I have reviewed several sites and numerous tutorials trying to determine the closest match for my situation and while I find many similar possible resolutions, no exact solution gives me what I think I need. With each attempt I either returned incorrect data, duplicate or unable to return all fields desired. Any assistance is greatly appreciated. Thanks, Newbie
I have three tables, they each share a primary_key of SUBR_ID. In lay terms, I am trying to extract BENEFIT_CARRY_OVER from TBL_SUBR_INDV_CARRY_OVER for all SUBR_ID and sub INDV_ID (one-to-many) where GRP_ID = '0G0000000', selecting first name, last name, and subscriber ID, Individual ID, and benefit carry over. Below are the referenced three tables and the statement attempts tried.
TBL_SUBR_INDV_CARRY_OVER:
SUBR_ID
INDV_ID
BENEFIT_CARRY_OVER
TBL_SUBR_GRP:
SUBR_ID
GRP_ID
TBL_SUBR_INDV:
SUBR_ID
INDV_ID
LNME
FNME
Attempt#1
select DISTINCT DCS2000.TBL_SUBR_GRP.SUBR_ID, DCS2000.TBL_SUBR_INDV.INDV_ID, LNME, FNME, GRP_ID, BENEFIT_YEAR, BENEFIT_CARRY_OVER
from DCS2000.TBL_SUBR_INDV_CARRY_OVER,
DCS2000.TBL_SUBR_GRP,
DCS2000.TBL_SUBR_INDV
where DCS2000.TBL_SUBR_INDV_CARRY_OVER.SUBR_ID = DCS2000.TBL_SUBR_INDV.SUBR_ID
and DCS2000.TBL_SUBR_INDV.SUBR_ID = DCS2000.TBL_SUBR_GRP.SUBR_ID
and DCS2000.TBL_SUBR_GRP.GRP_ID = '0G0000000'
and DCS2000.TBL_SUBR_INDV_CARRY_OVER.BENEFIT_CARRY_OVER > '0'
Attempt#2
select DCS2000.TBL_SUBR_INDV.SUBR_ID, DCS2000.TBL_SUBR_INDV.INDV_ID, DCS2000.TBL_SUBR_INDV.LNME, DCS2000.TBL_SUBR_INDV.FNME, DCS2000.TBL_SUBR_GRP.GRP_ID, DCS2000.TBL_SUBR_INDV_CARRY_OVER.BENEFIT_YEAR, DCS2000.TBL_SUBR_INDV_CARRY_OVER.BENEFIT_CARRY_OVER
from DCS2000.TBL_SUBR_INDV
join DCS2000.TBL_SUBR_GRP on (
where DCS2000.TBL_SUBR_INDV_CARRY_OVER.SUBR_ID = DCS2000.TBL_SUBR_INDV.SUBR_ID
and DCS2000.TBL_SUBR_INDV.SUBR_ID = DCS2000.TBL_SUBR_GRP.SUBR_ID
and DCS2000.TBL_SUBR_GRP.GRP_ID = '0G0000000'
and DCS2000.TBL_SUBR_INDV_CARRY_OVER.BENEFIT_CARRY_OVER > '0'
Attempt#3
SELECT LNME, FNME, SUBR_ID, INDV_ID
FROM DCS2000.TBL_SUBR_INDV
WHERE DCS2000.TBL_SUBR_INDV.SUBR_ID IN
(SELECT BENEFIT_CARRY_OVER
FROM DCS2000.TBL_SUBR_INDV_CARRY_OVER
WHERE DCS2000.TBL_SUBR_INDV_CARRY_OVER.SUBR_ID IN
(SELECT SUBR_ID
FROM DCS2000.TBL_SUBR_GRP
WHERE DCS2000.TBL_SUBR_GRP.GRP_ID = '0G0000000')
)
I assume that the duplicates occur because a single individual can have many carry-over records. Therefore, try:
select i.SUBR_ID,
i.INDV_ID,
max(i.LNME) LNME,
max(i.FNME) FNME,
max(g.GRP_ID) GRP_ID,
o.BENEFIT_YEAR,
sum(o.BENEFIT_CARRY_OVER) BENEFIT_CARRY_OVER
from DCS2000.TBL_SUBR_GRP g
join DCS2000.TBL_SUBR_INDV i
on g.SUBR_ID = i.SUBR_ID
join DCS2000.TBL_SUBR_INDV_CARRY_OVER o
on i.SUBR_ID = o.SUBR_ID and i.INDV_ID = o.INDV_ID and o.BENEFIT_CARRY_OVER > 0
where g.GRP_ID = '0G0000000'
group by i.SUBR_ID,
i.INDV_ID,
o.BENEFIT_YEAR
Note that the individual table needs to be joined to the carry-over table by both the subscriber and the individual ID; also, that numeric fields (such as BENEFIT_CARRY_OVER) should not have quotes around their values.
