I need an elegant way using VB.Net to iterate through a range of IP addresses when the input will come to my app as a string in this format:
192.168.100.8-10
This range would include 3 addresses:
192.168.100.8, 192.168.100.9, 192.168.100.10.
I found a solution in C# that uses the IP Address class that I could probably convert to VB but it seemed to be way too much code for what I need to do. I could definitely use a bunch of string parsing functions but I was hoping someone already had a simple way of doing this.
Here is a solution. It would be even easier using generic lists...
Dim arrFinalIpList() As String
Dim strIP As String = "192.168.100.8-10"
Dim arrIP() As String = strIP.Split(".")
Dim strPrefix As String = arrIP(0) & "." & arrIP(1) & "." & arrIP(2) & "."
Dim arrMinAndMax() As String = arrIP(3).Split("-")
Dim intCursor As Integer = 0
For intCursor = CInt(arrMinAndMax(0)) To CInt(arrMinAndMax(1))
If arrFinalIpList Is Nothing Then
ReDim arrFinalIpList(0)
arrFinalIpList(0) = strPrefix & intCursor.ToString()
Else
ReDim Preserve arrFinalIpList(arrFinalIpList.Count)
arrFinalIpList(arrFinalIpList.Count - 1) = strPrefix & intCursor.ToString()
End If
Next
Related
I have this String:
"[" & vbCrLf & " ""APPLE""" & vbCrLf & "]"
The only thing I need is APPLE.
I tried a few options with Split, Trim, Left and more, but they didn't work very well.
Thank you very much!
As the comments above have said, there's not enough information to give an answer without making assumptions, which could be wrong. I've assumed you want to extract the value between two quotation marks, regardless of what else is before or after.
If that's what you want, try this:
Dim Result As String = Nothing
Dim source As String = $"[{vbCrLf}""Apple""{vbCrLf}]"
Dim FirstQuote As Integer = source.IndexOf("""")
If FirstQuote > -1 And source.Length > FirstQuote Then
Dim SecondQuote As Integer = source.IndexOf("""", FirstQuote + 1)
If SecondQuote > FirstQuote Then
Result = source.Substring(FirstQuote + 1, SecondQuote - FirstQuote - 1)
End If
End If
If Result Is Nothing Then
'Handle Invalid Format
Else
'Process Result
End If
You would need to modify that so that you passed your source string, rather than defining it in the code. If you wanted to extract multiple words from a single string in the same format, just set FirstQuote = SecondQuote + 1, check that doesn't exceed the length of the source string and loop through again.
I am going to assume that you probably just need to get the first occurance of a string (in this case "apple") within square-brackets using split and so:
Dim AppleString As String = "This is an [Apple] or etc [...]"
console.WriteLine(AppleString.split("[")(1).split("]")(0).trim())
⚠️ This is not a solution for all purposes !!!
I am writing VBA code for an Excel workbook. I would like to be able to open a connection with an Access database, and then import a txt file (pipe delimited) and create a new table in the database from this txt file. I have searched everywhere but to no avail. I have only been able to find VBA code that will accomplish this from within Access itself, rather than from Excel. Please help! Thank you
Google "Open access database from excel VBA" and you'll find lots of resources. Here's the general idea though:
Dim db As Access.Application
Public Sub OpenDB()
Set db = New Access.Application
db.OpenCurrentDatabase "C:\My Documents\db2.mdb"
db.Application.Visible = True
End Sub
You can also use a data access technology like ODBC or ADODB. I'd look into those if you're planning more extensive functionality. Good luck!
I had to do this exact same problem. You have a large problem presented in a small question here, but here is my solution to the hardest hurdle. You first parse each line of the text file into an array:
Function ParseLineEntry(LineEntry As String) As Variant
'Take a text file string and parse it into individual elements in an array.
Dim NumFields As Integer, LastFieldStart As Integer
Dim LineFieldArray() As Variant
Dim i As Long, j As Long
'Determine how many delimitations there are. My data always had the format
'data1|data2|data3|...|dataN|, so there was always at least one field.
