I have a table for matches. The table has a column named matchdate, which is a datetime field.
If I have 3 matches on 2011-12-01:
2011-12-01 12:00:00
2011-12-01 13:25:00
2011-12-01 16:00:00
How do I query that? How do I query all matches on 1 single date?
I have looked at date_trunc(), to_char(), etc.
Isn't there some "select * where datetime in date" function?
Cast your timestamp value to date if you want simple syntax. Like this:
SELECT *
FROM tbl
WHERE timestamp_col::date = '2011-12-01'; -- date literal
However, with big tables this will be faster:
SELECT *
FROM tbl
WHERE timestamp_col >= '2011-12-01 0:0' -- timestamp literal
AND timestamp_col < '2011-12-02 0:0';
Reason: the second query does not have to transform every single value in the table and can utilize a simple index on the timestamp column. The expression is sargable.
Note excluded the upper bound (< instead of <=) for a correct selection.
You can make up for that by creating an index on an expression like this:
CREATE INDEX tbl_ts_date_idx ON tbl (cast(timestamp_col AS date));
Then the first version of the query will be as fast as it gets.
not sure if i am missing something obvious here, but i think you can just
select * from table where date_trunc('day', ts) = '2011-12-01';
Just use the SQL BETWEEN function like so:
SELECT * FROM table WHERE date BETWEEN '2011-12-01' AND '2011-12-02'
You may need to include times in the date literals, but this should include the lover limit and exclude the upper.
From rails I believe you can do:
.where(:between => '2011-12-01'..'2011-12-02')
Related
I have date formats that are as follows:
Date_str
19-12-2007
31-7-2009
3-1-2010
31-11-2009
etc.
I can't do the following:
CONCAT(RIGHT(Date_str,4),SUBSTRING(Date_str,3,3),LEFT(2))
because as you can see above, the dates are not the same length. Is there a way in SQL Server to extract the date as datetime/date?
I also tried
Convert(datetime, Date_str)
but it just threw an error:
The conversion of a varchar data type to a datetime data type resulted
in an out-of-range value.
If 2012+, I would use Try_Convert(). This will return bogus dates as NULL.
Example
Declare #YourTable Table ([Date_str] varchar(50))
Insert Into #YourTable Values
('19-12-2007')
,('31-7-2009')
,('3-1-2010')
,('31-11-2009')
Select *
,try_convert(date,Date_Str,105)
from #YourTable
Returns
Date_str (No column name)
19-12-2007 2007-12-19
31-7-2009 2009-07-31
3-1-2010 2010-01-03
31-11-2009 NULL -- Notice 11/31 is NOT a date
See https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql for date formats
You probably need
CONVERT(DateTime, Date_str, 105)
As I mentioned in the comments, the only realistic solution is to convert that string into a proper date-typed column. The current format doesn't allow date sorting, or search for a range of dates, eg to find entries in the last week, or between one date and the other.
Parsing with CONVERT or TRY_PARSE means that no indexes can be used to speed up queries. Each time :
WHERE CONVERT(Date, Date_str, 105) > '20170101'
is used, the server will have to scan the entire table to convert the data, then filter the rows.
If you can't change the type of the field itself, you can create a persisted computed column that returns the value as a date and add indexes to it. You'll be able to use that column for indexed querying:
alter table SomeTable add date2 as TRY_convert(Actual_Date,date_str,105) PERSISTED
create index IX_SomeTable_ActualDate on SomeTable (Actual_Date)
This will allow you to perform sorting without tricks:
SELECT *
FROM SomeTable
ORDER BY Actual_Date
Or run range queries that take advantage of the IX_SomeTable_ActualDate index:
SELECT *
FROM SomeTable
Where Actual_Date Between DATEADD(d,-7,GETDATE()) AND GETDATE()
If you have 1000 rows, you could get 1000 times better performance.
Existing applications won't even notice the change. Newer queries and applications will be able to take advantage of indexing and sorting
I had a similar problem: my column (<my_date_field>) had date values in the form of
2021-01
2021-02
2021-10
2021-12
and so on, with data type of nvarchar(4000), and I always ran into the Conversion failed when converting date and/or time from character string. error (when trying e.g. CAST(<my_date_field> AS DATE) or CAST(CAST(<my_date_field> AS VARCHAR(7)) AS DATE) etc.)
