What i want to do is convert this query , i want to use pagination but when i use query like this pagination not working
DB::select('SELECT *, ( ( weight * 400 ) + Making_charge) AS Sum FROM products WHERE '.$cat.' ='. $id.' ORDER BY sum ASC');
when i try to use pagination i get this error
Call to a member function links() on array (View:
i tried type casting but that did not work either
can anyone provide me valid reason or solution without disliking it
thank you
The reason why you are getting Call to a member function links() on array is because the QueryBuilder returns an array. Not a collection as Eloquent.
I changed your SQL query to use double quotes in order to use string interpolation, and the work sum to product_sum, since sum is a reserved word by mysql.
"SELECT *, (( weight * 400 ) + making_charge) as product_sum FROM products WHERE {$cat} = {$id} ORDER BY product_sum ASC";
Your query, using eloquent, will look as somethin like this:
Product::query()
->where($cat, $id)
->select(['*', DB::raw('(weight * 400 + making_charge) as product_sum')])
->orderBy('product_sum')
->get();
This query returns a collection. You can also paginate using laravel pagination:
$items_per_page = 10;
Product::query()
->where($cat, $id)
->select(['*', DB::raw('(weight * 400 + making_charge) as product_sum')])
->orderBy('product_sum') // The default direction is ASC
->paginate($items_per_page);
I tried to retrieve a value from the calculation of several columns,
in this case try to apply the formula "(a + (a / 25 * b)) - c" to be processed using sql language which I will use in codeigniter.
I also tried using "derived table" like SELECT .... FROM (SELECT... FROM...) AS dt
but I had difficulty when applying it to my case in codeigniter
private function _get_datatables_query(){
$intvl = '2';
$tgl_stok = '2019-09-30';
$this->db->SELECT('p.hso, p.no_part, p.nama_part, jml, sp.oh, sum(p.qty)+(sum(p.qty)/25*$intvl)-sp.oh as suggest');
$this->db->FROM('penjualan p');
$this->db->JOIN('stok_part sp', 'sp.no_part = p.no_part', 'left');
$this->db->WHERE("sp.tgl = '$tgl_stok' AND p.tgl BETWEEN DATE_SUB('$tgl_stok', INTERVAL $intvl DAY) AND '$tgl_stok'");
$this->db->GROUP_BY('p.no_part');
//...other code...
}
I want a column with the alias suggest in the code to produce a calculated value of several other columns
I know writing code that I created is not in accordance with the rules of writing SQL, I tried a number of ways but it did not work. I am very grateful for your help
Instead of var you should use parameter in this way you can easly pass the value you need and avoid sqlinjection eg:
$sql = "SELECT p.hso, p.no_part, p.nama_part, jml, sp.oh, sum(p.qty)+(sum(p.qty)/25*?)-sp.oh as suggest
FROM enjualan p
LEFT JOIN stok_part sp ON sp.no_part = p.no_part
WHERE sp.tgl = ? AND p.tgl BETWEEN DATE_SUB(?, INTERVAL ? DAY) AND ?
GROUP BY p.no_part";
$this->db->query($sql, array($intval,$tgl_stok, $tgl_stok, $intvl, tgl_stok ));
}
I was solved this case.
the problem is in my query:
$this->db->SELECT('p.hso, p.no_part, p.nama_part, jml, sp.oh, sum(p.qty)+(sum(p.qty)/25*$intvl)-sp.oh as suggest');
and replace it with
$this->db->SELECT("p.hso, p.no_part, p.nama_part, sum(p.qty) as jml, sp.oh, sum(p.qty)+(sum(p.qty)/25*'$intvl')-sp.oh as s_po");
my mistake was writing quotation marks in the query
I'm generating SQL programmatically so that, based on certain parameters, the query that needs to be executed could be different (i.e., tables used, unions, etc). How can I insert a string like this: "select * from table", into a %%sql block? I know that using :variable inserts variable into the %%sql block, but it does so as a string, rather than sql code.
