Here is an image:
This is how far I gone into coding:
CREATE TYPE appointment_list_type AS TABLE OF REF appointment_type;
/
CREATE OR REPLACE TYPE person_type AS OBJECT (
personID NUMBER,
Surname varchar2(10),
Forname varchar2(10),
dateOfBirth date,
AddressLine1 varchar2(30),
AddressLine2 varchar2(30),
Town varchar2(10),
contacTel1 varchar2(10),
contacTel2 varchar2(10)) NOT FINAL;
/
CREATE TYPE applicant_type UNDER person_type(
applicantID NUMBER,
maxPrice number(7,2),
desiredArea varchar2(10),
Attends appointment_list_type
);
/
CREATE TYPE salesperson_type UNDER person_type(
salespersonID NUMBER,
manager varchar2(10),
Makes appointment_list_type
);
/
This is creating the types of person seperating it into inheritance of Salesperson and Applicant.
CREATE TYPE appointment_type AS OBJECT(
appointmentID NUMBER,
Appdate date,
Apptime timestamp,
appointmentType varchar2(10),
levelOfInterest varchar2(10),
offerMade varchar2(10),
Made_by REF salesperson_type,
Attends_by REF applicant_type
);
/
This is appointment type, The references work for relating them together.
For creating the table:
CREATE TABLE person_table OF person_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Attends STORE AS attend_meeting_table;
CREATE TABLE applicant_table OF applicant_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Attends STORE AS attend_meeting_table;
CREATE TABLE salesperson_table OF salesperson_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Makes STORE AS makes_meeting_table;
CREATE TABLE appointment_table OF appointment_type (
appointmentID PRIMARY KEY NOT NULL,
SCOPE FOR (Made_by) IS person_table,
SCOPE FOR (Attends_by) IS person_table);
Also here is some code of what I done, I now here is my question:
How does inheritance work with doing 1 to many directly into Appointment?
I am realy confused by this. Can anyone out me help me on how to do this?
phuh, I think I finally figured whats bothering you...
Currently, the appointments REFd in applicant_table and salesperson_table are totally independent. That means that applicants could come to meetings with sales persons that are actually in a meeting with someone else :)
Of course you want all appointments to be stored in appointment_table.
That is the perfect use case for object views. You do not need these object tables at all. Relational tables are much easier to manage.
Just create normal tables and then object views, just like this one for SALESPERSON:
create view ov_salesperson as
(select personID,
salespersonID,
SALESPERSON_TYPE
(personID
Surname,
Forname,
dateOfBirth,
AddressLine1,
AddressLine2,
Town,
contacTel1,
contacTel2,
salespersonID,
manager,
CAST
(MULTISET
(Select appointment_type
(appointmentID,
Appdate,
Apptime,
appointmentType,
levelOfInterest,
offerMade,
salesperson_id,
applicant_id
)
From appointment_table A
Where A.salesperson_id = S.salesperson_id
)
as appointment_list_type
)
) as salesperson_obj
from salesperson_table S
);
Related
I have these two tables
CREATE TABLE Person
(
id_p number(3),
name varchar2(35),
email varchar2(35),
adress varchar2(35)
);
CREATE TABLE Contract_j
(
id_cj number(3),
data date,
object varchar2(30),
onorary number(6),
nr_pages number(4),
id_client number(3),
id_lawyer number(3)
);
id_p is the id of the person, and if that person is a client, id_p mathces with id_client
I have to find the name of the clients that have EXACTLY one legal assistance contract(Contract_j). How do I do that without using COUNT? I have to use at least one subquery and keywords suchs as ANY, ALL, IN, EXIST.
Alexia, the below query will give you the name of the clients that have EXACTLY one legal assistance contract. It uses a subquery and IN clause as per your constraints.
select name
from
Person
where id_p in (
select id_client
from Contract_j
group by id_client
having count(*)=1
)
I have three tables customer_cars, bookings, and replaced_parts ad below:
CREATE TABLE customer_cars(
pk_car_id NUMBER(11) NOT NULL,
car_plate_number VARCHAR2(15) NOT NULL
);
CREATE TABLE bookings(
pk_booking_id NUMBER(11),
fk_car_id NUMBER(11),
);
CREATE TABLE replaced_parts(
pk_parts_id VARCHAR2(25),
fk_booking_id NUMBER(11),
replaced_parts parts_varray_type
);
CREATE OR REPLACE TYPE parts_type AS OBJECT (
name VARCHAR2(25),
price NUMBER(10),
);
/
CREATE TYPE parts_varray_type AS
VARRAY(40) OF parts_type;
/
I am trying to get parts name from parts_varray_type of a car. All i have is car_plate_number. Using this plate number i want to find pk_car_id in customer_cars and then that pk_car_if id should match with fk_car_id in bookings to find bookings_id. Then the found booking id should match with fk_booking_id in replaced_parts to get the parts_name.
