I have two tables EXERCISE and EXERCISEUSER. I need to list all exercise entries and put an additional field in the query, which will return if that exercise exists in the table EXERCISEUSER. In other words, I need know if the user did that exercise. If so, it will have a row in EXERCISEUSER.
My current query is:
SELECT
"E".*,
"T"."NAME" AS "LEVEL"
FROM
"EXERCISE" AS "E"
INNER JOIN
"EXERCISETYPE" AS "T"
ON
E.STO_FK_EXERCISETYPEEXERCISE = T.PK_EXERCISETYPE
INNER JOIN
"LEVEL" AS "L"
ON
L.PK_LEVEL = E.STO_FK_LEVELEXERCISE
WHERE
(
E.STATUS = 1)
AND (
L.STATUS = 1)
AND (
L.PK_LEVEL = 5)
ORDER BY
"T"."ORDER" ASC
I will provide PK_USER too.
Thanks!
Well, i use a subquery, and reach the result i want.
SELECT
"E".*,
"T"."NAME" AS "LEVEL",
( SELECT COUNT(*) FROM STOUSER.EXERCISEUSER AS EU WHERE EU.STO_FK_EXERCISEEXERCISEUSER = E.PK_EXERCISE AND EU.STO_FK_USEREXERCISEUSER = 5978 ) AS MAKE_EXER_NUM
FROM
"STOUSER"."EXERCISE" AS "E"
INNER JOIN
"STOUSER"."EXERCISETYPE" AS "T"
ON
E.STO_FK_EXERCISETYPEEXERCISE = T.PK_EXERCISETYPE
INNER JOIN
"STOUSER"."LEVEL" AS "L"
ON
L.PK_LEVEL = E.STO_FK_LEVELEXERCISE
WHERE
(
E.STATUS = 1)
AND (
L.STATUS = 1)
AND (
L.PK_LEVEL = 5)
ORDER BY
"T"."ORDER" ASC
Thanks!
I think this should be done with a LEFT OUTER JOIN.
Related
I want to get fields from 2 different tables . The last field candidate_score_id has a many to one relationship. So how should I join the below 2 queries
1) To get candidate_score_id from the candidate_score table.
select candidate_score_id from candidate_score a where
a.assessment_id = NEW.assessment_id and
a.candidate_id = NEW.candidate_id and
a.attempt_Count = NEW.attempt_count;
2) To insert different fields in to the candidate_score_details table. The field in this table should be obtained by query above.
insert into candidate_score_details(candidate_score_details_id, candidate_id, assessment_id, attempt_count, score_type, score_tag,correct, candidate_score_id)
select uuid();
select a.candidate_id, a.assessment_id,a.attempt_count,"BY-COMPLEXITY",
case c.complexity
when 1 then "HIGH"
when 2 then "MEDIUM"
when 3 then "LOW"
end, count(*) from candidate_answer a, answer_key b, question_meta_data c where a.candidate_id = NEW.candidate_id and
a.assessment_id = NEW.assessment_id and
a.attempt_count = NEW.attempt_count and
a.assessment_id = b.assessment_id and
a.question_id = b.question_number and
a.response = b.answer and
a.question_id = c.question_number
group by a.candidate_id, a.assessment_id, a.attempt_count, c.complexity;
Just looking at the SQL joining aspect of your question, you'll need to specify the table I THINK you're aliasing a 2nd table with the "NEW" reference. If that's the case, then the query would be (replacing "OTHER_TABLE_NAME" with the name of the 2nd table:
select a.candidate_score_id
from candidate_score a
left join OTHER_TABLE_NAME new on
and a.assessment_id = NEW.assessment_id
and a.candidate_id = NEW.candidate_id
and a.attempt_Count = NEW.attempt_count
Seems that Query 1 has the same 3 criteria on the "candidate_score" table as for the "candidate_answer" table in Query 2.
So how about adding a LEFT JOIN of "candidate_score" to "candidate_answer" on those 3 fields?