The answer was staring me in the face:
query="""
select
*
from
sometable
"""
%sql $query
If you want to templatize your queries, you can use string.Template:
from string import Template
template = Template("""
SELECT *
FROM my_data
LIMIT $limit
""")
limit_one = template.substitute(limit=1)
limit_two = template.substitute(limit=2)
%sql $limit_one
Source: JupySQL documentation.
Important: If you use this approach, ensure you trust/sanitize the input!
I'd like to get value by the following SQL using Eloquent ORM.
- SQL
SELECT COUNT(*) FROM
(SELECT * FROM abc GROUP BY col1) AS a;
Then I considered the following.
- Code
$sql = Abc::from('abc AS a')->groupBy('col1')->toSql();
$num = Abc::from(\DB::raw($sql))->count();
print $num;
I'm looking for a better solution.
Please tell me simplest solution.
In addition to #delmadord's answer and your comments:
Currently there is no method to create subquery in FROM clause, so you need to manually use raw statement, then, if necessary, you will merge all the bindings:
$sub = Abc::where(..)->groupBy(..); // Eloquent Builder instance
$count = DB::table( DB::raw("({$sub->toSql()}) as sub") )
->mergeBindings($sub->getQuery()) // you need to get underlying Query Builder
->count();
Mind that you need to merge bindings in correct order. If you have other bound clauses, you must put them after mergeBindings:
$count = DB::table( DB::raw("({$sub->toSql()}) as sub") )
// ->where(..) wrong
->mergeBindings($sub->getQuery()) // you need to get underlying Query Builder
// ->where(..) correct
->count();
Laravel v5.6.12 (2018-03-14) added fromSub() and fromRaw() methods to query builder (#23476).
The accepted answer is correct but can be simplified into:
DB::query()->fromSub(function ($query) {
$query->from('abc')->groupBy('col1');
}, 'a')->count();
The above snippet produces the following SQL:
select count(*) as aggregate from (select * from `abc` group by `col1`) as `a`
The solution of #JarekTkaczyk it is exactly what I was looking for. The only thing I miss is how to do it when you are using
DB::table() queries. In this case, this is how I do it:
$other = DB::table( DB::raw("({$sub->toSql()}) as sub") )->select(
'something',
DB::raw('sum( qty ) as qty'),
'foo',
'bar'
);
$other->mergeBindings( $sub );
$other->groupBy('something');
$other->groupBy('foo');
$other->groupBy('bar');
print $other->toSql();
$other->get();
Special atention how to make the mergeBindings without using the getQuery() method
From laravel 5.5 there is a dedicated method for subqueries and you can use it like this:
Abc::selectSub(function($q) {
$q->select('*')->groupBy('col1');
}, 'a')->count('a.*');
or
Abc::selectSub(Abc::select('*')->groupBy('col1'), 'a')->count('a.*');
There are many readable ways to do these kinds of queries at the moment (Laravel 8).
// option 1: DB::table(Closure, alias) for subquery
$count = DB::table(function ($sub) {
$sub->from('abc')
->groupBy('col1');
}, 'a')
->count();
// option 2: DB::table(Builder, alias) for subquery
$sub = DB::table('abc')->groupBy('col1');
$count = DB::table($sub, 'a')->count();
// option 3: DB::query()->from(Closure, alias)
$count = DB::query()
->from(function ($sub) {
$sub->from('abc')
->groupBy('col1')
}, 'a')
->count();
// option 4: DB::query()->from(Builder, alias)
$sub = DB::table('abc')->groupBy('col1');
$count = DB::query()->from($sub, 'a')->count();
For such small subqueries, you could even try fitting them in a single line with PHP 7.4's short closures but this approach can be harder to mantain.
$count = DB::table(fn($sub) => $sub->from('abc')->groupBy('col1'), 'a')->count();
Note that I'm using count() instead of explicitly writing the count(*) statement and using get() or first() for the results (which you can easily do by replacing count() with selectRaw(count(*))->first()).
