I need assistance with this. Assuming the folllowing table:
http://img820.imageshack.us/img820/6821/captureior.png
I need a SQL server query to select row 2 only (S1) and retrieve which item in the column(i.e. S1...S5) doesnt have k
That returns something like this:
S1
S2
T1
T2
T3
S3
S4
(I intend to bind the rows items to a listbox that)
Well, with plain vanilla SQL you have no built-in way to check if a given value is numeric or not. however, for your particular case you can simply check if the value is not null and doesn't contain k:
select * from YourTable where sr is not null and sr not like '%k%'
If there's other possible non numerical characters than k that can be in the table, your best bet is to make some stored procedure that checks each character of a given strig if it's numeric or not and use that
Related
Table contains data as below
Table Name is REGISTER
Column Name is EXAM_CODE
Values like ('S6TJ','S7','S26','S24')
I want answer like below
Result set - > (6,7,26,24)
Please suggest solution - since regexp_replace is not recognized built in function name in SQL.
The complexity of the answer depends on two things: the RDBMS used and whether the numbers in the EXAM_CODE are contiguous.
I have assumed that the RDBMS is SQL Server and the numbers in EXAM_CODE are always contiguous. If not, please advise and I can revise the answer.
The following SQL shows a way of accomplishing the above using PATINDEX.:
CREATE TABLE #REGISTER (EXAM_CODE VARCHAR(10));
INSERT INTO #REGISTER VALUES ('S6TJ'),('S7'),('S26'),('S24');
SELECT LEFT(EXAM_CODE, PATINDEX('%[^0-9]%', EXAM_CODE) - 1)
FROM (
SELECT RIGHT(EXAM_CODE, LEN(EXAM_CODE) - PATINDEX('%[0-9]%', EXAM_CODE) + 1) + 'A' AS EXAM_CODE
FROM #REGISTER
) a
DROP TABLE #REGISTER
This outputs:
6
7
26
24
PATINDEX matches a specified pattern against a string (or returns 0 if there is no match).
Using this, the inner query fetches all of the string AFTER the first occurence of a number. The outer query then strips any text that may appear on the end of the string.
Note: The character A is appended to the result of the inner query in order to ensure that the PATINDEX check in the outer query will make a match. Otherwise, PATINDEX would return 0 and an error would occur.
I need to create a column name based on the value of other columns. I need to return a value from a column, but the specific name depends on the value insert on other table.
From intance:
Table A
Column1 | Column2
1 2
Base on that values I need to go to the table B to the column "VE12".
I need this dynamiclly, so the execute(#query) is my last option and I would like to avoid CASE WHEN statments because I have more than 50 options.
My query will be something like:
select case when fn.tab=8 and fo.pais=3 then cp.ve83 end
FROM fn
INNER JOIN fo ON fo.stamp = fn.stamp
INNER JOIN cp
If the value in the column tab is 8 and the value in column pais is 3 I should return the value in column ve83.
Thanks for all the help!
The only sensible option is to go back to the business meaning of the data and redesign the database according to that, instead of according to "technique-oriented abstractions" such as these that SQL was never intended to support.
The main reason for this is that SQL was founded on FIRST order logic, and this precludes supporting stuff like varying domains. Which you are doing (or at least seeking to do) because ve12 could be a DATETIME and ve83 could be a VARCHAR and ve56 coulb be a BLOB etc. etc. So there is just no way for you [or anyone else] to determine the data type of the results in your query, and it is even more impossible to attach meaning to what comes out of your desired query precisely because of this varying-domain and varying-source characteristic.
I want to create a function in sql server that take as input an id range and delete all the object in that range (included the start and the end).
Let's have for example:
delete_objects_with_id(id_start,id_end)
It will delete all the objects with the id in the range id_start and id_end.
The problem is that the id are of this form: id_start=2017-0001 id_end=2017-0050 is there a sql server function that iterate on a list given a range?
first_issue content id
2011-01-01 test 2011-0001
2012-10-01 test 2012-0001
2012-11-01 test 2012-0002
2012-11-01 test 2012-0003
No, there's no builtin SQL Server function that will iterate on a list given a range.
If the id values are always nine characters, in the format four numeric digits, a dash and four more digits, then a comparison to character strings would get you the id values.
That is, you could write a query (SQL SELECT statement) to return the id values in that range,
SELECT t.id
FROM myobjects t
WHERE t.id >= '2017-0001'
AND t.id <= '2017-0050'
ORDER BY t.id
and with that query, you could define a cursor loop, and loop through (iterate) through those id values returned.