NumFields = 0
For I = 1 To Len(LineEntry)
If Mid(LineEntry, i, 1) = "|" Then NumFields = NumFields + 1
Next i
ReDim LineFieldArray(1 To NumFields)
'Parse out each element from the string and assign it into the appropriate array value
LastFieldStart = 1
For i = 1 to NumFields
For j = LastFieldStart To Len(LineEntry)
If Mid(LineEntry, j , 1) = "|" Then
LineFieldArray(i) = Mid(LineEntry, LastFieldStart, j - LastFieldStart)
LastFieldStart = j + 1
Exit For
End If
Next j
Next i
ParseLineEntry = LineFieldArray
End Function
You then use another routine to add the connection in (I am using ADODB). My format for entries was TableName|Field1Value|Field2Value|...|FieldNValue|:
Dim InsertDataCommand as String
'LineArray = array populated by ParseLineEntry
InsertDataCommand = "INSERT INTO " & LineArray(1) & " VALUES ("
For i = 2 To UBound(LineArray)
If i = UBound(LineArray) Then
InsertDataCommand = InsertDataCommand & "'" & LineArray(i) & "'" & ")"
Else
InsertDataCommand = InsertDataCommand & LineArray(i) & ", "
End If
Next i
Just keep in mind that you will have to build some case handling into this. For example, if you have an empty value (e.g. Val1|Val2||Val4) and it is a string, you can enter "" which will already be in the ParseLineEntry array. However, if you are entering this into a number column it will fail on you, you have to insert "Null" instead inside the string. Also, if you are adding any strings with an apostrophe, you will have to change it to a ''. In sum, I had to go through my lines character by character to find these issues, but the concept is demonstrated.
I built the table programmatically too using the same parsing function, but of this .csv format: TableName|Field1Name|Field1Type|Field1Size|...|.
Again, this is a big problem you are tackling, but I hope this answer helps you with the less straight forward parts.
I'm learning for loop and I cannot get this problem fixed.
The problems are in the following codes.
dim rt as integer = 2
dim i As Integer = 0
dim currentpg as string = "http://homepg.com/"
For i = 0 To rt
currentpg = currentpg & "?pg=" & i
messagebox.show(currentpg)
next
'I hoped to get the following results
http://homepg.com/?pg=0
http://homepg.com/?pg=1
http://homepg.com/?pg=2
'but instead I'm getting this
http://homepg.com/?pg=0
http://homepg.com/?pg=0?pg=0
http://homepg.com/?pg=0?pg=0?pg=0
Please help me
Thank you.
You probably need something like this:
Dim basepg as string = "http://homepg.com/"
For i = 0 To rt
Dim currentpg As String = basepg & "?pg=" & i
messagebox.show(currentpg)
Next
Although a proper approach would be to accumulate results into a List(Of String), and then display in a messagebox once (or a textbox/file, if too many results). You don't want to bug user for every URL (what if there are 100 of them?). They would get tired of clicking OK.
First of all, you went wrong while copying the output of the buggy code. Here is the real one.
http://homepg.com/?pg=0
http://homepg.com/?pg=0?pg=1
http://homepg.com/?pg=0?pg=1?pg=2
It does not work because currentpg should be a constant but it is changed on each iteration.
Do not set, just get.
MessageBox.Show(currentpg & "?pg=" & i)
Or you can use another variable to make it more readable.
Dim newpg As String = currentpg & "?pg=" & i
MessageBox.Show(newpg)
Also, your code is inefficient. I suggest you to change it like this.
