I want to select rows according to the month of a date or timestamp column like this:
SELECT id, name, birthday
FROM employee.person
WHERE Month(birthday) > 10;
But I only get error messages in PostgreSQL.
How can this be done?
You can use EXTRACT function, like this:
SELECT id, name, birthday FROM employee.person
WHERE EXTRACT(MONTH FROM birthday) > 10;
Your problem comes from the fact that there is no such thing as Month function in PostgreSQL. Check online documentation here to see what you can get instead. Extract should be enough.
If you want you can also extract the month name using the following function.
SELECT TO_CHAR(DATE(REPORT_DATE), 'Month') FROM TABLE_NAME
Related
SELECT SUM(Total_A ) FROM Materials_List
This is the snippet of code that I have.
I need it to calculate by month and display by month using SQL.
I also would like it to be a code I can use for any month in the year not just one month at a time.
You seem to be looking for simple aggregation:
select
year(materials_datetime) yr,
month(materials_datetime) mn,
sum(total_a) sum_total_a
from materials_list
group by
year(materials_datetime),
month(materials_datetime)
order by yr, mn
This assumes that column materials_datetime contains the date/time that you want to use to aggregate the data.
I have a table with a date column where date is stored in this format:
2012-08-01 16:39:17.601455+0530
How do I group or group_and_count on this column by month?
Your biggest problem is that SQLite won't directly recognize your dates as dates.
CREATE TABLE YOURTABLE (DateColumn date);
INSERT INTO "YOURTABLE" VALUES('2012-01-01');
INSERT INTO "YOURTABLE" VALUES('2012-08-01 16:39:17.601455+0530');
If you try to use strftime() to get the month . . .
sqlite> select strftime('%m', DateColumn) from yourtable;
01
. . . it picks up the month from the first row, but not from the second.
If you can reformat your existing data as valid timestamps (as far a SQLite is concerned), you can use this relatively simple query to group by year and month. (You almost certainly don't want to group by month alone.)
select strftime('%Y-%m', DateColumn) yr_mon, count(*) num_dates
from yourtable
group by yr_mon;
If you can't do that, you'll need to do some string parsing. Here's the simplest expression of this idea.
select substr(DateColumn, 1, 7) yr_mon, count(*) num_dates
from yourtable
group by yr_mon;
But that might not quite work for you. Since you have timezone information, it's sure to change the month for some values. To get a fully general solution, I think you'll need to correct for timezone, extract the year and month, and so on. The simpler approach would be to look hard at this data, declare "I'm not interested in accounting for those edge cases", and use the simpler query immediately above.
It took me a while to find the correct expression using Sequel. What I did was this:
Assuming a table like:
CREATE TABLE acct (date_time datetime, reward integer)
Then you can access the aggregated data as follows:
ds = DS[:acct]
ds.select_group(Sequel.function(:strftime, '%Y-%m', :date_time))
.select_append{sum(:reward)}.each do |row|
p row
end
I'm working with a large transaction data set and would like to group a count of individual customer transactions by month. I am unable to use the timestamp function in the GROUP BY and return the following error:
BAD_QUERY (expression STRFTIME_UTC_USEC([DATESTART], '%b') in GROUP BY is invalid)
Is there a simple workaround to achieve this or should I build a calendar table (which may be the simplest option)?
You have to use an alias:
SELECT STRFTIME_UTC_USEC(DATESTART, '%b') as month, COUNT(TRANSACTION)
FROM datasetId.tableId
GROUP BY month
#Charles is correct but as an aside you can also group by column number.
SELECT STRFTIME_UTC_USEC(DATESTART, '%b') as month, COUNT(TRANSACTION) as count
FROM [datasetId.tableId]
GROUP BY 1
ORDER BY 2 DESC
I want to select a date from oracle table formatted like select (to_char(req_date,'MM/YYYY')) but I also want to order the result set on this date format.
I want them to be ordered like dates not strings.
Like this
09/2009
10/2009
11/2009
12/2009
01/2010
02/2010
03/2010
04/2010
05/2010
06/2010
07/2010
08/2010
09/2010
10/2010
11/2010
12/2010
Not like
01/2010
02/2010
03/2010
04/2010
05/2010
06/2010
07/2010
08/2010
09/2009
09/2010
10/2009
10/2010
11/2009
11/2010
12/2009
12/2010
Any way to do this in sql?
Full SQL is:
SELECT (to_char(req_date,'MM/YYYY')) as monthYear, count(req_id) as count
FROM REQUISITION_CURRENT t
GROUP BY to_char(req_date,'MM/YYYY')
Thanks
Try this. It works and it's efficient, but looks a little messy.
select to_char(trunc(req_date, 'MM'),'MM/YYYY') as monthYear
,count(req_id) as count
from requisition_current
group
by trunc(req_date, 'MM')
order
by trunc(req_date, 'MM');
Try this
select monthyear,yr,month,count(req_id)
from
(
SELECT (to_char(req_date,'MM/YYYY')) as monthYear, to_char(req_date,'YYYY') yr, to_char(req_date,'mm') month, req_id
FROM REQUISITION_CURRENT t
) x
GROUP BY monthyear,yr,month
order by yr, month
Please try
Select req_date, (to_char(req_date,'MM/YYYY')) from MY_TABLE order by req_date
You are free to add additional sort fields, even if they are the same field.
Just use order by req_date instead of order by to_char(req_date,'MM/YYYY').
Try
SELECT ...
ORDER BY MIN(req_date)
That'll get around Oracle's rules about what can be selected after a GROUP BY.
I am considerably late to the party, but the most intuitive way I've found to achieve this is the following:
SELECT DISTINCT
to_char(req_date,'MM/YYYY') as monthYear,
count(req_id) as count
FROM
REQUISITION_CURRENT t
GROUP BY
to_char(req_date,'MM/YYYY')
ORDER BY
to_date(monthYear,'MM/YYYY')
It's may not the most computationally efficient method since it converts the date to a character and then back to a date, but that is precisely what you are asking a query like this to do. It also saves you from adding support columns or nesting subqueries.
How would I go about doing a query that returns results of all rows that contain dates for current year and month at the time of query.
Timestamps for each row are formated as such: yyyy-mm-dd
I know it probably has something to do with the date function and that I must somehow set a special parameter to make it spit out like such: yyyy-mm-%%.
Setting days to be wild card character would do the trick but I can't seem to figure it out how to do it.
Here is a link to for quick reference to date-time functions in mysql:
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
Thanks
I think EXTRACT is the function you are looking for:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM timestamp_field) = EXTRACT(YEAR_MONTH FROM NOW())
you could extract the year and month using a function, but that will not be able to use an index.
if you want scalable performance, you need to do this:
SELECT *
FROM myTable
WHERE some_date_column BETWEEN '2009-01-01' AND '2009-01-31'
select * from someTable where year(myDt) = 2009 and month(myDt) = 9 and day(myDt) = 12