Is there a way to script consecutive Replace-All operations in Notepad++?
For example, I want to be able to first replace all “ characters with &ldquo and then to replace all ” characters with &rdquo and then I would like to replace all "string1" with "string2", etc...
Nevermind,
I finally figured it out, and it seems like a great solution.
I used PythonScript for NotePad++ (which is what I started with but which kept giving me errors, until I finally fixed a few things).
So, here is the code for those who may be interested:
# This Python file uses the following encoding: utf-8
import os, sys
editor.replace(r"“",r"“")
editor.replace(r"”",r"”")
editor.replace(r"’",r"’")
the r before the quotation marks allows the use of special characters as they are, and this is what was so difficult for me to get working.
Related
In vue, is there a way to have a value span multiple lines in an .env file. Ex:
Instead of:
someValue=[{"someValue":"Here is a really really long piece which should be split into multiple lines"}]
I want to do something like:
someValue=`[{"someValue":"Here is a really
really long piece which
should be split into multiple lines"}]`
Doing the latter gives me a JSON parsing error if I try to do JSON.parse(someValue) in my code
I don't know if this will work, but I can't format a comment appropriately enough to get the point across so see if this will work:
someValue=[{"someValue":"Here is a really\
really long piece which\
should be split into multiple lines"}]
Where "\" should escape the newline similar to how you can write long bash commands while escaping the newline. I'm not certain the .env interpreter will support it though.
EDIT
Looks like this won't work. This syntax was actually proposed, but I don't think it was incorporated. See motdotla/dotenv#333 (which is what Vue uses to parse .env).
Like #zero298 said, this isn't possible. Likely you could delimit the entry with a character that wouldn't show up normally in the text (^ is a good candidate), then parse it within the application using string.replace('^', '\n');
All.
I am used to programming VBA in Excel, but am new to the structures in Word.
I am working through a library of text files to update them. Many of them are either OCR documents, or were manually entered.
Each has a recurring pattern, the most common of which is unnecessary carriage returns.
For example, I am looking at several text files where there is a double return after each line. A search and replace of all double carriage returns removes all paragraph distinctions.
However, each line is approximately 30 characters long, and if I manually perform the following logic, it gives me a functional document.
If there is a double carriage return after 30+ characters, I replace them with a space.
If there were less than 30 characters prior to the double return, I replace them with a single return.
Can anyone help me with some rudimentary code that would help me get started on that? I could then modify it for each "pattern" of text documents I have.
e.g.
In this case, there are more than
thirty characters per line. And I
will keep going to illustrate this
example.
This would be a new paragraph, and
would be separated by another of
the single returns.
I want code that would return:
In this case, there are more than thirty character returns. And I will keep going to illustrate this example.
This would be a new paragraph, and would be separated by another of the single returns.
Let me know if anyone can throw something out that I can play with!
You can do this without code (which RegEx requires), simply using Word's own wildcard Find/Replace tools, where:
Find = ([!^13]{30,})[^13]{1,}
Replace = \1^32
and, to clean up the residual multi-paragraph breaks:
Find = [^13]{2,}
Replace = ^p
You could, of course, record the above as a macro...
Here is a RegEx that might work for you:
(\n\n)(?<!\.(\n\n))
The substitution is just a plain space, you can try it out (and modify / tweak it) here: https://regex101.com/r/zG9GPw/4
This 'pattern' tells the RegEx engine to look for the newline character \n which occurs x2 like this \n\n (worth noting this is from your question and might be different in your files, e.g. could be \r\n) and it assumes that a valid line break will be proceeded by a full stop: \..
In RegEx the full stop symbol is a single character wild card so it needs to be escaped with the '\' (n and r are normal characters, escaping them tells the RegEx engine they represent newline and return characters).
So... the expression is looking for a group of x2 newline characters but then uses a negative look-behind to exclude any matches where the previous character was a full stop.
Anyway, it's all explained on the site:
Here is how you could do a RegEx find and replace using NotePad++ (I'm not sure if it comes with RegEx or if a plugin is needed, either way it is easy). But you can set a location, filters (to target specific file types), and other options (such as search in sub-directories).
Other than that, as #MacroPod pointed out you could also do this with MS Word, document by document, not using any code :)
I have a CSV file which I'm trying to import to a SQL Server table. The file contains lines of 3 columns each, separated by a comma. The only problem is that some of the data in the second column contains an arbitrary number of commas. For example:
1281,I enjoy hunting, fishing, and boating,smith317
I would like to escape all occurrences of commas in each line except the first and the last, such that the result of this line would be:
1281,I enjoy hunting\, fishing\, and boating,smith317
I know I will need some type of regular expression to accomplish this task, but my knowledge of regular expressions is very limited. Currently, I'm trying to use Notepad++ find/replace with regex, but I am open to other ideas.
Any help would be greatly appreciated :-)
Okay, could be a manual stuff. Do this:
Normal find all the , and replace it with \,. Escape everything.
