I have 2 tables:
table1 contains (amount, date)
table2 contains (amount, revenue, date)
I need to:
sum table1.amount + table2.amount, sum table2.revenue
according to table1.date and table2.date
like:
select sum(table1.amount + table2.amount), sum(table2.revenue)
from table1,table2
where table1.date and table2.date = '2008-02%'
This will show the result for all year-month:
with table3 (amount, revenue, date) as
(
select amount, 0, date from table1
union all
select cost, revenue, date from table2
)
select year(date), month(date), sum(amount), sum(revenue)
from table3
group by year(date), month(date)
order by year(date), month(date);
SELECT SUM(amount), SUM(revenue)
FROM (
SELECT amount, 0 as revenue, theDate
FROM table1
UNION ALL
SELECT amount, revenue, theDate
FROM table2 ) AS DERIVED
WHERE (MONTH(DERIVED.theDate) = 2
AND YEAR(DERIVED.theDate) = 2008)
You could put the where clause in the UNION statement, which I probably would but this simplifies things for the example. If you have keys in the equation I'd do this differently with a full outer join or something like that but for your example this works.
If you want the date to show and view the sums for all the dates then the following would work:
SELECT SUM(amount), SUM(revenue), theDate
FROM (
SELECT amount, 0 as revenue, theDate
FROM table1
UNION ALL
SELECT amount, revenue, theDate
FROM table2 ) AS DERIVED
GROUP BY theDate
Hope that helps!
Related
How would I filter this SQL server database so only the green records are left aka the last recorded date every year for each Customer ID field.
If you want to get the rows, not only the date values, using ROW_NUMBER() is an option (you only need to use the appropriate PARTITON BY and ORDER BY clauses):
SELECT *
FROM (
SELECT
CustomerId,
[Date],
ROW_NUMBER() OVER (PARTITION BY CustomerId, YEAR[Date] ORDER BY [Date] DESC) AS Rn
FROM YourTable
) t
WHERE Rn = 1
To check the maximum date in the year, you can write a query to get for each year the date where not exists another (in the same year), as follow:
SELECT *
FROM yourtable t1
WHERE NOT EXISTS
(SELECT 1
FROM yourtable t2
WHERE t1.customerID = t2.customerID
AND t1.date > t2.date
AND DATEPART(YEAR, t1) = DATEPART(YEAR, t2))
If you have only two columns, then you can just use aggregation:
select customer_id, max(date)
from t
group by customer_id, year(date);
Say I added a Cost Difference column to the second table from Rishal (see the below link for this previous post), how would I also calculate and display that?
Using just the 1001 Account Number and adding the following amounts of ID1=$10, ID4=$33 and ID6=$50 to the first table, how would I display in Rishal's second table a result of $23 and $17 in addition to the other 3 columns that are already there?
I've used this code (from GarethD) and would like to insert my Cost Difference column within this...Thanks in advance,
SELECT ID,
AccountNumber,
Date,
NextDate,
DATEDIFF("D", Date, NextDate)
FROM ( SELECT ID,
AccountNumber,
Date,
( SELECT MIN(Date)
FROM YourTable T2
WHERE T2.Accountnumber = T1.AccountNumber
AND T2.Date > T1.Date
) AS NextDate
FROM YourTable T1
) AS T
Date Difference between consecutive rows
I would recommend using JOIN to bring in the entire next record:
SELECT T.*, DATEDIFF("D", t.Date, t.NextDate) as datediff,
TNext.Amount, (Tnext.Amount - T.Amount) as amountdiff
FROM (SELECT T1.*,
(SELECT MIN(Date)
FROM YourTable T2
WHERE T2.Accountnumber = T1.AccountNumber AND
T2.Date > T1.Date
) AS NextDate
FROM YourTable as T1
) AS T LEFT JOIN
YourTable as Tnext
ON t.Accountnumber = tnext.Accountnumber AND t.Date = tnext.Accountnumber;
I have 3 queries that counts for each company, number of rows during certain month, from 3 different tables, and returning the same columns :qty, month and company_name.
Instead of this I need to return 1 table with same 3 columns but qty must sum the value of all the 3 separated queries.
Can you suggest the best way to join or execute it in which I will not loose speed of execution.
Here is example of one of queries, the other 2 queries has exactly the same syntax, just instead T_CUSTSK, they use T_CUSTSK2 and T_CUSTSK3:
SELECT
COUNT(*) as qty,
DATEPART (MONTH, [start_date]) AS [month],
T_SYSCOM.company_name
FROM
T_CUSTSK
INNER JOIN
T_SYSCOM ON T_CUSTSK.company_id = T_SYSCOM.company_id
WHERE
DATEPART (MONTH, [start_date]) = 12
GROUP BY
DATEPART (MONTH, [start_date]), T_SYSCOM.company_name
ORDER BY
month, qty DESC
Union all will combine your queries.
