displaying reporting weeks - sql

I dont know how to loop through so that the query displays all the weeks from the reporting date?
The code determines the Mon - Sun week then should insert the values in a temp table to then query the weeks. I have hard coded the report_date and its hould display more than one record.
any ideas
DECLARE #REPORT_DATE DATETIME, #WEEK_BEGINING VARCHAR(10)
SELECT #REPORT_DATE = '2011-01-01T00:00:00'
--SELECT #REPORT_DATE = GETDATE() -- should grab the date now.
SELECT #WEEK_BEGINING = 'MONDAY'
IF #WEEK_BEGINING = 'MONDAY'
SET DATEFIRST 1
ELSE IF #WEEK_BEGINING = 'TUESDAY'
SET DATEFIRST 2
ELSE IF #WEEK_BEGINING = 'WEDNESDAY'
SET DATEFIRST 3
ELSE IF #WEEK_BEGINING = 'THURSDAY'
SET DATEFIRST 4
ELSE IF #WEEK_BEGINING = 'FRIDAY'
SET DATEFIRST 5
ELSE IF #WEEK_BEGINING = 'SATURDAY'
SET DATEFIRST 6
ELSE IF #WEEK_BEGINING = 'SUNDAY'
SET DATEFIRST 7
DECLARE #WEEK_START_DATE DATETIME, #WEEK_END_DATE DATETIME
--GET THE WEEK START DATE
SELECT #WEEK_START_DATE = #REPORT_DATE - (DATEPART(DW, #REPORT_DATE) - 1)
--GET THE WEEK END DATE
SELECT #WEEK_END_DATE = #REPORT_DATE + (7 - DATEPART(DW, #REPORT_DATE))
PRINT 'Week Start: ' + CONVERT(VARCHAR, #WEEK_START_DATE)
PRINT 'Week End: ' + CONVERT(VARCHAR, #WEEK_END_DATE)
CREATE TABLE #WeekList
(
month_date date
)
DECLARE #Interval int = 1
INSERT INTO #WeekList SELECT #WEEK_START_DATE
WHILE #Interval < 1
BEGIN
INSERT INTO #WeekList SELECT DATEADD(MONTH, - #Interval, #WEEK_START_DATE)
SET #Interval = #Interval + 1
END
SELECT
--Create the month ID code:
#WEEK_START_DATE AS Start_Week, #WEEK_END_DATE AS End_Week
FROM #WeekList
ORDER BY Start_Week DESC
DROP TABLE #WeekList

Using DATEADD and updating your #interval initialization and updated loop logic:
DECLARE #REPORT_DATE DATETIME, #WEEK_BEGINING VARCHAR(10)
SELECT #REPORT_DATE = '2011-01-01T00:00:00'
--SELECT #REPORT_DATE = GETDATE() -- should grab the date now.
SELECT #WEEK_BEGINING = 'MONDAY'
IF #WEEK_BEGINING = 'MONDAY'
SET DATEFIRST 1
ELSE IF #WEEK_BEGINING = 'TUESDAY'
SET DATEFIRST 2
ELSE IF #WEEK_BEGINING = 'WEDNESDAY'
SET DATEFIRST 3
ELSE IF #WEEK_BEGINING = 'THURSDAY'
SET DATEFIRST 4
ELSE IF #WEEK_BEGINING = 'FRIDAY'
SET DATEFIRST 5
ELSE IF #WEEK_BEGINING = 'SATURDAY'
SET DATEFIRST 6
ELSE IF #WEEK_BEGINING = 'SUNDAY'
SET DATEFIRST 7
DECLARE #WEEK_START_DATE DATETIME, #WEEK_END_DATE DATETIME
--GET THE WEEK START DATE
SELECT #WEEK_START_DATE = #REPORT_DATE - (DATEPART(DW, #REPORT_DATE) - 1)
--GET THE WEEK END DATE
SELECT #WEEK_END_DATE = #REPORT_DATE + (7 - DATEPART(DW, #REPORT_DATE))
PRINT 'Week Start: ' + CONVERT(VARCHAR, #WEEK_START_DATE)
PRINT 'Week End: ' + CONVERT(VARCHAR, #WEEK_END_DATE)
DECLARE #Interval int = datediff(WEEK,getdate(),#WEEK_START_DATE)+1
SELECT Start_Week=#WEEK_START_DATE
, End_Week=#WEEK_END_DATE
INTO #WeekList
WHILE #Interval <= 0
BEGIN
set #WEEK_START_DATE=DATEADD(WEEK,1,#WEEK_START_DATE)
set #WEEK_END_DATE=DATEADD(WEEK,1,#WEEK_END_DATE)
INSERT INTO #WeekList values (#WEEK_START_DATE,#WEEK_END_DATE)
SET #Interval += 1;
END
SELECT *
FROM #WeekList
ORDER BY Start_Week DESC
DROP TABLE #WeekList
Results (top 5 and bottom 5 of list):
Start_Week End_Week
----------------------- -----------------------
2012-03-12 00:00:00.000 2012-03-18 00:00:00.000
2012-03-05 00:00:00.000 2012-03-11 00:00:00.000
2012-02-27 00:00:00.000 2012-03-04 00:00:00.000
2012-02-20 00:00:00.000 2012-02-26 00:00:00.000
2012-02-13 00:00:00.000 2012-02-19 00:00:00.000
...
2011-01-24 00:00:00.000 2011-01-30 00:00:00.000
2011-01-17 00:00:00.000 2011-01-23 00:00:00.000
2011-01-10 00:00:00.000 2011-01-16 00:00:00.000
2011-01-03 00:00:00.000 2011-01-09 00:00:00.000
2010-12-27 00:00:00.000 2011-01-02 00:00:00.000
As an aside, you could also use the date type instead of Datetime, if you don't need to store the time.

