Objective-C ASCII decimal integer to NSString conversion - objective-c

How can I convert and ASCII decimal integer to an NSString in Objective-C? (Example: 36 to "$")
Thanks


Try this:
unichar asciiChar = 36;
NSString *stringWithAsciiChar = [NSString stringWithCharacters:&asciiChar length:1];


You can use the following:
NSString *s = [NSString stringWithFormat:#"%c", 36];
NSLog(#"%#", s); // $

Related

Convert text in an NSString to it's 8-byte ASCII Hex equivalent, and store back in an NSString

I want to convert the NSString #"2525" to the NSString #"0032003500320035". The 8-byte ASCII value for "2" in hex is "0032" and for "5" it's "0035". Just to get the c-string equivalent, I tried...
const char *pinUTF8 = [pin cStringUsingEncoding:NSASCIIStringEncoding];
...but as you can see I'm struggling with this and I knew it wasn't going to be that easy. Any tips?
Thanks so much in advance for your wisdom!

Try this:
NSString *str = #"2525";
const char *s = [str cStringUsingEncoding:NSASCIIStringEncoding];
size_t len = strlen(s);
NSMutableString *asciiCodes = [NSMutableString string];
for (int i = 0; i < len; i++) {
[asciiCodes appendFormat:#"%04x", (int)s[i]];
}
NSLog(#"%#", asciiCodes);

NSString to fixed length char array conversion

I am having a struct which contains a char array like this:
char name[10];
Now I need a way to convert NSString to this type of string.
I already can convert this string to a NSString:
NSString *string = [[NSString alloc] initWithBytes:name length:10
encoding:NSASCIIStringEncoding];

You can do this with getCString:maxLength:encoding: method of NSString:
char name[10];
NSString *s = #"Hello";
[s getCString:name maxLength:10 encoding:NSASCIIStringEncoding];

the full conversion process back and forth:
// from NSString through char* to NSString again
NSString *text = #"long text or short";
const char *constName = [text UTF8String];
char *name = malloc(sizeof(unichar) * text.length + 1);
memcpy(name, constName, sizeof(unichar) * text.length);
NSString *fromChar = [NSString stringWithUTF8String:name];
NSLog(#"%#", fromChar);
free(name);

Convert float value to NSString

Do you know how can i convert float value to nsstring value because with my code, there is an error.
My Code :
- (float)percent:(float)a :(float)b{
return a / b * 100;
}
- (void)objectLoader:(RKObjectLoader*)objectLoader didLoadObjects:(NSArray*)objects {
// ....
float tx_nb_demande_portabilite = [self percent: [(NSNumber*) [stat nb_demande_portabilite] floatValue] :[(NSNumber*) [stat nb_users] floatValue]];
NSString *tx_nb_demande_portabilite_st = [NSString stringWithFormat:#"%#", tx_nb_demande_portabilite];
//....
}
The error :
EXC_BAD ACCESS for NSString *tx_nb_demande_portabilite_st = [NSString stringWithFormat:#"%#", tx_nb_demande_portabilite];
Thank you for your help.

You need to use %f format specifier for float, not %#.
NSString *str = [NSString stringWithFormat:#"%f", myFloat];
To use specific number of digits after decimal use %.nf where n is number of digits after decimal point.
// 3 digits after decimal point
NSString *str = [NSString stringWithFormat:#"%.3f", myFloat];
Obj-C uses C printf style formatting. Please check printf man page for all other possible formatting.

one more option:
NSString * str = [NSNumber numberWithFloat:value].stringValue;

#"%f" sounds like more appropriate format string for float.

[NSString stringWithFormat:#"%f", tx_nb_demande_portabilite];

A modern (and less verbose) approach would be:
NSString *str = #(myFloat).description;

Convert integer to string and use each character

How is an integer converted to a string in objective c and how is each character of the string reached?
The equivalent to the java charAt() method.

NSString *myString = [NSString stringWithFormat:#"%i", 36];
[myString characterAtIndex:0]; //"3"
[myString characterAtIndex:1]; //"6"
Update: Note that characterAtIndex returns a unichar not a c char. Thanks #Chuck.

NSString get -characters

I want to get the characters of an NSString. Like this:
NSString *data;
const char * typein = [[data characters] UTF8String];
But obviously NSString won't respond to -characters. How do I get the characters of NSString?
thanks,
Elijah

You can use this function:
for(int i =0 ;i<[myString length]; i++) {
char character = [myString characterAtIndex:i];
}
or
NSString *str = #"astring";
const char *cString = [str UTF8String];

If you just want to get a cString from the NSString just call UTF8String as you are already doing and then iterate the array.