In order to get a string with 2 decimals value I've tried:
[[NSString stringWithFormat:#"%.2f",[[self CurrentValue] doubleValue]]]
this
[self CurrentValue] stringValue]
and this:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.numberStyle = NSNumberFormatterCurrencyStyle;
NSString *string = [formatter stringFromNumber:[self CurrentValue]];
[formatter release];
But it doesn't work. THe original number is a float = 22, and I always get a string "22", and not "22.00".
Thanks
I ran a few test scenarios and hopefully this can help you get to the bottom of it. The formatter is ideal if you are doing a currency, otherwise string1 is ideal. To work from this example you can set number up - NSNumber * number = [self CurrentValue];
NSNumber * number = [NSNumber numberWithInt:22];
NSString * string1 = [NSString stringWithFormat:#"%.2f",[number doubleValue]];
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.numberStyle = NSNumberFormatterCurrencyStyle;
NSString *string2 = [formatter stringFromNumber:number];
[formatter release];
NSLog(#"string 1 %#\nstring 2 %#\nstring 3 %#", string1, string2, [number stringValue]);
//output
string 1 22.00
string 2 $22.00
string 3 22
// top code with NSNumber * number = [NSNumber numberWithFloat:22];
string 1 22.00
string 2 $22.00
string 3 22
// top code with NSNumber * number = [NSNumber numberWithFloat:22.0];
string 1 22.00
string 2 $22.00
string 3 22
Summary:
The way the number is created is not significant here to the output if it is truly an int (floats with such as 4.20 will work as expected in every case, but every int value 22,22.0,22.000 gets treated the same by all 3 ways of creating a number. So choose the format you like best and implement that.
Seems you have extra [] around. You can try
[NSString stringWithFormat:#"%.2f",[[self CurrentValue] floatValue]]
or
[NSString stringWithFormat:#"%.2lf",[[self CurrentValue] doubleValue]] both are good to go.
It actually much simpler.
You said that "The original number is a float = 22". Now, remember that obj-c runtime class may differ from declared one. And when you instantiate your float variable with actually integer value - it is an integer one at runtime! You should change it to one of the following:float someFloatValue = 22f;float someFloatValue = 22.0;float someFloatValue = (float)22; (not sure about that one thought)
Happy coding...
Related
I need to make NSNumber to display only 4 decimal points. This part of code is works, but it outputs result without leading zero.
double resultRoundToDecimal = [result doubleValue];
NSNumberFormatter *resultFormatter = [[NSNumberFormatter alloc] init];
[resultFormatter setRoundingMode:NSNumberFormatterRoundHalfUp];
[resultFormatter setMaximumFractionDigits:4];
resultData = [resultFormatter stringFromNumber:[NSNumber numberWithDouble:resultRoundToDecimal]];
For example:
1/3 = .3333
I want:
1/3 = 0.3333
How I can to do this?
You could choose to use string formatter too, like below
float val=1./3;
NSString *resultData=[NSString stringWithFormat:#"%0.4f",val];
NSLog(#"Result = %#",resultData);
Prepend a 0 or use number formatter.
NSString *printStr = #"0";
printStr = [NSString stringByAppendingString: resultData];
Otherwise, you could use a number formatter or something similar. If your just outputting a string why not do that?
https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSNumberFormatter_Class/Reference/Reference.html
i'm looking for a way to represent a double value in a NSString meeting the following format requirements:
1.) no trailing zeros: x = 0.5000000 -> #"0.5"
2.) at least on decimal: x = 45 -> #"45.0"
3.) maximum 8 decimal characters (last one rounded): x = 0.000000005 -> #"0.00000001"
I tried with #"%.8f", #"%g" or #"%.8g" but all fail for at least one of the requirements.
I think I could do with #"%.8f" and then loop the characters of the string beginning with the last character of string to the front deleting the "0" characters,
Or start with a "%.8g" and append a ".0" if the string does not contain a decimal point.
Is there any smarter solution available?
You can do this with a number formatter, but you need to create an NSNumber with your double first:
NSNumber *halfNumber = [NSNumber numberWithDouble:0.5000000];
NSNumber *wholeNumber = [NSNumber numberWithDouble:45];
NSNumber *longNumber = [NSNumber numberWithDouble:0.000000005];
NSNumberFormatter *formatter = [NSNumberFormatter new];
formatter.numberStyle = NSNumberFormatterDecimalStyle;
formatter.roundingMode = NSNumberFormatterRoundHalfUp;
formatter.minimumFractionDigits = 1;
formatter.maximumFractionDigits = 8;
NSString *halfString = [formatter stringFromNumber:halfNumber];
NSString *wholeString = [formatter stringFromNumber:wholeNumber];
NSString *longString = [formatter stringFromNumber:longNumber];
NSLog(#"%#", halfString);
NSLog(#"%#", wholeString);
NSLog(#"%#", longString);
// Output is:
// 2012-11-12 04:22:41.181 Testing App[48069:fb03] 0.5
// 2012-11-12 04:22:41.182 Testing App[48069:fb03] 45.0
// 2012-11-12 04:22:41.183 Testing App[48069:fb03] 0.00000001
NSString * addString=[arrayyyy componentsJoinedByString:#","];
NSLog(#"add string is: %#",addString);// result is: 45,1
Now I want to convert above string into integer.