If you would like to list the weeks and the corresponding counts or sums, you can do this as follows
Sample data
myDate
----------
2012-03-15
2012-03-15
2012-03-15
2012-03-14
2012-03-14
2012-03-14
2012-03-14
2012-03-09
2012-03-09
2012-03-09
2012-03-08
2012-03-08
2012-03-08
2012-03-01
2012-03-01
2012-03-01
2012-03-01
2012-02-29
2012-02-29
2012-02-29
2012-02-29
2012-02-23
2012-02-23
2012-02-23
2012-02-22
2012-02-22
2012-02-22
2012-02-22
Script for sample data
create table #myTable(mydate Date)
insert into #myTable select DATEADD(day, -1, getdate())
insert into #myTable select DATEADD(day, -1, getdate())
insert into #myTable select DATEADD(day, -1, getdate())
insert into #myTable select DATEADD(day, -2, getdate())
insert into #myTable select DATEADD(day, -2, getdate())
insert into #myTable select DATEADD(day, -2, getdate())
insert into #myTable select DATEADD(day, -2, getdate())
insert into #myTable select DATEADD(day, -7, getdate())
insert into #myTable select DATEADD(day, -7, getdate())
insert into #myTable select DATEADD(day, -7, getdate())
insert into #myTable select DATEADD(day, -8, getdate())
insert into #myTable select DATEADD(day, -8, getdate())
insert into #myTable select DATEADD(day, -8, getdate())
insert into #myTable select DATEADD(day, -15, getdate())
insert into #myTable select DATEADD(day, -15, getdate())
insert into #myTable select DATEADD(day, -15, getdate())
insert into #myTable select DATEADD(day, -15, getdate())
insert into #myTable select DATEADD(day, -16, getdate())
insert into #myTable select DATEADD(day, -16, getdate())
insert into #myTable select DATEADD(day, -16, getdate())
insert into #myTable select DATEADD(day, -16, getdate())
insert into #myTable select DATEADD(day, -22, getdate())
insert into #myTable select DATEADD(day, -22, getdate())
insert into #myTable select DATEADD(day, -22, getdate())
insert into #myTable select DATEADD(day, -23, getdate())
insert into #myTable select DATEADD(day, -23, getdate())
insert into #myTable select DATEADD(day, -23, getdate())
insert into #myTable select DATEADD(day, -23, getdate())
Expected Result
Count WeekStart WeekEnd
----- ---------- ----------
7 2012-02-20 2012-02-24
8 2012-02-27 2012-03-02
6 2012-03-05 2012-03-09
7 2012-03-12 2012-03-16
How to do
SET DATEFIRST 1
SELECT
COUNT(*) [Count],
DATEADD(DD, -(DATEPART(DW, mydate)-1), mydate) [WeekStart],
DATEADD(DD, 7-(DATEPART(DW, mydate)+2), mydate) [WeekEnd]
FROM
#myTable
WHERE
DATEPART(dw, mydate) >= 1 AND DATEPART(dw, mydate) <= 5 -- only weekdays
GROUP BY
DATEADD(DD, -(DATEPART(DW, mydate)-1), mydate),
DATEADD(DD, 7-(DATEPART(DW, mydate)+2), mydate)
ORDER BY
DATEADD(DD, -(DATEPART(DW, mydate)-1), mydate)

