SQL Method of checking that INNER / LEFT join doesn't duplicate rows - sql

Is there a good or standard SQL method of asserting that a join does not duplicate any rows (produces 0 or 1 copies of the source table row)? Assert as in causes the query to fail or otherwise indicate that there are duplicate rows.
A common problem in a lot of queries is when a table is expected to be 1:1 with another table, but there might exist 2 rows that match the join criteria. This can cause errors that are hard to track down, especially for people not necessarily entirely familiar with the tables.
It seems like there should be something simple and elegant - this would be very easy for the SQL engine to detect (have I already joined this source row to a row in the other table? ok, error out) but I can't seem to find anything on this. I'm aware that there are long / intrusive solutions to this problem, but for many ad hoc queries those just aren't very fun to work out.
EDIT / CLARIFICATION: I'm looking for a one-step query-level fix. Not a verification step on the results of that query.

If you are only testing for linked rows rather than requiring output, then you'd use EXISTS.
More correctly, you need a "semi-join" but this isn't supported by most RDBMS unless as EXISTS
SELECT a.*
FROM TableA a
WHERE EXISTS (SELECT * FROM TableB b WHERE a.id = b.id)
Also see:
Using 'IN' with a sub-query in SQL Statements
EXISTS vs JOIN and use of EXISTS clause

SELECT JoinField
FROM MyJoinTable
GROUP BY JoinField
HAVING COUNT(*) > 1
LIMIT 1
Is that simple enough? Don't have Postgres but I think it's valid syntax.

Something along the lines of
SELECT a.id, COUNT(b.id)
FROM TableA a
JOIN TableB b ON a.id = b.id
GROUP BY a.id
HAVING COUNT(b.id) > 1
Should return rows in TableA that have more than one associated row in TableB.

Related

Oracle: Use only few tables in WHERE clause but mentioned more tables in 'FROM' in a jon SQL

What will happen in an Oracle SQL join if I don't use all the tables in the WHERE clause that were mentioned in the FROM clause?
Example:
SELECT A.*
FROM A, B, C, D
WHERE A.col1 = B.col1;
Here I didn't use the C and D tables in the WHERE clause, even though I mentioned them in FROM. Is this OK? Are there any adverse performance issues?
It is poor practice to use that syntax at all. The FROM A,B,C,D syntax has been obsolete since 1992... more than 30 YEARS now. There's no excuse anymore. Instead, every join should always use the JOIN keyword, and specify any join conditions in the ON clause. The better way to write the query looks like this:
SELECT A.*
FROM A
INNER JOIN B ON A.col1 = B.col1
CROSS JOIN C
CROSS JOIN D;
Now we can also see what happens in the question. The query will still run if you fail to specify any conditions for certain tables, but it has the effect of using a CROSS JOIN: the results will include every possible combination of rows from every included relation (where the "A,B" part counts as one relation). If each of the three parts of those joins (A&B, C, D) have just 100 rows, the result set will have 1,000,000 rows (100 * 100 * 100). This is rarely going to give the results you expect or intend, and it's especially suspect when the SELECT clause isn't looking at any of the fields from the uncorrelated tables.
Any table lacking join definition will result in a Cartesian product - every row in the intermediate rowset before the join will match every row in the target table. So if you have 10,000 rows and it joins without any join predicate to a table of 10,000 rows, you will get 100,000,000 rows as a result. There are only a few rare circumstances where this is what you want. At very large volumes it can cause havoc for the database, and DBAs are likely to lock your account.
If you don't want to use a table, exclude it entirely from your SQL. If you can't for reason due to some constraint we don't know about, then include the proper join predicates to every table in your WHERE clause and simply don't list any of their columns in your SELECT clause. If there's a cost to the join and you don't need anything from it and again for some very strange reason can't leave the table out completely from your SQL (this does occasionally happen in reusable code), then you can disable the joins by making the predicates always false. Remember to use outer joins if you do this.
Native Oracle method:
WITH data AS (SELECT ROWNUM col FROM dual CONNECT BY LEVEL < 10) -- test data
SELECT A.*
FROM data a,
data b,
data c,
data d
WHERE a.col = b.col
AND DECODE('Y','Y',NULL,a.col) = c.col(+)
AND DECODE('Y','Y',NULL,a.col) = d.col(+)
ANSI style:
WITH data AS (SELECT ROWNUM col FROM dual CONNECT BY LEVEL < 10)
SELECT A.*
FROM data a
INNER JOIN data b ON a.col = b.col
LEFT OUTER JOIN data c ON DECODE('Y','Y',NULL,a.col) = b.col
LEFT OUTER JOIN data d ON DECODE('Y','Y',NULL,a.col) = d.col
You can plug in a variable for the first Y that you set to Y or N (e.g. var_disable_join). This will bypass the join and avoid both the associated performance penalty and the Cartesian product effect. But again, I want to reiterate, this is an advanced hack and is probably NOT what you need. Simply leaving out the unwanted tables it the right approach 95% of the time.

