I have a textfile of rows of values, each field delimited by a single space. The end of each row is signalled by the Windows-style {carriage return, newline}.
I would like to replace each spaces with a comma using Notepad++ but I am unfamiliar with whitespace regex on Notepad++.
Any help would be appreciated.
\s works for me at least as a whitespace token, just as it does in normal regular expressions. A single regular space character in the replace dialog works just as well.
Related
I'm trying to replace newline etc kind of values using regexp_replace. But when I open the result in query result window, I can still see the new lines in the text. Even when I copy the result, I can see new line characters. See output for example, I just copied from the result.
Below is my query
select regexp_replace('abc123
/n
CHAR(10)
头疼,'||CHR(10)||'allo','[^[:alpha:][:digit:][ \t]]','') from dual;
/ I just kept for testing characters.
Output:
abc123
/n
CHAR(10)
头疼,
allo
How to remove the new lines from the text?
Expected output:
abc123 /nCHAR(10)头疼,allo
There are two mistakes in your code. One of them causes the issue you noticed.
First, in a bracket expression, in Oracle regular expressions (which follow the POSIX standard), there are no escape sequences. You probably meant \t as escape sequence for tab - within the bracket expression. (Note also that in Oracle regular expressions, there are no escape sequences like \t and \n anyway. If you must preserve tabs, it can be done, but not like that.)
Second, regardless of this, you include two character classes, [:alpha:] and [:digit:], and also [ \t] in the (negated) bracket expression. The last one is not a character class, so the [ as well as the space, the backslash and the letter t are interpreted as literal characters - they stand in for themselves. The closing bracket, on the other hand, has special meaning. The first of your two closing brackets is interpreted as the end of the bracket expression; and the second closing bracket is interpreted as being an additional, literal character that must be matched! Since there is no such literal closing bracket anywhere in the string, nothing is replaced.
To fix both mistakes, replace [ \t] with the [:blank:] character class, which consists exactly of space and tab. (And, note that [:alpha:][:digit:] can be written more compactly as [:alnum:].)
I would like to replace all pipes and line breaks with space in a free text field in my data base.
My current approach looks like the following:
SELECT
ID,
REGEXP_REPLACE(REGEXP_REPLACE(FREETEXT,'|',‘ ‘),‘\n',' ')
FROM TABLE
My idea is to replace the pipes | with a space and then the results get checked again and all linebreaks are replaced. Problem now is that there are still pipes in there which messes up the CSV since my delimter for that is |.
Hope anyone can help me out here.
PS: I am not able to change the delimter to something else.
The pipe symbol is a special character in a Regular Expression, splitting it into multiple alternatives, thus you must escape it.
If you want to replace all pipe and line break characters you don't have to nest:
RegExp_Replace(FREETEXT,'[\|\n\r]',' ')
\| pipe 0x7C
\n line feed 0x0A
\r carriage return 0x0D
But as those are single characters you can simply use
OTranslate(FREETEXT, '7C0A0D'xc,' ')
Only if you want to replace consecutive occurences of those characters with a single space you need a RegEx:
RegExp_Replace(FREETEXT,'[\|\n\r]+',' ')
I am trying to write a query which will tell me if certain record is having only the special characters. e.g- "%^&%&^%&" will error however "%HH678*(*))" is fine (as it's having alphanumeric values as well. I have written following query however, it's working fine only for English alphabets and numbers, if column is having some other characters like mandarin then also it's not giving expected value.Any help is highly appreciated.
SELECT * FROM test WHERE REGEXP_LIKE(sampletext, '[^]^A-Z^a-z^0-9^[^.^{^}^ ]' );
You may try this,
regexp_like(text, '^[^A-Za-z0-9]+$')
This would match the text only if the input text contains special chars ie, only chars which are not of letters or digits.
To detect strings containing only characters other than unaccented alphabetic, numeric, or white space characters try this:
regexp_like(text,'^[^a-zA-Z0-9[:space:]]+$')
If you don't think punctuation characters are special than add [:punct:] to the class of characters to ignore.
If you are looking for a specific set of characters you can use a character class of just those characters of interest, for example some common accented characters (note the lack of a leading ^ in the character class []:
regexp_like(text,'^[àèìòùÀÈÌÒÙáéíóúýÁÉÍÓÚÝâêîôûÂÊÎÔÛãñõÃÑÕäëïöüÿÄËÏÖÜŸçÇßØøÅåÆæœ]+$')
I have a text box in a project where user can write database queries, but I nedd to prevent statements like DELETE, DROP or use of comments (/* */, --) or semicolon ;.
I'm using the folowing RegExp to check the query. It must math only valid statments.
/^(?!.*\-\-)(?!.*\/\*)(?!.*\*\/)(?!.*;)(?!.*CREATE)(?!.*DROP)(?!.*ALTER)(?!.*UPDATE)(?!.*DELETE).*$/
The RegExp is working fine, but it's not matching also line breaks and carriage returns (\n, \r), which should be permited.
How can I update the RegExp to allow \n and \r?
#FabSa gave me the answer.
The trick is just set the PCRE_DOTALL flag, as I'm using PHP _preg_match(). This does make a dot (.) metacharacter matches all characters, incluind newline (\n).
So, the final regex is as folows:
/^(?!.*\-\-)(?!.*\/\*)(?!.*\*\/)(?!.*;)(?!.*CREATE)(?!.*DROP)(?!.*ALTER)(?!.*UPDATE)(?!.*DELETE).*$/s
I need a complete list of characters that should be escaped in sql string parameters to prevent exceptions. I assume that I need to replace all the offending characters with the escaped version before I pass it to my ObjectDataSource filter parameter.
No, the ObjectDataSource will handle all the escaping for you. Any parametrized query will also require no escaping.
As others have pointed out, in 99% of the cases where someone thinks they need to ask this question, they are doing it wrong. Parameterization is the way to go. If you really need to escape yourself, try to find out if your DB access library offers a function for this (for example, MySQL has mysql_real_escape_string).
SQL Books online:
Search for String Literals:
String Literals
A string literal consists of zero or more characters surrounded by quotation marks. If a string contains quotation marks, these must be escaped in order for the expression to parse. Any two-byte character except \x0000 is permitted in a string, because the \x0000 character is the null terminator of a string.
Strings can include other characters that require an escape sequence. The following table lists escape sequences for string literals.
\a
Alert
\b
Backspace
\f
Form feed
\n
New line
\r
Carriage return
\t
Horizontal tab
\v
Vertical tab
\"
Quotation mark
\
Backslash
\xhhhh
Unicode character in hexadecimal notation
Here's a way I used to get rid of apostrophes. You could do the same thing with other offending characters that you run into. (example in VB.Net)
Dim companyFilter = Trim(Me.ddCompany.SelectedValue)
If (Me.ddCompany.SelectedIndex > 0) Then
filterString += String.Format("LegalName like '{0}'", companyFilter.Replace("'", "''"))
End If
Me.objectDataSource.FilterExpression = filterString
Me.displayGrid.DataBind()