For example:
INSERT INTO candidate_score_details
(
candidate_score_details_id,
candidate_id,
assessment_id,
attempt_count,
score_type,
score_tag,
correct,
candidate_score_id
)
SELECT
uuid(),
answer.candidate_id,
answer.assessment_id,
answer.attempt_count,
'BY-COMPLEXITY' AS score_type,
(CASE meta.complexity
WHEN 1 THEN 'HIGH'
WHEN 2 THEN 'MEDIUM'
WHEN 3 THEN 'LOW'
END) AS score_tag,
COUNT(*) AS correct,
MAX(score.candidate_score_id) AS max_candidate_score_id
FROM candidate_answer AS answer
JOIN answer_key AS akey
ON (akey.assessment_id = answer.assessment_id AND akey.question_number = answer.question_id AND akey.answer = answer.response)
LEFT JOIN candidate_score AS score
ON (score.candidate_id = answer.candidate_id AND score.assessment_id = answer.assessment_id AND score.attempt_count = answer.attempt_count)
LEFT JOIN question_meta_data AS meta
ON meta.question_number = answer.question_id
WHERE answer.candidate_id = NEW.candidate_id
AND answer.assessment_id = NEW.assessment_id
AND answer.attempt_count = NEW.attempt_count
GROUP BY answer.candidate_id, answer.assessment_id, answer.attempt_count, meta.complexity;
I've got a very complex database with a lot of tables in SQLite. I'm trying to design a query that will report out a lot of data from those tables and also report out those sheep who may not have a record in one or more tables.
My query is:
SELECT sheep_table.sheep_id,
(SELECT tag_number FROM id_info_table WHERE official_id = "1" AND id_info_table.sheep_id = sheep_table.sheep_id AND (tag_date_off IS NULL or tag_date_off = '')) AS fedtag,
(SELECT tag_number FROM id_info_table WHERE tag_type = "4" AND id_info_table.sheep_id = sheep_table.sheep_id AND (tag_date_off IS NULL or tag_date_off = '')) AS farmtag,
(SELECT tag_number FROM id_info_table WHERE tag_type = "2" AND id_info_table.sheep_id = sheep_table.sheep_id AND (tag_date_off IS NULL or tag_date_off = '') and ( id_info_table.official_id is NULL or id_info_table.official_id = 0 )) AS eidtag,
sheep_table.sheep_name, codon171_table.codon171_alleles, sheep_ebv_table.usa_maternal_index, sheep_ebv_table.self_replacing_carcass_index, cluster_table.cluster_name, sheep_evaluation_table.id_evaluationid,
(sheep_table.birth_type +
sheep_table.codon171 +
sheep_evaluation_table.trait_score01 +
sheep_evaluation_table.trait_score02 +
sheep_evaluation_table.trait_score03 +
sheep_evaluation_table.trait_score04 +
sheep_evaluation_table.trait_score05 +
sheep_evaluation_table.trait_score06 +
sheep_evaluation_table.trait_score07 +
sheep_evaluation_table.trait_score08 +
sheep_evaluation_table.trait_score09 +
sheep_evaluation_table.trait_score10 +
(sheep_evaluation_table.trait_score11 / 10 )) as overall_score, sheep_evaluation_table.sheep_rank, sheep_evaluation_table.number_sheep_ranked,
sheep_table.alert01,
sheep_table.birth_date, sheep_sex_table.sex_abbrev, birth_type_table.birth_type,
sire_table.sheep_name as sire_name, dam_table.sheep_name as dam_name
FROM sheep_table
join codon171_table on sheep_table.codon171 = codon171_table.id_codon171id
join sheep_cluster_table on sheep_table.sheep_id = sheep_cluster_table.sheep_id
join cluster_table on cluster_table.id_clusternameid = sheep_cluster_table.which_cluster
join birth_type_table on sheep_table.birth_type = birth_type_table.id_birthtypeid
join sheep_sex_table on sheep_table.sex = sheep_sex_table.sex_sheepid
join sheep_table as sire_table on sheep_table.sire_id = sire_table.sheep_id
join sheep_table as dam_table on sheep_table.dam_id = dam_table.sheep_id
left outer join sheep_ebv_table on sheep_table.sheep_id = sheep_ebv_table.sheep_id
left outer join sheep_evaluation_table on sheep_table.sheep_id = sheep_evaluation_table.sheep_id
WHERE (sheep_table.remove_date IS NULL or sheep_table.remove_date is '' )
and (eval_date > "2014-10-03%" and eval_date < "2014-11%")
and sheep_ebv_table.ebv_date = "2014-11-01"
order by sheep_sex_table.sex_abbrev asc, cluster_name asc, self_replacing_carcass_index desc, usa_maternal_index desc, overall_score desc
If a given sheep does not have a record in the evaluation table or does not have a record in the EBV table no record is returned. I need all the current animals returned with all available data on them and just leave the fields for EBVs and evaluations null if they have no data.
