Understanding pointers? - objective-c

As the title suggests, I'm having trouble understanding exactly what a pointer is and why they're used. I've searched around a bit but still don't really understand. I'm working in Objective-C mainly, but from what I've read this is really more of a C topic (so I added both tags).
From what I understand, a variable with an asterisks in front points to an address in memory? I don't quite understand why you'd use a pointer to a value instead of just using the value itself.
For example:
NSString *stringVar = #"This is a test.";
When calling methods on this string, why is it a pointer instead of just using the string directly? Why wouldn't you use pointers to integers and other basic data types?
Somewhat off topic, but did I tag this correctly? As I was writing it I thought that it was more of a programming concept rather than something language specific but it does focus specifically on Objective-C so I tagged it with objective-c and c.

I don't quite understand why you'd use a pointer to a value instead of
just using the value itself.
You use a pointer when you want to refer to a specific instance of a value instead of a copy of that value. Say you want me to double some value. You've got two options:
You can tell me what the value is: "5": "Please double 5 for me." That's called passing by value. I can tell you that the answer is 10, but if you had 5 written down somewhere that 5 will still be there. Anyone else who refers to that paper will still see the 5.
You can tell me where the value is: "Please erase the number I've written down here and write twice that number in its place." That's called passing by reference. When I'm done, the original 5 is gone and there's a 10 in its place. Anyone else who refers to that paper will now see 10.
Pointers are used to refer to some piece of memory rather than copying some piece of memory. When you pass by reference, you pass a pointer to the memory that you're talking about.
When calling methods on this string, why is it a pointer instead of just using the string directly?
In Objective-C, we always use pointers to refer to objects. The technical reason for that is that objects are usually allocated dynamically in the heap, so in order to deal with one you need it's address. A more practical way to think about it is that an object, by definition, is a particular instance of some class. If you pass an object to some method, and that method modifies the object, then you'd expect the object you passed in to be changed afterward, and to do that we need to pass the object by reference rather than by value.
Why wouldn't you use pointers to integers and other basic data types?
Sometimes we do use pointers to integers and other basic data types. In general, though, we pass those types by value because it's faster. If I want to convey some small piece of data to you, it's faster for me to just give you the data directly than it is to tell you where you can find the information. If the data is large, though, the opposite is true: it's much faster for me to tell you that there's a dictionary in the living room than it is for me to recite the contents of the dictionary.

I think maybe you have got a bit confused between the declaration of a pointer variable, and the use of a pointer.
Any data type with an asterisk after it is the address of a value of the data type.
So, in C, you could write:
char c;
and that means value of c is a single character. But
char *p;
is the address of a char.
The '*' after the type name, means the value of the variable is the address of a thing of that type.
Let's put a value into c:
c = 'H';
So
char *p;
means the value of p is the address of a character. p doesn't contain a character, it contains the address of a character.
The C operator & yields the address of a value, so
p = &c;
means put the address of the variable c into p. We say 'p points at c'.
Now here is the slightly odd part. The address of the first character in a string is also the address of the start of the string.
So for
char *p = "Hello World. I hope you are all who safe, sound, and healthy";
p contains the address of the 'H', and implicitly, because the characters are contiguous, p contains the address of the start of the string.
To get at the character at the start of the string, the 'H', use the 'get at the thing pointed to' operator, which is '*'.
So *p is 'H'
p = &c;
if (*p == c) { ... is true ... }
When a function or method is called, to use the string of characters, the only the start address of the string (typically 4 or 8 bytes) need be handed to the function, and not the entire string. This is both efficient, and also means the function can act upon the string, and change it, which may be useful. It also means that the string can be shared.

A pointer is a special variable that holds the memory location of an other variable.
So what is a pointer… look at the definition mentioned above. Lets do this one step at a time in the three step process below:
A pointer is a special variable that holds the memory location of an
other variable.
So a pointer is nothing but a variable… its a special variable. Why is it special, because… read point 2
A pointer is a special variable that holds the memory location of an
other variable.
It holds the memory location of another variable. By memory location I mean that it does not contain value of another variable, but it stores the memory address number (so to speak) of another variable. What is this other variable, read point 3.
A pointer is a special variable that holds the memory location of an
other variable.
Another variable could be anything… it could be a float, int, char, double, etc. As long as its a variable, its memory location on which it is created can be assigned to a pointer variable.

