getting the id from a table in database - sql

i have 3 tables city, information and state. In my code i've shown the different cites under different state. what i want to do is to get the seperate ids of the cities so that i can run some queries in my 'information' table.
My model is given below:
function get_status(){
$states = $this->db->get('state');
$like = array();
$status = array();
foreach ($states->result() as $state){
$cities = $this->db->get_where('city', array('state_id'=> $state->id));
$like=$cities->result();
$status=$like[0]->city_id;
}
echo $status;
}
but when i run the code i only get the last id of the last city stored under the last state in the the table. for example the state 3 has city that has id 3. i'm only getting this id. but i want all the ids of the cities like- 1,2,3.
i'm using Codeigniter framework.
Thanks in advance

$like - it`s an array.
[0] - the first element of an array.
echo $like[0]->city_id;
I haven`t tested it. (In one iteration -> it takes all the cities from that ID)
function get_status(){
$states = $this->db->get('state');
$like = array();
$status = array();
foreach ($states->result() as $state){
$cities = $this->db->get_where('city', array('state_id'=> $state->id));
foreach ($cities->result() as &$v){
echo $v->city_id."<br/>";
}
echo "......<br/>";
}
}

Related

Get user data from database codeignter

I have two tables in one database, table one called: ci_admin, and table two called active_ingredient.
I want to get user data from the active_ingredient table where user_id equals admin_id from ci_admin table using the current user session.
this code, get data for all user, I need the data inserted by the user only:
$wh =array();
$SQL ='SELECT * FROM active_ingredient';
$wh[] = "SELECT 1
FROM ci_admin
WHERE ci_admin.admin_id = active_ingredient.user_id";
if(count($wh)>0)
{ $WHERE = implode(' and ',$wh);
return $this->datatable->LoadJson($SQL,$WHERE);
}
else
{
return $this->datatable->LoadJson($SQL);
}
Try this, it will help you.
$this->db->select('ai.*,ca.*');
$this->db->from('active_ingredient ai');
$this->db->join('ci_admin ca', 'ca.admin_id = ai.user_id', 'left');
$this->db->where($data); //pass the session data for exact filter
$query = $this->db->get();
return $query->result();

How to select data from table that not inserted on other table in codeigniter

I've two tables products, stock I want to select all rows from table products that not inserted on stock and i've 2 conditions
1: column products.s_compnay_id = users.u_company_id
2: cloumn stock.s_company_id =users.u_company_id
that's my model
<?php
Class UserProducts_m extends CI_Model{
function index(){
$session_data = $this->session->userdata('logged_in');
$name = $session_data['username'];
$this->db->select('u_company_id');
$this->db->from('users');
$this->db->where('u_username', $name);
$user_data = $query = $this->db->get();
if ($user_data->num_rows() > 0) {
foreach ($query->result_array() as $row_userdata) {
$usercompanyid[] = $row_userdata;
}
$usercompany=$usercompanyid[0]['u_company_id'];
}
$query="select products.* from products where !FIND_IN_SET(products.p_id,select stock.s_p_id from stock and stock.s_company_id=$usercompany and p_company_id=$usercompany)";
$this->db->query($query);
$result= $this->db->get();
if ($result->num_rows() > 0) {
foreach ($result->result_array() as $row_result) {
$product_data[] = $row_result;
}
}
//return $result=$query->result();
}
}
?>
And that's my controller
<?php
Class UserProducts extends CI_Controller {
function index(){
$this->load->model("UserProducts_m");
$this->load->model("user");
$this->load->view("userproducts_v",array(
'userdata'=>$this->user->userdata(),
'userproducts'=>$this->UserProducts_m->index()
));
}
}
?>
that's my errors
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'select stock.s_p_id from stock and stock.s_company_id=1 and p_company_id=1)' at line 1
select products.* from products where !FIND_IN_SET(products.p_id,select stock.s_p_id from stock and stock.s_company_id=1 and p_company_id=1)
Filename: C:/xampp/htdocs/Elvan/system/database/DB_driver.php
Line Number: 691
I suggest you try putting curly braces around the vars in your query statement. Then it should resolve to array values properly.
$query="select products.* from products where
!find_in_set(products.p_id,select stock.s_p_id from stock and
stock.s_company_id = {$usercompanyid[0]['u_company_id']} and
p_company_id = {$usercompanyid[0]['u_company_id']})";
I see a couple other problems.
The line
$result= $this->db->get();
is not needed because $this->db->query($query); already returned a database result object. Do this
$result = $this->db->query($query);
if ($result->num_rows() > 0)
{ ...
Then you have this useless block of code (Pardon me for being blunt)
foreach ($result->result_array() as $row_result)
{
$product_data[] = $row_result;
}
This is useless because your code just copies array values from one array to another. You'll save a lot of code execution with the following which produces the same thing your foreach loop does.
$product_data = $result->result_array();
result->array() returns an array where each item is an array representing a table row.
You did the same thing earlier adding items to the $usercompanyid array. Do this.
if ($user_data->num_rows() > 0)
{
$usercompanyid = $query->result_array();
}
One last problem. It appears that UserProducts_m::index() does not return anything.
You can use the NOT IN sql query for this.
SELECT *
FROM products
WHERE product_id NOT IN (select field name form stock where clause);

