Here is the question and database info.
Use the UNION command to prepare a full statement for customer 'C001' - it should be laid out as follows. (Note that the values shown below are not correct.) You may be able to use '' or NULL for blank values - if necessary use 0.
Here is a link to the webpage with the database info. http://sqlzoo.net/5_0.htm or see the image below.
Here is what I have tried:
SELECT sdate AS LineDate, "delivery" AS LEGEND, price*quantity AS Total,"" AS Amount
FROM shipped
JOIN product ON (shipped.product=product.id)
WHERE badguy='C001'
UNION
SELECT rdate,notes, "",receipt.amount
FROM receipt
WHERE badguy='C001'
Here is what I get back:
Wrong Answer. The correct answer has 5 row(s).
The amounts don't seem right in the amount column and I can't figure out how to order the data by the date since it is using two different date columns (sdate and rdate which are UNIONED).
Looks like the data in the example is being aggregated by date and charge type using group by, that's why you are getting too many rows.
Also, you can sort by the alias of the column (LineDate) and the order by clause will apply to all the rows in the union.
SELECT sdate AS LineDate, "delivery" AS LEGEND, SUM(price*quantity) AS Total,"" AS Amount
FROM shipped
JOIN product ON (shipped.product=product.id)
WHERE badguy='C001'
GROUP BY sdate
UNION
SELECT rdate, notes, "",receipt.amount
FROM receipt
WHERE badguy='C001'
ORDER BY LineDate
It's usually easiest to develop each part of the union separately. Pay attention to the use of "null" to separate the monetary columns. The first select gets to name the columns.
select s.sdate as tr_date, 'Delivery' as type, sum((s.quantity * p.price)) as extended_price, null as amount
from shipped s
inner join product p on p.id = s.product
where badguy = 'C001'
group by s.sdate
union all
select rdate, notes, null, sum(amount)
from receipt
where badguy = 'C001'
group by rdate, notes
order by tr_date
Related
I need to update the following query so that it only returns one child record (remittance) per parent (claim).
Table Remit_To_Activate contains exactly one date/timestamp per claim, which is what I wanted.
But when I join the full Remittance table to it, since some claims have multiple remittances with the same date/timestamps, the outermost query returns more than 1 row per claim for those claim IDs.
SELECT * FROM REMITTANCE
WHERE BILLED_AMOUNT>0 AND ACTIVE=0
AND REMITTANCE_UUID IN (
SELECT REMITTANCE_UUID FROM Claims_Group2 G2
INNER JOIN Remit_To_Activate t ON (
(t.ClaimID = G2.CLAIM_ID) AND
(t.DATE_OF_LATEST_REGULAR_REMIT = G2.CREATE_DATETIME)
)
where ACTIVE=0 and BILLED_AMOUNT>0
)
I believe the problem would be resolved if I included REMITTANCE_UUID as a column in Remit_To_Activate. That's the REAL issue. This is how I created the Remit_To_Activate table (trying to get the most recent remittance for a claim):
SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
MAX(claim_id) AS ClaimID,
INTO Latest_Remit_To_Activate
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID
Claims_Group2 contains these fields:
REMITTANCE_UUID,
CLAIM_ID,
BILLED_AMOUNT,
CREATE_DATETIME
Here are the 2 rows that are currently giving me the problem--they're both remitts for the SAME CLAIM, with the SAME TIMESTAMP. I only want one of them in the Remits_To_Activate table, so only ONE remittance will be "activated" per Claim:
enter image description here
You can change your query like this:
SELECT
p.*, latest_remit.DATE_OF_LATEST_REMIT
FROM
Remittance AS p inner join
(SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
claim_id,
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID) as latest_remit
on latest_remit.claim_id = p.claim_id;
This will give you only one row. Untested (so please run and make changes).
Without having more information on the structure of your database -- especially the structure of Claims_Group2 and REMITTANCE, and the relationship between them, it's not really possible to advise you on how to introduce a remittance UUID into DATE_OF_LATEST_REMIT.