To answer each of your questions:
(1) From what I understand, a variable with an asterisks in front points
to an address in memory?
You can see it that way more or less. The asterisk is a dereference operator, which takes a pointer and returns the value at the address contained in the pointer.
(2) I don't quite understand why you'd use a pointer to a value instead of
just using the value itself.
Because pointers allow different sections of code to share information, better than copying the value here and there, and also allows pointed variables or objects to be modified by called function. Further, pointers enabled complex linked data structures. Read this short tutorial Pointers and Memory.
(3) Why wouldn't you use pointers to integers and other basic data types?
String is a pointer, unlike int or char. A string is a pointer that points to the starting address of data that contains the string, and return all the value from the starting address of the data until an ending byte.
string is a more complex datatype than char or int, for example. In fact, don't think sting as type like int of char. string is a pointer that points to a chunk of memory. Due to its complexity, having a Class like NSString to provide useful functions to work with them becomes very meaningful. See NSString.
When you use NSString, you do not create a string; you create an object that contains a pointer to the starting address of the string, and in addition, a collection of methods that allows you to manipulate the output of the data.

I have heard the analogy that an object is like a ballon, an the string you're holding it with is the pointer. Typically, code is executed like so:
MyClass *someObj = [[MyClass alloc] init];
The alloc call will allocate the memory for the object, and the init will instantiate it with a defined set of default properties depending on the class. You can override init.
Pointers allow references to be passed to a single object in memory to multiple objects. If we worked with values without pointers, you wouldn't be able to reference the same object in memory in two different places.

NSString *stringVar = #"This is a test.";
When calling methods on this string, why is it a pointer instead of just using the string directly?
This is a fairly existential question. I would posit it this way: what is the string if not its location? How would you implement a system if you can't refer to objects somehow? By name, sure... But what is that name? How does the machine understand it?
The CPU has instructions that work with operands. "Add x to y and store the result here." Those operands can be registers (say, for a 32-bit integer, like that i in the proverbial for loop might be stored), but those are limited in number. I probably don't need to convince you that some form of memory is needed. I would then argue, how do you tell the CPU where to find those things in memory if not for pointers?
You: "Add x to y and store it in memory."
CPU: OK. Where?
You: Uh, I dunno, like, where ever ...
At the lowest levels, it doesn't work like this last line. You need to be a bit more specific for the CPU to work. :-)
So really, all the pointer does is say "the string at X", where X is an integer. Because in order to do something you need to know where you're working. In the same way that when you have an array of integers a, and you need to take a[i], i is meaningful to you somehow. How is that meaningful? Well it depends on your program. But you can't argue that this i shouldn't exist.
In reality in those other languages, you're working with pointers as well. You're just not aware of it. Some people would say that they prefer it that way. But ultimately, when you go down through all the layers of abstraction, you're going to need to tell the CPU what part of memory to look at. :-) So I would argue that pointers are necessary no matter what abstractions you end up building.

Related

What's the difference between (ReturnClass *)methodName... and (ReturnClass)methodName... in Objective-C?

Quick question: The difference between (ReturnClass *)methodName... and (ReturnClass)methodName... in Objective-C?
I know (ReturnType *)methodName... returns an instance of ReturnClass as opposed to (ReturnClass)methodName just returning what?
Thank you.
if your ReturnClass is an object (which is most likely) then you can't use it without *. You'll get a compilation error. Otherwise *is a pointer to instance (primitive type or struct), and absence of * is instance itself
EDIT: Brilliant explanation on pointers from Joe:
Think of the instance as your house and the pointer as your address. Your house is a large object, so instead of making copies of your house and passing it to your friends when you have a party you give them your address so they can get to your house. Now if you had a small object, like a flyer, it would be easy to just make copies and pass out rather than give everyone instructions to get to that piece of paper. Think of the large object (house) as an Objective-C class or struct full of info, and the small object (flyer) as a primitive like int, BOOL, double etc

Does setting one pointer to an object to nil affect the object or other pointers to it?

