I have 3 tables A, B, and C. I want to get the subId and text for each id. I also want to know IF the id has some eId linked to it.
I've used INNER JOIN on A and B and then LEFT JOIN'd that result with tabel C. My SQL string so far is:
SELECT DISTINCT A.id,A.subId, B.text, C.eId
FROM A
INNER JOIN B ON A.id=B.id
LEFT JOIN C ON A.id=C.id
WHERE B.text='something'
The problem is that C.eId has multiple entries for each id. So I'm getting output like this:
=================================
id | subId | text | eId
1 e12 etc
2 e12 etc
2 t23 etc p1111
3 e12 etc
4 e12 etc p1234
4 e12 etc p4325
I want to remove the lines like the last one ("4 e12 etc p4325") because I already know that 4, e12 has some other eId linked to it. I need id and subId to be PrimaryKeys.
How do I do this? DISTINCT worked until I added multiple id's to an eId.
Edit: I use MSSQL if that makes a difference.
I don't recall if it works this way, try it and tell me:
SELECT DISTINCT A.id,A.subId, B.text,
(select top 1 C.eId from C where C.id = A.id) AS eId
FROM A
INNER JOIN B ON A.id=B.id
WHERE B.text='etc'
Related
I need to right join 2 tables with 3 conditions but the resulting table is bigger than left or right table.
left_table a is like the following:
capacity value group_id level_id tags
100 3 a ab
120 5 a afb lala
122 4 b afg hhh
122 6 c adfg
right table b is like the following: bigger than left table
user group_id level_id tags
adsf a ab
af a abf df
sf a afb lala
dsf b afg hhh
sdf c adfg
I want to append the value and capacity value to the right table b. I have used the following query but the resulting table is larger than the right table. I noticed that it is due to the NULL in tags in both the right and left tables, but i am wondering how to resolve this issue.
select a.capacity, a.value, b.*
from a
right join b
on a.group_id = b._group_id
and a.level_id = b.level_id
and a.tags = b.tags
I noticed that it is due to the NULL in tags in both the right and left tables
No, this is not the cause of duplicates. In fact NULL values fail the comparison, so you will not get a match at all if either value is NULL. That is, the row in b will be returned with NULL values for the columns from a.
If you want NULL values to match as being equal, then you need a NULL-safe comparison -- and Presto supports the SQL Standard is not distinct from. I also strongly prefer left join over right join:
select a.capacity, a.value, b.*
from b left join
a
on a.group_id = b._group_id and
a.level_id = b.level_id and
a.tags is not distinct from b.tags;
If you are getting duplicates, it is because you have duplicates in a. You can check for this using:
select group_id, level_id, tags, count(*)
from a
group by group_id, level_id, tags
having count(*) >= 2;
Hi i have a lot of inner in a query but i can't print column in different table, for example:
where
Table A
id f
-----------
xxx gggg
bbb kkkk
Table B
name code
-----------
ccc dddd
bbb oooo
My code:
select A.id,A.F from (query1)as stima
join
(select B.name,B.code from B as aaaa query)as noome
on noome.code=stima.F;
But if i want put name columns of B table in 'select A.id,A.F' how can i do?
My output is id and colum F but i want output: id,F and name columns.
Any time you have a column in an inner query that you want to use in an outer query, you have to make sure the inner query selects it. It will then become part of the query block with the new alias you give it:
SELECT
a.Name,
a.SomethingElse,
b.ColumnX,
b.ColumnYYY
FROM
(
SELECT c.Name, d.SomethingElse FROM c JOIN d ON ..
) a
JOIN
(
SELECT e.ColumnX, f.ColY as ColumnYYY FROM e JOIN f ON ..
) b
When they're in the inner queries the columns are like d.SomethingElse and f.ColY but when they pass outside of those brackets, they get a new alias, because they are part of the data block that is aliased by a or b, so you no longer refer to them as their inner names.. Particularly in the case of f.ColY it was renamed to ColumnYYY and also given a new "table" alias of b..
You can use any columns from the tables of the from clause.
