Consider the following query:
SELECT operation, [...] FROM tableName
The operation field will retrieve an integer from 1 to 4. What I would like to do is assign a string value to a variable in the SQL query, based on the integer value of operation.
If it were up to me, I would have a corresponding table that contained the name of each operation, in which case a JOIN would pick up the operation string. Unfortunately, I do not control the database.
I don't know if this is even something SQL can do, and I could certainly iterate over the returned data using PHP to perform this task instead, but it makes sense to do it all in one hit if possible.
Try something kile this:
SELECT
CASE
operation
WHEN 1 THEN 'OP1'
WHEN 2 THEN 'OP2'
WHEN 3 THEN 'OP3'
WHEN 4 THEN 'OP4'
ELSE
'Unknown OP'
END OperationName
,
[...] FROM tableName
select
case when operation = 1 then
'1st operation'
case when operation = 2 then
'2nd operation'
else
'Unknown operation'
end operation_name
from tableName
Related
I'm using sqlite to store JSON data that I have no control over. I have a logs table that looks like this.
id
value
s8i13s85e8f34zm8vikkcv5n
{"key":["a","b"]}
m2abxfn2n9pkyc9kjmko5462
{"key": "sometext"}
Then I use the following query to get the rows where value.key contains a:
SELECT * FROM logs WHERE EXISTS (SELECT * FROM json_each(json_extract(logs.value,'$.key')) WHERE json_each.value = 'a')
The query works fine if key is an array or if it doesn't exist. But it fails if is a string (like the second row of the table)
The error I get is:
SQL error or missing database (malformed JSON)
And it is because json_each throws if the parameter is an string.
Because of the requirements I can't control the user data or the queries.
Ideally I would like to figure out a query that either doesn't fail or that detects that the value is a string instead of an array and uses LIKE to see if the string contains 'a'.
Any help would be appreciated. Happy holidays :)
Use a CASE expression in the WHERE clause which checks if the value is an array or not:
SELECT *
FROM logs
WHERE CASE
WHEN value LIKE '{"key":[%]}' THEN
EXISTS (
SELECT *
FROM json_each(json_extract(logs.value,'$.key'))
WHERE json_each.value = 'a'
)
ELSE json_extract(value,'$.key') = 'a'
END;
See the demo.
I am trying to replace a range of values with a string. I know how to do it with the replace function but that, as far as I know, requires them to be done one at a time.
Is there a way to select a range of values, for example (1-200), and replace them with a singular string value say "BLANK"?
I have tried WHEN, THEN and SET but get a syntax error near WHEN or SET as I try these.
Base Code Idea
Select DATA
WHEN DATA >= 1 THEN 'BLANK'
WHEN DATA <200 THEN 'BLANK
END
FROM DATABANK
Thanks!
Is this what you want?
select data,
case when data not between 1 and 200 then data end as new_data
from databank
What this does is take the integer value of data, and replace any value that's in the 1-200 range with null values, while leaving other values unchanged. The result goes into column new_data.
The assumption here is that data is a number - so the alternative value has to be consistent with that datatype (string 'BLANK' isn't): I went for null, which is consistent with any datatype, and is the default value returned by a case expression when no branch matches.
If you wanted something else, say 0, you would do:
select data,
case when data between 1 and 200 then 0 else data end as new_data
from databank
I have one column that called 'message' and includes several data such as fund_no, detail, keywords. This column is in table called 'trackemails'.
I have another table, called 'sendemails' that has a column called 'Fund_no'.
I want to retrieve all data from 'trackemail' table that the column 'message' contains characters same as 'Fund_no' in 'trackemails' Table.
I think If I want to check the equality, I would write this code:
select
case when t.message=ts.fund_no then 1 else 0 end
from trackemails t, sendemails s
But, I do want something like below code:
select
case when t.message LIKE ts.fund_no then 1 else 0 end
from trackemails t, sendemails s
I would be appreciate any advice to how to do this:
SELECT *
FROM trackemails tr
INNER JOIN sendemail se on tr.Message like '%' + se.Fund_No + '%'
Dear Check SQL CHARINDEX() Function. This function finds a string in another string and returns int for the position they match. Like
SELECT CHARINDEX('ha','Elham')
-- Returns: 3
And as you need:
SELECT *
,(SELECT *
FROM sendemail
WHERE CHARINDEX(trackemails.Message,sendemail.Fund_No)>0 )
FROM trackemails
For more information, If you want something much better for greater purposes, you can use Fuzzy Lookup Component in SSDT SSIS. This Component gives you a new column in the output which shows the Percentages of similarity of two values in two columns.
Let me first point out that my question is going to be very very close to this question: map-column-data-to-a-value-oracle
Please quickly read that one first.
Now in my case I need the exact same thing but not as the primary query. Instead I need the information as one part of my query.
I have this table:
someId | someValue | dataType
1 | 500 | 1
2 | someValue | 2
And I know that dataType "1" means "Integer". I also know the meaning of the other values in the dataType column.
So I want to select all entries in the table but have their dataTypes as their human readable values instead of their numbers:
Results:
1, 500, Integer
2, someString, String
Trying to apply the solution of the question I linked, I created a subquery like
SELECT
someId,
someValue,
(
SELECT CASE
WHEN dataType = 1 THEN 'INTEGER'
WHEN dataType = 2 THEN 'FLOAT'
WHEN dataType = 3 THEN 'TEXT'
ELSE 'DATE'
END
myTable
) as myDataType
I will get a subquery that returns more than 1 result and Oracle will complain.
Since I access the DB through SQL directly, I need a "pure SQL" solution. Otherwise I could just parse the value through a mapping, in say PHP. But that's not possible here. I am shooting some queries at a DB to try and gather information about the data and structure, which we don't know about. So only SQL is available.
Get rid of the subquery:
SELECT someId,
someValue,
CASE
WHEN dataType = 1 THEN 'INTEGER'
WHEN dataType = 2 THEN 'FLOAT'
WHEN dataType = 3 THEN 'TEXT'
ELSE 'DATE'
END as Datatype
from myTable
I am looking to compare two string fields in an update statement. The statement updates the field to 1 if there is a text match and 0 if not. The problem is that say BLPU_TEXT is '55' and then BLPU_PAO_SAO is 'XX55XXX' it is returning 0. But I want it to return 1 if there is any match.
UPDATE NAG_ANALYSIS.AA3_ALL N
SET N.CARTO_BLPU_BLPU_MATCH =
(CASE WHEN N.BLPU_TEXT LIKE '%'||N.BLPU_PAO_SAO||'%'
THEN 1 ELSE 0 END);
Many thanks for your time
Since you're looking for '55' in 'XX55XXX', you need to switch the variables in your WHEN:
from
WHEN N.BLPU_TEXT LIKE '%'||N.BLPU_PAO_SAO||'%'
to
WHEN N.BLPU_PAO_SAO LIKE '%'||N.BLPU_TEXT||'%'
This will turn to WHEN 'XX55XXX' LIKE '%55%'.
It works just like in a regular SQL SELECT [...] WHERE y LIKE z, where the pattern z is searched for in each column y value.