Although I know the main difference between Deep Copy and Shallow Copy but what I want to ask here is something practical.
I have
NSArray *firstArray = [NSArray arrayWithObjects:#"first", #"second",#"third", nil];
NSArray *secondArray = firstArray;
secondArray = nil;
NSLog(#"First Array : %#",firstArray);
NSLog(#"Secon Array : %#",secondArray);
Both the firstArray and secondArray has the same reference as seen by putting break point.
Now my question is this, if both have same REFERENCE then why the firstArray does not change if the secondArray is changed.
I am really confused here...
Can any one please make me clear.
Thanks in anticipation.
I need to use ASCII art to explain this better...
firstArray
\
\
NSArray - the actual data
/
/
secondArray
firstArray and secondArray are just pointers, holding the same numerical (virtual) memory address where the NSArray data is stored. If one of the pointers is set to point to nil, or to some other data for that matter, it won't trigger any change in the NSArray nor the other pointer.
Note especially that while firstArray and secondArray both held the same value initially, they are distinct variables at different memory addresses. You can see that if you print:
NSLog(#"First Array : %#",&firstArray);
NSLog(#"Secon Array : %#",&secondArray);
I think you were mistaking the address they pointed to (the NSArray data's address) for their address, and then concluding they were different names for the same variable. They're not! Each has different memory.
You might want to read up on pointers: What does "dereferencing" a pointer mean?
pointers and references
A pointer variable is much like an integer variable - it takes a few bytes of memory (regardless of the size of the objects at which it may be pointed) and stores a number. That number can be used to record the (virtual) memory address (how many bytes from the 0 origin of (virtual) memory) at which a particular object of the pointed-to type may be found. So, it's a bit like having a piece of paper on which we can write the address of a house. Now, the pointer is NOT the house (data-object), and you can erase the original address and write the address of some other house anytime you like, and you can use that address to find the house. This is what happened in this question... you effectively had two "pieces of paper" on which you'd "written" the address of your "house", then erased one of them, and expected a dramatic affect such as the other piece of paper being erased and/or the house/object being destroyed. Pointers don't work like that.
Some languages have a distinct mechanism - which has been called "references", "aliases", "links" and many other things in various languages' terminology - that works like an additional name or alias for an object. Anything you "do" to one of these things is transparently done to that object instead. Returning to our house analogy: this is like having different names for your house - instead of using the street address, you may call it "home", or "my castle", and if you give the instruction "burn home" your house will really burn. With a pointer to your home - saying "burn pointer-to-home" just burns the piece of paper unless you go to a little extra effort to "dereference" the pointer and operate on the house.
When they need to be passed around the program at run-time, they reference/aliases/things... are typically implemented like pointers - effectively variables that store the address of the data object. But, regardless of whether they've been passed around at run-time or only existed transiently in the compiler's internal records, they operate as described above.
So, to people from a background where "reference" is the technical term used to describe these reference/alias/whatever things, it's "wrong" to hear people say pointers are references... our reaction is "no they're not - you'll burn the paper instead of the house if you think like that". But, there are whole communities of programmers for whom "reference" is another term for "pointer", and these other things might be known as "aliases" or "links" or "pseudonyms" or goodness knows what, or they might just not exist in that language/community (e.g. for C programmers).
All our discussion in comments is just about this potential confusion.
The important this is that you understand that operating on a pointer affects the numeric address in memory that pointer stores, and not the pointed-to object unless you dereference that pointer, and not other pointers to that object (unless they're all "smart pointers" with some deliberately orchestrated synchronisation).
I suggest you read the above until you can't get any more out of it, then re-read What does "dereferencing" a pointer mean? then reread this etc. until you're happy you've grasped it all.
Your current understanding
In comments below, you say:
Up to my understanding, Pointer is a variable that can contain a memory address in it and memory address is always takes as in sense of reference to a value.
The memory address in the pointer can reference/point-at a legitimate object/value, or it may be uninitialised or garbage, just as an integer variable may have a useful number in it or be uninitialised (not yet set), or hold some left-over value after earlier processing that you're no longer interested in.
Let me clear my point here, A Pointer has a memory address , at that memory address there will be some value.
That's ambiguous but correct however you mean it. The ambiguity: the pointer has a memory address in the sense of the memory where the pointer itself is stored. In that sense, every variable has a memory address. But, pointers also have a memory address in the sense of the memory address of the pointed-to data. (This is explained in my other answer linked above.)
So if some one has to get that value, there must be a reference to reach there and that reference is the property of that Point that is containing it.
Well, I think by value you mean the poined-to value: you must have a "memory address" to reach there (whether you want to call that address a reference is discussed above), and that address is stored in the pointer, so you could consider it a "property" of the pointer if you use "property" in the sense used by some languages. So yes! :-) I think your understanding's probably correct, but your terminology is still a little imprecise and ambiguous.

