Using VB.Net
When i add a the number with zeros means, it is showing exact result without zero's
For Example
Dim a, b, c as int32
a = 001
b = 5
c = a + b
a = 009
b = 13
c = a + b
Showing output as 6 instead of 006, 22 instead of 022
Expected output
006
022
How to do this.
Need vb.net code help
You need to store a number as a string if you want to store the exact number of zeros. Then addition won't work though.
If you just want to display the number with 3 digits, you can store it as an integer and format the result when you print it.
c.ToString("D3")
zero is nothing.. If you do a regular mathematical calculation of 001 + 5 the result is still 6. I would suggest you check out string padding.
Related
I have a one mainframe file data like as below
000000720000{
I need to parse the data and load into a hive table like below
72000
the above field is income column and "{" sign which denotes +ve amount
datatype used while creating table income decimal(11,2)
in layout.cob copybook using INCOME PIC S9(11)V99
could someone help?
The number you want is 7200000 which would be 72000.00.
The conversion you are looking for is:
Positive numbers
{ = 0
A = 1
B = 2
C = 3
D = 4
E = 5
F = 6
G = 7
H = 8
I = 9
Negative numbers (this makes the whole value negative)
} = 0
J = 1
K = 2
L = 3
M = 4
N = 5
O = 6
P = 7
Q = 8
R = 9
Let's explain why.
Based on your question the issue you are having is when packed decimal data is unpacked UNPK into character data. Basically, the PIC S9(11)V2 actually takes up 7 bytes of storage and looks like the picture below.
You'll see three lines. The top is the character representation (missing in the first picture because the hex values do not map to displayable characters) and the lines below are the hexadecimal values. Most significant digit on top and least below.
Note that in the rightmost byte the sign is stored as C which is positive, to represent a negative value you would see a D.
When it is converted to character data it will look like this
Notice the C0 which is a consequence of the unpacking to preserve the sign. Be aware that this display is on z/OS which is EBCDIC. If the file has been transferred and converted to another code-page you will see the correct character but the hex values will be different.
Here are all the combinations you will likely see for positive numbers
and here for negative numbers
To make your life easy, if you see one of the first set of characters then you can replace it with the corresponding number. If you see something from the second set then it is a negative number.
I have a column using bits to record status of every mission. The index of bits represents the number of mission while 1/0 indicates if this mission is successful and all bits are logically isolated although they are put together.
For instance: 1010 is stored in decimal means a user finished the 2nd and 4th mission successfully and the table looks like:
uid status
a 1100
b 1111
c 1001
d 0100
e 0011
Now I need to calculate: for every mission, how many users passed this mission. E.g.: for mission1: it's 0+1+1+0+1 = 5 while for mission2, it's 0+1+0+0+1 = 2.
I can use a formula FLOOR(status%POWER(10,n)/POWER(10,n-1)) to get the bit of every mission of every user, but actually this means I need to run my query by n times and now the status is 64-bit long...
Is there any elegant way to do this in one query? Any help is appreciated....
The obvious approach is to normalise your data:
uid mission status
a 1 0
a 2 0
a 3 1
a 4 1
b 1 1
b 2 1
b 3 1
b 4 1
c 1 1
c 2 0
c 3 0
c 4 1
d 1 0
d 2 0
d 3 1
d 4 0
e 1 1
e 2 1
e 3 0
e 4 0
Alternatively, you can store a bitwise integer (or just do what you're currently doing) and process the data in your application code (e.g. a bit of PHP)...
uid status
a 12
b 15
c 9
d 4
e 3
<?php
$input = 15; // value comes from a query
$missions = array(1,2,3,4); // not really necessary in this particular instance
for( $i=0; $i<4; $i++ ) {
$intbit = pow(2,$i);
if( $input & $intbit ) {
echo $missions[$i] . ' ';
}
}
?>
Outputs '1 2 3 4'
Just convert the value to a string, remove the '0's, and calculate the length. Assuming that the value really is a decimal:
select length(replace(cast(status as char), '0', '')) as num_missions as num_missions
from t;
Here is a db<>fiddle using MySQL. Note that the conversion to a string might look a little different in Hive, but the idea is the same.
If it is stored as an integer, you can use the the bin() function to convert an integer to a string. This is supported in both Hive and MySQL (the original tags on the question).
Bit fiddling in databases is usually a bad idea and suggests a poor data model. Your data should have one row per user and mission. Attempts at optimizing by stuffing things into bits may work sometimes in some programming languages, but rarely in SQL.
Suppose I have a table as follows:
id name length
1 A 21.5
2 B 12.4
3 C 0
4 D 17
5 E 1
I wish to get:
id name length
1 A 21.5
5 E 1
Meaning all rows that hase length that ends up with 1.
length is a numeric column.
It's very simple thing to do with programing languages but it seems quite not natural for SQL. How can I do that efficiently and simply?
My only thought is to convert the field to Text and then lose eveything after the . then convert it to array and choose the letter in the position of array length. This will probebly work but it seems like a very bad solution.
You can use FLOOR and modulo division:
SELECT *
FROM tab
WHERE FLOOR(length) % 10 = 1;
SqlFiddleDemo
I want to convert data in to a specific format in Apache Pig so that I can use a reporting tool on top of it.
For example:
10:00,abc
10:00,cde
10:01,abc
10:01,abc
10:02,def
10:03,efg
The output should be in the following format:
abc cde def efg
10:00 1 1 0 0
10:01 2 0 0 0
10:02 0 0 1 0
The main problem here is that a value can occur multiple times in a row, depending on the different values available in the sample csv file, up to a total of 120.
Any suggestions to tackle this are more than welcome.
Thanks
Gagan
Try something like the following:
A = load 'data' using PigStorage(",") as (key:chararray,value:chararray);
B = foreach A generate key,(value=='abc'?1:0) as abc,(value=='cde'?1:0) as cde,(value=='efg'?1:0) as efg;
C = group B by key;
D = foreach C generate group as key, COUNT(abc) as abc, COUNT(cde) as cde, COUNT(efg) as efg;
That should get you a count of the occurances of a particular value for a particular key.
EDIT: just noticed the limit 120 part of the question. If you cannot go above 120 put the following code
E = foreach D generate key,(abc>120?"OVER 120":abc) as abc,(cde>120?"OVER 120":cde) as cde,(efg>120?"OVER 120":efg) as efg;
var a = 123456789
var b = 6
based on 'b' I need to trim 'a'. example if 'a' having 8 digits I need to trim 'a' upto 6 digits(123456). if b is 8 I need to trim upto 8 digits. Please help me
It sounds like the easiest way to do what you want is to:
Convert a to a string.
Take the left-most digits up to a maximum of b.
This is likely easier than trying to do what you ask arithmetically.
I assume you're in javascript?
var a = "123456789";
var b = 6;
var n = a.substr(0,b);