I have a Date type column where are values in this format
1.1.2012 10:10:11
I need to create a filter which would filter these values by day, month and year.
I've tried
where like '% 1.1.2012 %'
but this seems to not working.
Oracle not store your date field formatted, but you can format the output with to_char function. For example:
select to_char(date_field,'dd/mm/yyyy hh24:mi:ss')
If you query a date without formatting, the output format will depend on the tool that you are using and your NLS_DATE parameter too.
To filter dates in Oracle you can use the to_date function, that receives an string and parse to date with some specific format. You can see all options of to_date here
Options to filter your date field:
where date_field between to_date('1.1.2012 00:00','d.m.yyyy hh24:mi') and to_date('1.1.2012 23:59','d.m.yyyy hh24:mi')
-- you possibly will lost some performance with this second one
where trunc(date_field) = to_date('1.1.2012','d.m.yyyy')
In MSSQL, you can use date-functions, that are easy to handle. One way would be like this:
where Year (date) = 2012
and Month(date) = 1
and Day (date) = 1
But there are other solutions. Take a look at the following page for mor information:
http://msdn.microsoft.com/en-us/library/ms186724.aspx
I worked recently with string-representations of datetime-values. I recommend not do it and to work always with the dates, because of compatibility, speaking of the MSSQL-Server.
If you use string-representations of datetime-values you need to be very careful with formats on different language-settings than the one on your own server.
Strings can be interpreted different on other servers (ISO-format vs us-format).
One possibility would be to do something like this:
WHERE date_and_time >=to_date( '01.01.2012','dd.mm.yyyy') and date_and_time <= to_date('01.01.2012','dd.mm.yyyy');
date_and_time is the name of your Date column.
edit: This is for Oracle
Related
i'm trying to define a rule that count rows where date format is dd/mm/yyyy and greater than a specific date in sql but i couldn't find the right function to use.
The second part is working : SELECT COUNT (*) FROM CUSTOMER WHERE DAT_0 >= '01/01/1995' but how could i specify the format too
In Standard SQL, the WHERE clause would look like:
WHERE DAT_0 >= DATE '1995-01-01'
Many databases would simply accept this without the DATE as well:
WHERE DAT_0 >= '1995-01-01'
In your comment DATE_0 is a date column
Therefore we can change it to any format as below using to_char then to_date
to_date(to_char(DATE_0,'yyyymmdd'),'yyyy-mm-dd')
When comparing you can try this, converting the date to_number, i find it very easy
to_number(to_char(DATE_0,'yyyymmdd')) > 19950101
if datatype of "DAT_0" is date or datetime or timestamp , they are recorded as a specific format specified by default datetime setting in your database engine , therefore you can't have multiple format inside the column , so there is no concern there
I am not getting data between two years, below is between condition
to_char(Wfc.APPLYDTM,'MM/DD/YYYY') between '12/11/2019' and '01/10/2020'
but I am getting data between '12/11/2019' and '12/31/2019' & '01/11/2020' and '01/01/2020' for these dates but not between two different years.
Please help
Try using TO_DATE instead of TO_CHAR, and then compare against valid Oracle date literals:
SELECT *
FROM Wfc
WHERE TO_DATE(APPLYDTM, 'MM/DD/YYYY') BETWEEN date '2019-12-11' AND date '2019-01-10';
Note that if APPLYDTM already be a date, then you don't need to call TO_DATE on it. It doesn't make sense to convert your data to character, if you intend to work with it as a date.
You should convert your data to Date to be able to compare correctly.
The main idea is you should compare date value instead of string value.
to_date(Wfc.APPLYDTM,'MM/dd/yyyy') between to_date('12/11/2019','MM/dd/yyyy') and to_date('01/10/2020','MM/dd/yyyy')
Read here to more details.
Do not convert date/time values to strings! Use the built in functionality.