I have tried this:
NSInteger myInt=[addString intValue];
//NSLog(#"myInt is: %d",myInt);// result is: 45
If you expected 45.1 then there are two things wrong :
45.1 is not an integer. You would have to use floatValue to read the value.
45,1 (notice the comma) is not a valid float number. While 45,1 is valid in some locale (i.e. in french its 1 000,25 instead of 1,000.25) you would have to convert the string with an NSNumberFormatter before reading the floatValue.
.
// Can't compile and verify this right now, so please bear with me.
NSString *str = #"45,1";
NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init] autorelease];
NSLocale *locale = [[[NSLocale alloc] initWithLocaleIdentifier:#"fr_FR"] autorelease]; // lets say French from France
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setLocale:locale];
float value = [[formatter numberFromString:str] floatValue]; // value = 45.1
Try out NSExpression which works with mathematical symbols too (i.e. +, -, /, *):
NSNumber *numberValue = [[NSExpression expressionWithFormat:inputString] expressionValueWithObject:nil context:nil];
// do something with numberValue
From reading the question a lot, I think I may understand what you want.
The starting point seems to be:
NSLog(#"add string is: %#",addString);// result is: 45,1
And the current ending point is:
NSLog(#"myInt is: %d",myInt);// result is: 45
But it seems that you still want to print out 45,1
My guess on this is that you have an array of 2 strings [#"45",#"1"] called arrayyyy and you want to print out both values as integers. If this is so then what I think you want is:
NSInteger myInt1 = [[arrayyyy objectAtIndex:0] intValue];
NSInteger myInt2 = [[arrayyyy objectAtIndex:1] intValue];
NSLog(#"add string is: %d,%d",myInt1,myInt2);
Note This will crash horribly with an NSRangeException if there are not at least two strings in the array. So at the very least you should do:
NSInteger myInt1 = -1;
NSInteger myInt2 = -1;
if ([arrayyyy length] >0) myInt1 = [[arrayyyy objectAtIndex:0] intValue];
if ([arrayyyy length] >1) myInt2 = [[arrayyyy objectAtIndex:1] intValue];
NSLog(#"add string is: %d,%d",myInt1,myInt2);
But even this is bad as it assumes that the guard value of -1 will not be present in the actual data.
Is there any way to format an NSNumber with leading 0's and decimals? For example, I need to have the ability to write 4.5 as well as 000. Currently I have it where it will allow decimals, but not leading 0's.
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
NSString *myString = [f numberFromString:#"4.5"];
NSLog(#"myString: %#",myString);
NSString *myOtherString = [f numberFromString:#"000"];
NSLog(#"myOtherString:%#",myOtherString);
The output from above would be: 'myString:4.5' and 'myOtherString:0'. I need to be able to do both '4.5' and '000' as output.
I have looked at Apple's "Data Formatting Guide" without much success.
Note that [f numberFromString:#"4.5"] returns an NSNumber* not a NSString*
You want something like this:
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
NSNumber *myNumber;
NSString *myString;
myNumber = [f numberFromString:#"4.5"];
[f setNumberStyle:kCFNumberFormatterDecimalStyle];
myString = [f stringFromNumber:myNumber];
NSLog(#"myString: %#",myString);
myNumber = [f numberFromString:#"000"]; // Note that the extra zeros are useless
[f setFormatWidth:3];
[f setPaddingCharacter:#"0"];
myString = [f stringFromNumber:myNumber];
NSLog(#"myString: %#",myString);
NSLog output:
myString: 4.5
myString: 000
If you don't have strings to start with just create number like:
myNumber = [NSNumber numberWithFloat:4.5];
myNumber = [NSNumber numberWithInt:0];
Or just use standard formatting:
myString = [NSString stringWithFormat:#"%.1f", [myNumber floatValue]];
myString = [NSString stringWithFormat:#"%03d", [myNumber intValue]];
Or if you don't need an NSNumber representation just use standard formatting :
myString = [NSString stringWithFormat:#"%.1f", 4.5];
myString = [NSString stringWithFormat:#"%03d", 0];
You could try something like:
NSString *myString = [NSString stringWithFormat:#"%03f", [myNSNumber floatValue]];
This, following the printf format, will print your number forcing at least 3 digits to be printed and padding with '0's any empty space.