The problem is that due to the one to many, a simple join across all three tables will give a duplicate row for the data you are interested in. The join has to make an entire row for every row joined together. Whereas what you want is a single row.
I often find that to build a complex query is best done in parts
So, first to find all the ids with the value of interest, with a single row for each. It I'll shorten names somewhat due to the keyboard i am using.
Select distinct subr_id from subrgrp where grpid = 0000006
Then combine this with the next table up
Select distinct indvid from subrindv where subrid in (Select distinct subr_id from subrgrp where grpid = 0000006)
Then select the final rows of interest.
Select carryover from subrindv where indvid in (Select distinct indvid from subrindv where subrid in (Select distinct subr_id from subrgrp where grpid = 0000006))
The alternative is to use GROUP BY to group multiple rows into one.
Related
I have a table named Ticket Numbers, which (for this example) contain the columns:
Ticket_Number
Assigned_Group
Assigned_Group_Sequence_No
Reported_Date
Each ticket number could contain 4 rows, depending on how many times the ticket changed assigned groups. Some of these rows could contain an assigned group of "Desktop Support," but some may not. Here is an example:
Example of raw data
What I am trying to accomplish is to get the an output that contains any ticket numbers that contain 'Desktop Support', but also the assigned group of the max sequence number. Here is what I am trying to accomplish with SQL:
Queried Data
I'm trying to use SQL with the following query but have no clue what I'm doing wrong:
select ih.incident_number,ih.assigned_group, incident_history2.maxseq, incident_history2.assigned_group
from incident_history_public as ih
left join
(
select max(assigned_group_seq_no) maxseq, incident_number, assigned_group
from incident_history_public
group by incident_number, assigned_group
) incident_history2
on ih.incident_number = incident_history2.incident_number
and ih.assigned_group_seq_no = incident_history2.maxseq
where ih.ASSIGNED_GROUP LIKE '%DS%'
Does anyone know what I am doing wrong?
You might want to create a proper alias for incident_history. e.g.
from incident_history as incident_history1
and
on incident_history1.ticket_number = incident_history2.ticket_number
and incident_history1.assigned_group_seq_no = incident_history2.maxseq
In my humble opinion a first error could be that I don't see any column named "incident_history2.assigned_group".
I would try to use common table expression, to get only ticket number that contains "Desktop_support":
WITH desktop as (
SELECT distinct Ticket_Number
FROM incident_history
WHERE Assigned_Group = "Desktop Support"
),
Than an Inner Join of the result with your inner table to get ticket number and maxSeq, so in a second moment you can get also the "MAXGroup":
WITH tmp AS (
SELECT i2.Ticket_Number, i2.maxseq
FROM desktop D inner join
(SELECT Ticket_number, max(assigned_group_seq_no) as maxseq
FROM incident_history
GROUP BY ticket_number) as i2
ON D.Ticket_Number = i2.Ticket_Number
)
SELECT i.Ticket_Number, i.Assigned_Group as MAX_Group, T.maxseq, i.Reported_Date
FROM tmp T inner join incident_history i
ON T.Ticket_Number = i.Ticket_Number and i.assigned_group_seq_no = T.maxseq
I think there are several different method to resolve this question, but I really hope it's helpful for you!
For more information about Common Table Expression: https://www.essentialsql.com/introduction-common-table-expressions-ctes/
Hi I have a redshift table of articles that has a field on it that can contain many accounts. So there is a one to many relationship between articles to accounts.
However I want to create a new view where it lists the partner id's in one column and in another column a count of how many times the partner id appears in the articles table.
I've attempted to do this using regex and created a new redshift view, but am getting weird results where it doesn't always build properly. So one day it will say a partner appears 15 times, then the next 17, then the next 15, when the partner id count hasn't actually changed.
Any help would be greatly appreciated.
SELECT partner_id,
COUNT(DISTINCT id)
FROM (SELECT id,
partner_ids,
SPLIT_PART(partner_ids,',',i) partner_id
FROM positron_articles a
LEFT JOIN util.seq_0_to_500 s
ON s.i < regexp_count (partner_ids,',') + 2
OR s.i = 1
WHERE i > 0
AND regexp_count (partner_ids,',') = 0
ORDER BY id)
GROUP BY 1;
Let's start with some of the more obvious things and see if we can start to glean other information.
Next GROUP BY 1 on your outer query needs to be GROUP BY partner_id.
Next you don't need an order by in your INNER query and the database engine will probably do a better job optimizing performance without it so remove ORDER BY id.