I think you need this:
select A.id,A.F, noome.name -- this
from (query1)as stima
join
(select B.name,B.code from B as aaaa query)as noome
on noome.code=stima.F;
I have sql query where I have to join three tables. One of this is a table with data of invoice, it looks like this:
INVOICE
ID CUSTOMER_NAME TAXID NUMBER LABEL GUID
1 CUSTOMER1 8739281100 FV001/2019 1 04EABFB3-0B9D-4749-B99D-A4EBEE079633
POSITION OF INVOICE
ID ID_INV POSITION_NAME COUNT
1 1 NAME1 3
2 1 NAME2 2,5
TABLE WITH LABEL
ID NAME VALUE GUID_INV
1 LABEL1 true 04EABFB3-0B9D-4749-B99D-A4EBEE079633
When I want to run this query I have statement like this multiple rows in singleton select.
This is for Firebird 2.5.
SELECT
a.ID,
a.GUID,
a.NUMBER,
a.CUSTOMER_NAME,
b.COUNT,
(select usrd.LABEL from USER_FIELD_DEFS usrd
where usrd.GUID_INV=a.GUID and (usrd.ID=1 and usrb.VALUE='true')) as LABEL_NAME
FROM INVOICE a
join POSITION_INVOICE b ON a.ID=b.ID_INV
I want to get result like this
1 04EABFB3-0B9D-4749-B99D-A4EBEE079633 FV001/2019 CUSTOMER1 3 LABEL1
1 04EABFB3-0B9D-4749-B99D-A4EBEE079633 FV001/2019 CUSTOMER1 2,5 LABEL1
Please help with this. I know that solution maybe is very simple but I have some eclipse of the mind:)
This should give you the rows you want based on the 3 tables you provided. If there is a chance that an invoice has no position then simply replace the inner join with left join
SELECT
I.[Id]
,I.[GUID]
,I.[NUMBER]
,I.[CUSTOMER_NAME]
,IP.[POSITION_NAME]
,L.[NAME]
FROM [INVOICE] I
INNER JOIN [IN_P] IP ON IP.ID_INV = I.Id
LEFT JOIN [LABEL] L ON L.[GUID_INV] = I.[GUID]
You are just missing one more join here. Assuming USER_FIELD_DEFS is the same as TABLE WITH LABEL that you have mentioned here
SELECT
a.ID,
a.GUID,
a.NUMBER,
a.CUSTOMER_NAME,
b.COUNT,
c.NAME
FROM INVOICE a
JOIN POSITION_INVOICE b ON a.ID=b.ID_INV
JOIN USER_FIELD_DEFS c ON c.GUID_INV = a.GUID AND c.ID=1 and c.VALUE='true'
Here is the case:
There is a user table
id email orders_counter
=================================
1 a#a.com 5
2 b#b.com 3
3 c#c.com 0
And a user data table for user's other data
id user_id title value
=======================================
1 1 Name Peter Johnson
2 1 Tel 31546988
3 2 Name Alan Johnson
4 2 Tel 56984887
If I want to fetch all user that
1, orders_counter greater then 3
2, Name contain 'Johnson'
3, Tel contain '88'
AT THE SAME TIME
What is my sql, and if I want to do it rubyonrails way
what is the ActiveRecord code
I know I can it one by one and then join all of them together, but it waste too much resource while conditions build up
Select * From `user` u
inner join `userdata` d on d.user_id=u.id and d.title='Name' and d.value like '%Johnson%'
inner join `userdata` c on c.user_id=u.id and c.title='Tel' and c.value like '%88%'
where orders_counter > 3
the way that you've got your user data table structured, you'll almost always have to join on that table several times in order to "pivot" those values into columns. I'd recommend just creating a table that has name and tel as columns. then the query becomes a lot more simple
select * from `user` u
inner join `user_data` d on d.Tel like '%88%' and d.Name like '%johnson%'
where u.orders_counter > 3
try this one up,
SELECT a.*, b.*
FROM user a
INNER JOIN data b
ON a.id = b.user_ID
WHERE a.orders_counter > 3 AND
(b.title = 'NAME' AND b.value like '%johnson%') AND
(b.title = 'TEL' AND b.tel like '%88%')
try this:
select *
from user U join user_data D
on U.id=D.user_id
where U.orders_counter>3
and D.title='Name' and value like '%Johnson%'
and D.title='Tel' and value like '%88%'
Hi Guys I have a table relation which works like this (legacy)
A has many B and B has many C;
A has many C as well
Now I am having trouble coming up with a SQL which will help me to get all B (Id of B to make it simple) mapped to certain A(by Id) AND any B which has a collection of C that's a subset of Cs of that A.