What is the biggest advantage of using pointers in ObjectiveC

I realize 99% of you think "what the h***…" But please help me to get my head around the this concept of using pointers. I'm sure my specific question would help lots of newbies.
I understand what pointers ARE and that they are a reference to an adress in memory and that by using the (*) operator you can get the value in that address.
Let's say:
int counter = 10;
int *somePointer = &counter;
Now I have the address in memory of counter, and I can indirectly point to its value by doing this:
int x = *somePointer;
Which makes x = 10, right?
But this is the most basic example, and for this case I could use int x = counter; and get that value, so please explain why pointers really are such an important thing in Objective-C and some other languages... in what case would only a pointer make sense?
Appreciate it.
Objective-C has pointers because it is an evolution of C, which used pointers extensively. The advantage of a pointer in an object-oriented language like Objective-C is that after you create an object, you can pass around a pointer to the object instead of passing around the object itself. In other words, if you have some object that takes up a large amount of storage space, passing around a pointer is a lot more memory-efficient than passing around a copy of the object itself. This may not be noticeable in simple cases when you’re only dealing with primitive types like ints, but when you start dealing with more complex objects the memory and time savings are enormous.
More importantly, pointers make it much easier for different parts of your code to talk to each other. If variables could only be passed to functions “by value” instead of “by reference” (which is what happens when you use pointers), then functions could never alter their inputs. They could only change the state of your program by either returning a value or by changing a global variable—the overuse of which generally leads to sloppy, unorganized code.
Here’s a concrete example. Suppose you have an Objective-C method that will parse a JSON string and return an NSDictionary:
+ (NSDictionary *)parseJsonString:(NSString *)json
error:(NSError **)error;
The method will do the parsing and return an NSDictionary if everything goes okay. But what if there’s some problem with the input string? We want a way to indicate to the user (or at least to the programmer) what happened, so we have a pointer to a pointer to an NSError, which will contain that information. If our method fails (probably returning nil), we can dereference the error parameter to see what went wrong. What we’ve effectively done is to give our method two different kinds of return values: usually, it will return an NSDictionary, but it could also return an NSError.
If you want to read more about this, you may have better luck searching for “pointers in C” rather than “pointers in Objective-C”; pointers are of course used extensively in Objective-C, but all of the underlying machinery is identical to that of C itself.
What is the biggest advantage of using pointers in ObjectiveC
I'd say the biggest advantage is that you can use Objective-C at all - all Objective-C objects are pointers are accessed using pointers (the compiler and the runtime won't let you create objects statically), so you wouldn't get any further without them...
Item:
What if I told you to write me a program that would maintain a set of counters, but the number of counters would be entered by the user when he started the program. We code this with an array of integers allocated on the heap.
int *counters = malloc(numOfCounters * sizeof(int));
Malloc works with memory directly, so it by nature returns a pointer. All Objective-C objects are heap-allocated with malloc, so these are always pointers.
Item:
What if I told you to write me a function that read a file, and then ran another function when it was done. However, this other function was unknown and would be added by other people, people I didn't even know.
For this we have the "callback". You'd write a function that looked like this:
int ReadAndCallBack(FILE *fileToRead, int numBytes, int whence, void(*callback)(char *));
That last argument is a pointer to a function. When someone calls the function you've written, they do something like this:
void MyDataFunction(char *dataToProcess);
ReadAndCallBack(myFile, 1024, 0, MyDataFunction);
Item:
Passing a pointer as a function argument is the most common way of returning multiple values from a function. In the Carbon libraries on OSX, almost all of the library functions return an error status, which poses a problem if a library function has to return something useful to the programmer. So you pass the address where you'd like the function to hand information back to you...
int size = 0;
int error = GetFileSize(afilePath,&size);
If the function call returns an error, it is in error, if there was no error, error will probably be zero and size will contain what we need.
The biggest advantage of pointers in Objective-C, or in any language with dynamic allocation, is that your program can handle more items than the names that you invent in your source code.

What points to a pointer?