Since you are using SQL Server, however, it is possible to use a window function to introduce a synthetic means to choose among remittances having the same timestamp. For example, it looks like you could approach the problem something like this:
select *
from (
select
r.*,
row_number() over (partition by cg2.claim_id order by cg2.create_datetime desc) as rn
from
remittance r
join claims_group2 cg2
on r.remittance_uuid = cg2.remittance_uuid
where
r.active = 0
and r.billed_amount > 0
and cg2.active = 0
and cg2.billed_amount > 0
) t
where t.rn = 1
Note that that that does not depend on your DATE_OF_LATEST_REMIT table at all, it having been subsumed into the inline view. Note also that this will introduce one extra column into your results, though you could avoid that by enumerating the columns of table remittance in the outer select clause.
It also seems odd to be filtering on two sets of active and billed_amount columns, but that appears to follow from what you were doing in your original queries. In that vein, I urge you to check the results carefully, as lifting the filter conditions on cg2 columns up to the level of the join to remittance yields a result that may return rows that the original query did not (but never more than one per claim_id).
A co-worker offered me this elegant demonstration of a solution. I'd never used "over" or "partition" before. Works great! Thank you John and Gaurasvsa for your input.
if OBJECT_ID('tempdb..#t') is not null
drop table #t
select *, ROW_NUMBER() over (partition by CLAIM_ID order by CLAIM_ID) as ROW_NUM
into #t
from
(
select '2018-08-15 13:07:50.933' as CREATE_DATE, 1 as CLAIM_ID, NEWID() as
REMIT_UUID
union select '2018-08-15 13:07:50.933', 1, NEWID()
union select '2017-12-31 10:00:00.000', 2, NEWID()
) x
select *
from #t
order by CLAIM_ID, ROW_NUM
select CREATE_DATE, MAX(CLAIM_ID), MAX(REMIT_UUID)
from #t
where ROW_NUM = 1
group by CREATE_DATE
I have following SQL Query which return result
of itemno and no of total quantity sale.I want itemdescripton column against each item no as well.ITEMDESC# column in table invitems.
SQL QUERY :
select INITEMS.ITEMNO,(COUNT(INITEMS.ITEMNO)*COUNT(INITEMS.QTY)) 'Item
Sale',INITEMS.ITEMDESC#1 from InvItems INITEMS
INNER JOIN InvHdr HDR ON INITEMS.INVNO=HDR.INVNO
WHERE INITEMS.TYPE='3'
GROUP BY INITEMS.ITEMNO,INITEMS.ITEMDESC#1
I want max date (last date item sale) column in result.Date column in InvHdr table against each InvNo
As explain in the earlier comments, your query does not works because you have different ITEMDESC for the same ITEMNO
This you "gives" you the result that you want
select INITEMS.ITEMNO,
MAX(INITEMS.ITEMDESC#1) AS 'ITEMDESC',
(COUNT(INITEMS.ITEMNO)*COUNT(INITEMS.QTY)) 'Item Sale'
FROM InvItems INITEMS
INNER JOIN InvHdr HDR ON INITEMS.INVNO = HDR.INVNO
WHERE INITEMS.TYPE = '3'
GROUP BY INITEMS.ITEMNO
But you must check why there are such as in your data. You can list out those ITEMNO that is of such case
SELECT ITEMNO
FROM InvItems
GROUP BY ITEMNO
HAVING MAX(ITEMDESC#1) <> MIN(ITEMDESC#1)
Assuming you are working with an SQL Server version higher than 2005 (which is a pretty safe assumption these days), you can use the over clause with aggregating functions, thus potentially eliminating the need for the group by clause (that is potentially since group by will return distinct results for each value (or set of values) that exists in the group by clause - so you might also need to use distinct:
SELECT initems.itemno,
COUNT(initems.itemno) OVER (PARTITION BY initems.itemno)
* SUM(initems.qty) OVER (PARTITION BY initems.itemno)
FROM InvItems AS initems
WHERE initems.type = '3'
I have at least 8 tables from where I need to match the customer name and fetch the quantities and get the sum of all the quantities fetched from these 8 tables. I am trying to write a code which will ignore the customer whose sum of quantities is zero.
For an example lets take two tables purchase_sugar and sales_sugar I have tried a lot of queries but only this one is returning some result which is wrong.
SELECT sum(purchase_sugar.qty + sales_sugar.qty) AS Total_Amount from purchase_sugar inner join sales_sugar on purchase_sugar.supplier = sales_sugar.customer WHERE purchase_sugar.supplier = "+str(x.id)+"
The Table structures are like:
purchase_sugar have two columns supplier and qty.