Your logic is most simply expressed as:
Wfc.APPLYDTMbetween >= DATE '2019-12-11' AND
Wfc.APPLYDTMbetween < DATE '2020-01-11'
Note that the date constants are provided using the DATE keyword. This supposed ISO 8601 standard date formats (happily!).
Also note the use of >= and < rather than BETWEEN. The date data type in Oracle can include a time component -- even if you don't see it when you query the table. This ensures that all date/times are included in the range.
As an added benefit, this can use an index on (APPLYDTMbetween). Using a function usually precludes using an index, unless you have defined a function-based index.
For some reason (I have no control over this) dates are stored as Integers in an iSeries AS400 DB2 system that I need to query. E.g. today will be stored as:
20,171,221
Being in the UK I need it to be like the below in Date format:
21/12/2017
This is from my query: (OAORDT = date field)
Select
Date(SUBSTR( CHAR( OAORDT ),7,2) ||'/' || SUBSTR(CHAR ( OAORDT ),5,2) || '/' || SUBSTR(CHAR (OAORDT ),1,4)) AS "Order Date"
from some.table
However, all I get is Nulls. If I remove the Date function, then it does work but its now a string, which I don't want:
Select
SUBSTR( CHAR( OAORDT ),7,2) ||'/' || SUBSTR(CHAR ( OAORDT ),5,2) || '/' || SUBSTR(CHAR (OAORDT ),1,4) AS "Order Date"
from some.table
How do I convert the OAORDT field to Date?
Just to update - I will be querying this from MS SQL Server using an OpenQuery
Thanks.
1) How do I convert the OAORDT field to Date?
Simplest is to use TIMESTAMP_FORMAT :
SELECT DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD'))
2) Being in the UK I need it to be [...] in Date format 21/12/2017 :
SELECT VARCHAR_FORMAT(DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD')),'DD/MM/YYYY')
Note, you didn't specify where you are doing this, but since you tagged as ibm-midrange, I am answering for embedded SQL. If you want JDBC, or ODBC, or interactive SQL, the concept is similar, just the means of achieving it is different.
Make sure SQL is using dates in the correct format, it defaults to *ISO. For you it should be *EUR. In RPG, you can do it this way:
exec sql set option *datfmt = *EUR;
Make sure that set option is the first SQL statement in your program, I generally put it immediately between D and C specs.
Note that this is not an optimal solution for a program. Best practice is to set the RPG and SQL date formats both to *ISO. I like to do that explicitly. RPG date format is set by
ctl-opt DatFmt(*ISO);
SQL date format is set by
exec sql set option *datfmt = *ISO;
Now all internal dates are processed in *ISO format, and have no year range limitation (year can be 0001 - 9999). And you can display or print in any format you please. Likewise, you can receive input in any format you please.
Edit Dates are a unique beast. Not every language, nor OS knows how to handle them. If you are looking for a Date value, the only format you need to specify is the format of the string you are converting to a Date. You don't need to (can't) specify the internal format of the Date field, and the external format of a Date field can be mostly anything you want, and different each time you use it. So when you use TIMESTAMP_FORMAT() as #Stavr00 mentioned:
DATE(TIMESTAMP_FORMAT(CHAR(OAORDT),'YYYYMMDD'))
The format provided is not the format of the Date field, but the format of the data being converted to a Timestamp. Then the Date() function converts the Timestamp value into a Date value. At this point format doesn't matter because regardless of which external format you have specified by *DATFMT, the timestamp is in the internal timestamp format, and the date value is in the internal date format. The next time the format matters is when you present the Date value to a user as a string or number. At that point the format can be set to *ISO, *EUR, *USA, *JIS, *YMD, *MDY, *DMY, or *JUL, and in some cases *LONGJUL and the *Cxxx formats are available.
Since none of variants suited my needs I've came out with my own.
It is as simple as:
select * from yourschema.yourtable where yourdate = int(CURRENT DATE - 1 days) - 19000000;
This days thing is leap year-aware and suits most needs fine.