Related

Get every 2 weeks on particular days SQL Server

I have a query getting the days in particular day that I selected and show the days in a month. My problem is that I need every two weeks of the month. And I also need to get long date format: dddd, dd MMMM yyyy and eliminate the time. Please help me.
DECLARE #startDate DATETIME = '9/1/2019'
DECLARE #endDate DATETIME = '12/31/2019'
DECLARE #dayOfWeek INT = 1;
WITH cte_Recursion AS
(
SELECT #startDate AS [Date]
UNION ALL
SELECT DATEADD(DAY, 1, [Date])
FROM cte_Recursion
WHERE [Date] < #endDate
)
SELECT [Date]
FROM cte_Recursion
WHERE DATEPART(WEEKDAY, [Date]) = #dayOfWeek
OPTION (MAXRECURSION 0)
The data returned looks like this:
2019-09-01 00:00:00.000
2019-09-08 00:00:00.000
2019-09-15 00:00:00.000
2019-09-22 00:00:00.000
2019-09-29 00:00:00.000
2019-10-06 00:00:00.000
2019-10-13 00:00:00.000
2019-10-20 00:00:00.000
2019-10-27 00:00:00.000
2019-11-03 00:00:00.000
2019-11-10 00:00:00.000
2019-11-17 00:00:00.000
2019-11-24 00:00:00.000
And I need to get like this (every other week):
2019-09-01 00:00:00.000
2019-09-15 00:00:00.000
2019-09-29 00:00:00.000
2019-10-13 00:00:00.000
2019-10-27 00:00:00.000
2019-11-10 00:00:00.000
2019-11-24 00:00:00.000
By changing your CTE to start on the correct day of the week, you can then change the recursion to add 14 days instead of 1, giving you the desired result without further manipulation:
DECLARE #startDate DATETIME = '9/1/2019'
DECLARE #endDate DATETIME = '12/31/2019'
DECLARE #dayOfWeek INT = 1;
WITH cte_Recursion AS
(SELECT DATEADD(DAY, ((#dayOfWeek - DATEPART(WEEKDAY, #startDate)) % 7 + 7) %7, #startDate) AS [Date]
UNION ALL SELECT DATEADD(DAY, 14, [Date])
FROM cte_Recursion
WHERE DATEADD(DAY, 14, [Date]) < #endDate)
SELECT [Date] FROM cte_Recursion
Output:
Date
01/09/2019 00:00:00
15/09/2019 00:00:00
29/09/2019 00:00:00
13/10/2019 00:00:00
27/10/2019 00:00:00
10/11/2019 00:00:00
24/11/2019 00:00:00
08/12/2019 00:00:00
22/12/2019 00:00:00
Demo on dbfiddle
To change the date format to dddd, dd MMMM yyyy, simply replace the final SELECT with:
SELECT FORMAT([Date], 'dddd, dd MMMM yyyy') AS [Date] FROM cte_Recursion
Output:
Date
Sunday, 01 September 2019
Sunday, 15 September 2019
Sunday, 29 September 2019
Sunday, 13 October 2019
Sunday, 27 October 2019
Sunday, 10 November 2019
Sunday, 24 November 2019
Sunday, 08 December 2019
Sunday, 22 December 2019
Demo on dbfiddle
you can use it :
DECLARE #startDate DATETIME = '9/1/2019'
DECLARE #endDate DATETIME = '12/31/2019'
DECLARE #dayOfWeek INT = 1;
WITH cte_Recursion AS
(
SELECT #startDate AS [Date]
UNION ALL SELECT DATEADD(DAY, 1, [Date])
FROM cte_Recursion WHERE [Date] < #endDate
)
SELECT [Date] FROM cte_Recursion
WHERE DATEPART(WEEKDAY, [Date]) = #dayOfWeek
and DATEPART(WEEK, [Date]) % 2 = 0
OPTION (MAXRECURSION 0)
You could use a recursive CTE as
WITH CTE AS
(
SELECT '2019-09-01 00:00:00.000' ADate
UNION SELECT '2019-09-08 00:00:00.000'
UNION SELECT '2019-09-15 00:00:00.000'
UNION SELECT '2019-09-22 00:00:00.000'
UNION SELECT '2019-09-29 00:00:00.000'
UNION SELECT '2019-10-06 00:00:00.000'
UNION SELECT '2019-10-13 00:00:00.000'
UNION SELECT '2019-10-20 00:00:00.000'
UNION SELECT '2019-10-27 00:00:00.000'
UNION SELECT '2019-11-03 00:00:00.000'
UNION SELECT '2019-11-10 00:00:00.000'
UNION SELECT '2019-11-17 00:00:00.000'
UNION SELECT '2019-11-24 00:00:00.000'
),
F AS
(
SELECT CAST('2019-09-01 00:00:00.000' AS DATETIME) ADate
UNION ALL
SELECT DATEADD(Day, 14, F.ADate)
FROM F
WHERE ADate < '2019-11-24 00:00:00.000'
)
SELECT *
FROM F;