You can then wrap your statement with another query that sums:
select sum(qty), month, company_name from (
Select count(*) as qty, datepart(month, [start_date]) as [month], T_SYSCOM.company_name
from T_CUSTSK
INNER JOIN T_SYSCOM
ON T_CUSTSK.company_id=T_SYSCOM.company_id
where datepart(month, [start_date])=12
group by datepart(month, [start_date]), T_SYSCOM.company_name
order by month, qty DESC
union all
<second query>
union all
<third query> )
group by month, company_name
Try this you could do UNION ALL of all the T_CUSTSKx tables in the subquery and join that result once with T_SYSCOM table.
I'm assuming the start_date is in T_CUSTSK table
Select count(*) as qty, datepart(month, [start_date]) as [month], T2.company_name
from (
SELECT company_id,start_date FROM T_CUSTSK
UNION ALL
SELECT company_id,start_date FROM T_CUSTSK2
UNION ALL
SELECT company_id,start_date FROM T_CUSTSK3
) T1
INNER JOIN #T_SYSCOM T2
ON T1.company_id=T2.company_id
where datepart(month, [start_date])=12
group by datepart(month, [start_date]), T2.company_name
order by month, qty DESC
kindly let me know if this works
I am trying to write a statement and just a bit puzzled what is the best way to put it together. So I am doing a UNION on a number of tables and then from there I want to produce as the output a count for the UserID within that day.
So I will have numerous tables union such as:
Order ID, USERID, DATE, Task Completed.
UNION
Order ID, USERID, DATE, Task Completed
etc
Above is layout of the table which will have 4 tables union together with same names.
Then statement output I want is for a count of USERID that occurred within the last 24 hours.
So output should be:
USERID--- COUNT OUTPUT-- DATE
I was attempting a WHERE statement but think the output is not what I am after exactly, just thinking if anyone can point me in the right direction and if there is alternative way compared to the union? Maybe a joint could be a better alternative, any help be appreciated.
I will eventually then put this into a SSRS report, so it gets updated daily.
You can try this:
select USERID, count(*) as [COUNT], cast(DATE as date) as [DATE]
from
(select USERID, DATE From SomeTable1
union all
select USERID, DATE From SomeTable2
....
) t
where DATE <= GETDATE() AND DATE >= DATEADD(hh, -24, GETDATE())
group by USERID, cast(DATE as date)
First, you should use union all rather than union. Second, you need to aggregate and use count distinct to get what you want:
So, the query you want is something like:
select count(distinct userid)
from ((select date, userid
from table1
where date >= '2015-05-26'
) union all
(select date, userid
from table2
where date >= '2015-05-26'
) union all
(select date, userid
from table3
where date >= '2015-05-26'
)
) du
Note that this hardcodes the date. In SQL Server, you would do something like:
date >= cast(getdate() - 1 as date)
And in MySQL
date >= date_sub(curdate(), interval 1 day)
EDIT:
I read the question as wanting a single day. It is easy enough to extend to all days:
select cast(date as date) as dte, count(distinct userid)
from ((select date, userid
from table1
) union all
(select date, userid
from table2
) union all
(select date, userid
from table3
)
) du
group by cast(date as date)
order by dte;
For even more readability, you could use a CTE:
;WITH cte_CTEName AS(
SELECT UserID, Date, [Task Completed] FROM Table1
UNION
SELECT UserID, Date, [Task Completed] FROM Table2
etc
)
SELECT COUNT(UserID) AS [Count] FROM cte_CTEName
WHERE Date <= GETDATE() AND Date >= DATEADD(hh, -24, GETDATE())
I think this is what you are trying to achieve...
Select
UserID,
Date,
Count(1)
from
(Select *
from table1
Union All
Select *
from table2
Union All
Select *
from table3
Union All
Select *
from table4
) a
Group by
Userid,
Date
SELECT date, id, sum(revenue)
FROM table
WHERE date between '2013-01-01' and '2013-01-08'
GROUP BY date, id
HAVING sum(revenue)>1000
Returns rows that have revenue>1000.
SELECT date, id, sum(revenue)
FROM table
WHERE date between '2013-01-01' and '2013-01-08'
AND id IN (SELECT id FROM table where date between '2013-01-01' and '2013-01-08' GROUP BY id HAVING sum(revenue)>1000)
GROUP BY date, id
Returns rows for id's whose total revenue over the date period is >1000 as desired. But this query is much slower. Any quicker way to do this?
Make sure you have indexes on the date and id columns, and try this variation:
select t.date, t.id, sum(t.revenue)
from table t
inner join (
select id
from table
where date between '2013-01-01' and '2013-01-08'
group by id
having sum(revenue) > 1000
) ts on t.id = ts.id
where t.date between '2013-01-01' and '2013-01-08'
group by t.date, t.id
it's not MySQL, it's Vertica ;)
Cris, what projection and order by you using in CREATE TABLE ???
Do you try using database designer
see http://my.vertica.com/docs/6.1.x/HTML/index.htm#14415.htm