Same way days can be turned to months or years.
No need for heavy artillery like VARCHAR_FORMAT/TIMESTAMP_FORMAT.
Below worked for me:
select date(substring(trim(DateCharCol), 1, 2)||'/'||substring(trim(DateCharCol), 3, 2)||'/'||'20'||substring(trim(DateCharCol), 5, 2)) from yourTable where TableCol =?;
So I have a table where the dates are formatted as such: 15-Jan-13
That would obviously be January 15th, 2013.
The problem is, when I try to search a date range between 01/01/2014 and SYSDATE, it errors out.
Does anyone know the proper way in which I would format this based off of how my dates are stored?
FYI my raw data is stored as: 15-JAN-13 02.23.27.000000000 PM -05:00
I'm converting it as
TRUNC(variable_name)
Given that you are asking about "sysdate" then I would assume you are using Oracle. It would also seem that the the column with the dates are not actual in the date format. Best option would be to change the column to a date type. If for some reason that isn't an option, the next best thing to do is to translate the text to a date as part of your query:
select *
from foo
where to_date(your_column, 'dd-Mon-yy') between to_date('01/01/2014', 'mm/dd/yyyy')
and sysdate
Note that to_date is expecting it's second argument to match the structure of the date specified so '01/01/2014' would match the date format 'mm/dd/yyyy' and your_column (value: '15-Jan-13') would match a different format 'dd-Mon-yy'. Once everything is translated to a date, Oracle can perform appropriate date comparisons.
DISCLAIMER: The translation of your_column to a date using to_date means that if an index is defined on your_column, it won't be used. If this is a large table you can expect sub-optimal performance. One additional reason to change the column data type to a date.
I am trying to update a date in a SQL table. I am using Peoplesoft Oracle. When I run this query:
Select ASOFDATE from PASOFDATE;
I get 4/16/2012
I tried running this query
UPDATE PASOFDATE SET ASOFDATE = '11/21/2012';
but it is not working.
Does anyone know how I would change the date to the one desired?
This is based on the assumption that you're getting an error about the date format, such as an invalid month value or non-numeric character when numeric expected.
Dates stored in the database do not have formats. When you query the date your client is formatting the date for display, as 4/16/2011. Normally the same date format is used for selecting and updating dates, but in this case they appear to be different - so your client is apparently doing something more complicated that SQL*Plus, for example.
When you try to update it it's using a default date format model. Because of how it's displayed you're assuming that is MM/DD/YYYY, but it seems not to be. You could find out what it is, but it's better not to rely on the default or any implicit format models at all.
Whether that is the problem or not, you should always specify the date model:
UPDATE PASOFDATE SET ASOFDATE = TO_DATE('11/21/2012', 'MM/DD/YYYY');
Since you aren't specifying a time component - all Oracle DATE columns include a time, even if it's midnight - you could also use a date literal:
UPDATE PASOFDATE SET ASOFDATE = DATE '2012-11-21';
You should maybe check that the current value doesn't include a time, though the column name suggests it doesn't.
Here is how you set the date and time:
update user set expiry_date=TO_DATE('31/DEC/2017 12:59:59', 'dd/mm/yyyy hh24:mi:ss') where id=123;
If this SQL is being used in any peoplesoft specific code (Application Engine, SQLEXEC, SQLfetch, etc..) you could use %Datein metaSQL. Peopletools automatically converts the date to a format which would be accepted by the database platform the application is running on.
In case this SQL is being used to perform a backend update from a query analyzer (like SQLDeveloper, SQLTools), the date format that is being used is wrong. Oracle expects the date format to be DD-MMM-YYYY, where MMM could be JAN, FEB, MAR, etc..
Just to add to Alex Poole's answer, here is how you do the date and time:
TO_DATE('31/DEC/2017 12:59:59', 'dd/mm/yyyy hh24:mi:ss')