My table structure is this
id last_mod_dt nr is_u is_rog is_ror is_unv
1 x uuid1 1 1 1 0
2 y uuid1 1 0 1 1
3 z uuid2 1 1 1 1
I want the count of rows with:
is_ror=1 or is_rog =1
is_u=1
is_unv=1
All in a single query. Is it possible?
The problem I am facing is that there can be same values for nr as is the case in the table above.
Case statments provide mondo flexibility...
SELECT
sum(case
when is_ror = 1 or is_rog = 1 then 1
else 0
end) FirstCount
,sum(case
when is_u = 1 then 1
else 0
end) SecondCount
,sum(case
when is_unv = 1 then 1
else 0
end) ThirdCount
from MyTable
you can use union to get multiple results e.g.
select count(*) from table with is_ror=1 or is_rog =1
union
select count(*) from table with is_u=1
union
select count(*) from table with is_unv=1
Then the result set will contain three rows each with one of the counts.
Sounds pretty simple if "all in a single query" does not disqualify subselects;
SELECT
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_ror=1 OR is_rog=1) cnt_ror_reg,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_u=1) cnt_u,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_unv=1) cnt_unv;
how about something like
SELECT
SUM(IF(is_u > 0 AND is_rog > 0, 1, 0)) AS count_something,
...
from table
group by nr
I think it will do the trick
I am of course not sure what you want exactly, but I believe you can use the logic to produce your desired result.
Related
I have re-written this query about 20 times today and I keep getting close but no dice... I'm sure this is easy-peasy for y'all, but my SQL (Oracle) is pretty rusty.
Here's what I need:
PersonID Count1 Count2 Count3 Count4
1 0 0 2 1
2 1 1 1 0
3 1 1 1 2
Data is coming from several sources. I have a table People, and a table Values. People can have any number of values in that table.
PersonID Item Value
1 Check1 3
1 Check2 3
1 Check3 4
2 Check4 2
2 Check5 3
2 Check6 1
.. etc
So the query would, for each PersonID, count how many times the particular Value appears. The values are always 1, 2, 3, or 4. I tried to do 4 subqueries, but it wouldn't read the PersonID from the main query and just returned the count of all instances of value=1.
I was then thinking do a Group_By ... I don't know. Any help is appreciated!
ETA: I've deleted & re-written the query many times in many ways and unfortunately did not save any intermediate attempts. I didn't include it originally because I was in the middle of rearranging it again, and it's not runnable as-is. But here it is as it stands now:
/*sources are the tested requirements
values are the scores people received on the tested sources
people are those who were tested on the requirements */
WITH sub_query4 (
SELECT values.personid,
count (values.ID) as count4 --how many 4s
FROM values
INNER JOIN sources ON values.valueid = sources.sourceid
INNER JOIN people ON people.personid = values.personid
WHERE values.yearid = 2017
AND values.quarter = 'Q1'
AND instr (sources.identifier, 'TESTBANK.01', 1 ,1) > 0
AND values.value = '4'
GROUP_BY people.personid
)
SELECT p.first_name,
p.last_name,
p.position,
p.email,
p.locationid,
sub_query4.count4 as count4 --eventually this would repeat for 1, 2, & 3
FROM people p
WHERE p.locationid=406
AND p.position in (9,10);
values is a bad name for a table because it is a SQL keyword.
In any case, conditional aggregation should work:
select personid,
sum(case when value = 1 then 1 else 0 end) as cnt_1,
sum(case when value = 2 then 1 else 0 end) as cnt_2,
sum(case when value = 3 then 1 else 0 end) as cnt_3,
sum(case when value = 4 then 1 else 0 end) as cnt_4
from values
group by personid;
I prefer to use PIVOT for this. Here is Example SQL Fiddle
SELECT "PersonID", val1,val2,val3,val4 FROM
(
SELECT "PersonID", "Value" from VALS
)
PIVOT
(
count("Value")
FOR "Value" IN (1 as val1, 2 as val2, 3 as val3, 4 as val4)
);
I have a historization table called CUR_VALID. This table looks something like this:
ID CUR_VALID
1 N
1 N
1 Y
2 N
2 Y
3 Y
For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong. The statment for checking if there are multiple Y I already got. Now I only need to check for every ID if there is one Y existing. Im just not sure how to do that. This is what I have so far. So how do I check if the Value 'Y' exists?
SELECT Count(1) [Number of N]
,MAX(CUR_VALID = 'N')
,[BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
FROM db.dbo.table
GROUP BY [BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
Having MAX(CUR_VALID = 'N') > 1
Why are you fiddling with 'N' when you are interested in 'Y'?
Use conditional aggregation to get the count of the value your are interested in.
SELECT
COUNT(*) AS number_of_all,
COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) AS number_of_y,
COUNT(CASE WHEN cur_valid = 'N' THEN 1 END) AS number_of_n,
bill_id,
bill_month,
bill_src_id,
FROM db.dbo.table
GROUP BY bill_id, bill_month, bill_src_id;
Add a HAVING clause in order to get only valid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) = 1
or invalid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) <> 1
bills.
The following query will give you the list of id for which your integrity condition is not met: For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong.
select T1.id from table T1 where (select count(*) from table T2 where T2.id=T1.id and T2.CUR_VALID='Y')!=1
This query returns both not having at least one 'Y' value and more than one 'Y' value ID's.
First, sum up the Y values and relate to each id, then select not 1 ones from that table.
select * from (
select ID, SUM(case when CUR_VALID = 'Y' then 1 else 0 end) as CNT
from table
group by ID
) b where b.CNT <> 1
DBFiddle
As I understand, you want to get all the id for which your integrity check passes. And integrity check for you means, there is only one row with CUR_VALID value equal to Y in the CUR_VALID table.