I have failed to come up with a decent sql specially for the second part and was wondering if I can get any tips / suggestions re how I can do that.
Thanks
EDIT:
Table A
Id |..
------------
1 |..
Table B
Id |..
--------------
2 |..
Table A_B_rel
A_id | B_id
-----------------
1 | 2
C is a strange table. The data of C (single column) is actually just duped in 2 rel table for A and B. so its like this
Table B_C_Table
B_Id| C_Value
-----------------
2 | 'Somevalue'
Table A_C_Table
A_Id| C_Value
-------------
1 | 'SomeValue'
So I am looking for Bs the C_Values of which are subset of certain A_C_Values.
Yes, the second part of your problem is a bit tricky. We've got B_C_Table on the one hand, and a subset of A_C_Table where A_ID is a specific ID, on the other.
Now, if we use an outer join, we'll be able to see which rows in B_C_Table have no match in A_C_Table:
SELECT *
FROM B_C_Table bc
LEFT JOIN A_C_Table ac ON bc.C_Value = ac.C_Value AND ac.A_ID = #A_ID
Note that it is important to put the ac.A_ID = #A_ID into the ON clause rather than into WHERE, because in the latter case we would be filtering out non-matching rows of #A_ID, which is not what we want.
The next step (to achieving the final query) would be to group rows by B and count rows. Now, we will calculate both the total number of rows and the number of matching rows.
SELECT
bc.B_ID,
COUNT(*) AS TotalCount,
COUNT(ac.A_ID) AS MatchCount
FROM B_C_Table bc
LEFT JOIN A_C_Table ac ON bc.C_Value = ac.C_Value AND ac.A_ID = #A_ID
GROUP BY bc.B_ID
As you can see, to count matches, we simply count ac.A_ID values: in case of no match the corresponding column will be NULL and thus not counted. And if indeed some rows in B_C_Table do not match any rows in the subset of A_C_Table, we will see different values of TotalCount and MatchCount.
And that logically leads us towards the final step: comparing those counts. (For, obviously, if we can obtain values, we can also compare them.) But not in the WHERE clause, of course, because aggregate functions aren't allowed in WHERE. It's the HAVING clause that is used to compare values of grouped rows, including aggregated values too. So...
SELECT
bc.B_ID,
COUNT(*) AS TotalCount,
COUNT(ac.A_ID) AS MatchCount
FROM B_C_Table bc
LEFT JOIN A_C_Table ac ON bc.C_Value = ac.C_Value AND ac.A_ID = #A_ID
GROUP BY bc.B_ID
HAVING COUNT(*) = COUNT(ac.A_ID)
The count values aren't really needed, of course, and when you drop them you will be able to UNION the above query with the one selecting B_ID from A_B_rel:
SELECT B_ID
FROM A_B_rel
WHERE A_ID = #A_ID
UNION
SELECT bc.B_ID
FROM B_C_Table bc
LEFT JOIN A_C_Table ac ON bc.C_Value = ac.C_Value AND ac.A_ID = #A_ID
GROUP BY bc.B_ID
HAVING COUNT(*) = COUNT(ac.A_ID)
Sounds like you need to think in terms of double negation, i.e. there should not exist any B_C that does not have a matching A_C (and I'm guessing there should be at least one B_C).
So, try something like
select B.B_id
from Table_B B
where exists (select 1 from B_C_Table BC
where BC.B_id = B.B_id)
and not exists (select 1 from B_C_Table BC
where BC.B_id = B.B_id
and not exists(select 1 from B_C_Table AC
join A_B_Rel ABR on AC.A_id = ABR.A_id
where ABR.B_id = B.B_id
and BC.C_Value = AC.C_Value))
Perhaps this is what you're looking for:
SELECT B_id
FROM A_B_rel
WHERE A_id = <A ID>
UNION
SELECT a.B_Id
FROM B_C_Table a
LEFT JOIN A_C_Table b ON a.C_Value = b.C_Value AND b.A_Id = <A ID>
GROUP BY a.B_Id
HAVING COUNT(CASE WHEN b.A_Id IS NULL THEN 1 END) = 0
The first SELECT gets all B's which are mapped to a particular A (<A ID> being the input parameter for the A ID), then we tack onto that result set any additional B's whose entire set of C_Value's are within the subset of the C_Value's of the particular A (again, <A ID> being the input parameter).