Im trying to generate RSS page with CListView but i got additional generated html in my results:
<div id="yw0" class="list-view">
<div class="items">
and
<div class="keys" style="display:none" title="/index.php/rss"><span>2383</span><span>4743</span><span>1421</span></div>
How can i remove it?
actually it is quite simple, only a few lines of code.
INSTEAD of using CListView, just use its guts:
$data = $dataProvider->getData();
foreach($data as $i => $item)
Yii::app()->controller->renderPartial('your_item_view',
array('index' => $i, 'data' => $item, 'widget' => $this));
that's it.
You can't do it without changing CListView class (yii v.1.1.8).
CListView extends CBaseListView
http://code.google.com/p/yii/source/browse/tags/1.1.8/framework/zii/widgets/CBaseListView.php
/**
* Renders the view.
* This is the main entry of the whole view rendering.
* Child classes should mainly override {#link renderContent} method.
*/
public function run()
{
$this->registerClientScript();
echo CHtml::openTag($this->tagName,$this->htmlOptions)."\n";
$this->renderContent();
$this->renderKeys();
echo CHtml::closeTag($this->tagName);
}
/**
* Renders the key values of the data in a hidden tag.
*/
public function renderKeys()
{
echo CHtml::openTag('div',array(
'class'=>'keys',
'style'=>'display:none',
'title'=>Yii::app()->getRequest()->getUrl(),
));
foreach($this->dataProvider->getKeys() as $key)
echo "<span>".CHtml::encode($key)."</span>";
echo "</div>\n";
}
There's a very good wiki tutorial on Yii site about generating Feeds. CListView is intended to display an html list of items, not feed of any kind.
Related
My Model returns this to my Controller:
namespace app\models;
use yii\data\ActiveDataProvider;
use \yii\db\ActiveRecord;
class Questions extends ActiveRecord{
public static function getQuestionById($id){
return Questions::find()->select('title, is_textarea')->where(['id'=>$id])->one();
}
public static function model($className=__CLASS__)
{
return parent::instance();
}
}
In the Controller, it's sent to the View:
return $this->render('question', ['question' => Question::getQuestionById($id)]);
Then in my View, I must display the question like such:
<?= $question['attributes']['title'] ?>
Isn't there a way to display in a more human-friendly way, for example:
<?= $question->title ?>
I tried it and it's throwing a "Trying to get property of non-object" exception. I thought that was the way to go in Yii, just like Django, CodeIgniter, etc but I can't find an example in the documentation how to display model data in views
While sending to the view you are assigning ['questions'=>$question] so using
$questions->title
should work
To avoid "Trying to get property of non-object" exception you should check that $question exists
Controller
public function actionTest($id)
{
$question = Question::getQuestionById($id);
if (empty($question)) {
throw new \yii\web\NotFoundHttpException('Question not found');
}
return $this->render('test', [
'question' => $question,
]);
}
View
<?php
use yii\helpers\Html;
use yii\web\View;
use app\models\Question;
/**
* #var $this View
* #var $question Question
*/
?>
<div>
<h1><?= Html::encode($question->title) ?></h1>
<p>
<?= Html::encode($question->is_textarea) ?>
</p>
</div>
I think you should clarify which are the steps you need to achieve what you want:
Pass the data to your view. In your case, you want to pass a model of Questions. You don't need to pass data from the model to the controller. Actually, the data you need is the model itself.
So you can simply do this inside your controller's action:
public function actionTest($id)
{
$question = Questions::findOne(['id' => $id]);
return $this->render('test', [
'question' => $question,
]);
}
Display the data. Now in your view file you simply access to the model fields that you need:
<?= $question->title ?>
I Need Help in Yii, i get problem in my form, the problem is if i put id in textfield then client validation not showing for that field but another field no problem. This is my code in form
<div class="row">
<?php echo $form->labelEx($model,'latar_belakang'); ?>
<?php echo $form->textField($model,'latar_belakang',array('id' => 'latarbelakang','class' => 'input-block-level')); ?>
<?php echo $form->error($model,'latar_belakang'); ?>
<?php echo $form->labelEx($model,'rumusan_masalah'); ?>
<?php echo $form->textField($model,'rumusan_masalah',array('id' => 'rumusanmasalah','class' => 'input-block-level')); ?>
<?php echo $form->error($model,'rumusan_masalah'); ?>
</div>
for your knows i use id in textfield for calculaten field with jquery which i put in form . this is my jquery code in form
Yii::app()->clientScript->registerCoreScript('jquery');
Yii::app()->clientScript->registerScript('totalValues',"
function totalValues()
{
var lb = $('#latarbelakang').val() ;
var rm = $('#rumusanmasalah').val();
var tot = parseInt(lb) + parseInt(rm);
$('#nilaiakhir').val( tot );
}
", CClientScript::POS_HEAD);
Yii::app()->clientScript->registerScript('changeTotals', "
$('#latarbelakang').change( function(){ totalValues(); } );
$('#rumusanmasalah').change( function(){ totalValues();} );
", CClientScript::POS_END);
What i must do ? for solving this problem ?.