I'm not understanding why I'm not getting them all since none of the sheep have all 3 ID types (federal, farm and EID) so there are nulls in those fields and I was expecting nulls in the evaluation sum and ebv fields as well.
Totally lost in what to do to fix it.
The problem would appear to be that you're using eval_date in the WHERE statement. I'm assuming that eval_date is in the sheep_evaluation_table, so when you use it in WHERE, it gets rid of any rows where eval_date is NULL, which it would be when you're using a LEFT OUTER JOIN and there's no matching record in sheep_evaluation_table.
Try putting the eval_date filter on the join instead, like this:
left outer join sheep_evaluation_table on sheep_table.sheep_id = sheep_evaluation_table.sheep_id
AND (eval_date > "2014-10-03%" and eval_date < "2014-11%")
WHERE (sheep_table.remove_date IS NULL or sheep_table.remove_date is '' )
How to find records with duplicate values in any column using Activerecord or SQL?
SELECT leads.id, leads.name, leads.email, leads.created_at, array_agg(tn2.id) as ids
FROM "leads" join leads tn2
on leads.name = tn2.name
or leads.cpf_cnpj = tn2.cpf_cnpj
or leads.email = tn2.email
or leads.phone -> 'cellphone' = tn2.phone -> 'cellphone'
or leads.phone -> 'residence' = tn2.phone -> 'residence'
or leads.phone -> 'commercial' = tn2.phone -> 'commercial'
GROUP BY leads.id ORDER BY leads.created_at DESC
Using array_agg I want only ids from repeated objects, but it gives me from all records.
Currently, I'm using PostgreSQL.
How to find records with duplicate values in any column?
SELECT l.id, l.name, l.email, l.created_at, array_agg(l2.id) AS ids
FROM leads l
WHERE EXISTS (
SELECT 1
FROM leads
WHERE id <> l.id
AND (
name = l.name
OR cpf_cnpj = l.cpf_cnpj
OR email = l.email
OR phone->'cellphone' = l.phone->'cellphone'
OR phone->'residence' = l.phone->'residence'
OR phone->'commercial' = l.phone->'commercial'
)
);
But it seems like you want something different:
How to get an array of IDs for each row from rows that have the same value in at least one of several given columns, youngest entry first?
SELECT l.id, l.name, l.email, l.created_at
, array_agg(l2.id ORDER BY l2.created_at DESC NULL LAST) AS dupe_ids
FROM leads l
JOIN leads l2 ON l2.id <> l.id
AND (
l2.name = l.name
OR l2.cpf_cnpj = l.cpf_cnpj
OR l2.email = l.email
OR l2.phone->'cellphone' = l.phone->'cellphone'
OR l2.phone->'residence' = l.phone->'residence'
OR l2.phone->'commercial' = l.phone->'commercial'
)
GROUP BY l.id
ORDER BY l.created_at DESC NULL LAST;
Assuming id is the primary key.