Dim iterations As Integer = 2
Dim prefix As String = "http://homepg.com/?pg="
For index As Integer = 0 To iterations
MessageBox.Show(prefix & index)
Next
'How to reverse "This is Friday" to "Friday is this" in vb.net in Easiest Way
Dim str As String = txtremarks.Text
Dim arr As New List(Of Char)
arr.AddRange(str.ToCharArray)
arr.Reverse()
Dim a As String = ""
For Each l As Char In arr
a &= l
Next
' I saw on a few forums that to use SPLIT function. Please help
Yes you can use split. You can also use join and the reverse method:
Dim test = "This is Friday"
Dim reversetest = String.Join(" ", test.Split().Reverse)
First you'll want to split your sentence into individual words. This is where you'd use the String.Split method.
Once you have an array containing your individual words, you can reverse that array. Perhaps using Linq's Enumerable.Reverse extension method.
Finally, you can put the words back together into a string. The String.Join method allows you to join the elements of a string array back into a single string.
I'm not a VB programmer, but something like this should work:
Dim str As String = "this is friday"
Dim split As String() = str.Split(" ")
Dim result as String = String.Join(" ", split.Reverse())
Here's a way to do it in 1 line:
Dim reverse As String = "This is friday".Split().Reverse().Aggregate(Function(left, right) String.Join(" ", left, right))
Do note that this has a horrible performance overhead.
Yes, you can Split your String via " " (space) and insert results into array.
Next, read array from the end to start.
Good luck!
Try this...
Dim txt As String = "This is friday"
Dim txtarray() As String = Split(txt.Trim(), " ")
Dim result As String = ""
For x = txtarray.GetUpperBound(0) To 0 Step -1
result += txtarray(x) & " "
Next x
MsgBox(result.Trim())
I am getting a type mismatch error in VBA and I am not sure why.
The purpose of this macro is to go through a column in an Excel spreadsheet and add all the emails to an array. After each email is added to the first array, it's also supposed to added to a second array but split into two pieces at the # symbol in order to separate name from domain. Like so: person#gmail.com to person and gmail.com.
The problem that I'm getting is that when it gets to the point where it's supposed to split the email, it throws a Type Mismatch error.
Specifically this part:
strDomain = Split(strText, "#")
Here is the complete code:
Sub addContactListEmails()
Dim strEmailList() As String 'Array of emails
Dim blDimensioned As Boolean 'Is the array dimensioned?
Dim strText As String 'To temporarily hold names
Dim lngPosition As Long 'Counting
Dim strDomainList() As String
Dim strDomain As String
Dim dlDimensioned As Boolean
Dim strEmailDomain As String
Dim i As Integer
Dim countRows As Long
'countRows = Columns("E:E").SpecialCells(xlVisible).Rows.Count
countRows = Range("E:E").CurrentRegion.Rows.Count
MsgBox "The number of rows is " & countRows
'The array has not yet been dimensioned:
blDimensioned = False
Dim counter As Long
Do While counter < countRows
counter = counter + 1
' Set the string to the content of the cell
strText = Cells(counter, 5).Value
If strText <> "" Then
'Has the array been dimensioned?
If blDimensioned = True Then
'Yes, so extend the array one element large than its current upper bound.
'Without the "Preserve" keyword below, the previous elements in our array would be erased with the resizing
ReDim Preserve strEmailList(0 To UBound(strEmailList) + 1) As String
Else
'No, so dimension it and flag it as dimensioned.
ReDim strEmailList(0 To 0) As String
blDimensioned = True
End If
'Add the email to the last element in the array.
strEmailList(UBound(strEmailList)) = strText
'Also add the email to the separation array
strDomain = Split(strText, "#")
If strDomain <> "" Then
If dlDimensioned = True Then
ReDim Preserve strDomainList(0 To UBound(strDomainList) + 1) As String
Else
ReDim strDomainList(0 To 0) As String
dlDimensioned = True
End If
strDomainList(UBound(strDomainList)) = strDomain
End If
End If
Loop
'Display email addresses, TESTING ONLY!
