I have a TreeGrid in SmartClient. Now I want to color some set of lines like line numbers 3-5, 7-11 etc. I am using an external button which passes the values to the SmartClient. Can anybody tell me how to do that? A button is passing the value and it's working fine. But the problem is, where to get the value in SmartClient and how can I color that set of lines.
Since TreeGrid is a ListGrid, I would imagine you could override the getCellStyle function and set the colors as you see necessary.
http://www.smartclient.com/docs/8.1/a/b/c/go.html#search=getcellstyle
So basically in pseudo code:
if (row >= 3 and row <=5)
return "style1"
if (row >= 7 and row <=11)
return "style2"
else
return this.baseStyle
where style1 and 2 are defined in css
And how to custom and keep states with using specific style name (myStyle) like :
myStyle
myStyleDark
myStyleOver
myStyleOverDark
myStyleSelected
myStyleSelectedDark
myStyleSelectedOver
myStyleSelectedOverDark
myStyleDisabled
myStyleDisabledDark
I try to use #Override of getCellStyle
for returning "myStyleA" or "myStyleB"
which i want conserve dynamics suffixs : "Dark", "Over", "Selected", ...
An idea ?...
http://www.smartclient.com/smartgwt/javadoc/com/smartgwt/client/widgets/grid/ListGrid.html
The state of the record is indicated by adding a suffix to the base style.
There are four independent boolean states, which are combined in the order given:
"Disabled" : whether the cell is disabled; enable by setting the "enabled" flag on record returned by getCellRecord
"Selected" : whether cell is selected; enable by passing a Selection object as "selection"
"Over" : mouse is over this cell; enable with showRollovers
"Dark" : alternating color bands; enable with alternateRowStyles
Related
There is a good tutorial on how to achieve this in Odoo-8 here:
Tutorial , but it doesn't work on Odoo-12.
Odoo natively allows you to set a field of your model as a basis for color differentiation in calendar view.
<calendar ... color="your_model_field">
The problem is that he will decide automagically what color to assign to every value.
I need to be able to decide what color mapping to use.
Doing some diving in the web module js files, more specifically on
web/static/src/js/views/calendar/calendar_renderer.js on line 266
I found a promising function which appears to be the one responsible for deciding which color to set.
getColor: function (key) {
if (!key) {
return;
}
if (this.color_map[key]) {
return this.color_map[key];
}
// check if the key is a css color
if (typeof key === 'string' && key.match(/^((#[A-F0-9]{3})|(#[A-F0-9]{6})|((hsl|rgb)a?\(\s*(?:(\s*\d{1,3}%?\s*),?){3}(\s*,[0-9.]{1,4})?\))|)$/i)) {
return this.color_map[key] = key;
}
var index = (((_.keys(this.color_map).length + 1) * 5) % 24) + 1;
this.color_map[key] = index;
return index;
},
This function is fed the value of your field (for every calendar event) and returns the color to be used "supposedly" as background for the calendar event square.
According to the second if statement, if you manage to instantiate the CalendarRenderer class with a color_map object which has the possible values of your field as keys and color codes as values you should be ok.
According the the third if statement, if the values of your field are strings with color codes (#FFF, rgb(x, y, z) , etc) they will be set in the color_map object and returned to be used as background colors.
The last part I guess is how odoo decides on a color when no mapping is provided.
I tried both approaches with the same efect:
Image displaying the calendar view
Namely, all the calendar events are rendered with the default color taken from the fullcalendar.css stylesheet (line 529), but the color reference displays correctly on the sidebar to the right.
I would appreciate any light shed on this matter, It has to be possible to make this work!.
Thanks.
I'm just wondering how can I change background colour of mandatory fields while adding new row.
So for example name and surname would be red (mandatory) and phone would be default white.
Thank you
Patryk
The best way to do this is through the grid's designer -- in most cases you don't need to write any code to accomplish this.
If you go to the Grid View designer, select the menu item "Appearance" and "Format Rules:"
From here, you can add a format condition by clicking the plus icon:
Under "Column," pick the column you want the format condition to apply to.
Under "Rule," pick an appropriate rule -- based on what you described, you probably want "Format Based on a Value," FormatConditionRuleValue.
On the "Rule" tab of this same dialog, you can set your "Value1" and "Condition" properties accordingly, for example Value1 = 15, Condition = "equals."
The "Appearance" property will let you determine how to format the cell based on these conditions.
The beauty of this approach is it's all designer-based code, and it's very easy to customize. The logic behind the formatting is also very transparent. The format conditions have been expanded to let you evaluate expressions as well, meaning you can create your own formulas using other column values and functions.
If all else fails, you can use the RowCellStyle event, but my first attempt would always to be to use the designer tools.
You can use an event gvView_CustomDrawCell and set background color only if the line is in state that you need (Added, Detached ...)
private void gvView_CustomDrawCell(object sender, DevExpress.XtraGrid.Views.Base.RowCellCustomDrawEventArgs e)
{
if (e.Column != null && (e.Column.Name == bgcName.Name || e.Column.Name == bgcSureName.Name))
{
DataRow focusedRow = gvView.GetDataRow(e.RowHandle);
if (focusedRow != null)
{
if (focusedRow.RowState == DataRowState.Added)
{
e.Appearance.BackColor = Color.FromArgb(80, 10, 30, 200);
}
}
}
}
asd
I have a Master-Detail set up with 2 grids. On the master grid, I have the ShowOnlyPredefinedDetails option set to false.
