I am using PHP Yii Framework with MongoDB(yiimongodbsuite). I have created a Model which extends from EMongoDocument.
<?php
class MyModel extends EMongoDocument
{
public $attr1;
public $attr2;
// rules, custom validations and other functions....
public function setAttributes($values, $safeOnly=true)
{
if(!is_array($values))
return;
if($this->hasEmbeddedDocuments())
{
$attributes=array_flip($safeOnly ? $this->getSafeAttributeNames() : $this->attributeNames());
foreach($this->embeddedDocuments() as $fieldName => $className)
if(isset($values[$fieldName]) && isset($attributes[$fieldName]))
{
$this->$fieldName->setAttributes($values[$fieldName], $safeOnly);
unset($values[$fieldName]);
}
}
parent::setAttributes($values, $safeOnly);
}
}
In Controller,
$dataModel = new MyModel();
$dataModel->setAttributes($_POST['MyModel']);
if($dataModel->validate()){
$dataModel->save();
}
the above code is not setting the attribute value.
Please let me know if there is any mistake.
You need to make sure that the 'safe' validation rules is used on each level.
To understand more read this http://www.yiiframework.com/wiki/161/understanding-safe-validation-rules/
Try to determine which valdation errors you have:
if(!$model->validate()) {
die( print_r($model->getErrors()) );
}
Related
How to load a template file from my admin controller in custom module in prestashop 1.6
if (!defined('_PS_VERSION_')) exit;
class QueryAllTrxController extends ModuleAdminController
{
public $module;
public function __construct()
{
parent::__construct();
}
public function initContent()
{
parent::initContent();
$this->setTemplate('display.tpl');
//$this->setTemplate(_PS_THEME_DIR_.'mypage.tpl');
}
}
I had the same problem and it took forever to figure out.
I ended up spotting the solution in this video : https://www.youtube.com/watch?v=CdnJpLqqvcM
Any this is how I got it to work :
1 - Create the controller in ModuleName/controllers/AdminMyControllerNameController.php
class AdminMyControllerNameController extends ModuleAdminController
{
public function __construct()
{
$this->display = 'view';
$this->meta_title = $this->l('metatitle');
$this->toolbar_title = $this->l('tollbartitle');
parent::__construct();
}
public function initContent()
{
$this->show_toolbar = true;
$this->display = 'view';
$this->meta_title = $this->l('META TITLE');
parent::initContent();
$this->setTemplate('templatename.tpl');
}
public function initToolBarTitle()
{
$this->toolbar_title = $this->l('TOOLBAR TITLE??');
}
public function initToolBar()
{
return true;
}
}
2 - Create the template file in ModuleName/views/admin/my_controller_name/template.tpl
You have to create a directory in the views/admin folder using the name of your controller written in snake case.
Anyway I hope this will help.
WORKING CODE HERE
Background:
You want to add a custom admin page with a custom module controller. But you cannot customize template because you're stuck with this error message:
Fatal error: Uncaught --> Smarty: Unable to load template file '/var/www/html/admin-dev/themes/default/template/catalog/index.tpl' <-- thrown in /var/www/html/tools/smarty/sysplugins/smarty_internal_templatebase.php on line 129
Your current source code is:
class AdminYourModuleNameProductsController extends ModuleAdminController {
public function initContent() {
parent::initContent();
// enable these lines if you're stuck with damn stupid blank page with just 500 error
// ini_set('display_errors', '1');
// ini_set('display_startup_errors', '1');
// error_reporting(E_ALL);
$this->setTemplate('products/index.tpl');
}
}
And you don't know what to do because PrestaShop dev doc is the worst document in the history of ecommerce platform developer document and moreover its forum is full of chitchats and junks.