I have tried all possible joins and sub-queries but I cant get the data to only return one value from table 2 that exactly matches the vendor ID. If I dont have the address included in the query, I get one hit for the vendor ID. How can I make it so that when I add the address, I only want the one vendor that I get prior to adding the address.
The vendor from table one must be VEN-CLASS IS NOT NULL.
This was my last attempt using subquery:
SELECT DISTINCT APVENMAST.VENDOR_GROUP,
APVENMAST.VENDOR,
APVENMAST.VENDOR_VNAME,
APVENMAST.VENDOR_CONTCT,
APVENMAST.TAX_ID,
Subquery.ADDR1
FROM (TEST.dbo.APVENMAST APVENMAST
INNER JOIN
(SELECT APVENADDR.ADDR1,
APVENADDR.VENDOR_GROUP,
APVENADDR.VENDOR,
APVENMAST.VEN_CLASS
FROM TEST.dbo.APVENADDR APVENADDR
INNER JOIN TEST.dbo.APVENMAST APVENMAST
ON (APVENADDR.VENDOR_GROUP = APVENMAST.VENDOR_GROUP)
AND (APVENADDR.VENDOR = APVENMAST.VENDOR)
WHERE (APVENMAST.VEN_CLASS IS NOT NULL)) Subquery
ON (APVENMAST.VENDOR_GROUP = Subquery.VENDOR_GROUP)
AND (APVENMAST.VENDOR = Subquery.VENDOR))
INNER JOIN TEST.dbo.APVENLOC APVENLOC
ON (APVENMAST.VENDOR_GROUP = APVENLOC.VENDOR_GROUP)
AND (APVENMAST.VENDOR = APVENLOC.VENDOR)
WHERE (APVENMAST.VEN_CLASS IS NOT NULL)
Try this:
SELECT APVENMAST.VENDOR_GROUP
, APVENMAST.VENDOR
, APVENMAST.VENDOR_VNAME
, APVENMAST.VENDOR_CONTCT
, APVENMAST.TAX_ID
, APVENADDR.ADDR1
FROM TEST.dbo.APVENMAST APVENMAST
INNER JOIN (
select VENDOR_GROUP, VENDOR, ADDR1
, row_number() over (partition by VENDOR_GROUP, VENDOR order by ADDR1) r
from TEST.dbo.APVENADDR
) APVENADDR
ON APVENADDR.VENDOR_GROUP = APVENMAST.VENDOR_GROUP
AND APVENADDR.VENDOR = APVENMAST.VENDOR
AND APVENADDR.r = 1
--do you need this table; you're not using it...
--INNER JOIN TEST.dbo.APVENLOC APVENLOC
--ON APVENMAST.VENDOR_GROUP = APVENLOC.VENDOR_GROUP
--AND APVENMAST.VENDOR = APVENLOC.VENDOR
WHERE APVENMAST.VEN_CLASS IS NOT NULL
--if the above inner join was to filter results, you can do this instead:
and exists (
select top 1 1
from TEST.dbo.APVENLOC APVENLOC
ON APVENMAST.VENDOR_GROUP = APVENLOC.VENDOR_GROUP
AND APVENMAST.VENDOR = APVENLOC.VENDOR
)
I found another column in the APVENLOC table that I can filter on to get the unique vendor. Turns out if the vendor address is for the main office, the vendor location is set blank.
Easier than I thought it would be!
SELECT DISTINCT APVENMAST.VENDOR_GROUP,
APVENMAST.VENDOR,
APVENMAST.VENDOR_VNAME,
APVENADDR.ADDR1,
APVENMAST.VENDOR_SNAME,
APVENADDR.LOCATION_CODE,
APVENMAST.VEN_CLASS
FROM TEST.dbo.APVENMAST APVENMAST
INNER JOIN TEST.dbo.APVENADDR APVENADDR
ON (APVENMAST.VENDOR_GROUP = APVENADDR.VENDOR_GROUP)
AND (APVENMAST.VENDOR = APVENADDR.VENDOR)
WHERE (APVENADDR.LOCATION_CODE = ' ')
Shaji
I'd preferably like to first query listed below and just group by stories.id, but I get the following error:
ERROR: column "u.first_name" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: SELECT "s".*, "u"."first_name", "u"."last_name", ("i"."filen...