I was able to convert them to date with the following code:
SELECT
CONVERT(date, <my_date_field> + '-01') AS first_day_of_month
FROM my_table
which resulted in
2021-08-01
2021-07-01
2021-06-01
2021-05-01
Is that possible? Can one
SELECT * FROM DATES_TBL WHERE DATES_TBL.DATES IN(NULL, >=SYSDATE)
? Maybe I am formatting it incorrectly, or missing a tick?
What I would like to select are values from the date field that are NULL or greater than today's date (>=SYSDATE). Any help would be appreciated.
SQL 10g
SELECT *
FROM DATES_TBL
WHERE DATES IS NULL OR DATES >= SYSDATE
The NULL value is a special value so you must write your statement like that:
SELECT *
FROM DATES_TBL
WHERE DATES IS NULL
OR DATES >= SYSDATE
This is definitely not a valid syntax: IN queries require specific items; also, because in SQL null never equals anything, including other nulls, it does not make sense to put nulls into an IN list.
What you need instead is an OR:
SELECT * WHERE (DATES_TBL.DATES IS NULL) OR (DATES_TBL.DATES>=SYSDATE)
-- ^^^^^^^^^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^^^^^^^^^^^
-- | |
-- | +- This is how you compare for >=
-- +------------- This is how you check for NULL
Every time I try to use an OR clause it causes a lot of run time
In cases when OR is introduced to combine non-overlapping results (which is true in this case, because a column is either null or is greater than SYSDATE, but not both) you can use UNION ALL to potentially speed up the search:
SELECT * WHERE DATES_TBL.DATES IS NULL
UNION ALL
SELECT * WHERE DATES_TBL.DATES >= SYSDATE
You need to make sure that DATES_TBL.DATES column is indexed.
Assuming this is for Oracle, try this:
SELECT * FROM DATES_TBL WHERE (DATES_TBL.DATES is null or DATES_TBL.DATES >= sysdate)
The parenthesis make it work.
My table has records like these
23-MAY-11 11.40.39.000000 AM
The following query brings nothing
SELECT *
FROM my_table
WHERE tenant_pha = 'test'
AND create_date >= TO_DATE('05/10/2011','mm/dd/yyyy')
AND create_date <= TO_DATE('05/23/2011','mm/dd/yyyy')
However, the below query will bring data
SELECT *
FROM my_table
WHERE tenant_pha = 'test'
AND create_date >= TO_DATE('05/10/2011','mm/dd/yyyy')
AND create_date <= TO_DATE('05/24/2011','mm/dd/yyyy')
I think this is because create_date column is time stamp.
How can I change my query to bring the desired result ( I want to avoid doing functions on the left side columns because they will make the query long).
You are right about the timestamp. '05/23/2011' is the same as '05/23/2011 12:00 AM'.
To include the whole day I usually move my date up by a day. < '05/24/2011' will include all of 5/23.
or change to '05/23/2011 23:59:59'
You can use trunc() without problems, you only need to create a function based index.
If you create this index:
CREATE INDEX idx_trunc_date ON my_table (trunc(create_date));
then the following condition will make use of that index:
AND trunc(create_date) >= TO_DATE('05/10/2011','mm/dd/yyyy')
I'm facing a strange query result and I want to ask you why I'm facing this issue.
I store some datetime data into TestTable as following :
creation_time
-----------------------
2010-07-10 00:01:43.000
2010-07-11 00:01:43.000
2010-07-12 00:01:43.000
This table is created and filled as following :
create table TestTable(creation_time datetime);
Insert into TestTable values('2010-07-10 00:01:43.000');
Insert into TestTable values('2010-07-11 00:01:43.000');
Insert into TestTable values('2010-07-12 00:01:43.000');
when I execute this query , I get two rows only instead of three as I expected:
SELECT * FROM TestTable
WHERE creation_time BETWEEN CONVERT(VARCHAR(10),'2010-07-10',111) -- remove time part
and CONVERT(VARCHAR(10),'2010-07-12',111) -- remove time part
Or if I execute this query , the same issue ..
SELECT * FROM TestTable
WHERE CONVERT(datetime,creation_time,111) BETWEEN CONVERT(VARCHAR(10),'2010-07-10',111) -- remove time part
and CONVERT(VARCHAR(10),'2010-07-12',111) -- remove time part
My Question :
Why the last row ('2010-07-12 00:01:43.000') does not appear in
the result even if I set the date range to cover all the day from 2010-07-10 to 2010-07-12?