Solution
Place index.tpl at
{%PRESTA_ROOT%}/modules/{%YOUR MODULE DIR%}/views/templates/admin/{% snake case version of controller %}/products/index.tpl
For example, if your module name is yourmodulename and the controller name is AdminYourModuleNameProductsController (as in the example), the correct path is:
{%PRESTA_ROOT%}/modules/yourmodulename/views/templates/admin/your_module_name_products/products/index.tpl
If the error still persists:
Check this line:
{%PRESTA_ROOT%}/classes/controller/ModuleAdminController.php
public function createTemplate($tpl_name)
{
if (file_exists(_PS_THEME_DIR_.'modules/'.$this->module->name.'/views/templates/admin/'.$tpl_name) && $this->viewAccess()) {
// echo the following line and exit
return $this->context->smarty->createTemplate(_PS_THEME_DIR_.'modules/'.$this->module->name.'/views/templates/admin/'.$tpl_name, $this->context->smarty);
} elseif (file_exists($this->getTemplatePath().$this->override_folder.$tpl_name) && $this->viewAccess()) {
// echo the following line and exit
return $this->context->smarty->createTemplate($this->getTemplatePath().$this->override_folder.$tpl_name, $this->context->smarty);
}
// the error occurs because php get reach to the following line:
return parent::createTemplate($tpl_name);
}
Do as I commented and you can get the correct file path. Make sure the file exists in the path.
My PrestaShop version is 1.6.1.24
The code $this->setTemplate('display.tpl'); is loading a template file modules/your-custom-module/views/templates/admin/display.tpl or modules/your-custom-module/display.tpl.
The classname must be named that way: AdminQueryAllTrxController
you can put display.tpl in :
modules\module_name\views\templates\admin\classe_name(QueryAllTrx)
and use :$this->setTemplate('display.tpl'); in your AdminQueryAllTrxController
First of all add controller to your module:
modules\module_name\controllers\admin\SomeNameController.php
and extend it by ModuleAdminController, you need at least two methods for it to work properly __construct and initContent
put the following code to the later method:
$this->content .= $this->context->smarty->fetch($this->pathToTpl);
$this->context->smarty->assign(array(
'content' => $this->content,
));
You could replace $this->pathToTpl with any path which is pointed to your tpl file, I'm prefer to create the path dynamically. You can see a simple example here:
class SomeNameController extends ModuleAdminController{
var $pathToTpl;
public function __construct()
{
$this->bootstrap = true;
$this->context = Context::getContext();
$this->pathToTpl = _PS_MODULE_DIR_ .
$this->module->name . // put the name of module
'/views/templates/admin' .
'/' .
'templateName.tpl';
parent::__construct();
}
public function initContent()
{
parent::initContent();
$this->content .= $this->context->smarty->fetch($this->pathToTpl);
$this->context->smarty->assign(array(
'content' => $this->content,
));
}
}
finally you need to place templateName.tpl in the path you wanted to be:
modules\module_name\views\templates\admin\templateName.tpl
I just started with learning how to test within Laravel. I came across some problems though..
I'm testing my controller and want to check if a View has a variable assigned.
My controller code:
class PagesController extends \BaseController {
protected $post;
public function __construct(Post $post) {
$this->post = $post;
}
public function index() {
$posts = $this->post->all();
return View::make('hello', ['posts' => $posts]);
}
}
And my view contains a foreach loop to display all posts:
#foreach ($posts as $post)
{{post->id}}
#endforeach
Last but not least my test file:
class PostControllerTest extends TestCase {
public function __construct()
{
// We have no interest in testing Eloquent
$this->mock = Mockery::mock('Eloquent', 'Post');
}
public function tearDown()
{
Mockery::close();
}
public function testIndex() {
$this->mock->shouldReceive('all')->once()->andReturn('foo');
$this->app->instance('Post', $this->mock);
$this->call('GET', '/');
$this->assertViewHas('posts');
}
}
Now comes the problem, when I run "phpunit" the following error appears:
ErrorException: Invalid argument supplied for foreach()
Any ideas why phpunit returns this error?
Your problem is here:
$this->mock->shouldReceive('all')->once()->andReturn('foo');
$this->post->all() (which is what you're mocking) should return an array, and that's what your view expects. You're returning a string.
$this->mock->shouldReceive('all')->once()->andReturn(array('foo'));
should take care of the error you have, though you'll then get an error of the "Getting property of non-object" type.