Thanks B4..
By default Yii generates ids of fields dynamically using model name and field name.
For example for 'password' field of 'User' model the id would be 'User_password'
You can inspect a field(to which you have not given your custom id) with firebug and see the auto generated id. also yii maps error messages with those auto generated ids in response. that is why your error messages are not showing.
what you can do is to try to call that js function with yii generated id.
I'm basically trying to create a multi-step form using the CActiveForm class in Yii. The idea is I want to use the built-in functionality to achieve this in the simplest way possible. The requirement I have is as follows:
A multi step ONE PAGE form (using DIVs that show/hide with jQuery)
AJAX validation on EACH step (validate step-specific attributes only)
The validation MUST work using the validateOnChange() and validateOnSubmit() methods
This is a half-working solution I have developed so far:
View:
<div class="form">
<?php $form = $this->beginWidget('CActiveForm', array(
'id'=>'listing-form',
'enableClientValidation'=>false,
'enableAjaxValidation'=>true,
'clientOptions'=>array(
'validateOnChange'=>true,
'validateOnSubmit'=>true,
'afterValidate'=>'js:validateListing',
),
)); ?>
<?php echo $form->errorSummary($model); ?>
<div class="step" id="step-1">
// model input fields
<?php echo CHtml::submitButton('Next Step', array('name'=>'step1')); ?>
</div>
<div class="step" id="step-2" style="display: none;">
// model input fields
<?php echo CHtml::submitButton('Next Step', array('name'=>'step2')); ?>
</div>
<div class="step" id="step-3" style="display: none;">
// model input fields
<?php echo CHtml::submitButton('Submit', array('name'=>'step3')); ?>
</div>
<?php $this->endWidget(); ?>
</div>
JavaScript:
function validateListing(form, data, hasError)
{
if(hasError)
{
// display JS flash message
}
else
{
if($('#step-1').css('display') != 'none')
{
$('#step-1').hide();
$('#step-2').show();
}
else if($('#step-2').css('display') != 'none')
{
$('#step-2').hide();
$('#step-3').show();
}
else if($('#step-3').css('display') != 'none')
{
return true; // trigger default form submit
}
}
}
Controller:
public function actionCreate()
{
$model = new Listing;
// step 1 ajax validation
if(isset($_POST['step1']))
{
$attributes = array('name', 'address1', 'etc');
$this->performAjaxValidation($model, $attributes);
}
// step 2 ajax validation
if(isset($_POST['step2']))
{
$attributes = array('category', 'type', 'etc');
$this->performAjaxValidation($model, $attributes);
}
// step 3 ajax validation
if(isset($_POST['step3']))
{
$attributes = array('details', 'source', 'etc');
$this->performAjaxValidation($model, $attributes);
}
// process regular POST
if(isset($_POST['Listing']))
{
$model->attributes = $_POST['Listing'];
if($model->validate()) // validate all attributes again to be sure
{
// perform save actions, redirect, etc
}
}
$this->render('create', array(
'model'=>$model,
));
}
protected function performAjaxValidation($model, $attributes=null)
{
if(isset($_POST['ajax']) && $_POST['ajax']==='listing-form')
{
echo CActiveForm::validate($model, $attributes);
Yii::app()->end();
}
}
To summarise. Basically what I have is a form with 3 submit buttons (one for each step). In my controller I check which submit button was pressed and I run AJAX validation for the attributes specific to that step.
I use a custom afterValidate() function to show/hide the steps upon submit. On step 3, the default form submit is triggered, which posts all the form attributes to the controller.
This works well, except it won't work with validateOnChange() (since the submit button doesn't get posted). Also I was wondering whether this is actually the best way to do this, or if anyone knows of a better way?
Thanks.
I'd suggesting using scenarios to turn on and off the appropriate rules. Adjust the model scenario based on what is sent to your controller.
Note: this may also be a really good place to use a CFormModel instead of a CActiveRecord, depending on what is in your form.
Edit: can you add a hidden field to each div section that contains the info about what step you are on? Seems like that should work instead of your submit buttons.
OPTION 1
When you do not receive a button, why not validate the entire form, why do you need to validate only specific attributes? Yii will validate the entire model, send back all the errors but only that particular error will be shown by the active form because that is how it works already.
OPTION 2
You can have 3 forms (not 1 like you have now), 1 on each step. Also create 3 scenarios 1 for each step.
Each form has a hidden field that gets posted with the form, it can actually be the scenario name just validate it when it comes in. Validate the model using this hidden field to set the scenario you are on.
You can cache parts on the model when the form is submitted successfully and at the end you have the complete model.
you can always have custom validation and it won't break your normal form validation
in your model
private $step1 = false;
private $step2 = false;
private $all_ok = false;
protected function beforeValidate()
{
if(!empty($this->attr1) && $this->attr2) // if the fields you are looking for are filled, let it go to next
{
$this->step1 = true;
}
if($this->step1)
{
... some more validation
$this->step2 = true;
}
if($this->step2)
{
... if all your logic meets
$this->all_ok = true;
}
// if all fields that your looking for are filled, let parent validate them all
// if they don't go with their original rules, parent will notify
if($this->all_ok)
return parent::beforeValidate();
$this->addError($this->tableSchema->primaryKey, 'please fillout the form correctly');
return false;
}
I think better create specific class for each step of validation and use scenarios with rules. Below is small example.