If you want your final results to be ordered then add an ORDER BY partner_id or similar clause after your group by of your OUTER query.
It looks like there are also problems with how you are splitting a partnerid from partnerids but I am not positive about that because I need to understand your view and the data it provides to know how that affects your record count for partnerid.
Next your LEFT JOIN statement on the util.seq_0_to_500 I am pretty sure you can drop off the s.i = 1 as the first condition will satisfy that as well because 2 is greater than 1. However your left join really acts more like an inner join because you then exclude any non matches from positron_articles that don't have a s.i > 0.
Oddly then your entire join and inner query gets kind of discarded because you only want articles that have no commas in their partnerids: regexp_count (partner_ids,',') = 0
I would suggest posting the code for your util.seq_0_to_500 and if you have a partner table let use know about that as well because you can probably get your answer a lot easier with that additional table depending on how regexp_count works. I suspect regex_count(partnerids,partnerid) exampleregex_count('12345,678',1234) will return greater than 0 at which point you have no choice but to split the delimited strings into another table before counting or building a new matching function.
If regex_count only matches exact between commas and you have a partner table your query could be as easy as this:
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
positron_articles a
LEFT JOIN PARTNERTABLE p
ON regexp_count(a.partnerids,p.partnerid) > 0
GROUP BY
p.partner_id
I will actually correct myself as I just thought of a way to join a partner table without regexp_count. So if you have a partner table this might work for you. If not you will need to split strings. It basically tests to see if the partnerid is the entire partnerids, at the beginning, in the middle, or at the end of partnerids. If one of those is met then the records is returned.
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
PARTNERTABLE p
INNER JOIN positron_articles a
ON
(
CASE
WHEN a.partnerids = CAST(p.partnerid AS VARCHAR(100)) THEN 1
WHEN a.partnerids LIKE p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid THEN 1
ELSE 0
END
) = 1
GROUP BY
p.partner_id
I have one SQL statement as:
SELECT ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP
FROM
RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES,
RSKLMOBILEB2E.MEDIA_TYPE MEDIA,
RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
WHERE ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
AND ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
AND ARTICLES.ARTCL_SRC_ID = 1
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT
Now I need to combine another SQL statement into one which is:
SELECT COUNT ( * )
FROM RSKLMOBILEB2E.NEWS_LIKES LIKES, RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
WHERE LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
Basically I have one table which contains articles and I need to include the user likes which is in another table.
Use a subquery to add the likescount in your first query like this:
SELECT ARTICLES.NEWS_ARTCL_ID
,ARTICLES.NEWS_ARTCL_TTL_DES
,ARTICLES.NEWS_ARTCL_CNTNT_T
,ARTICLES.NEWS_ARTCL_PUB_DT
,ARTICLES.NEWS_ARTCL_AUTH_NM
,ARTICLES.NEWS_ARTCL_URL
,ARTICLES.MEDIA_URL
,ARTICLES.ARTCL_SRC_ID
,SOURCES.ARTCL_SRC_NM
,MEDIA.MEDIA_TYPE_DESCRIP
,(
SELECT COUNT(*)
FROM RSKLMOBILEB2E.NEWS_LIKES LIKES
WHERE LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
) AS LikesCount
FROM RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
,RSKLMOBILEB2E.MEDIA_TYPE MEDIA
,RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
WHERE ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
AND ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
AND ARTICLES.ARTCL_SRC_ID = 1
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT;
I'm not sure what you are trying to achieve but it seems you want to count all the data from 2 tables. You can edit your query to something like this.
SELECT COUNT (ARTICLES.*) FROM RSKLMOBILEB2E.NEWS_LIKES LIKES
JOIN RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
ON LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
I think that solution is in using Analytic Functions. Please have a look on https://oracle-base.com/articles/misc/analytic-functions
Please check following query (keep in mind I have no idea about your table structures). Due to left join records might be duplicated, this is why grouping is added.
SELECT ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP,
count(LIKES.ID) over ( partition by ARTICLES.NEWS_ARTCL_ID ) as num_likes
FROM RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
join RSKLMOBILEB2E.MEDIA_TYPE MEDIA
on ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
join RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
on ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
LEFT JOIN RSKLMOBILEB2E.NEWS_LIKES LIKES
ON LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
WHERE
ARTICLES.ARTCL_SRC_ID = 1
group by ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT
I also changed coma-separated list of tables from where condition to joins. I think this is more readable since table join conditions are separated from result filtering in where clause.
I am putting together a nice little database for adding values to options, all these are setup through a map (Has and Belongs to Many) table, because many options are pointing to a single value.
So I am trying to specify 3 option.ids and a single id in a value table - four integers to point to a single value. Three tables. And I am running into a problem with the WHERE part of the statement, because if multiple values share an option there are many results. And I need just a single result.