And sales_sugar have structure like customer and qty.
How can I get the SUM of QUANTITIES of these tables if I provide one name and search it through these tables and get the quantities. The other thing is that I dont want the customer to be found in all the tables. If it is found in one table we should just get the quantity from that one table and for that reason I don't think that JOIN is useful or may be i am wrong.
To take care of the situation where a supplier/customer is not in all the tables, you can use union all and group by:
select name, sum(p_qty) as sum_p, sum(s_qty) as sum_s,
sum(p_qty) + sum(s_qty)
from ((select ps.supplier as name, ps.qty as p_qty, 0 as s_qty
from purchase_sugar ps
) union all
(select ss.customer as name, 0, ss.qty
from sales_sugar ss
)
) s
group by name;
Notes:
This query gets results for all names. You can use a where clause to restrict the results to one name.
You don't have to split the quantities into two (or eight) different columns, if you just want the overall sum.
You can aggregate before the union all, but that is not necessary.
you should JOIN the sum and not sum the join
select t1.purchase_sum + sales_sum as Total_Amount
from (
select purchase_sugar.supplier, sum(purchase_sugar.qty) as purchase_sum
from purchase_sugar
group by purchase_sugar.supplier
) t1
inner join (
select sales_sugar.customer, sum(sales_sugar.qty) as sales_sum
from sales_sugar
group by sales_sugar.customer
) t2 on t1.supplier = t2.customer and t1.supplier = "+str(x.id)+"
My SQL is quite rusty, so much that I have not created a view before and I am not entirely sure how to do what I need. Perhaps I need a stored procedure. Here is the deal.
We have a a database of ticket history (purchases). We want to filter on a certain SKU, but we want all line items from each ticket that has that SKU. For isntance, Someone buys a shirt and a hat. I want to filter on the shirt to find everyone who wants a shirt but display the entire ticket showing the shirt and the hat.
I thought my query would be something like this but I don't think it would work.
select
ticket_id, post_date, qty_sold, total_price, sales_total
from
ticket_history
where
sku = 'xxxx'
Union
select
sku as trans_sku, qty_sold as trans_qty_sold, desc as trans_desc, total_price as trans_total_price
from
ticket_history
where
ticket_id = <the ticket id in first query>
Perhaps a sub-select is what is needed but I'm not too understanding of how to do that either.
Any suggestions would be great.
I am not sure what you are trying to do here and whether UNION is what you are looking for or not.
In your query the columns are different and doesn't matched between the two queries. Any way, you can use a Common table Expression so that you can reuse the subquery, this should solve your problem:
WITH FirstQuery
AS
(
select
ticket_id,
post_date,
qty_sold,
total_price,
sales_total
from ticket_history
where sku = 'xxxx'
)
SELECT *
FROM FirstQuery
UNION
SELECT
... -- You should select the same number of columns
... -- and with the same data types to match the first columns
from ticket_history
where ticket_id IN(SELECT ticket_id FROM FirstQuery);
Here the FirstQuery acts like a subquery, but here you can reuse it later like what we did and use it in the where clause.
But, again the columns you selected in the first query:
ticket_id,
post_date,
qty_sold,
total_price,
sales_total
are different than the columns you selected in the second query:
sku as trans_sku,
qty_sold as trans_qty_sold,
desc as trans_desc,
total_price as trans_total_price
These columns should be matched (the count of them and data types). Otherwise you will got an error.
Things to note about UNION:
the columns count should be the same between the two queries.
The columns' names are driven from the first query.
When doing a UNION, the selected columns must match between the two select's. (Same number of columns, and matching data types.)
Maybe you want a self join instead?
select th1.ticket_id, th1.post_date, th1.qty_sold, th1.total_price, th1.sales_total,
th2.sku as trans_sku, th2.qty_sold as trans_qty_sold,
th2.desc as trans_desc, th2.total_price as trans_total_price
from ticket_history th1
left join ticket_history th2 on th2.ticket_id = th1.ticket_id
where th1.sku = 'xxxx'
LEFT JOIN to get th1 rows even if there are no matching th2 row.
Hi guys, I am stuck with a stubborn problem which I am unable to solve. Am trying to compile a report wherein all the dates coming from different tables would need to come into a single date field in the report. Ofcourse, the max or the most recent date from all these date columns needs to be added to the single date column for the report. I have multiple users of multiple branches/courses for whom the report would be generated.