Need to add specific time to CTE_Dates calendar

I have a Dates CTE that allows me to fill in the dates between date stamped records. (Thanks SO!) However, I need the CTE_Dates table to time stamp its "StatusDate" column with a specific time instead of '00:00:00.000' and am not quite sure how to go about ding so. Here is the CTE_Dates code:
DECLARE #StartDate date = '07/15/2017'
DECLARE #EndDate date = '07/30/2017'
;WITH cte_Dates AS
(
SELECT
CASE WHEN DATEPART(DAY, #StartDate) = 1 THEN #StartDate ELSE DATEADD(Day, DATEDIFF(Day, 1, #StartDate) + 1, 0) END AS StatusDate
UNION ALL
SELECT DATEADD(Day, 1,StatusDate)
FROM cte_Dates
WHERE DATEADD(Day, 1, StatusDate) <= #EndDate
)
--this select statement actually pulls data from 2 CTE's that are joined but represents how I am pulling the StatusDate from CTE_Dates
select
CASE WHEN CAST(statusDate as Date) IS NULL
THEN LAG(cast(StatusDate as Date)) OVER (PARTITION BY item_no ORDER BY statStart)
ELSE StatusDate END as StatusDate,
SELECT * from cte_dates
Results:
StatusDate
2017-07-15 00:00:00.000
2017-07-16 00:00:00.000
2017-07-17 00:00:00.000
2017-07-18 00:00:00.000
2017-07-19 00:00:00.000
2017-07-20 00:00:00.000
2017-07-21 00:00:00.000
2017-07-22 00:00:00.000
2017-07-23 00:00:00.000
2017-07-24 00:00:00.000
2017-07-25 00:00:00.000
2017-07-26 00:00:00.000
2017-07-27 00:00:00.000
2017-07-28 00:00:00.000
2017-07-29 00:00:00.000
2017-07-30 00:00:00.000
The CTE works great! Except I need the timestamp to be noon...
Just add time value to date like this.
DECLARE #StartDate date = '07/15/2017'
DECLARE #EndDate date = '07/30/2017'
;WITH cte_Dates AS
(
SELECT
CASE WHEN DATEPART(DAY, #StartDate) = 1 THEN #StartDate ELSE DATEADD(Day, DATEDIFF(Day, 1, #StartDate) + 1, 0) END
+ '12:00'
AS StatusDate
UNION ALL
SELECT DATEADD(Day, 1,StatusDate)
FROM cte_Dates
WHERE DATEADD(Day, 1, StatusDate) <= #EndDate
)
SELECT * FROM CTE_Dates
You could use dateadd, adding 12 hours:
SELECT DATEADD(HOUR, 12, StatusDate) AS StatusDate FROM CTE_Dates
I would just use two CTEs:
DECLARE #StartDate date = '2017-07-15';
DECLARE #EndDate date = '2017-07-30';
DECLARE #time time = '04:00:00';
WITH cte_Dates AS (
SELECT CASE WHEN DATEPART(DAY, #StartDate) = 1 THEN #StartDate ELSE DATEADD(Day, DATEDIFF(Day, 1, #StartDate) + 1, 0) END AS StatusDate
UNION ALL
SELECT DATEADD(Day, 1,StatusDate)
FROM cte_Dates
WHERE DATEADD(Day, 1, StatusDate) <= #EndDate
),
cte_DateTimes as (
select cast(statusDate as datetime) + cast(#time as datetime)
from cte_Dates
)
SELECT *
FROM CTE_DateTimes;

How can i get the First Date and Last Date between selected months?