This means that I see a little + sign that allows me to expand the details of the detail grid (in the master grid). I would like to rename
some columns in that section as well as hide certain columns. I'm using VB.NET How do I go about this. See image.
You can accomplish this by using the grid control ViewRegistered event, from there you can modify the columns in that grid view that have columns within them that you want to modify, rename, or remove. Here is an example, I hope that it helps:
private void myGridControl_ViewRegistered(object sender, DevExpress.XtraGrid.ViewOperationEventArgs e)
{
if (e != null)
{
if (e.View != null)
{
//Inside of this statement you can adjust, add, and modify all of the columns inside of that grid that appears when you click on the +
(e.View as GridView).Columns["myHiddenColumn"].Visible = false;
(e.View as GridView).Columns.Add(new GridColumn() { Name = "AddColumn", Caption = "Name To Display", Visible = true, FieldName = "DataField"});
(e.View as GridView).Columns["DataField"].OptionsColumn.AllowEdit = false;
(e.View as GridView).Columns["DataField"].OptionsColumn.AllowFocus = false;
(e.View as GridView).Columns["DataField"].OptionsColumn.ReadOnly = true;
}
}
}
I think all you need to do is create a second grid view for your details. If you haven't already done this, do the following:
In your grid designer, click "Retrieve Details" if you have not already done so. This will cause the designer to recognize that you have a second level in your bound object:
Once you see the second layer, now you need a new grid view for it. Click on "Click here to change view" and select "Create a new view" and pick "GridView."
Now you will see both grid views from the designer, and clicking on one or the other will change the context of the menus to the left:
For example, if you have gridView2 selected, when you click on the "Layout" menu, it will show the current layout for your detail grid rather than the master grid. From here, you can remove or add columns as you see fit. Likewise, from the "Columns" menu you will see the new columns (you may have to add them to the view by dragging them over), and you can change the Caption property to change the text of the title.
I suggest you use the Data Annotation attributes with properties of your data-classes to declare how you data should be displayed in GridControl:
To skip column generation for the specific property you can mark this property with the <DisplayAttribute(AutoGenerateField := false)> declaration.
To prevent column from displaying you can mark this property with the <DisplayAttribute(Order := -1)> declaration. Later, user can show this column via Column Chooser UI.
To specify the column caption use the <DisplayAttribute(Name := "YOUR CAPTION")> declaration.
You can also control filtering/editing/formatting and validation capabilities.
Related Links:
Tutorial: Create and Manage Data in Code and Apply Data Annotation Attributes
Video Tutorial: Create and Manage Data in Code and Apply Data Annotation Attributes
I want to change the font color of a row after a cell in that row has been edited and set to a certain value.
myStore is the dojo.data.ItemFileWriteStore associated to the dojox.grid.DataGrid dataGrid.
I have written this:
myStore.onSet = function(item, attribute, oldValue, newValue) {
if (item.myField == myValue) {
var index = dataGrid.selection.selectedIndex;
dojo.style(dataGrid.getRowNode(index), "color" , "red");
}
}
but unfortunately this doesn't make any effect...
UPDATE: I added the following style property: "backgroundColor" : "red". Well, the background color of the row changes to red, but when the mouse moves away from the row, the color changes back to the default! It might be that some default event handlers restore the default styles...
The dojo.style line works if you call it by itself. Either your function isn't being called at all, the if's condition false or there is no row selected and you are getting an invalid number for the index. (You can put some console.logs there to check)
I am new to flex.
I need your help. Can anyone help me please.
My Requirement:
Flex Datagrid should be filter based on 3 checkboxes.(Checkboxes can be checked with several combinations).
My Code:
Checkboxes:
Data Provider:
MXML code:
Here i have to filter the datagrid when i check the different combinations of 3 checkboxes.
The checkbox values are from Staus column of arraycollection.
When i select 'completed' checkbox and 'onhold' check box, datagrid should display only those records which have Status as "Completed" & "On Hold".
Similarly for all combinations of c
Can anyone give simple solution please ?
Thanks,
Anand.k
Use an ArrayCollection as your dataProvider and assign a filtering function to its filterFunction property :
var provider:ArrayCollection;
At the part where you instantiate your array, give it a filterFunction :
provider.filterFunction = myFilteringFunction;
With the code of the filterFunction like this :
private function myFilteringFunction(item:ObjectTypeInYourArray) : Boolean {
var show:Boolean;
if(item.completed == checkBox1.checked &&
item.onHold == checkBox2.checked){
show = true;
}
return show;
}
It's an example with two checkboxes. The type of value assigned to the completed and onHold attributes of your object may not be boolean so you'll have to convert them somehow before comparing them to the state of the checkboxes but I think you get the idea.
Basically the filterFunction that you pass to your arraycollection is applied to each of the items inside and return true or false depending on you code inside (e.g check if the object has the right values for its properties). When true the values are showed
At the change events of your checkboxes, you refresh the dataProvider :
provider.refresh();
Hope that helps