The reason for this is simple: It returns the number instead of an object with an awkwardly named property (count(*) unless you used an alias in the query)
Which looks better?
// using count() in the builder
echo $count;
// using selectRaw('count(*)')->first() in the builder
echo $count->{'count(*)'};
Correct way described in this answer: https://stackoverflow.com/a/52772444/2519714
Most popular answer at current moment is not totally correct.
This way https://stackoverflow.com/a/24838367/2519714 is not correct in some cases like: sub select has where bindings, then joining table to sub select, then other wheres added to all query. For example query:
select * from (select * from t1 where col1 = ?) join t2 on col1 = col2 and col3 = ? where t2.col4 = ?
To make this query you will write code like:
$subQuery = DB::query()->from('t1')->where('t1.col1', 'val1');
$query = DB::query()->from(DB::raw('('. $subQuery->toSql() . ') AS subquery'))
->mergeBindings($subQuery->getBindings());
$query->join('t2', function(JoinClause $join) {
$join->on('subquery.col1', 't2.col2');
$join->where('t2.col3', 'val3');
})->where('t2.col4', 'val4');
During executing this query, his method $query->getBindings() will return bindings in incorrect order like ['val3', 'val1', 'val4'] in this case instead correct ['val1', 'val3', 'val4'] for raw sql described above.
One more time correct way to do this:
$subQuery = DB::query()->from('t1')->where('t1.col1', 'val1');
$query = DB::query()->fromSub($subQuery, 'subquery');
$query->join('t2', function(JoinClause $join) {
$join->on('subquery.col1', 't2.col2');
$join->where('t2.col3', 'val3');
})->where('t2.col4', 'val4');
Also bindings will be automatically and correctly merged to new query.
I like doing something like this:
Message::select('*')
->from(DB::raw("( SELECT * FROM `messages`
WHERE `to_id` = ".Auth::id()." AND `isseen` = 0
GROUP BY `from_id` asc) as `sub`"))
->count();
It's not very elegant, but it's simple.
This works fine
$q1 = DB::table('tableA')->groupBy('col');
$data = DB::table(DB::raw("({$q1->toSql()}) as sub"))->mergeBindings($q1)->get();
I could not made your code to do the desired query, the AS is an alias only for the table abc, not for the derived table.
Laravel Query Builder does not implicitly support derived table aliases, DB::raw is most likely needed for this.
The most straight solution I could came up with is almost identical to yours, however produces the query as you asked for:
$sql = Abc::groupBy('col1')->toSql();
$count = DB::table(DB::raw("($sql) AS a"))->count();
The produced query is
select count(*) as aggregate from (select * from `abc` group by `col1`) AS a;
->selectRaw('your subquery as somefield')
Deriving off mpskovvang's answer, here is what it would look like using eloquent model. (I tried updating mpskovvang answer to include this, but there's too many edit requests for it.)
$qry = Abc::where('col2', 'value')->groupBy('col1')->selectRaw('1');
$num = Abc::from($qry, 'q1')->count();
print $num;
Produces...
SELECT COUNT(*) as aggregate FROM (SELECT 1 FROM Abc WHERE col2='value' GROUP BY col1) as q1
how to do a select * from table in jython and get the result for each row into a list or string.
i know how to do for select counmn_name1 ,column_name2 from table1 but not able to figure out for select *
Please suggest .thanks
If you use JDBC then you can use JDBC ResultSetMetaData interface:
rs = c.executeQuery("SELECT * FROM a_tmp_table")
while (rs.next()):
rsmd = rs.getMetaData()
print('columnCnt: %d' % (rsmd.getColumnCount()))
for i in range(rsmd.getColumnCount()):
print(rs.getString(i + 1))
If you use zxJDBC (comes with Jython) then you can follow the cross-implementation DB-API protocol to execute queries and retrieve results.