How can i get the First Date and Last Date between selected months?
For example I Enter year 2015, and month 09 to 2016 08
The return values must be:
StartDate EndDate
20150901 20150930
20151001 20151031
20151101 20151130
20151201 20151231
20160101 20160131
20160201 20160229
20160301 20160331
20160401 20160430
20160501 20160531
20160601 20160630
20160701 20160731
20160801 20160831
I've found multiple queries that do the same but just for 1 inserted date. for example:
DECLARE #mydate DATETIME
SELECT #mydate = GETDATE()
SELECT CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(#mydate)-1),#mydate),101) AS Date_Value,
'First Day of Current Month' AS Date_Type
UNION
SELECT CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,1,#mydate))),DATEADD(mm,1,#mydate)),101) ,
'Last Day of Current Month'
But I couldn't find one that can do this for Between statement
I have two udf's which can be used independently or in conjunction. They dynamically create date ranges with variable dateparts and/or increments.
Select * from [dbo].[udf-Create-Range-Date-Span]('2015-09-01','2016-08-01','MM',1)
DateR1 DateR2
2015-09-01 00:00:00.000 2015-10-01 00:00:00.000
2015-10-01 00:00:00.000 2015-11-01 00:00:00.000
2015-11-01 00:00:00.000 2015-12-01 00:00:00.000
2015-12-01 00:00:00.000 2016-01-01 00:00:00.000
2016-01-01 00:00:00.000 2016-02-01 00:00:00.000
2016-02-01 00:00:00.000 2016-03-01 00:00:00.000
2016-03-01 00:00:00.000 2016-04-01 00:00:00.000
2016-04-01 00:00:00.000 2016-05-01 00:00:00.000
2016-05-01 00:00:00.000 2016-06-01 00:00:00.000
2016-06-01 00:00:00.000 2016-07-01 00:00:00.000
2016-07-01 00:00:00.000 2016-08-01 00:00:00.000
Now, I specifically use the cap so I can query data (including time) which are between the DateR1 and DateR2 and
However, with a little twist, you can change the output. For example:
Select DateR1=cast(DateR1 as Date),DateR2=DateAdd(DD,-1,cast(DateR2 as Date)) from [dbo].[udf-Create-Range-Date-Span]('2015-09-01','2016-08-01','MM',1)
DateR1 DateR2
2015-09-01 2015-09-30
2015-10-01 2015-10-31
2015-11-01 2015-11-30
2015-12-01 2015-12-31
2016-01-01 2016-01-31
2016-02-01 2016-02-29
2016-03-01 2016-03-31
2016-04-01 2016-04-30
2016-05-01 2016-05-31
2016-06-01 2016-06-30
2016-07-01 2016-07-31
The two function are as follows:
CREATE FUNCTION [dbo].[udf-Create-Range-Date] (#DateFrom datetime,#DateTo datetime,#DatePart varchar(10),#Incr int)
Returns
#ReturnVal Table (RetVal datetime)
As
Begin
With DateTable As (
Select DateFrom = #DateFrom
Union All
Select Case #DatePart
When 'YY' then DateAdd(YY, #Incr, df.dateFrom)
When 'QQ' then DateAdd(QQ, #Incr, df.dateFrom)
When 'MM' then DateAdd(MM, #Incr, df.dateFrom)
When 'WK' then DateAdd(WK, #Incr, df.dateFrom)
When 'DD' then DateAdd(DD, #Incr, df.dateFrom)
When 'HH' then DateAdd(HH, #Incr, df.dateFrom)
When 'MI' then DateAdd(MI, #Incr, df.dateFrom)
When 'SS' then DateAdd(SS, #Incr, df.dateFrom)
End
From DateTable DF
Where DF.DateFrom < #DateTo
)
Insert into #ReturnVal(RetVal) Select DateFrom From DateTable option (maxrecursion 32767)
Return
End
AND
CREATE FUNCTION [dbo].[udf-Create-Range-Date-Span] (#Date1 datetime,#Date2 datetime,#DatePart varchar(10),#Incr int)
-- Syntax Select * from [dbo].[udf-Create-Range-Date-Span]('2016-10-01','2020-10-01','YY',1)
-- Syntax Select * from [dbo].[udf-Create-Range-Date-Span]('2016-01-01','2016-12-31','MM',1)
