I have tried this a few different ways and it never seems to work:
SUM(
Select count(*) from table1 where month = 1 +
Select count(*) from table1 where month = 2 +
Select count(*) from table1 where month = 3
)
What is the proper way to do it? SUM(IF(case)) also didn't work.
Will this do what you want?
SELECT
COUNT(*)
FROM
Table1
WHERE month in (1,2,3)
Related
I have a few tables in my DB. Let's call them table1, table2, table3.
All of them have a column named value.
I need to create a query that will return a single number, where this number is the sum of all the value columns from all the tables together...
I've tried the following way:
SELECT (SELECT SUM(value) FROM table1) + (SELECT SUM(value) FROM table2) + (SELECT SUM(value) FROM table3) as total_sum
But when at least one of the inner SUM is NULL, the entire total value (total_sum here) is NULL, so that's not very trustworthy.
When there is no value in a certain inner SUM query, I need it to return 0, so it doesn't affect the rest of the SUM.
To make it more clear, let's say I have the following 2 tables:
TABLE1:
ID | NAME | VALUE
1 Name1 1000
2 Name2 2000
3 Name3 3000
TABLE2:
ID | NAME | VALUE
1 Name1 1500
2 Name2 2500
3 Name3 3500
Eventually, the query I need will return a single value - 13500, which is the total sum of all the values under the VALUE column of all the tables here.
All the other columns have no meaning for the needed query, and I even don't care much for performance in this case.
You can achieve it using Coalesce as follows
SELECT
(SELECT coalesce(SUM(value),0) FROM table1) +
(SELECT coalesce(SUM(value),0) FROM table2) +
(SELECT coalesce(SUM(value),0) FROM table3) as total_sum
Another approach is to use union all to merge all values into single table
select distinct coalesce(sum(a.value), 0) as total_sum from
(select value from table1
union all
select value from table 2
union all
select value from table 3) a;
You can use the ISNULL function to take care of the NULLs.
SELECT ISNULL((
SELECT SUM(value) FROM table1
)
, 0
) + ISNULL((
SELECT SUM(value) FROM table2
)
, 0
) + ISNULL((
SELECT SUM(value) FROM table3
)
, 0
) AS total_sum;
You could simply sum all of them:
select sum(total) as Total
from (
select sum(value) as total from Table1
union all
select sum(value) as total from Table2
union all
select sum(value) as total from Table3
) t;
How can I get LastAmount and CurrentAmount from a table which has latest Date between this two tables? For example, I want to get value from 2016 March, but the result I need is a value from the latest date.
SELECT TOP 1
*
FROM (
(SELECT * FROM TABLE1)
UNION ALL
(SELECT * FROM TABLE2)
) AS T WHERE monthCondition
ORDER BY T.CreatedData DESC
I'm having a hard time summing up a column on two tables. The scenario is something like this (refer to the image below)
Table 1 may have a lot of rows per Date. But Table 2 may only consists of two rows of data per Date. What I wanted to do is to sum up all Item/Price (Table1) according to their Date and ADD them with another SUM of Item/Price of Table2. The category of SUM is by Date.
I tried any joins statement (left, right or inner) but it does not produce the result that I am expecting to. My expected result is the Result table. But on my query, it produces a very high value.
Thanks.
Use a UNION clause like this:
WITH t(d, p) AS (
SELECT [Date], Price FROM Table1
UNION ALL
SELECT [Date], Price FROM Table2
)
SELECT d, SUM(p) FROM t GROUP BY d
You can do this with UNION ALL in either a subquery or a cte, cte shown here:
;WITH cte AS (SELECT [Date], Price
FROM Table1
UNION ALL
SELECT [Date], Price
FROM Table2
)
SELECT [Date], SUM(Price) AS Total_Price
FROM cte
GROUP BY [Date]
Demo: SQL Fiddle
Try This,
with cte (C_Date,C_Price)
as
(
SELECT date,SUM(price) FROM table_1
group by date
union
SELECT date,SUM(price) FROM table_2
group by date
)
select c_date,SUM(c_price) from cte
group by C_Date
Try this
Select t.date,P1+P2
from(
Select Date,sum(Price) P1
from table1 t
group by Date
) t
left join
(
Select Date,sum(Price) P2
from table t2
group by date
) t1 on t.date = t1.date
group by date
I want to take the below statement and fuse it into one query.
SELECT COUNT(*) AS count1 WHERE Month='11' AND Flag = 1
SELECT COUNT(*) AS count2 WHERE Month='11' AND Flag = 2
SELECT COUNT(*) AS count1 WHERE Month='12' AND Flag = 1
SELECT COUNT(*) AS count2 WHERE Month='12' AND Flag = 2
I want this to display as one query with columns count1 and count2 and rows month 11 and month 12.
Is there a syntax for this?
You can combine SUM and CASE to get various counts in one go:
SELECT
Month,
SUM(CASE WHEN Flag=1 THEN 1 ELSE 0 END) as count1,
SUM(CASE WHEN Flag=2 THEN 1 ELSE 0 END) as count2
from
...
WHERE Month in ('11','12')
GROUP BY
Month /* Other columns? */
With two columns only, it can be something like this:
select
(SELECT COUNT(*) FROM tablename WHERE Month='11' AND Flag = 1) as 'count1'
(SELECT COUNT(*) FROM tablename WHERE Month='11' AND Flag = 2) as 'count2'
UNION ALL
select
(SELECT COUNT(*) FROM tablename WHERE Month='12' AND Flag = 1),
(SELECT COUNT(*) FROM tablename WHERE Month='12' AND Flag = 2)
Replace tablename with the name of your table.
How about this:
select
month, flag, count(*)
from
table
where
month in ('11', '12') and
flag in (1, 2)
group by
month, flag;
If I have two tables like this:
Table1
Month
1
3
Table 2
Month
1
4
How do I get the following result set?
Result Set
Month
1
3
4
Use the UNION operator like this:
SELECT Month FROM Table1
UNION
SELECT Month FROM Table2
The SQL UNION operator combines two or more SELECT statements and produces a single result with unique values.
SELECT [Month]
FROM Table1
UNION
SELECT [Month]
FROM Table2
You will want to use a UNION to combine the results into a single set.
SELECT Month
FROM Table1
UNION
SELECT Month
FROM Table2
By default UNION only grabs distinct values, therefore your exact result. If you wanted duplicate values you could use UNION ALL which would show month 1 in your example twice.
Here is a good tutorial that shows the differences as well.
Use UNION:
SELECT month FROM table1 UNION SELECT month FROM table2
SELECT Month FROM Table 1 UNION Select Month FROM Table 2 should do the trick
Here is my solution
declare # temptable table( months varchar(10) )
inserto into #temptable(months)
select distinct Month from Table1
inserto into #temptable(months)
select distinct Month from Table2
select disticnt * from #temptable
Maybe there is a better way?