You could do this:
$mockPost = new stdClass();
$mockPost->id = 1;
$this->mock->shouldReceive('all')->once()->andReturn(array($mockpost));
You should mock the view as well:
public function testIndex() {
$this->mock->shouldReceive('all')->once()->andReturn('foo');
$this->app->instance('Post', $this->mock);
View::shouldReceive('make')->with('hello', array('posts', 'foo'))->once();
$this->call('GET', '/');
}
I have two project in yii framework and I want to use both project using SimpleSAMLphp with SSO. The condition, I need is if I login from the first project, i want access to the second project.
Thank you in advance.
First you load the SAML library by temporarily disabling the Yii autoloader. This is just to let you use the SAML classes and methods:
<?php
class YiiSAML extends CComponent {
private $_yiiSAML = null;
static private function pre() {
require_once (Yii::app()->params['simpleSAML'] . '/lib/_autoload.php');
// temporary disable Yii autoloader
spl_autoload_unregister(array(
'YiiBase',
'autoload'
));
}
static private function post() {
// enable Yii autoloader
spl_autoload_register(array(
'YiiBase',
'autoload'
));
}
public function __construct() {
self::pre();
//We select our authentication source:
$this->_yiiSAML = new SimpleSAML_Auth_Simple(Yii::app()->params['authSource']);
self::post();
}
static public function loggedOut($param, $stage) {
self::pre();
$state = SimpleSAML_Auth_State::loadState($param, $stage);
self::post();
if (isset($state['saml:sp:LogoutStatus'])) {
$ls = $state['saml:sp:LogoutStatus']; /* Only for SAML SP */
} else return true;
return $ls['Code'] === 'urn:oasis:names:tc:SAML:2.0:status:Success' && !isset($ls['SubCode']);
}
public function __call($method, $args) {
$params = (is_array($args) and !empty($args)) ? $args[0] : $args;
if (method_exists($this->_yiiSAML, $method)) return $this->_yiiSAML->$method($params);
else throw new YiiSAMLException(Yii::t('app', 'The method {method} does not exist in the SAML class', array(
'{method}' => $method
)));
}
}
class YiiSAMLException extends CException {
}
Then you define a filter extending the CFilter Yii class:
<?php
Yii::import('lib.YiiSAML');
class SAMLControl extends CFilter {
protected function preFilter($filterChain) {
$msg = Yii::t('yii', 'You are not authorized to perform this action.');
$saml = new YiiSAML();
if (Yii::app()->user->isGuest) {
Yii::app()->user->loginRequired();
return false;
} else {
$saml_attributes = $saml->getAttributes();
if (!$saml->isAuthenticated() or Yii::app()->user->id != $saml_attributes['User.id'][0]) {
Yii::app()->user->logout();
Yii::app()->user->loginRequired();
return false;
}
return true;
}
}
}
And finally, in the controllers you are interested to restrict, you override the filters() method:
public function filters() {
return array(
array(
'lib.SAMLControl'
) , // perform access control for CRUD operations
...
);
}
Hope it helps.
It can be done simply using "vendors" directory.
Download PHP Library from https://simplesamlphp.org/
Implement it in Yii Framework as a vendor library. (http://www.yiiframework.com/doc/guide/1.1/en/extension.integration)
Good Luck :)
I came across an Yii Extension for SimpleSAMLphp in github
https://github.com/asasmoyo/yii-simplesamlphp
You can load the simplesamlphp as a vendor library and then specify the autoload file in the extension.
Apart from the extension you can copy all the necessary configs and metadatas into the application and configure SimpleSAML Configuration to load the configurations from your directory, so you can keep the vendor package untouched for future updates.
I am working on a project which includes a REST API component. I have a controller dedicated to handling all of the REST API calls.
Is there any way to catch all exceptions for that specific controller so that I can take a different action for those exceptions than the rest of the application's controllers?
IE: I'd like to respond with either an XML/JSON formatted API response that contains the exception message, rather than the default system view/stack trace (which isn't really useful in an API context). Would prefer not having to wrap every method call in the controller in its own try/catch.
Thanks for any advice in advance.
You can completely bypass Yii's default error displaying mechanism by registering onError and onException event listeners.
Example:
class ApiController extends CController
{
public function init()
{
parent::init();
Yii::app()->attachEventHandler('onError',array($this,'handleError'));
Yii::app()->attachEventHandler('onException',array($this,'handleError'));
}
public function handleError(CEvent $event)
{
if ($event instanceof CExceptionEvent)
{
// handle exception
// ...