Regex find ^(.*)(\\,) and replace it with $1,.
Regex find (\\,)(.*)$ and replace it with ,$2.
Worked for me in Sublime Text 2.
I am currently trying to estimate the number of times each character is used in a large sample of traditional Chinese characters. I am interested in characters not words. The file also includes punctuation and western characters.
I am reading in an example file of traditional Chinese characters. The file contains a large sample of traditional Chinese characters. Here is a small subset:
首映鼓掌10分鐘 評語指不及《花樣年華》
該片在柏林首映，完場後獲全場鼓掌10分鐘。王家衛特別為該片剪輯「柏林版本
增減20處 趙本山香港戲分被刪
在柏林影展放映的《一代宗師》版本
教李小龍武功 葉問決戰散打王
另一增加的戲分是開場時葉問（梁朝偉飾）
My strategy is to read each line, split each line into a list, and go through and check each character to see if it already exists in a list or a dictionary of characters. If the character does not yet exist in my list or dictionary I will add it to that list, if it does exist in my list or dictionary, I will increase the counter for that specific character. I will probably use two lists, a list of characters, and a parallel list containing the counts. This will be more processing, but should also be much easier to code.
I have not gotten anywhere near this point yet.
I am able to read in the example file successfully. Then I am able to make a list for each line of my file. I am able to print out those individual lines into my output file and sort of reconstitute the original file, and the traditional Chinese comes out intact.
However, I run into trouble when I try to make a list of each character on a particular line.
I've read through the following article. I understood many of the comments, but unfortunately, was unable to understand enough of it to solve my problem.
How to do a Python split() on languages (like Chinese) that don't use whitespace as word separator?
My code looks like the following
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import codecs
wordfile = open('Chinese_example.txt', 'r')
output = open('Chinese_output_python.txt', 'w')
LINES = wordfile.readlines()
Through various tests I am sure the following line is not splitting the string LINES[0] into its component Chinese characters.
A_LINE = list(LINES[0])
output.write(A_LINE[0])
I mean you want to use this, from answerer 'flow' at How to do a Python split() on languages (like Chinese) that don't use whitespace as word separator? :
from re import compile as _Re
_unicode_chr_splitter = _Re( '(?s)((?:[\ud800-\udbff][\udc00-\udfff])|.)' ).split
def split_unicode_chrs( text ):
return [ chr for chr in _unicode_chr_splitter( text ) if chr ]
to successfully split a line of traditional Chinese characters.. I just had to know the proper syntax to handle encoded characters.. pretty basic.
my_new_list = list(unicode(LINE[0].decode('utf8')));
I am attempting to parse a Wikipedia SQL dump with the Python regular expressions library. The ultimate goal is to import this dump into PostgreSQL, but I know the apostrophes in strings need to be doubled, beforehand.
Every apostrophe in a string in this dump is preceded by a backwards slash, though, and I'd rather not remove the backwards slashes.
(42,'Thirty_Years\'_War',33,5,0,0)
Using the command
re.match(".*?([\w]+?'[\w\s]+?).*?", line)
I cannot identify the apostrophe in the middle of 'Thirty_Years\'_War', when 'line' is parsed from a text file.
For comparison, these lines work fine when parsed (sans the last line).
The person's car
The person's car's gasoline
Hodges' Harbrace Handbook
'Hodges' Harbrace Handbook'
portspeople',1475,29,0,0),(42,'Thirty_Years\'_War',33,5,0,0)
Correct and expected output (sans the last line):
The person''s car
The person''s car''s gasoline
Hodges'' Harbrace Handbook
('Hodges'' Harbrace Handbook')
portspeople',1475,29,0,0),(42,'Thirty_Years\'_War',33,5,0,0)
Using the command
re.match(".*?([\w\\]+?'[\w\s]+?).*?", line)
breaks it.
The person''s car
The person''''s car''''s gasoline
Hodges'' Harbrace Handbook
(''''''''Hodges'''''''' Harbrace Handbook'''''''')
portspeople'''''''''''''''',1475,29,0,0),(42,''''''''''''''''Thirty_Years\''''''''''''''''_War'''''''''''''''',33,5,0,0)
Is it stuck in some sort sort of loop? What is the correct regex code to use?
I am not thinking about SQL injection attacks because this script is only going to be used for parsing dumps of Wikipedia articles (that don't contain examples of SQL injection attacks).
If the dump consists of things like the string you provided, you could try something like this:
re.findall(r"[^,\(\)]+")
Where the character class contains all known separators.
EDIT: Only use regex for parsing when there is no better way :)
Most Python database interfaces will take care of quoting SQL statements for you. For example, with the psycopg driver, you would write something like:
mystring="""This is 'a string' that contains single quotes."""
c.execute('INSERT INTO mytable (mycolumn) VALUES (%s)', mystring)
...and the database driver will take care of correctly quoting the values for you. Look at some of the examples in the documentation. In fact, their first example is remarkably like this one.