As I understand pointers contain the address of data at another memory location?
When an app is running how is the location of pointers kept track of?
Why bother keeping track of the pointer, why not just directly keep track of address the pointer holds?
Additionally if I have the following code:
NSString *string = #"hello";
string = #"bye";
I am changing the value stored in the pointer named string (is it the pointer that is named string or the NSString object?) to the address of the new string ("bye"), right?
So how would I go about changing directly the object stored at the address held by the pointer?
(Also what is the correct terminology to use where I have used "keep track of"?)
Thanks
Why bother keeping track of the pointer, why not just directly keep
track of address the pointer holds?
Object references in objective C are actually pointers, so each time you use an object (such as NSString), you use a pointer to it - (NSString *)
I am changing the value stored in the pointer named string (is it the
pointer that is named string or the NSString object?) to the address
of the new string ("bye"), right?
Right.
So how would I go about changing directly the object stored at the
address held by the pointer?
In the case of such strings, they are immutable, and you can't change them, in case of other objects, you call their methods, or set their properties.
When an app is running how is the location of pointers kept track of?
Pointers are stored as any other variable; they typically take the same size as an unsigned long, but this is by no means guaranteed, just to give you an idea of how they are implemented. Compilers are free to do a huge variety of optimizations, so the pointers may be stored in memory, they may be stored in registers, or they may exist only as hypothetical entities if they are optimized away.
Consider the following code:
void foo(void) {
char *c;
char buf[100];
for (c=buf; c < buf+100; c++ {
c = '0';
}
}
In this case, the variable c is being used to write an ASCII 0 character to every character in the buf array. c may exist only in a register, because it does not live beyond this function. (There are better ways of writing this code.)
Consider the following code:
struct foo {
char name[10];
struct foo *next;
}
The member next in this case is a pointer to further struct foo objects -- say, a linked list of these things. These pointers must be stored in memory, because they are part of the contract of these objects -- they have to be there. There is no way around these pointers, either -- the objects they point to can be replaced with other objects on the programmer's whim. And, since the number of these objects is determined entirely at runtime, the compiler can't just keep track of the addresses in its symbol tables, as it would for stack-allocated variables.
So how would I go about changing directly the object stored at the address held by the pointer?
This is complicated by your example's use of "foo" strings in the code. These are saved in read-only memory in the process address space, so you cannot modify them. (Surprise!) If you initialize the strings with another method, you can modify the data via the pointer:
char *c = malloc(10);
strcpy(c, "hello");
c[0] = 'H';
printf("c: %s\n", c);
This will overwrite the h with H in the allocated space available via the c pointer. Accessing pointers as if they were arrays is the same re-writing the pointer access like this:
c[0] = 'f';
c+0 = 'f';
And, in fact, array accesses are pretty similar -- the name of the array is the same as a pointer to its first element.
It's a little complicated; the book Expert C Programming covers pointers in astonishing detail and is well worth the money.
Q : So how would I go about changing directly the object stored at the address held by the pointer?
Ans : start using NSMutableString if you want to change the content of memory location pointed by the your string pointer.
NSString is inmutable type ie you can't change the content but you can make the pointer to point somewhere else. "hello" to "bye" in your case.

How does a NSMutableString exactly work?

I know all instances of NSString are inmutable. If you assign a new value to a string new memory is addressed and the old string will be lost.
But if you use NSMutableString the string will always keep his same address in memory, no matter what you do.
I wonder how this exactly works. With methods like replaceCharactersInRange I can even add more characters to a string so I need more memory for my string. What happens to the objects in memory that follow the string? Are they all relocated and put somewhere else in memory? I don't think so. But what is really going on?
I know all instances of NSString are
inmutable. If you assign a new value
to a string new memory is addressed
and the old string will be lost.
That isn't how mutability works, nor how references to NSStrings work. Nor how pointers work.
A pointer to an object -- NSString *a; declares a variable a that is a pointer to an object -- merely holds the address in memory of the object. The actual object is [generally] an allocation on the heap of memory that contains the actual object itself.
In those terms, there is really no difference at runtime between:
NSString *a;
NSMutableString *b;
Both are references to -- addresses of -- some allocation in memory. The only difference is during compile time, b will be treated differently than a and the compiler will not complain if, say, you use NSMutableString methods when calling b (but would when calling a).
As far as how NSMutableString works, it contains a buffer (or several buffers -- implementation detail) internally that contain the string data. When you call one of the methods that mutate the string's contents, the mutable string will re-allocate its internal storage as necessary to contain the new data.
Objects do not move in memory. Once allocated, an allocation will never move -- the address of the object or allocation will never change. The only semi-exception is when you use something like realloc() which might return a different address. However, that is really just a sequence of free(); malloc(); memcpy();.
I'd suggest you revisit the Objective-C Programming Guide or, possibly, a C programming manual.
the NSMutableString works just like the C++ std::string do. i don't know exactly how they work, but there are two popular approaches:
concating
you create a struct with two variables. one char and one pointer.
when a new char(or more are added) you create a new instance of the struct, and add the address to the last struct instance of the string. this way you have a bunch of structs with a pointer directing to the next struct.
copy & add
the way most newbies will go. not the worst, but maybe the slowest.
you save a "normal" unmutable string. if a new char is added, you allocate a area in the memory with the size of the old string +1, copy the old string and concate the new char. that's a very simple approach, isn't it?
a bit more advanced version would be to create the new string with a size +50, and just add the chars and a new null at the end, don't forget the to overwrite the old null. this way it's more efficient for string with a lot of changes.
as i said before, i don't know how std::string or NSMutableString approaches this issue. but these are the most common ways.