I have a table like this
C1 C2
1 0
1 1
i want the count of rows where c1=1 and the count of rows where c2=0 in one single query instead of separate queries.
select
sum(case c1 when 1 then 1 else 0 end) Count_c1,
sum(case c2 when 0 then 1 else 0 end) Count_c2
from YourTable
You can use the UNION keyword:
SELECT "ones", COUNT(*) WHERE c1=1
UNOIN
SELECT "zeroes", COUNT(*) WHERE c2=0
Related
I would like to get list of unique id that have 'condition=1' before 'condition=2'.
id
date
condition1
condition2
1
2022/02
1
0
1
2022/04
0
1
1
2022/05
0
0
2
2021/09
0
1
2
2022/01
1
0
3
2022/02
1
0
3
2022/05
0
1
In this case it would be 1 and 3.
SELECT id, MIN(date) FROM TABLE GROUP BY id
I know that i can do something like this to get first dates for id but i just cant figure out what to do for my problem
We can GROUP BY id and build two conditional MIN dates using CASE WHEN.
In the HAVING clause we say that the minimum date with condition 1 must appear before the minimum date with condition 2.
SELECT id
FROM yourtable
GROUP BY id
HAVING MIN(CASE WHEN condition1 = 1 THEN date END) <
MIN(CASE WHEN condition2 = 1 THEN date END)
ORDER BY id;
Try out here: db<>fiddle
Something like:
SELECT DISTINCT Id
FROM
(SELECT id, MIN(date)
FROM TheTable
WHERE Condition1 = 1
GROUP BY Id) c1
INNER JOIN
(SELECT Id, MIN(date)
FROM TheTable
WHERE Condition2 = 1
GROUP BY Id) c2
ON c1.Id=C2.Id AND c1.Date < c2.Date
I tried set the count of rows which have a specific value for multiple columns in the same query
this is what I have tried...
SELECT
COUNT(*) AS house_with_12_rooms,
COUNT(*) AS house_with_4_rooms
FROM housetable
WHERE num_of_rooms = "twelve"
OR num_of_rooms = "four"
since there are 157 rows with houses with 12 rooms and 1 row with houses with 4 rooms the result adds up the counts in the result table RATHER THAN placing 157 and 1 respectively.
Row house_with_12_rooms house_with_4_rooms
1 158 158
Could someone give me a clue on how to set up the query properly?
Use conditional aggregation:
SELECT SUM(CASE WHEN num_of_rooms = 'twelve' THEN 1 ELSE 0 END) AS house_with_12_rooms,
SUM(CASE WHEN num_of_rooms = 'four' THEN 1 ELSE 0 END) AS house_with_4_rooms
FROM housetable
WHERE num_of_rooms IN ('twelve', 'four')
I'm looking to run a count SQL query on multiple columns at once. 83 of them. For each, I'd simply like to figure out how many instances there are in which the value = 1.
ex.
select count(*) from [filename.filename]
where [Column001] = 1
select count(*) from [filename.filename]
where [Column002] = 1
All data in each column is marked with wither a 0 or a 1.
Instead of writing 83 small queries, is there a way for me to write it all in one query and have them all display as a table with the results?
This seems to be what you want:
SELECT SUM(CASE WHEN Column_1 = 1 THEN 1 ELSE 0 END) N_1,
SUM(CASE WHEN Column_2 = 1 THEN 1 ELSE 0 END) N_2,
SUM(CASE WHEN Column_3 = 1 THEN 1 ELSE 0 END) N_3,
.....
SUM(CASE WHEN Column_83 = 1 THEN 1 ELSE 0 END) N_83
FROM YourTable;
I'm trying to figure out how to return a select query showing a count of all values in a column that are greater than 0. Then in the next column show a count of all values that = 0.
Example:
ID ColumnA
1 1
2 2
3 1
4 2
5 0
6 0
7 1
Would return a result for the select query of:
NumberOfGreaterThan0 NumberThatEqual0
5 2
You can use conditional aggregates for this via CASE expression:
SELECT COUNT(CASE WHEN ColumnA > 0 THEN 1 END) AS NumberOfGreaterThan0
,COUNT(CASE WHEN ColumnA = 0 THEN 1 END) AS NumberThatEqual0
FROM YourTable
This works because aggregate functions ignore NULL values.
You can use a couple of count functions over case expressions:
SELECT COUNT(CASE WHEN columa > 0 THEN 1 ELSE NULL END) AS NumberOfGreaterThan0,
COUNT(CASE columa WHEN 0 THEN 1 ELSE NULL END) AS NumberThatEqual0
FROM my_table
I have 2 tables, one (Jobs) contains the list of the jobs and second contains the details of the records in each job.
Jobs
JobID Count
A 2
B 3
Records
JobID RecordID ToBeProcessed IsProcessed
A A1 1 1
A A2 1 1
B B1 1 1
B B2 1 0
B B3 1 0
How would I be able to create a query that would list all the jobs that have the count of ToBeProcessed which has a value of 1 is equal to the count of isProcessed that has a value of 1? Thanks in advance. Any help is greatly appreciated.
Start with the calculation of the number of items with ToBeProcessed set to 1 or IsProcessed set to one:
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
This gives you all counts, not only ones where ToBeProcessedIsOne is equal to IsProcessedIsOne. To make sure that you get only the records where the two are the same, use either a HAVING clause, or a nested subquery:
-- HAVING clause
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
HAVING SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END)=SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END)
-- Nested subquery with a condition
SELECT * FROM (
SELECT
JobID
, SUM(CASE WHEN ToBeProcessed=1 THEN 1 ELSE 0 END) ToBeProcessedIsOne
, SUM(CASE WHEN IsProcessed=1 THEN 1 ELSE 0 END) IsProcessedIsOne
FROM Records
GROUP BY JobID
) WHERE ToBeProcessedIsOne = IsProcessedIsOne
Note: if ToBeProcessed and IsProcessed are of type that does not allow values other than zero or one, you can replace the CASE statement with the name of the column, for example:
SELECT
JobID
, SUM(ToBeProcessed) ToBeProcessedIsOne
, SUM(IsProcessed) IsProcessedIsOne
FROM Records
GROUP BY JobID
HAVING SUM(ToBeProcessed)=SUM(IsProcessedD)
if im not misunderstanding your question it looks like you just need a WHERE clause in your statement to see when they are both equal to 1.
SELECT
r.JobID AS j_id,
r.RecordID as r_id,
r.ToBeProcessed AS tbp,
r.IsProcessed AS ip
FROM Records AS r
WHERE r.ToBeProcessed = 1 AND r.IsProcessed = 1
GROUP BY j_id;
let me know if this is not what you are asking for.
if its a count from a different table then just do a count of the tbp and ip rows grouped by jobID and then the where should still do the trick