INSERT INTO customer_cars (pk_car_id, car_plate_number)
VALUES(200000,'5651L');
INSERT INTO bookings(pk_booking_id, fk_car_id)
VALUES(700000,200000);
INSERT INTO replaced_parts (pk_parts_id, fk_booking_id, replaced_parts)
VALUES(700000,600000,
parts_varray_type(
parts_type('CLUTCH', 2000)));
Above is the insert statements. Now using plate number '5651L' i want to display clutch , 2000 from parts parray type.
Something like:
SELECT..
FROM..(Usings joins or any other methods)
WHERE pk_car_id = '5651L';
It should display name and price from parts varray type.
I am trying to create a table using a disjoint subtype relationship.
For example, if the Supertype is furniture, and I have 3 Subtypes of furniture: chair, couch, and table.
Then:
CREATE TABLE Furniture
(order_num NUMBER(15), desc VARCHAR2(20), type VARCHAR2(10));
How do I make an option to pick type of chair, couch or table?
You can use REFERENCES in the CREATE TABLE.
CREATE TABLE Furniture_SubTypes
(
sub_type VARCHAR(10) PRIMARY KEY
);
INSERT INTO Furniture_SubTypes VALUES ('Chair');
INSERT INTO Furniture_SubTypes VALUES ('Couch');
INSERT INTO Furniture_SubTypes VALUES ('Table');
CREATE TABLE Furniture
(
order_num NUMBER,
description VARCHAR(20),
sub_type REFERENCES Furniture_SubTypes(sub_type)
);
Use a check constraint:
CREATE TABLE Furniture (
order_num NUMBER(15),
description VARCHAR2(20),
type VARCHAR2(10),
check (type in ('chair', 'couch', 'table'))
);
Note that desc is a poor choice for a column name, because it is a keyword in SQL (used for order by).
I have some tables and need to create object views on top of them.
CREATE TABLE Person (
Nr NUMBER(4) PRIMARY KEY,
Name VARCHAR2(15));
CREATE TABLE Professor (
Nr NUMBER(4) PRIMARY KEY,
HabilThema VARCHAR2(30));
I also created types:
CREATE OR REPLACE TYPE Person_Typ AS OBJECT(
Nr INTEGER,
Name VARCHAR2(15)
);
CREATE OR REPLACE TYPE Professor_Typ AS OBJECT(
Nr INTEGER,
Habilthema VARCHAR2(30),
Person REF Person_Typ
);
As you can see there is a reference from a professor row to a person row. The view of the professors now should also include the columns of the person. Something like:
CREATE VIEW People OF Person_Typ
WITH OBJECT IDENTIFIER(Nr) AS
SELECT p.Nr, p.Name FROM Person p;
CREATE VIEW Professors OF Professor_Typ
WITH OBJECT IDENTIFIER(Nr) AS
SELECT p.Nr, p.Habilthema, p.Person.Name, MAKE_REF(People,p.Nr) FROM Professor p;
^
|_ Name of professor from Person table
But this does not work:
"P"."PERSON"."NAME" invalid identifier
Can this even be achieved by an object view? How?
hi i'm using oracle 11g to create a table with Object-Relational Features but its not creating the table for some reason
here what i have
create type Name as object (
firstname varchar2(20),
surname varchar2(20))
final
create type Address as object (
street varchar2(20),
city varchar2(20),
postal_code varchar2(8))
not final
and for the table
create table people (
(pname Name,
paddress Address,
dateOfBirth date);
yet its not creating the table, i know its probably something simple and straight forward but i just cant seam to get it to create the table, if somebody could point me in the right direction to get it to create the table that would be great
also when i try create the table i get the following error
ORA-00904: "%s: invalid identifier"
*Cause:
*Action:
Vendor code 904Error at line:2 colimn:2
You can try this:
CREATE TYPE Name as object (firstname varchar2(20), surname varchar2(20)) FINAL;
CREATE TYPE Address as object (street varchar2(20), city varchar2(20), postal_code varchar2(8)) NOT FINAL;
CREATE TABLE people (pname Name, paddress Address, dateOfBirth date);
DEMO
try this
create type Name as object (
firstname varchar2(20),
surname varchar2(20))
final );
create type Address as object (
street varchar2(20),
city varchar2(20),
postal_code varchar2(8))
not final);