I would like to hear if anyone can tell me a simple syntax that accomplishes the same as the following (with the same flexibility):
SELECT C.CompanyName,
(SELECT Count(*) FROM Employees WHERE CompanyId = C.Id) as EmployeeCount
FROM Company C
Now, what's important is that the inner SELECT giving the EmployeeCount is:
An independent SELECT statement
This means that it should work with any existing SELECT, even if it already contains joins etc.
Can use values from the parent SELECT
I know that this scenario can be easily accomplished in other ways, but the above is a simplified example to explain the challenge. My real scenario is a complex SELECT statement where I do not want to complicate it by adding more joins. Performance is no issue.
Using INNER JOIN:
SELECT C.CompanyName, Count(E.*) as EmployeeCount
FROM Company C
INNER JOIN Employees E on E.CompanyId = C.Id
Using NESTED JOIN:
SELECT C.CompanyName, Count(E.1) as EmployeeCount
FROM Company C, Employess E
WHERE E.CompanyId = C.Id
If you want to use the same syntax, at least put this:
SELECT C.CompanyName,
(SELECT Count(1) FROM Employees WHERE CompanyId = C.Id) as EmployeeCount
FROM Company C
If you need all the data to be shown, even the ones the companies without any Employees, you can use a LEFT OUTER JOIN:
SELECT C.CompanyName, Count(E.*) as EmployeeCount
FROM Company C
LEFT OUTER JOIN Employees E on E.CompanyId = C.Id
Try using a derived table, which statifies both your conditions.
An independent SELECT statement.
a. Using a Derived Table allows you to keep your independent Select Statement
Can use values from the parent SELECT.
a. As an Inner join you can still use values from the parent select.
SELECT
C.CompanyName,
EC.EmployeeCount
FROM Company C
INNER JOIN (SELECT
Count(*) AS EmployeeCount
FROM Employees ) EC
ON WHERE EC.CompanyId = C.Id
If your inner select is complicated, then why not make a view of it:
CREATE VIEW EmpSelect AS
SELECT CompanyId, whatever FROM Employees;
Then
SELECT
C.CompanyName, Count(*) AS EmpCount
FROM
Company C
LEFT JOIN EmpSelect E
ON C.Id = E.CompanyId
GROUP BY
C.CompanyName;
Related
Hello I want to join these two queries together. I have tried many combinations of writing and rewriting the code and I have become stuck.
The two queries I want to join are:
SELECT a.lastname, a.firstname
FROM athletes a,
(SELECT athlete#, COUNT(event#)
FROM results
GROUP BY athlete#
HAVING COUNT(event#) > 1 ) b
WHERE a.athlete# = b.athlete#
ORDER BY a.lastname;
and
SELECT sc.datetime, e.name
FROM event e JOIN schedule sc USING (event#);
The first query does a count on the athletes having more than one event and returns the correct number of 19, when I try to add the 2nd query into the first I end up pulling most of the data from the results table.
If you want events for athletes have competed more than once, which seems like a reasonable interpretation, then:
select a.lastname, a.firstname, e.name, sc.datetime
from athletes a join
(select r.*, count(*) over (partition by athelete#) as cnt
from results r
) r
on a.athlete# = r.athelete# and cnt > 1 join
event e
on r.event# = e.event# join
schedule s
on e.event# = s.event#;
SELECT a.lastname, a.firstname, sc.datetime, e.name
FROM athletes a
inner join (SELECT athlete#, COUNT(event#)
FROM results
GROUP BY athlete#
HAVING COUNT(event#) > 1 ) b on a.athlete# = b.athlete#
inner join results r on r.athlete# =b.athlete#
inner join event e on e.event# = r.event#
inner join schedule sc on sc.event# = e.event#
ORDER BY a.lastname;
I have 4 tables, in that I want to fetch records from all 4 and aggregate the values
I have these tables
I am expecting this output
but getting this output as a Cartesian product
It is multiplying the expenses and allocation
Here is my query
select
a.NAME, b.P_NAME,
sum(a.DURATION) DURATION,
sum(b.[EXP]) EXPEN
from
(select
e.ID, a.P_ID, e.NAME, a.DURATION DURATION
from
EMPLOYEE e
inner join
ALLOCATION a ON e.ID = a.E_ID) a
inner join
(select
p.P_ID, e.E_ID, p.P_NAME, e.amt [EXP]
from
PROJECT p
inner join
EXPENSES e ON p.P_ID = e.P_ID) b ON a.ID = b.E_ID
and a.P_ID = b.P_ID
group by
a.NAME, b.P_NAME
Can anyone suggest something about this.