fetch image and text from database using joomla 2.5

i have one one issue in fetch image and text from database by module what to do for this issue and i add my table name and field name #__home_service_item this is my table name in that table two field one is image and image_name than i have one error for that question i display my error
Warning: Invalid argument supplied for foreach() in C:\wamp\www\Joomla_2.5.8-Stable-Full_Package\modules\mod_home\tmpl\default.php on line 40
please give me any clue for that problem i also add my code
<?php
defined('_JEXEC') or die('Restricted access');
$items = $params->get('items', 1);
$db =& JFactory::getDBO();
$query = "SELECT id
FROM #__home_service_item
WHERE published = '1'
ORDER BY id DESC";
$db->setQuery( $query, 0 , $items );
$rows = $db->loadObjectList();
foreach($rows as $row)
{
echo 'ID: '.$row->id.' </br>';
}
?>
please give one clue
do print_r($rows) and see if any records are returning from the database. I think that you have a problem with your query. If there are no results returning try enclosing your foreach statement with in a try catch or ignore warnings.
Also try to set $db->setQuery($query); instead of $db->setQuery( $query, 0 , $items );
If you just need one row result use $db->loadResult();

kohana orm join duplicate objects result

I'm trying to query the country table with the below query to print all countries with the corresponding cities. Now i'm getting a duplicated country object for each city instead of have one country object for all cities.
$all = ORM::factory('country')->select('cities.*')->join('cities','LEFT')->on('country.id', '=', 'country_id' )->find-all();
foreach ($all as $country) {
echo $caountry->name;
foreach($country->cities as $city ){
echo $city->name;
}
}
Appreciate your help,
AA
If you are using MySQL and only need the name of the city, you can use GROUP_CONCAT function and then convert it to array using PHP's explode.
$all = ORM::factory('country')
->select('country.name',DB::epxr('GROUP_CONCAT(cities.name) AS cities'))
->join('cities','LEFT')
->on('country.id', '=', 'country_id' )
->group_by("country.id")
->find-all();
foreach ($all as $country) {
echo $country->name;
foreach(explode(",",$country->cities) as $city ){
echo $city;
}
}

Yii: adding custom fields

Is there a simple way of adding custom fields to a model? Say I have a table "user" with 3 fields: id, name and surname. I want this:
$user = User::model()->findByPk(1);
$echo $user->fullName; // echoes name and surname
Please note: I want this custom field to be added via sql, smth like
$c = new CDbCriteria();
$c->select = 'CONCAT("user".name, "user".surname) as fullName';
$user = User::model()->find($c);
Problem is that fullName property is not set.
UPD:
here is the code for a little bit trickier problem -- custom field from another table. This is how it's done:
$model = Application::model();
$model->getMetaData()->columns = array_merge($model->getMetaData()->columns, array('fullName' => 'CONCAT("u".name, "u".surname)'));
$c = new CDbCriteria();
$c->select = 'CONCAT("u".name, "u".surname) as fullName';
$c->join = ' left join "user" "u" on "t".responsible_manager_id = "u".id';
$model->getDbCriteria()->mergeWith($c);
foreach ($model->findAll() as $o) {
echo '<pre>';
print_r($o->fullName);
echo '</pre>';
}
You can add a function to the User class:
public function getFullName() { return $this->name.' '.$this->surname; }
This will return the full name as if it were an attribute from the database. This is much easier than adding a calculated column to the SQL.
In model
public function getMetaData(){
$data = parent::getMetaData();
$data->columns['fullName'] = array('name' => 'fullName');
return $data;
}
Thus not recommended