SELECT value.id, value.name FROM value
LEFT JOIN (option_map_value, option_table)
ON (value.id = option_map_value.value_id AND option_map_value.option_table_id = option_table.id)
WHERE option_table.id IN (5, 2, 3) AND value.y_axis_id = 16;
The problem with the statement seems to be the IN on the WHERE clause. If one of the numbers are different in the IN() part, then there are multiple results - which is not good.
I have tried DISTINCT, which again works if there is one result, but returns many if there is many. The closest we have gotten to is adding a count - to return to value with the most options at the top.
So is there a way to do the WHERE to be more specific. I cannot break it out into option_table.id = 5 AND option_table.id = 2 - because that one fails. But can the WHERE clause be more specifc?
Maybe it is me being pedantic, but I would like to be able to return just the single result, instead of a count of results... Any ideas?
The problem with the statement seems to be the IN on the WHERE clause. If one of the numbers are different in the IN() part, then there are multiple results - which is not good. I have tried DISTINCT, which again works if there is one result, but returns many if there is many. The closest we have gotten to is adding a count - to return to value with the most options at the top.
You were very close, considering the DISTINCT:
SELECT v.id,
v.name
FROM VALUE v
LEFT JOIN OPTION_MAP_VALUE omv ON omv.value_id = v.id
LEFT JOIN OPTION_TABLE ot ON ot.id = omv.option_table_id
WHERE ot.id IN (5, 2, 3)
AND v.y_axis_id = 16
GROUP BY v.id, v.name
HAVING COUNT(*) = 3
You were on the right track, but needed to use GROUP BY instead in order to be able to use the HAVING clause to count the DISTINCT list of values.
Caveat emptor:
The GROUP BY/HAVING COUNT version of the query is dependent on your data model having a composite key, unique or primary, defined for the two columns involved (value_id and option_table_id). If this is not in place, the database will not stop duplicates being added. If duplicate rows are possible in the data, this version can return false positives because a value_id could have 3 associations to the option_table_id 5 - which would satisfy the HAVING COUNT(*) = 3.
Using JOINs:
A safer, though more involved, approach is to join onto the table that can have multiple options, as often as you have criteria:
SELECT v.id,
v.name
FROM VALUE v
JOIN OPTION_MAP_VALUE omv ON omv.value_id = v.id
JOIN OPTION_TABLE ot5 ON ot5.id = omv.option_table_id
AND ot5.id = 5
JOIN OPTION_TABLE ot2 ON ot2.id = omv.option_table_id
AND ot2.id = 2
JOIN OPTION_TABLE ot3 ON ot3.id = omv.option_table_id
AND ot3.id = 3
WHERE v.y_axis_id = 16
GROUP BY v.id, v.name
Need help on a query using sql server 2005
I am having two tables
code
chargecode
chargeid
orgid
entry
chargeid
itemNo
rate
I need to list all the chargeids in entry table if it contains multiple entries having different chargeids
which got listed in code table having the same charge code.
data :
code
100,1,100
100,2,100
100,3,100
101,11,100
101,12,100
entry
1,x1,1
1,x2,2
2,x3,2
11,x4,1
11,x5,1
using the above data , it query should list chargeids 1 and 2 and not 11.
I got the way to know how many rows in entry satisfies the criteria, but m failing to get the chargeids
select count (distinct chargeId)
from entry where chargeid in (select chargeid from code where chargecode = (SELECT A.chargecode
from code as A join code as B
ON A.chargecode = B.chargeCode and A.chargetype = B.chargetype and A.orgId = B.orgId AND A.CHARGEID = b.CHARGEid
group by A.chargecode,A.orgid
having count(A.chargecode) > 1)
)
First off: I apologise for my completely inaccurate original answer.
The solution to your problem is a self-join. Self-joins are used when you want to select more than one row from the same table. In our case we want to select two charge IDs that have the same charge code:
SELECT DISTINCT c1.chargeid, c2.chargeid FROM code c1
JOIN code c2 ON c1.chargeid != c2.chargeid AND c1.chargecode = c2.chargecode
JOIN entry e1 ON e1.chargeid = c1.chargeid
JOIN entry e2 ON e2.chargeid = c2.chargeid
WHERE c1.chargeid < c2.chargeid
Explanation of this:
First we pick any two charge IDs from 'code'. The DISTINCT avoids duplicates. We make sure they're two different IDs and that they map to the same chargecode.
Then we join on 'entry' (twice) to make sure they both appear in the entry table.
This approach gives (for your example) the pairs (1,2) and (2,1). So we also insist on an ordering; this cuts to result set down to just (1,2), as you described.