The following should work:
SELECT e.Name,p.Name,COALESCE(d.Duration,0),COALESCE(exp.Expen,0)
FROM
Employee e
CROSS JOIN
Project p
LEFT JOIN
(SELECT E_ID,P_ID,SUM(Duration) as Duration FROM Allocation
GROUP BY E_ID,P_ID) d
ON
e.E_ID = d.E_ID and
p.P_ID = d.P_ID
LEFT JOIN
(SELECT E_ID,P_ID,SUM(AMT) as Expen FROM Expenses
GROUP BY E_ID,P_ID) exp
ON
e.E_ID = exp.E_ID and
p.P_ID = exp.P_ID
WHERE
d.E_ID is not null or
exp.E_ID is not null
I've tried to write a query that will produce results where e.g. there are rows in Expenses but no rows in Allocations (or vice versa) for some particular E_ID,P_ID combination.
Use left join in select query by passing common id for all table
Hi I got the answer what I want from some modification in the query
The above query is also working like a charm and have done some modification to the original query and got the answer
Just have to group by the inner queries and then join the queries it will then not showing Cartesian product
Here is the updated one
select a.NAME,b.P_NAME,sum(a.DURATION) DURATION,sum(b.[EXP]) EXPEN from
(select e.ID,a.P_ID, e.NAME,sum(a.DURATION) DURATION from EMPLOYEE e inner join ALLOCATION a
ON e.ID=a.E_ID group by e.ID,e.NAME,a.P_ID) a
inner join
(select p.P_ID,e.E_ID, p.P_NAME,sum(e.amt) [EXP] from PROJECT p inner join EXPENSES e
ON p.P_ID=e.P_ID group by p.P_ID,p.P_NAME,e.E_ID) b
ON a.ID=b.e_ID and a.P_ID=b.P_ID group by a.NAME,b.P_NAME
Showing the correct output
I am having trouble trying to solve this problem, I would like to only add a salary up if the
employee's id is distinct. I thought I could do this using the decode() function but I am having trouble defining an expression suitable. I was aiming for something like
SUM(DECODE(S.ID,IS DISTINCT,S.SALARY))
But this isn't going to work!
So the full query looks like
SELECT B.ID, SUM(S.SALARY), COUNT(DISTINCT S.ID), COUNT(DISTINCT RM.MEMBER_ID)
FROM BRANCH B
INNER JOIN STAFF S ON S.BRANCH_ID = B.ID
INNER JOIN RECRUIT_MEMBER RM ON RM.BRANCH_ID = B.ID
GROUP BY B.ID;
But the problem is with SUM(S.SALARY) it's adding up salaries from duplicate ID's
I don't know about DECODE, but this should work:
SELECT
SUM(S.SALARY)
FROM <table> S
WHERE NOT EXISTS (
SELECT ID FROM <table> WHERE ID=S.ID GROUP BY ID HAVING COUNT(*)>1
)
Perhaps something like this...
SELECT E.ID, SUM(E.Salary)
FROM Employers E
WHERE E.ID IN (SELECT DISTINCT E2.ID FROM Employers E2)
GROUP BY E.ID
If not, perhaps you could post some sample data so that I can understand better
The joins are introducing duplicate rows. One way to fix this is by adding a row number to sequentially identify different ids. The real way would be to fix the joins so this doesn't happen, but here is the first way:
SELECT B.ID, SUM(CASE WHEN SEQNUM = 1 THEN S.SALARY END),
COUNT(DISTINCT S.ID), COUNT(DISTINCT RM.MEMBER_ID)
FROM (SELECT B.ID, S.ID, RM.MEMBER_ID,
ROW_NUMBER() OVER (PARTITION BY S.ID ORDER BY S.ID) as seqnum
FROM BRANCH B
INNER JOIN STAFF S ON S.BRANCH_ID = B.ID
INNER JOIN RECRUIT_MEMBER RM ON RM.BRANCH_ID = B.ID
) t
GROUP BY B.ID
You can create a virtual table with only one salary per ID like this...
SELECT
...whatever fields you've already got...
s.Salary
FROM
...whatever tables and joins you've already got...