If the id values aren't in a canonical format, then the range operation isn't necessarily going to work. You'd need a mechanism to convert the id values into values that are canonical, so you can do a range.
But I'm not getting why you would need (or want) to iterate, if by "objects" you are referring to "rows" in a table. If you can write a SELECT statement that returns those rows, you could write a DELETE statement using the same predicates, and delete the rows in one fell swoop.
DELETE
FROM myobjects
WHERE id >= '2017-0001'
AND id <= '2017-0050'
It's not at all clear what you are attempting to achieve, why you would need to "iterate". But a cursor loop is one way to do that.
Again, to answer the question you asked: No. There is no "sql server function that iterate on a list given a range"
There is a simple workaround, Just remove - character and cast id as BIGINT
(This will work assuming that the first part of the id is year value and the second part is an id for each year)
DELETE FROM TABLE_1
WHERE CAST(REPLACE(id,'-','') as BIGINT) >= CAST(REPLACE(id_start,'-','') as BIGINT)
AND CAST(REPLACE(id,'-','') as BIGINT) <= CAST(REPLACE(id_end,'-','') as BIGINT)
Or use BETWEEN
DELETE FROM TABLE_1
WHERE CAST(REPLACE(id,'-','') as BIGINT) BETWEEN CAST(REPLACE(id_start,'-','') as BIGINT)
AND CAST(REPLACE(id_end,'-','') as BIGINT)
I have a table in Postgres. In that table more than 1000 names are there. Most of the names are start with SHRI or SMT. I want to delete this SHRT and SMT from the names and to save original name only. How can I do that with out any database function?
I'll step you through the logic:
Select left(name,3) from table
This select statement will bring back the first 3 chars of a column (the 'left' three). If we are looking for SMT in the first three chars, we can move it to the where statement
select * from table where left(name,3) = 'SMT'
Now from here you have a few choices that can be used. I'm going to keep to the left/right style, though replace could likely be used. We want the chars to the right of the SMT, but we don't know how long each string is to pick out those chars. So we use length() to determine that.
select right(name,length(name)-3) from table where left(name,3) = 'SMT'
I hope my syntax is right there, I'm lacking a postgres environment to test it. The logic is 'all the chars on the right of the string except the last 3 (the minus 3 excludes the 3 chars on the left. change this to 4 if you want all but the last 4 on the left)
You can then change this to an update statement (set name = right(name,length(name)-3) ) to update the table, or you can just use the select statement when you need the name without the SMT, but leave the SMT in the actual data.
I have table with 3 columns. One is Id, second column is Name and the third one Description. How can I select the value in the Description field by giving the column index, 3?
Thanks in advance
You can't, from plain SQL (other than in the ORDER BY clause, which won't give you the value but will allow you to sort the result set by it).
If you are using another programming language to construct a dynamic query, you could use that to identify the column being selected by its index number.
Alternatively, you could parameterise your query to return a specific column based on a case statement - like so:
select a, b, c, d, e, ...,
case ?
when 1 then a
when 2 then b
when 3 then c
when 4 then d
when 5 then e
...
end as parameterised_column
from ...
The problem with referring to a column by an index number is that, one day, someone may add a column and break your application as the wrong value will be returned.
This principle is enforced in SQL because you can select named columns, or all columns using the * syntax.
This principle is not enforced in programming languages, where you can usually access the column by ordinal in code, but you should consider the principle before deciding to use a statement such as (psuedo code)
value = results[0].column[2].value;
It should be possible. You'd have to query the system tables (which do vary from one version of SQL to another) to get the 3rd (or Nth) column name as a string to form a following query using that column name.
In SQL 2000 the tables you'll need to start with are syscolumns with a join to sysobjects for the table name. Then the rank() function on "Colid" will give you the Nth column and "name" (shockingly) the name of the column. Once you've got that in a variable the following command can return the value, compare to it, order by it or whatever you need.
This is how you can retrieve a Column's name by passing it's index.
Here variable AcID is used as the index of the column.
Below is the code e.g
dim gFld as string
vSqlText1 = "Select * from RecMast where ID = 1000"
vSql1 = New SqlClient.SqlCommand(vSqlText1, cnnRice)
vRs1 = vSql1.ExecuteReader
if vRs1.Read then
gFld = vRs1.GetName(AcID)
msgbox gfld
end if
declare #searchIndex int
set #searchIndex = 3
select Description from tbl_name t where t.Id = #searchIndex