There are multiple blogs and the latest date w.r.t to the blogtitle needs to be grouped, i.e. max(date_value) from the six date columns should give the greatest or latest date for that blogtitle.
Expected Result:
select u.batch_uid as ext_person_key, u.user_id, cm.batch_uid as ext_crs_key, cm.crs_id, ir.role_id as
insti_role, (CASE when b.JOURNAL_IND = 'N' then
'BLOG' else 'JOURNAL' end) as item_type, gm.title as item_name, gm.disp_title as ITEM_DISP_NAME, be.blog_pk1 as be_blogPk1, bc.blog_entry_pk1 as bc_blog_entry_pk1,bc.pk1,
b.ENTRY_mod_DATE as b_ENTRY_mod_DATE ,b.CMT_mod_DATE as BlogCmtModDate, be.CMT_mod_DATE as be_cmnt_mod_Date,
b.UPDATE_DATE as BlogUpDate, be.UPDATE_DATE as be_UPDATE_DATE,
bc.creation_date as bc_creation_date,
be.CREATOR_USER_ID as be_CREATOR_USER_ID , bc.creator_user_id as bc_creator_user_id,
b.TITLE as BlogTitle, be.TITLE as be_TITLE,
be.DESCRIPTION as be_DESCRIPTION, bc.DESCRIPTION as bc_DESCRIPTION
FROM users u
INNER JOIN insti_roles ir on u.insti_roles_pk1 = ir.pk1
INNER JOIN crs_users cu ON u.pk1 = cu.users_pk1
INNER JOIN crs_mast cm on cu.crsmast_pk1 = cm.pk1
INNER JOIN blogs b on b.crsmast_pk1 = cm.pk1
INNER JOIN blog_entry be on b.pk1=be.blog_pk1 AND be.creator_user_id = cu.pk1
LEFT JOIN blog_CMT bc on be.pk1=bc.blog_entry_pk1 and bc.CREATOR_USER_ID=cu.pk1
JOIN gradeledger_mast gm ON gm.crsmast_pk1 = cm.pk1 and b.grade_handler = gm.linkId
WHERE cu.ROLE='S' AND BE.STATUS='2' AND B.ALLOW_GRADING='Y' AND u.row_status='0'
AND u.available_ind ='Y' and cm.row_status='0' and and u.batch_uid='userA_157'
I am getting a resultset for the above query with multiple date columns which I want > > to input into a single columnn. The dates have to be the most recent, i.e. max of the dates in the date columns.
I have successfully done the Unpivot by using a view to store the above
resultset and put all the dates in one column. However, I do not
want to use a view or a table to store the resultset and then do
Unipivot simply because I cannot keep creating views for every user
one would query for.
The max(date_value) from the date columns need to be put in one single column. They are as follows:
* 1) b.entry_mod_date, 2) b.cmt_mod_date ,3) be.cmt_mod_date , 4) b.update_Date ,5) be.update_date, 6) bc.creation_date *
Apologies that I could not provide the desc of all the tables and the
fields being used.
Any help to get the above mentioned max of the dates from these
multiple date columns into a single column without using a view or a
table would be greatly appreciated.*
It is not clear what results you want, but the easiest solution is to use greatest().
with t as (
YOURQUERYHERE
)
select t.*,
greatest(entry_mod_date, cmt_mod_date, cmt_mod_date, update_Date,
update_date, bc.creation_date
) as greatestdate
from t;
select <columns>,
case
when greatest (b_ENTRY_mod_DATE) >= greatest (BlogCmtModDate) and greatest(b_ENTRY_mod_DATE) >= greatest(BlogUpDate)
then greatest( b_ENTRY_mod_DATE )
--<same implementation to compare each time BlogCmtModDate and BlogUpDate separately to get the greatest then 'date'>
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
case
when greatest (be_cmnt_mod_Date) >= greatest (be_UPDATE_DATE)
then greatest( be_cmnt_mod_Date )
when greatest (be_UPDATE_DATE) >= greatest (be_cmnt_mod_Date)
then greatest( be_UPDATE_DATE )
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
GREATEST(bc_creation_date)
,<columns>
FROM table
<rest of the query>