}
elseif($event instanceof CErrorEvent)
{
// handle error
// ...
}
$event->handled = TRUE;
}
// ...
}
I wasn't able to attach events in controller, and I did it by redefinition CWebApplication class:
class WebApplication extends CWebApplication
{
protected function init()
{
parent::init();
Yii::app()->attachEventHandler('onError',array($this, 'handleApiError'));
Yii::app()->attachEventHandler('onException',array($this, 'handleApiError'));
}
/**
* Error handler
* #param CEvent $event
*/
public function handleApiError(CEvent $event)
{
$statusCode = 500;
if($event instanceof CExceptionEvent)
{
$statusCode = $event->exception->statusCode;
$body = array(
'code' => $event->exception->getCode(),
'message' => $event->exception->getMessage(),
'file' => YII_DEBUG ? $event->exception->getFile() : '*',
'line' => YII_DEBUG ? $event->exception->getLine() : '*'
);
}
else
{
$body = array(
'code' => $event->code,
'message' => $event->message,
'file' => YII_DEBUG ? $event->file : '*',
'line' => YII_DEBUG ? $event->line : '*'
);
}
$event->handled = true;
ApiHelper::instance()->sendResponse($statusCode, $body);
}
}
In index.php:
require_once(dirname(__FILE__) . '/protected/components/WebApplication.php');
Yii::createApplication('WebApplication', $config)->run();
You can write your own actionError() function per controller. There are several ways of doing that described here
I'm using the following Base controller for an API, it's not stateless API, mind you, but it can serve just aswell.
class BaseJSONController extends CController{
public $data = array();
public $layout;
public function filters()
{
return array('mainLoop');
}
/**
* it all starts here
* #param unknown_type $filterChain
*/
public function filterMainLoop($filterChain){
$this->data['Success'] = true;
$this->data['ReturnMessage'] = "";
$this->data['ReturnCode'] = 0;
try{
$filterChain->run();
}catch (Exception $e){
$this->data['Success'] = false;
$this->data['ReturnMessage'] = $e->getMessage();
$this->data['ReturnCode'] = $e->getCode();
}
echo json_encode($this->data);
}
}
You could also catch dbException and email those, as they're somewhat critical and can show underlying problem in the code/db design.
Add this to your controller:
Yii::app()->setComponents(array(
'errorHandler'=>array(
'errorAction'=>'error/error'
)
));
I'm trying to write some loggin failure info in database from a custom authentication handler.
My problem is to gain access to the database since I don't know where the Doctrine object might be stored
Here's my code for now :
namespace MyApp\FrontBundle\Controller;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Request as Request;
use Symfony\Component\HttpFoundation\RedirectResponse as RedirectResponse;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Symfony\Component\Security\Http\Authentication as Auth;
use Symfony\Component\Security\Core\Exception\AuthenticationException as AuthException;
class SecurityHandler implements Auth\AuthenticationFailureHandlerInterface
{
public function onAuthenticationFailure(Request $request, AuthException $token)
{
try
{
$lastLoginFailure = new DateTime();
// get database object here
}
catch(\Exception $ex)
{
}
}
}
Any ideas ?
Turn your SecurityHandler into a service and then inject the doctrine entity manager into it.
http://symfony.com/doc/current/book/service_container.html
Start command php app/console container:debug.
Copy doctrine.orm.entity_manager and paste to your hadler constructor arguments like
[...., #doctrine.orm.entity_manager].
In hadler use Doctrine\ORM\EntityManager;
I think you should extends your class "SecurityHandler" with ContainerAware if you want to use service since your Security Handler is not a controller.
class SecurityHandler extend ContainerAware implements Auth\AuthenticationFailureHandlerInterface{
public function onAuthenticationFailure(Request $request, AuthException $token)
{
try
{
$lastLoginFailure = new DateTime();
// get database object here
$doctrine = $this->container->get('doctrine');
$repository = $doctrine->getRepository('*NAME OF REPO*');
}
catch(\Exception $ex)
{
}
}
}