LEFT JOIN (SELECT ID, MAX(SALARY) as "Salary" FROM SALARY_TABLE GROUP BY ID) s
ON whatevertable.ID = s.ID
I seem to be running into a query syntax error but cannot seem to isolate it. I am using MS Access and when I run the queries I get a syntax error in FROM clause.
I have two tables and they are in a one to many relationship:
Table 1 called (customer) with the following fields:
ID
FirstName
Table 2 called (tblservice) with the following fields:
serviceID
Timing
Total
customerID <-Foreign Key
First Query:
select c.id, c.firstname, avg(s.Total) / (select count(id) from customer) as LifetimeValue
from tblservice as s join customer as c on s.id = c.id
group by s.id
Second Query(30 day span):
select c.id, c.firstname, avg(s.Total) / (select count(id) from customer) as LifetimeValue
from tblservice as s join customer as c on s.id = c.id
where (s.Timing)>=DateAdd("d",-30,Date())
group by s.id
Try this:
select c.id, c.firstname, avg(s.Total) / count(c.id) as LifetimeValue
from tblservice as s inner join customer as c on s.id = c.id
group by c.id, c.firstname
and
select c.id, c.firstname, avg(s.Total) / count(c.id) as LifetimeValue
from tblservice as s inner join customer as c on s.id = c.id
where (s.Timing)>=DateAdd("d",-30,Date())
group by c.id, c.firstname
You cannot select c.id and c.firstname unless you group by them. And you can use count(c.id) since you are already grouping by c.id. I have not used SQL in MS Access though. So I am not 100% sure. Try it out.
MS Access may require you to use INNER JOIN instead of just JOIN.
I'm trying to do something like:
SELECT c.id, c.name, COUNT(orders.id)
FROM customers c
JOIN orders o ON o.customerId = c.id
However, SQL will not allow the COUNT function. The error given at execution is that c.Id is not valid in the select list because it isn't in the group by clause or isn't aggregated.
I think I know the problem, COUNT just counts all the rows in the orders table. How can I make a count for each customer?
EDIT
Full query, but it's in dutch... This is what I tried:
select k.ID,
Naam,
Voornaam,
Adres,
Postcode,
Gemeente,
Land,
Emailadres,
Telefoonnummer,
count(*) over (partition by k.id) as 'Aantal bestellingen',
Kredietbedrag,
Gebruikersnaam,
k.LeverAdres,
k.LeverPostnummer,
k.LeverGemeente,
k.LeverLand
from klanten k
join bestellingen on bestellingen.klantId = k.id
No errors but no results either..
When using an aggregate function like that, you need to group by any columns that aren't aggregates:
SELECT c.id, c.name, COUNT(orders.id)
FROM customers c
JOIN orders o ON o.customerId = c.id
GROUP BY c.id, c.name
If you really want to be able to select all of the columns in Customers without specifying the names (please read this blog post in full for reasons to avoid this, and easy workarounds), then you can do this lazy shorthand instead:
;WITH o AS
(
SELECT CustomerID, CustomerCount = COUNT(*)
FROM dbo.Orders GROUP BY CustomerID
)
SELECT c.*, o.OrderCount
FROM dbo.Customers AS c
INNER JOIN dbo.Orders AS o
ON c.id = o.CustomerID;
EDIT for your real query
SELECT
k.ID,
k.Naam,
k.Voornaam,
k.Adres,
k.Postcode,
k.Gemeente,
k.Land,
k.Emailadres,
k.Telefoonnummer,
[Aantal bestellingen] = o.klantCount,
k.Kredietbedrag,
k.Gebruikersnaam,
k.LeverAdres,
k.LeverPostnummer,
k.LeverGemeente,
k.LeverLand
FROM klanten AS k
INNER JOIN
(
SELECT klantId, klanCount = COUNT(*)
FROM dbo.bestellingen
GROUP BY klantId
) AS o
ON k.id = o.klantId;
I think this solution is much cleaner than grouping by all of the columns. Grouping on the orders table first and then joining once to each customer row is likely to be much more efficient than joining first and then grouping.
The following will count the orders per customer without the need to group the overall query by customer.id. But this also means that for customers with more than one order, that count will repeated for each order.
SELECT c.id, c.name, COUNT(orders.id) over (partition by c.id)
FROM customers c
JOIN orders ON o.customerId = c.id