I use Sql server 2005 express edition with windows xp 32-bits.
I'm trying to don't use a workaround solution such as increasing the date range to cover additional day to get the days I want.
Thanks .
You need to remove the time part from creation_time as well. Just use the same CONVERT if it works.
Currently you're asking if 2010-07-12 00:01:43.000 is less than 2010-07-12 00:00:00.000, which is not true.
it does not show the date because you have removed the time part, which would make the date equivalent to '2010-07-12 00:00:00.000' and since the last row is greater than this, so it is not displaying in the query results.
Your script should look like this:
SELECT *
FROM TestTable
WHERE creation_time BETWEEN
convert(datetime, convert(char, '2010-07-10', 106))-- remove time part
and **DATEADD**(day, 1, convert(datetime, convert(char, '2010-07-**11**', 106))) -- remove time part and add 1 day
This script will return all between 2010-07-10 00:00:00 and 2010-07-12 00:00:00. Basically this means all items created in 2 days: 2010-07-10 and 2010-07-11.
Converting columns in your table for comparison can be costly and cause indexes to not be used. If you have a million rows in your table and you have an index on creation_time, you will be doing an index scan and converting all million values to a string for comparison.
I find it better to use >= the start date and < (end date + 1 day):
SELECT *
FROM TestTable
WHERE creation_time >= '2010-07-10'
AND creation_time < dateadd(day, 1, '2010-07-12')
And the reason your second one may not work is because format 111 uses slashes ("2010/07/10"), format 120 uses dashes ("2010-07-10"). Your converts aren't doing anything to your start and end date because you are converting a string to varchar, not a date. If you did this, it might work, but I would still recommend not doing the conversion:
SELECT * FROM TestTable
WHERE CONVERT(datetime, creation_time, 111) BETWEEN
CONVERT(VARCHAR(10), CONVERT(datetime, '2010-07-10'), 111) -- remove time part
and CONVERT(VARCHAR(10), CONVERT(datetime, '2010-07-12'), 111) -- remove time part
Date/time inclusive between 7/10/2010 and 7/12/2010:
SELECT * FROM TestTable
WHERE creation_time BETWEEN
CONVERT(VARCHAR,'2010-07-10',101) -- remove time part
and CONVERT(VARCHAR,'2010-07-13',101) -- remove time part
Suppose I have a date 2010-07-29. Now I would like to check the result of one day ahead. how to do that
For example,
SELECT *
from table
where date = date("2010-07-29")
How to do one day before without changing the string "2010-07-29"?
I searched and get some suggestion from web and I tried
SELECT *
from table
where date = (date("2010-07-29") - 1 Day)
but failed.
MySQL
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATE_SUB('2010-07-29', INTERVAL 1 DAY)
AND '2010-07-29'
Change DATE_SUB to DATE_ADD if you want to add a day (and reverse the BETWEEN parameters).
SQL Server
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATEADD(dd, -1, '2010-07-29')
AND '2010-07-29'
Oracle
SELECT *
FROM TABLE t
WHERE t.date BETWEEN TO_DATE('2010-07-29', 'YYYY-MM-DD') - 1
AND TO_DATE('2010-07-29', 'YYYY-MM-DD')
I used BETWEEN because the date column is likely DATETIME (on MySQL & SQL Server, vs DATE on Oracle), which includes the time portion so equals means the value has to equal exactly. These queries give you the span of a day.
If you're using Oracle, you can use the + and - operators to add a number of days to a date.
http://psoug.org/reference/date_func.html
Example:
SELECT SYSDATE + 1 FROM dual;
Will yield tomorrow's date.
If you're not using Oracle, please tell use what you ARE using so we can give better answers. This sort of thing depends on the database you are using. It will NOT be the same across different databases.
Depends of the DateTime Functions available on the RDBMS
For Mysql you can try:
mysql> SELECT DATE_ADD('1997-12-31',
-> INTERVAL 1 DAY);
mysql> SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
-> '1997-12-02'
If youre using MSSQL, you're looking for DateAdd() I'm a little fuzzy on the syntax, but its something like:
Select * //not really, call out your columns
From [table]
Where date = DateAdd(dd, -1, "2010-07-29",)
Edit: This syntax should be correct: it has been updated in response to a comment.
I may have the specific parameters in the wrong order, but that should get you there.
In PL SQL : select sysdate+1 from dual;