Find rows with same ID and have a particular set of names - sql

Question

EDIT:
I have a table with 3 rows like so.
ID NAME REV
1 A 0
1 B 0
1 C 0
2 A 1
2 B 0
2 C 0
3 A 1
3 B 1
I want to find the ID wich has a particular set of Names and the REV is same
example:
Edit2: GBN's solution would have worked perfectly, but since i do not have the access to create new tables. The added constraint is that no new tables can be created.
if input = A,B then output is 3
if input = A ,B,C then output is 1 and not 1,2 since the rev level differs in 2.

Answer 1

The simplest way is to compare a COUNT per ID with the number of elements in your list:
SELECT
ID
FROM
MyTable
WHERE
NAME IN ('A', 'B', 'C')
GROUP BY
ID
HAVING
COUNT(*) = 3;
Note: ORDER BY isn't needed and goes after the HAVING if needed
Edit, with question update. In MySQL, it's easier to use a separate table for search terms
DROP TABLE IF EXISTS gbn;
CREATE TABLE gbn (ID INT, `name` VARCHAR(100), REV INT);
INSERT gbn VALUES (1, 'A', 0);
INSERT gbn VALUES (1, 'B', 0);
INSERT gbn VALUES (1, 'C', 0);
INSERT gbn VALUES (2, 'A', 1);
INSERT gbn VALUES (2, 'B', 0);
INSERT gbn VALUES (2, 'C', 0);
INSERT gbn VALUES (3, 'A', 0);
INSERT gbn VALUES (3, 'B', 0);
DROP TABLE IF EXISTS gbn1;
CREATE TABLE gbn1 ( `name` VARCHAR(100));
INSERT gbn1 VALUES ('A');
INSERT gbn1 VALUES ('B');
SELECT
gbn.ID
FROM
gbn
LEFT JOIN
gbn1 ON gbn.`name` = gbn1.`name`
GROUP BY
gbn.ID
HAVING
COUNT(*) = (SELECT COUNT(*) FROM gbn1)
AND MIN(gbn.REV) = MAX(gbn.REV);
INSERT gbn1 VALUES ('C');
SELECT
gbn.ID
FROM
gbn
LEFT JOIN
gbn1 ON gbn.`name` = gbn1.`name`
GROUP BY
gbn.ID
HAVING
COUNT(*) = (SELECT COUNT(*) FROM gbn1)
AND MIN(gbn.REV) = MAX(gbn.REV);
Edit 2, without extra table, use a derived (inline) table:
SELECT
gbn.ID
FROM
gbn
LEFT JOIN
(SELECT 'A' AS `name`
UNION ALL SELECT 'B'
UNION ALL SELECT 'C'
) gbn1 ON gbn.`name` = gbn1.`name`
GROUP BY
gbn.ID
HAVING
COUNT(*) = 3 -- matches number of elements in gbn1 derived table
AND MIN(gbn.REV) = MAX(gbn.REV);

Answer 2

Similar to gbn, but allowing for the possibility of duplicate ID/Name combinations:
SELECT ID
FROM MyTable
WHERE NAME IN ('A', 'B', 'C')
GROUP BY ID
HAVING COUNT(DISTINCT NAME) = 3;

Answer 3

OKAY!... I solved my problem ! I modified GBN's logic to do it without a search table using the IN clause
1 flaw with doing MAX(rev) = MIN(REV) is: if i have a data like so .
ID NAME REV
1 A 0
1 B 1
1 A 1
then when I use a query like
Select ID from TABLE
where NAME in {A,B}
groupby ID
having count(*) = 2
and MIN(REV) = MAX(REV)
it will not show me the ID 1 as the min and max are different and the count is 3.
So i simply add another column to the groupby
so the final query is
Select ID from TABLE
where NAME in {A,B}
groupby ID,REV
having count(*) = 2
and MIN(REV) = MAX(REV)
Thanks,to all that helped. !