-- Syntax Select * from [dbo].[udf-Create-Range-Date-Span]('2016-10-01','2016-10-31','MI',15)
-- Syntax Select * from [dbo].[udf-Create-Range-Date-Span]('2016-10-01','2016-10-02','SS',1)
Returns Table
As
Return (
Select DateR1 = RetVal
,DateR2 = LEAD(RetVal,1,#Date2) OVER (ORDER BY RetVal)
From (Select * from [dbo].[udf-Create-Range-Date](#Date1,#Date2,#DatePart,#Incr) ) A
Where RetVal<#Date2
)
You don't need UDFs for this - You can do this with a single query:
Declare #FromYear Int = 2015,
#FromMonth Int = 9,
#ToYear Int = 2016,
#ToMonth Int = 8
Declare #FromDate Date = (Select DateAdd(Year, #FromYear - 1900, DateAdd(Month, #FromMonth - 1, 0))),
#ToDate Date = (Select DateAdd(Year, #ToYear - 1900, DateAdd(Month, #ToMonth - 1, 0)))
;With Date (Date) As
(
Select #FromDate Union All
Select DateAdd(Month, 1, Date)
From Date
Where Date < #ToDate
)
Select Convert(Varchar, Year(Date)) + Right('00' + Convert(Varchar, Month(Date)), 2) + Right('00' + Convert(Varchar, Day(Date)), 2) As StartDate,
Convert(Varchar, Year(Date)) + Right('00' + Convert(Varchar, Month(Date)), 2) + Right('00' + Convert(Varchar, Day(DateAdd(Day, -1, DateAdd(Month, DateDiff(Month, 0, Date) + 1, 0)))), 2) As EndDate
From Date
Option (MaxRecursion 0)
Output
StartDate EndDate
20150901 20150930
20151001 20151031
20151101 20151130
20151201 20151231
20160101 20160131
20160201 20160229
20160301 20160331
20160401 20160430
20160501 20160531
20160601 20160630
20160701 20160731
20160801 20160831
If you're able to move to SQL Server 2012 or later, however, the query is much simpler:
Declare #FromYear Int = 2015,
#FromMonth Int = 9,
#ToYear Int = 2016,
#ToMonth Int = 8
Declare #FromDate Date = DateFromParts(#FromYear, #FromMonth, 1),
#ToDate Date = DateFromParts(#ToYear, #ToMonth, 1)
;With Date (Date) As
(
Select #FromDate Union All
Select DateAdd(Month, 1, Date)
From Date
Where Date < #ToDate
)
Select Format(Date, N'yyyyMMdd') As StartDate,
Format(EoMonth(Date), N'yyyyMMdd') As EndDate
From Date
Option (MaxRecursion 0)
Try this. Its also a very small script. I like the idea of the CTE from Siyual. But this is much shorter.
DECLARE #inputYear INT = 2015,
#inputMonth INT = 09
SELECT DATEADD(MONTH, #inputMonth-1, DATEADD(YEAR, #inputYear-1900, 0)) AS FirstDayOfTheMonth,
DATEADD(s,-1, DATEADD(MONTH, #inputMonth, DATEADD(YEAR, #inputYear-1900, 0))) AS LastDayOfTheMonth
Your task is also possible using one single ANSI sql statement.
However, you need two tables ALL_YEARS and ALL_MONTHS that contain the used set of years and month.
E.g. if you consider possible years between 1900 and 2099, the table ALL_YEARS must contain the numbers between 1900 and 2099.
The table ALL_MONTHS must contain the numbers between 1 and 12.
Using these two tables, the statement looks as follows:
select to_date('01.' || to_char(all_months.month_value) || '.' || to_char(all_years.year_value ), 'dd.mm.yyyy') first_day ,
add_months(to_date('01.' || to_char(all_months.month_value) || '.' || to_char(all_years.year_value ), 'dd.mm.yyyy'), 1) -1 last_day
from all_years,
all_months
where to_date('01.' || to_char(all_months.month_value) || '.' || to_char(all_years.year_value ), 'dd.mm.yyyy') between
to_date('01.02.2014', 'dd.mm.yyyy') and
to_date('01.07.2016', 'dd.mm.yyyy');
The output is as follows:
01.02.14 28.02.14
01.03.14 31.03.14
01.04.14 30.04.14
01.05.14 31.05.14
01.06.14 30.06.14
...
01.06.16 30.06.16
01.07.16 31.07.16

