1 as length
FROM (SELECT "text" FROM test.fragments ORDER BY random() LIMIT 1)frag
UNION ALL
--recursive term
SELECT
CAST(recCTE.sentence || ' ' || frag.text as VARCHAR(200)),
recCTE.length + 1
FROM
reccte, (SELECT "text" from test.fragments ORDER BY random() LIMIT 1)frag
WHERE recCTE.length <= 20 --Sentence word length
)
--Select the full sentence made
SELECT sentence FROM recCTE WHERE length = 20;
This is a little involved, but it's perfect for your needs. A recursive CTE query is made up of three parts.
The recursive seed - This is the portion of the query that is non-recursive. It's the starting point for the query. We just grab one random word from the table.
The recursive term - This is the portion of the query that is recursive. It refers back to itself ...FROM recCTE .... Again, we just grab one word from the table at random and stick it onto the sentence. While doing this we keep track of how deep we are in the iterations so we can stop after 20 loops.
The final select statement to select the full sentence from the recursive CTE. Each iteration creates a record, so we just grab the record that has made it to 20. Change "20" in the recursive CTE and final Select statement to change the length of the sentence.
Editting to add a version that uses character length:
This is a little trickier because we have to use ORDER BY random() LIMIT 1 to get a random text from the fragments table, but you can't ORDER BY and LIMIT in a recursive CTE. So getting exactly 20 characters is difficult, but.. we can get <= 20, which is pretty close:
WITH RECURSIVE recCte (sentence, length) AS
(
SELECT
CAST("text" AS VARCHAR(200)) as sentence,
length("text") as length
FROM (SELECT "text" FROM test.fragments ORDER BY random() LIMIT 1)frag
UNION ALL
SELECT
CAST(cte.sentence || ' ' || frag.text as VARCHAR(200)),
cte.length + 1 + length(frag.text)
FROM
reccte cte, (SELECT text FROM test.fragments ORDER BY random() LIMIT 1) frag
WHERE
length(frag.text) < (20-cte.length)
AND cte.length <= 20 --Sentence word length
)
SELECT sentence, length FROM recCTE ORDER BY length DESC LIMIT 1;
The big changes here are changing the Length field to calculate the character length and to add that restriction in the WHERE clause of the recursive term. Finally we ORDER BY length DESC to sort the cte's records by character length, and LIMIT 1 to grab the biggest one we created through the iterations.

How to select a repeatable random number with setseed in postgres sql?

What I am trying to achieve is selecting a control group for a process. To do this I am using random(), and for debugging / consistency I would like to be able to set the random number in a repeatable fashion. Meaning, I run the query once it assigns user 123 random number .001. At a different time I delete the previous data, I call the same query, and once again user 123 is assigned random number .001.
I have tried:
SELECT setseed(0);
SELECT 1, random() from generate_series(1,10);
I receive a different random number with every run.
SELECT 1, setseed(0), random() from generate_series(1,10);
Each row receives the same random number, which is useless.
I'm sure there is something I don't understand here. Any help is appreciated.
Do a union all of the setseed() query with the desired query. It is necessary to match the column types from both queries. setseed() returns void.
select setseed(0), null
union all
select null, random()
from generate_series(1, 10)
offset 1
;
The offset 1 clause eliminates the setseed() row from the result set

How to select a specific number of bytes from SQLite table?

I have a simple SQLite table with 1 column where I'm selecting a random number of records:
SELECT * FROM vocabulary ORDER BY RANDOM() LIMIT 100;
Is there a way to select a specific number of bytes, instead of rows? Something along the lines of:
SELECT * FROM vocabulary ORDER BY RANDOM() LIMIT BYTES 1024;
You can't limit your select via the SQLite-engine to a specific number of bytes across rows. Note though that LIMIT simply stops reading when the limit is reached. You can do the same thing by keeping a count in your calling code and then stop reading the data once you've reached the number of bytes you want.
Precisely how will depend on what environment you're programming in.