//protected/extensions/validators
class StepOneMyModelValidator extends CValidator
{
/**
* #inheritdoc
*/
protected function validateAttribute($object, $attribute)
{
/* #var $object YourModel */
// validation step 1 here.
if (exist_problems) {
$object->addError($attribute, 'step1 is failed');
}
...
Create other classes(steps) for validation...
// in your model
public function rules()
{
return array(
array('attr', 'ext.validators.StepOneMyModelValidator', 'on' => 'step1'),
...
How to use in controller:
$model = new Listing();
$steps = array('step1', 'step2', /* etc... */);
foreach($_POST as $key => $val) {
if (in_array($key, $steps)) {
$model->setScenario($key);
break;
}
}
$model->validate();
echo '<pre>';
print_r($model->getErrors());
echo '</pre>';
die();
Or we can validate all steps in one validator.
How to customize error display messages in yii? for example I need to display my error messages like below
div class="error-left"></div>
<div class="error-inner">This field is required.</div>
I can obtain the second div by applying class "error-inner" to the htmlOptions of $form->error(..).
<?php echo $form->error($model,'category_title',array('class'=>'error-inner')); ?>
But how can I display the first div before that?
You can't with Yii's default components. But you still could create your custom CActiveForm class and override the error() method, to add your custom HTML there.
<?php
class MyActiveForm extends CActiveForm
{
public function error($model,$attribute,$htmlOptions=array(),$enableAjaxValidation=true,$enableClientValidation=true)
{
$html = '<div class="error-left"></div>';
$html .= parent::error($model, $attribute, $htmlOptions, $enableAjaxValidation,$enableClientValidatin);
return $html;
}
}
The code below shows the two column layout in Yii. The $content variable holds a search form and a gridview form.
I'm trying to get the gridview to appear to the right of the Advanced Search Section in this two-column grid format. Kind of brain farting here, where in the standard Giix structure is the variable $content given it's contents? I didn't see it in the basemodel or controller.
Thanks in advance.
<?php /* #var $this Controller */ ?>
<?php $this->beginContent('//layouts/main'); ?>
<div class="span-24">
<div id="content">
<?php echo $content; ?>
</div><!-- content -->
</div>
<div class="span-5 last">
<div id="sidebar">
<?php
$this->beginWidget('zii.widgets.CPortlet', array(
'title'=>'Operations',
));
$this->widget('zii.widgets.CMenu', array(
'items'=>$this->menu,
'htmlOptions'=>array('class'=>'operations'),
));
$this->endWidget();
?>
</div><!-- sidebar -->
</div>
<?php $this->endContent(); ?>
$content is given its content when your controller call $this->render() at the end of its action.
public function actionIndex() {
// renders the view file 'protected/views/site/index.php'
// using the default layout 'protected/views/layouts/main.php'
[some code...]
$this->render('index');
}
The process involved is a bit obfuscated but you can easily trace it down by setting a breakpoint and looking at the stack in your debugger.
You can also read the code :
render() is a method of the CController class :
public function render($view, $data = null, $return = false) {
if ($this->beforeRender($view)) {
$output = $this->renderPartial($view, $data, true); // (1)
if (($layoutFile = $this->getLayoutFile($this->layout)) !== false)
$output = $this->renderFile($layoutFile, array('content' => $output), true); // (2)
[snip...]
}
}
(1) If no error occurs before rendering, the view is populated and its HTML code assigned to $output : $output = $this->renderPartial($view, $data, true);
(2) Then, unless you stated in your action that the view must not be decorated by the layout by colling $this->setLayout(false), the Decorator pattern is applied and the internal view set in the layout :
$output = $this->renderFile($layoutFile, array('content' => $output), true)
Here, you shall notice that the second argument is an array : array('content' => $output)
renderfile() is a method of CBaseController which, at some point, will call
public function renderInternal($_viewFile_, $_data_ = null, $_return_ = false) {
// we use special variable names here to avoid conflict when extracting data
if (is_array($_data_))
extract($_data_, EXTR_PREFIX_SAME, 'data'); // (1)
else
$data = $_data_;
if ($_return_) {
ob_start();
ob_implicit_flush(false);
require($_viewFile_); // (2)
return ob_get_clean();
}
else
require($_viewFile_);
}
And that's where your answer lies :
(1) $data is still our array('content' => $output). The extract function will build and initialize variables from this array, namely your $content variable.
(2) The layout file is now required. $content exists in its scope, as well, of course, as your controller wich lies behind $this
Use a grid layout in the specific view. It should something like
<div class='span-10'>
//search form
</div>
<div class='span-9'>
//grid
</div>