For lngPosition = LBound(strEmailList) To UBound(strEmailList)
MsgBox strEmailList(lngPosition)
Next lngPosition
For i = LBound(strDomainList) To UBound(strDomainList)
MsgBox strDomainList(strDomain)
Next
'Erase array
'Erase strEmailList
End Sub
ReDiming arrays is a big hassle. Welcome to the world of collections and Dictionarys. Collection objects are always accessible. Dictionaries require a reference to Microsoft Scripting Runtime (Tools>References>scroll down to find that text and check the box> OK). They dynamically change size for you, you can add, remove items very easily compared to arrays, and Dictionaries especially allow you to organize your data in more logical ways.
In the below code I used a dictionary there the key is the domain (obtained with the split function). Each value for a key is a collection of email addresses with that domain.
Put a break point on End Sub and look at the contents of each of these objects in your locals window. I think you'll see they make more sense and are easier in general.
Option Explicit
Function AllEmails() As Dictionary
Dim emailListCollection As Collection
Set emailListCollection = New Collection 'you're going to like collections way better than arrays
Dim DomainEmailDictionary As Dictionary
Set DomainEmailDictionary = New Dictionary 'key value pairing. key is the domain. value is a collection of emails in that domain
Dim emailParts() As String
Dim countRows As Long
Dim EmailAddress As String
Dim strDomain As String
'countRows = Columns("E:E").SpecialCells(xlVisible).Rows.Count
Dim sht As Worksheet 'always declare your sheets!
Set sht = Sheets("Sheet1")
countRows = sht.Range("E2").End(xlDown).Row
Dim counter As Long
Do While counter < countRows
counter = counter + 1
EmailAddress = Trim(sht.Cells(counter, 5))
If EmailAddress <> "" Then
emailParts = Split(EmailAddress, "#")
If UBound(emailParts) > 0 Then
strDomain = emailParts(1)
End If
If Not DomainEmailDictionary.Exists(strDomain) Then
'if you have not already encountered this domain
DomainEmailDictionary.Add strDomain, New Collection
End If
'Add the email to the dictionary of emails organized by domain
DomainEmailDictionary(strDomain).Add EmailAddress
'Add the email to the collection of only addresses
emailListCollection.Add EmailAddress
End If
Loop
Set AllEmails = DomainEmailDictionary
End Function
and use it with
Sub RemoveUnwantedEmails()
Dim allemailsDic As Dictionary, doNotCallSheet As Worksheet, emailsSheet As Worksheet
Set doNotCallSheet = Sheets("DoNotCallList")
Set emailsSheet = Sheets("Sheet1")
Set allemailsDic = AllEmails
Dim domain As Variant, EmailAddress As Variant
Dim foundDoNotCallDomains As Range, emailAddressesToRemove As Range
For Each domain In allemailsDic.Keys
Set foundDoNotCallDomains = doNotCallSheet.Range("A:A").Find(domain)
If Not foundDoNotCallDomains Is Nothing Then
Debug.Print "domain found"
'do your removal
For Each EmailAddress In allemailsDic(domain)
Set emailAddressesToRemove = emailsSheet.Range("E:E").Find(EmailAddress)
If Not emailAddressesToRemove Is Nothing Then
emailAddressesToRemove = ""
End If
Next EmailAddress
End If
Next domain
End Sub
strDomain must store array of the split text, therefore,
Dim strDomain As Variant
Afterwards, strDomain should be referenced by index, if operations with certain fragments will be made:
If strDomain(i) <> "" Then
The split function returns an array of strings based on the provided separator.
In your if you are sure that the original string is an email, with just one "#" in it then you can safely use the below code:
strDomain = Split(strText, "#")(1)
This will get you the part after "#" which is what you are looking for.
Split returns an array:
Dim mailComp() As String
[...]
mailComp = Split(strText, "#")
strDomain = mailComp(1)
Try strDomain = Split(strText,"#")(1) to get the right hand side of the split where (0) would be the left. And of course works with more than 2 splits as well. You could dim you string variable as an array strDomain() and then Split(strText,"#") will place all the seperated text into the array.