How about this as a variation on theme for the 000's
NSNumber *myNumber;
NSString *myString =#"000" ;
NSString * myStringResult;
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
[f setHasThousandSeparators:FALSE]; //-- remove seperator
[f setMinimumIntegerDigits:[myString length ]]; //-- set minimum number of digits to display using the string length.
myNumber = [f numberFromString:myString];
myStringResult = [f stringFromNumber:myNumber];
NSLog(#"myStringResult: %#",myStringResult);
Since this is asked often and Apple's docs suck, this is the answer that people will be looking for. The link below has two solutions. One using NSString stringWithFormat: and the other using NSNumberFormatter.
https://stackoverflow.com/a/11131497/1058199
If I have a number int aNum = 2000000 how do I format this so that I can display it as the NSString 2,000,000?
Use NSNumberFormatter.
Specifically:
NSNumberFormatter *formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle]; // this line is important!
NSString *formatted = [formatter stringFromNumber:[NSNumber numberWithInteger:2000000]];
[formatter release];
By default NSNumberFormatter uses the current locale so the grouping separators are set to their correct values by default. The key thing is to remember to set a number style.
Don't do your own number formatting. You will almost certainly not get all the edge cases right or correctly handle all possible locales. Use the NSNumberFormatter for formatting numeric data to a localized string representation.
You would use the NSNumberFormatter instance method -setGroupingSeparator: to set the grouping separator to #"," (or better yet [[NSLocale currentLocale] objectForKey:NSLocaleGroupingSeparator]; thanks #ntesler) and -setGroupingSize: to put a grouping separator every 3 digits.
There's a static method on NSNumberFormatter that does just what you need:
int aNum = 2000000;
NSString *display = [NSNumberFormatter localizedStringFromNumber:#(aNum)
numberStyle:NSNumberFormatterDecimalStyle];
This way is a little more succinct than creating a new NSNumberFormatter if you don't need to do any additional configuration of the formatter.
Even easier:
NSNumber *someNumber = #(1234567890);
NSString *modelNumberString = [NSString localizedStringWithFormat:#"%#", someNumber];
NSLog(#"Number with commas: %#", modelNumberString);
coworker just taught me this today. #amazing
Think some as i will get this post looking for sample.
So if you are working with number make attention on next params:
setNumberStyle:NSNumberFormatterCurrencyStyle // if you are working with currency
It could be also
setNumberStyle:NSNumberFormatterDecimalStyle
All code is For ARC.
If you are working with Integer and need to get result such as 200,000
int value = 200000;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSString * newString = [formatter stringFromNumber:[NSNumber numberWithInteger:value]];
If you are working with Float and need to get result such as 200,000.00
float value = 200000;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setMaximumFractionDigits:2]; // Set this if you need 2 digits
NSString * newString = [formatter stringFromNumber:[NSNumber numberWithFloat:value]];
EDIT
To have ability to use different digital separators use NSLocale.
Add to code where NSLocale is specified on Locale Identifier:
[formatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:#"de_DE"]];
or use current local:
[formatter setLocale:[NSLocale currentLocale]];
Swift version
let formatter = NSNumberFormatter()
formatter.numberStyle = .DecimalStyle
formatter.maximumFractionDigits = decimalPlaces
let result = formatter.stringFromNumber(NSNumber(double: 8.0))
By http://ios.eezytutorials.com
An easy solution could be this. My answer is almost same like #Nazir's answer but with a small trick.
double current_balance = 2000000.00;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
//[formatter setNumberStyle:NSNumberFormatterCurrencyStyle]; //if you want for currency with $ sign
[formatter setMinimumFractionDigits:2]; // Set this if you need 2 digits
[formatter setMaximumFractionDigits:2]; // Set this if you need 2 digits
NSString * currency_format = [NSString stringWithFormat:#"%#", [formatter stringFromNumber:[NSNumber numberWithDouble:current_balance]]];
For Swift 4.0
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
formatter.minimumFractionDigits = 2
formatter.maximumFractionDigits = 2
let result = formatter.string(from: NSNumber(value: 123456))
For those who need to do it with strings of numbers and not just integers (I.e. Big Numbers) I made the following macro:
#define addCommas(__string) (\
(^NSString *(void){\
NSString *__numberString = __string;\
NSString *__integerPortion = __numberString;\
NSString *__decimalPortion = #"";\
if ([__string containsString:#"."]) {\
__integerPortion = [__numberString componentsSeparatedByString:#"."][0];\
__decimalPortion = st(#".%#", [__numberString componentsSeparatedByString:#"."][1]);\
}\
int __i = (int)__integerPortion.length-3;\
while (__i > 0) {\
__integerPortion = st(#"%#,%#", substringInRange(__integerPortion, 0, __i), substringInRange(__integerPortion, __i, (int)__integerPortion.length));\
__i -= 3;\
}\
__numberString = st(#"%#%#", __integerPortion, __decimalPortion);\
return __numberString;\
})()\
)