I need to convert sysdate in YYYYMM format to validate the expiry date, this is the query I have written but am facing the below error.
select to_char (to_date(sysdate,'MM/DD/YYYY'),'YYYYMM') from dual;
ORA-01858: a non-numeric character was found where a numeric was expected
There is no reason to convert sysdate to a date. So just use:
select to_char(sysdate, 'YYYYMM')
If you wanna to format the date, try "DATE_FORMAT" way:
SELECT DATE_FORMAT('2011-11-11 13:14:01','%m%Y')
or you wanna to get the difference between the expired date and sysdate,you may try "DATEDIFF":
SELECT DATEDIFF('2001-01-01','2001-02-02') -> -32
I am trying to convert a varchar2(30) of this format
10/10/2019 08:09:48 AM
into date_time or date so I can order it by start_time. I tried the following
SELECT MIN(TO_DATE(START_TIME,'MON/DD/YYYY HH:MI:SS'))
I think it works because no syntax errors but I keep getting "not a valid month" that time structure up there is how the data looks I dont see an obscure date format.
Any ideas what the issue is?
this is for SQL ORACLE DEVELOPER
MON is for "Jan - Dec". Use MM:
SELECT MIN(TO_DATE(START_TIME,'MM/DD/YYYY HH:MI:SS'))
You will also need to account for your "AM/PM" part:
SELECT MIN(TO_DATE(START_TIME,'MM/DD/YYYY HH:MI:SS AM'))
If this does not work out of the box, try explicitly setting the language to American:
SELECT MIN(TO_DATE(START_TIME, 'MM/DD/YYYY HH:MI:SS AM', 'NLS_DATE_LANGUAGE=American'))
I'm trying to create a date subtract two days and then convert it to a char. For some reason I'm getting the following error:
ORA-01830: date format picture ends before converting entire input string
Here's my code:
SELECT TO_CHAR(to_date('20-JUL-01 10:40:12')-2, 'dd-Mon-yy 24HH:MI:SS') as "Subtract 2 Days"
FROM DUAL;
I'm not sure what's wrong, it seems to be an issue with the seconds
The Oracle default is a 12-hour clock with AM/PM. So, you need a date format for the date conversion:
SELECT TO_CHAR(to_date('20-JUL-01 10:40:12', 'dd-Mon-yy HH24:MI:SS')-2,
'dd-Mon-yy HH24:MI:SS') as "Subtract 2 Days"
FROM DUAL;
Also, the correct 24-hour signifier is "HH24", not "24HH".
I have a situation where I need to convert the datetime value stored as string to Timestamp:
I am using oracle database
This actually works for me select TO_DATE('11-27-2013 21:28:41', 'MM-DD-YYYY HH24:MI:SS') from dual;
But my date value now is diffent from the above:
select TO_DATE('Sunday 6/1/2014 8:00AM', 'MM-DD-YYYY HH24:MI:SS') from dual; - failed. I have 'Sunday' inside my date.
You have to specify a correct format mask to the TO_DATE function. See a full list of format masks along with documentation for the function here: http://www.techonthenet.com/oracle/functions/to_date.php
You can correct your problem by:
SELECT TO_DATE('Sunday 6/1/2014 8:00AM', 'DAY M/D/YYYY HH:MIAM') FROM DUAL;
Try using the correct format. I think this will work:
select TO_DATE('Sunday 6/1/2014 8:00AM', 'DAY MM/DD/YYYY HH:MI AM')
Here is a SQL Fiddle.
The following seems to work fine:
SELECT TO_DATE('Sunday 6/1/2014 8:00AM', 'DAY MM/DD/YYYY HH:MIAM') FROM DUAL
Share and enjoy.
I have a date column in a table stored as MM/DD/YYYY format. I have to select and store the same date in another table in YYYY-MM-DD format i.e. XSD Date Format. But I am not able to do it. I am using this query:
select to_date(date_column,'YYYY-MM-DD') from table;
But still I am not able to do it. Giving me error
ORA-01843 : not a valid month
use
select to_char(date_column,'YYYY-MM-DD') from table;
It sounds like you've got it the wrong way round. If your existing data is in MM/DD/YYYY format, then you want:
select to_date(date_column,'MM/DD/YYYY') from table;
to convert the existing data to DATE values. (I do wonder why they're not stored as dates, to be honest...)