This can be achieved by a group by clause:
select id from CUR_VALID
where CUR_VALID.CUR_VALID = 'Y'
group by id
having count(CUR_VALID.CUR_VALID) = 1;
I have two queries and I want to get the maximum value of the two of them.
MAX((SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=0),
(SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=1))
You can calculate both result in a single query and then apply TOP:
select top 1
HasHuman,
COUNT(p.[ItemID]) as cnt
from [dbo].[Table]
group by HasHuman
order by cnt desc
You could even do this in a single query:
SELECT
CASE WHEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END) >
SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END)
THEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END)
ELSE SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END) END
FROM [dbo].[Table]
WHERE ItemID IS NOT NULL -- you were not counting NULLs
SELECT MAX(RC)
FROM (SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=0
UNION
SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=1
) A
How does one turn these multiple rows into one row? N and Y are bool values.
Id IsPnt IsPms, IsPdt
1 N Y N
1 N Y N
1 Y N N
into this
Id IsPnt IsPms, IsPdt
1 Y Y N
Edit:
The query that produces the resultset looks like this
select b.id,
CASE mpft.PlanIndCd WHEN 'PBMN' THEN 1 ELSE 0 END AS IsPnt,
CASE mpft.PlanIndCd WHEN 'PBMT' THEN 1 ELSE 0 END AS IsPbt,
CASE mpft.PlanIndCd WHEN 'PBMS' THEN 1 ELSE 0 END AS IsPms
from vw_D_SomveViewName pb
-- bunch of joins
where mpft.PlanIndCd in ('HANR', 'PBMN','PBMT','PBMS','HAWR')
You can simply use MAX() on this if the values are really Y and N only.
SELECT ID, MAX(IsPnt) IsPnt, MAX(IsPms) IsPms, MAX(IsPdt) IsPdt
FROM tableName
GROUP BY ID
UPDATE 1
SELECT b.id,
MAX(CASE mpft.PlanIndCd WHEN 'PBMN' THEN 1 ELSE 0 END) AS IsPnt,
MAX(CASE mpft.PlanIndCd WHEN 'PBMT' THEN 1 ELSE 0 END) AS IsPbt,
MAX(CASE mpft.PlanIndCd WHEN 'PBMS' THEN 1 ELSE 0 END) AS IsPms
FROM vw_D_SomveViewName pb
-- bunch of joins
WHERE mpft.PlanIndCd in ('HANR', 'PBMN','PBMT','PBMS','HAWR')
GROUP BY b.ID
Will this work?
select
id,
max(IsPnt),
max(IsPms),
max(IsPdt)
from
table
GROUP BY
id
After the edit of your question, you can simply use the PIVOT table operator directly instead of using the MAX expression, something like:
SELECT
Id,
PBMN AS IsPnt,
PBMT AS IsPbt,
PBMS AS IsPms
FROM
(
SELECT
id,
mpft.PlanIndCd,
ROW_NUMBER() OVER(PARTITION BY id
ORDER BY ( SELECT 1)) AS RN
from vw_D_SomveViewName pb
-- bunch of joins
where mpft.PlanIndCd in ('HANR', 'PBMN','PBMT','PBMS','HAWR')
) AS t
PIVOt
(
MAX(RN)
FOR PlanIndCd IN ([PBMN], [PBMT], [PBMS])
) AS p;
You can see it in action in the following demo example:
Demo on SQL Fiddle
select Id, MAX(IPnt), MAX(IsPms), MAX(IsPdt)
from table etc
Quick one,
I have a table, with the following structure
id lid taken
1 1 0
1 1 0
1 1 1
1 1 1
1 2 1
Pretty simply so far right?
I need to query the taken/available from the lid of 1, which should return
taken available
2 2
I know I can simply do two counts and join them, but is there a more proficient way of doing this rather than two separate queries?
I was looking at the following type of format, but I can not for the life of me get it executed in SQL...
SELECT
COUNT(case taken=1) AS taken,
COUNT(case taken=0) AS available FROM table
WHERE
lid=1
Thank you SO much.
You can do this:
SELECT taken, COUNT(*) AS count
FROM table
WHERE lid = 1
GROUP BY taken
This will return two rows:
taken count
0 2
1 2
Each count corresponds to how many times that particular taken value was seen.
Your query is correct just needs juggling a bit:
SELECT
SUM(case taken WHEN 1 THEN 1 ELSE 0 END) AS taken,
SUM(case taken WHEN 1 THEN 0 ELSE 1 END) AS available FROM table
WHERE
lid=1
Alternatively you could do:
SELECT
SUM(taken) AS taken,
COUNT(id) - SUM(taken) AS available
FROM table
WHERE
lid=1
SELECT
SUM(case WHEN taken=1 THEN 1 ELSE 0 END) AS taken,
SUM(case WHEN taken=0 THEN 1 ELSE 0 END) AS available
FROM table
WHERE lid=1
Weird application of CTE's:
WITH lid AS (
SELECT DISTINCT lid FROM taken
)
, tak AS (
SELECT lid,taken , COUNT(*) AS cnt
FROM taken t0
GROUP BY lid,taken
)
SELECT l.lid
, COALESCE(a0.cnt, 0) AS available
, COALESCE(a1.cnt, 0) AS taken
FROM lid l
LEFT JOIN tak a0 ON a0.lid=l.lid AND a0.taken = 0
LEFT JOIN tak a1 ON a1.lid=l.lid AND a1.taken = 1
WHERE l.lid=1
;