php - how do I use a form to display data with multiple where conditions? - where-clause

Question

I created a database for a volunteers list. Then a form to pull out the personal info for volunteers who signed up to volunteer for particular tasks. I'm a beginner with php, and I have looked all over for an answer and tried multiple ways of doing it, but alas, no luck.
Here is the critical code I am currently struggling with:
if(isset($_POST['planning']) && $_POST['planning'] == '1')
{ $result1 = mysql_query("SELECT * FROM volunteers WHERE planning = '1'");}
if(isset($_POST['signatures']) && $_POST['signatures'] == '1')
{ $result2 = mysql_query("SELECT * FROM volunteers WHERE signatures = '1'");
$newresult1 = array_merge($result1, $result2);}
if(isset($_POST['canvassing']) && $_POST['canvassing'] == '1')
{ $result3 = mysql_query("SELECT * FROM volunteers WHERE canvassing = '1'");
$newresult2 = array_merge($newresult1, $result3);}
if(isset($_POST['phone_bank']) && $_POST['phone_bank'] == '1')
{ $result4 = mysql_query("SELECT * FROM volunteers WHERE phone_bank = '1'");
$newresult3 = array_merge($newresult2, $result4);}
if(isset($_POST['media']) && $_POST['media'] == '1')
{ $result5 = mysql_query("SELECT * FROM volunteers WHERE media = '1'"); $newresult4 =
array_merge($newresult3, $result5);}
if(isset($_POST['press_releases']) && $_POST['press_releases'] == '1')
{ $result6 = mysql_query("SELECT * FROM volunteers WHERE press_releases = '1'");
$newresult5 = array_merge($newresult4, $result6);}
if(isset($_POST['volunteer_coordinator']) && $_POST['volunteer_coordinator'] == '1')
{ $result7 = mysql_query("SELECT * FROM volunteers WHERE volunteer_coordinator =
'1'");
$newresult6 = array_merge($newresult5, $result7);}
if(isset($_POST['speaker']) && $_POST['speaker'] == '1')
{ $result8 = mysql_query("SELECT * FROM volunteers WHERE speaker = '1'"); $newresult7
= array_merge($newresult6, $result8);}
if(isset($_POST['house_parties']) && $_POST['house_parties'] == '1')
{ $result9 = mysql_query("SELECT * FROM volunteers WHERE house_parties = '1'");
$newresult8 = array_merge($newresult7, $result9);}
if(isset($_POST['web_page']) && $_POST['web_page'] == '1')
{ $result10 = mysql_query("SELECT * FROM volunteers WHERE web_page = '1'");
$newresult9
= array_merge($newresult8, $result10);}
if(isset($_POST['other']) && $_POST['other'] == '1')
{ $result11 = mysql_query("SELECT * FROM volunteers WHERE other = '1'"); $newresult10
= array_merge($newresult9, $result11);}
$newresult10 = array_unique($newresult10);
while($row = mysql_fetch_array($newresult10)) {
echo $row['first_name'] . " " . $row['last_name'];
echo " ";
echo $row['email'];
echo " ";
echo $row['phone'];
echo "<br />";
I much appreciated any suggestions.

Answer 1

You could write it so that it's more like this
[EDIT]-------- I think this is what your looking for
$postVars = array(
"canvassing"=>"1",
"other"=>"1"
//and you would go on post name valid post value
);
//start the query
$query="SELECT * FROM volunteers WHERE ";
//loop thru the posibable post vars and check and add to the query
$andcount=0;
foreach($postVars as $name=>$value){
if(isset($_POST[$name]) && $_POST[$name] == $value){
if($andcount>0)$query.=" AND ";
$query.=" ".$name."= '".mysql_real_escape_string($value)."'";
$andcount++;
}
}
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
echo $row['first_name'] . " " . $row['last_name'];
echo " ";
echo $row['email'];
echo " ";
echo $row['phone'];
echo "<br />";
}