If you want to perform the conversion in one step, you might want:
select to_char(to_date(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD') from table;
In other words, for each row, parse it in MM/DD/YYYY format, then reformat it to YYYY-MM-DD format.
(I'd still suggest trying to keep data in its "natural" type though, rather than storing it as text in the first place.)
I assume that you can use the Oracle SQL Developer, which you can download from here.
You can define the date format which you want to work with:
ALTER SESSION SET nls_date_format='yyyy-mm-dd';
With this, now you can perform a query like this:
SELECT * FROM emp_company WHERE JDate = '2014-02-25'
If you want to be more specific you can define the date format like this:
ALTER SESSION SET nls_date_format='yyyy-mm-dd hh24:mi:ss';
To convert a DATE column to another format, just use TO_CHAR() with the desired format, then convert it back to a DATE type:
SELECT TO_DATE(TO_CHAR(date_column, 'DD-MM-YYYY'), 'DD-MM-YYYY') from my_table
select to_date(to_char(ORDER_DATE,'YYYY/MM/DD'))
from ORDERS;
This might help but, at the end you will get a string not the date. Apparently,
your format problem will get solved for sure .
For military time formatting,
select TO_CHAR(SYSDATE, 'yyyy-mm-dd hh24:mm:ss') from DUAL
--2018-07-10 15:07:15
If you want your date to round DOWN to Month, Day, Hour, Minute, you can try
SELECT TO_CHAR( SYSDATE, 'yyyy-mm-dd hh24:mi:ss') "full-date" --2018-07-11 10:40:26
, TO_CHAR( TRUNC(SYSDATE, 'year'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-year"-- 2018-01-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'month'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-month" -- 2018-07-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'day'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-Sunday" -- 2018-07-08 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'dd'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-day" -- 2018-07-11 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'hh'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-hour" -- 2018-07-11 10:00:00
, TO_CHAR( TRUNC(SYSDATE, 'mi'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-minute" -- 2018-07-11 10:40:00
from DUAL
For formats literals, you can find help in
https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions242.htm#SQLRF52037
You can do this simply by :
select to_char(to_date(date_column, 'MM/DD/YYYY'), 'YYYY-MM-DD') from table
According to the comments, the data-type in the datatable is DATE.
So you should simply use:
"select date_column from table;"
Now if you execute the select you will get back a date data-type, which should be what you need for the .xsd.
Culture-dependent formating of the date should be done in the GUI (most languages have convenient ways to do so), not in the select-statement.
Basically , Data in a Date column in Oracle can be stored in any user defined format or kept as default.
It all depends on NLS parameter.
Current format can be seen by : SELECT SYSDATE FROM DUAL;
If you try to insert a record and insert statement is NOT in THIS format then it will give :
ORA-01843 : not a valid month error.
So first change the database date format before insert statements ( I am assuming you have bulk load of insert statements) and then execute insert script.
Format can be changed by :
ALTER SESSION SET nls_date_format = 'mm/dd/yyyy hh24:mi:ss';
Also You can Change NLS settings from SQL Developer GUI , (Tools > preference> database > NLS)
Ref: http://oracle.ittoolbox.com/groups/technical-functional/oracle-sql-l/how-to-view-current-date-format-1992815
This worked for me! You can convert to datatype you want be it a date or string
to_char(TO_DATE(TO_CHAR(end_date),'MM-DD-YYYY'),'YYYY-MM-DD') AS end_date
Late reply but for.databse-date-type the following line works.
SELECT to_date(t.given_date,'DD/MM/RRRR') response_date FROM Table T
given_date's column type is Date
Just to piggy back off of Yahia, if you have a timestamp you can use this function to cast exclusively as date, removing the timestamps.
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYY-MM-DD') AS TrackerKey__C
Or in my case I need the below format
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYYMMDD') AS TrackerKey__C
SELECT TO_DATE(TO_CHAR(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD')
FROM table;
if you need to change your column output date format just use to_char this well get you a string, not a date.
use
SELECT STR_TO_DATE(date_column,'%Y-%m-%d') from table;
also gothrough
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html