The second query works but does not group by stories.id and generates the wrong results. Is it possible to select from multiple tables and not group by all of them?
The table panels also has a column updated_at. I would like to get the newest file per story according to panels.updated_at.
SELECT
"s".*,
"u"."first_name",
"u"."last_name",
("i"."filename" || '.' || "i"."extension") AS "file"
FROM
"stories" "s"
LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id")
LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id")
WHERE
"s"."complete" = false AND
"s"."created_by" = 205700489
GROUP BY
"s"."id",
ORDER BY
"s"."created_at" DESC
SELECT
"s".*,
"u"."first_name",
"u"."last_name",
("i"."filename" || '.' || "i"."extension") AS "file"
FROM
"stories" "s"
LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id")
LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id")
WHERE
"s"."complete" = false AND
"s"."created_by" = 205700489
GROUP BY
"s"."id",
"u"."first_name",
"u"."last_name", "i"."filename",
"i"."extension"
ORDER BY
"s"."created_at" DESC
Updated after clarification of the question:
SELECT DISTINCT ON (s.created_at, s.id)
s.*
,u.first_name
,u.last_name
,concat_ws('.', i.filename, i.extension) AS file
FROM stories s
LEFT JOIN users u ON u.uid = s.user_id
LEFT JOIN panels p ON p.story_id = s.id
LEFT JOIN images i ON i.id = p.image_id
WHERE s.complete = false
AND s.created_by = 205700489
ORDER BY s.created_at DESC, s.id, p.updated_at DESC;
Grouping by primary key requires PostgreSQL 9.1.
I use concat_ws(), because I don't know which columns might be NULL. If both i.filename and i.extension are defined NOT NULL, you can simplify.
Effect of the additional ORDER BY item p.updated_at DESC is that the "newest" file will be picked per story. The query technique is explained in full under this related question:
Select first row in each GROUP BY group?
You can write something like:
SELECT
"s".*,
(SELECT "u"."first_name"
FROM "users" "u"
WHERE "s"."user_id" = "u"."uid"
LIMIT 1) ,
(SELECT "u"."last_name"
FROM "users" "u"
WHERE "s"."user_id" = "u"."uid"
LIMIT 1),
(SELECT "i"."filename" || '.' || "i"."extension"
FROM "panels" "p"
JOIN "images" "i" ON ("p"."image_id" = "i"."id")
WHERE "p"."story_id" = "s"."id"
LIMIT 1) AS "file"
FROM
"stories" "s"
WHERE
"s"."complete" = false AND
"s"."created_by" = 205700489
ORDER BY
"s"."created_at" DESC
It will get only 1 record from "users" and "panels" JOIN "images" per record in "stories" .
Add ORDER BY, extra WHERE or some aggregates to get what you need from "users" and "panels" JOIN "images"
UPD Also, you can use something like this:
SELECT *
FROM (
SELECT DISTINCT ON ("s"."id")
"s".*,
"u"."first_name",
"u"."last_name",
("i"."filename" || '.' || "i"."extension") AS "file"
FROM
"stories" "s"
LEFT JOIN "panels" "p" ON("p"."story_id" = "s"."id")
LEFT JOIN "users" "u" ON("s"."user_id" = "u"."uid")
LEFT JOIN "images" "i" ON ("p"."image_id" = "i"."id")
WHERE
"s"."complete" = false AND
"s"."created_by" = 205700489
ORDER BY
"s"."id"
) t ORDER BY "t"."created_at" DESC
It will leave only one row for every distinct "s"."id"