Find out the number of Days and nights using sql query

I would like to find out the number of days and nights in a given date range in sql. Can anyone help me? Thanks in advance.
Try something like this:
declare #t table(datefrom datetime, dateto datetime)
insert #t values('2012-01-01 11:30', '2012-01-01 12:30')
insert #t values('2012-01-01 11:30', '2012-01-02 00:30')
insert #t values('2012-01-01 12:30', '2012-01-02 13:00')
insert #t values('2012-01-01 12:30', '2012-01-02 00:30')
insert #t values('2012-01-01 00:00', '2012-01-03 00:00')
select datefrom, dateto,
datediff(day, datefrom - .5,dateadd(minute, -1, dateto)) nights,
datediff(day, datefrom, dateadd(minute, -1, dateto)+.5) days
from #t t
Result:
datefrom dateto nights days
2012-01-01 11:30 2012-01-01 12:30 1 1
2012-01-01 11:30 2012-01-02 00:30 2 1
2012-01-01 12:30 2012-01-02 13:00 1 2
2012-01-01 12:30 2012-01-02 00:30 1 1
2012-01-01 00:00 2012-01-03 00:00 2 2
See the AnandPhadke's comment, and here is the code :)
DECLARE #StartDate DATETIME = '2012-01-01'
DECLARE #EndDate DATETIME = '2012-02-01'
SELECT DATEDIFF(DAY, #StartDate, #EndDate) AS [Days], DATEDIFF(DAY, #StartDate, #EndDate) AS [Nights ]
Have you tried Datediff
Nights
select DATEDIFF (d, getdate()-1,getdate())
Days
select DATEDIFF (d, getdate()-1,getdate()) - 1

find records from previous x days?

How can I come up with a stored procedure that selects results for past 30 days?
where MONTH(RequestDate) > 6 and DAY(RequestDate) >= 10
and MONTH(RequestDate) < 21 and DAY(RequestDate) < 7
SELECT *
FROM Table
WHERE GETDATE() >= DATEADD(DAY, -30, GETDATE())
Substitute the first GETDATE() with the appropriate column name.
SELECT *
FROM Table
WHERE Table.ColumnName >= DATEADD(DAY, -30, GETDATE())
Are you looking for last 30 days or last month? To find start and end of each month ("generic" as your comment says), use:
select dateadd(month,datediff(month,0,getdate()),0),
dateadd(mm,datediff(mm,-1,getdate()),-1)
Something like this?
CREATE PROC GetSomeHistory
#NumDaysPrevious int
AS
BEGIN
SELECT * FROM MyTable
WHERE RequestDate BETWEEN DATEADD(dd, -1 * #NumDaysPrevious, getdate())
AND getdate();
END
......
EXEC GetSomeHistory 55;
SELECT *
FROM Table
WHERE myDate >= DATEADD(MONTH, -1, GETDATE())
doing it by month is different than doing it in 30-day blocks. Test this out as follows...
declare #mydate smalldatetime
set #mydate = '07/6/01'
select #mydate
select DATEADD(month, 2, #mydate), DATEDIFF(day, DATEADD(month, 2, #mydate), #mydate)
select DATEADD(month, 1, #mydate), DATEDIFF(day, DATEADD(month, 1, #mydate), #mydate)
select DATEADD(month, -1, #mydate), DATEDIFF(day, DATEADD(month, -1, #mydate), #mydate)
select DATEADD(month, -2, #mydate), DATEDIFF(day, DATEADD(month, -2, #mydate), #mydate)
select DATEADD(month, -3, #mydate), DATEDIFF(day, DATEADD(month, -3, #mydate), #mydate)
Here are the results:
2001-07-06 00:00:00
2001-09-06 00:00:00 | -62
2001-08-06 00:00:00 | -31
2001-06-06 00:00:00 | 30
2001-06-06 00:00:00 | 30
2001-05-06 00:00:00 | 61
2001-04-06 00:00:00 | 91