SQL subselect statement very slow on certain machines

I've got an sql statement where I get a list of all Ids from a table (Machines).
Then need the latest instance of another row in (Events) where the the id's match so have been doing a subselect.
I need to latest instance of quite a few fields that match the id so have these subselects after one another within this single statement so end up with results similar to this...
This works and the results are spot on, it's just becoming very slow as the Events Table has millions of records. The Machine table would have on average 100 records.
Is there a better solution that subselects? Maybe doing inner joins or a stored procedure?
Help appreciated :)
You can use apply. You don't specify how "latest instance" is defined. Let me assume it is based on the time column:
Select a.id, b.*
from TableA a outer apply
(select top(1) b.Name, b.time, b.weight
from b
where b.id = a.id
order by b.time desc
) b;
Both APPLY and the correlated subquery need an ORDER BY to do what you intend.
APPLY is a lot like a correlated query in the FROM clause -- with two convenient enhances. A lateral join -- technically what APPLY does -- can return multiple rows and multiple columns.

Determine datatypes of columns - SQL selection

Is it possible to determine the type of data of each column after a SQL selection, based on received results? I know it is possible though information_schema.columns, but the data I receive comes from multiple tables and is joint together and the data is renamed. Besides that, I'm not able to see or use this query or execute other queries myself.
My job is to store this received data in another table, but without knowing beforehand what I will receive. I'm obviously able to check for example if a certain column contains numbers or text, but not if it is originally stored as a TINYINT(1) or a BIGINT(128). How to approach this? To clarify, it is alright if the data-types of the columns of the source and destination aren't entirely the same, but I don't want to reserve too much space beforehand (or too less for that matter).
As I'm typing, I realize I'm formulation the question wrong. What would be the best approach to handle described situation? I thought about altering tables on the run (e.g. increasing size if needed), but that seems a bit, well, wrong and not the proper way.
Thanks
Can you issue the following query about your new table after you create it?
SELECT *
INTO JoinedQueryResults
FROM TableA AS A
INNER JOIN TableB AS B ON A.ID = B.ID
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'JoinedQueryResults'
Is the query too big to run before knowing how big the results will be? Get a idea of how many rows it may return, but the trick with queries with joins is to group on the columns you are joining on, to help your estimate return more quickly. Here's of an example of just returning a row count from the query above which would have created the JoinedQueryResults table above.
SELECT SUM(A.NumRows * B.NumRows)
FROM (SELECT ID, COUNT(*) AS NumRows
FROM TableA
GROUP BY ID) AS A
INNER JOIN (SELECT ID, COUNT(*) AS NumRows
FROM TableB
GROUP BY ID) AS B ON A.ID = B.ID
The query above will run faster if all you need is a record count to help you estimate a size.
Also try instantiating a table for your results with a query like this.
SELECT TOP 0 *
INTO JoinedQueryResults
FROM TableA AS A
INNER JOIN TableB AS B ON A.ID = B.ID

SQL referring to same table in a query Stuck

I have a query that requires me to join/refers to the same table, however, I am unable to get a result using the query.
Below is a sample of my query
SELECT a."column1", b."column1" as anotherColumn
FROM table1 AS a, table2 AS b
where a.'x' = b.'x'
AND NOT a.'y' = b.'y'
This query take forever to load. However, if I just run:
SELECT a."column1"
FROM table1 AS A
it only takes 14sec.
I'm currently using PostgreSQL with Pgadmin. table1 has 1.4million table currently.
Is it because there is a lock on the table 1 when it was first referred to as a?
EDIT : Each row contains the record of "author","book published" and in this case, there might be many authors for a book hence being collaborators. What I am trying to achieve is to find out the number of collaborators for each author
What I am trying to achieve is to find out the number of collaborators for each author
Something like this would count the number of authors, and I guess where that number is greater than 1, the number of collaborators is that number - 1
select b.name, count(a.*)-1 as num_collaborators
from books b
inner join authors a on b.id = a.book_id
group by b.name
having count(a.*) > 1
--original
SELECT a."column1", b."column1" as anotherColumn
FROM table1 AS a, table2 AS b
;
--amended
SELECT a."column1", b."column1" as anotherColumn
FROM table1 AS a, table2 AS b
where a.'x' = b.'x'
AND NOT a.'y' = b.'y'
Over 25 years ago ANSI standards for SQL introduced a more "explicit" syntax for joins and using this is well established as "best practice" now.
One of the greatest benefits of this "explicit join syntax" is that accidentally forgetting to join properly becomes impossible, unlike the original query which did forget the joining predicate. (& When that happens an unexpected Cartesian product is produced.)
So, I encourage you to stop using commas between table names. Taking that simple step will help you use better join syntax.

SQL (any) Request for insight on a query optimization

I have a particularly slow query due to the vast amount of information being joined together. However I needed to add a where clause in the shape of id in (select id from table).
I want to know if there is any gain from the following, and more pressing, will it even give the desired results.
select a.* from a where a.id in (select id from b where b.id = a.id)
as an alternative to:
select a.* from a where a.id in (select id from b)
Update:
MySQL
Can't be more specific sorry
table a is effectively a join between 7 different tables.
use of * is for examples
Edit, b doesn't get selected
Your question was about the difference between these two:
select a.* from a where a.id in (select id from b where b.id = a.id)
select a.* from a where a.id in (select id from b)
The former is a correlated subquery. It may cause MySQL to execute the subquery for each row of a.
The latter is a non-correlated subquery. MySQL should be able to execute it once and cache the results for comparison against each row of a.
I would use the latter.
Both queries you list are the equivalent of:
select a.*
from a
inner join b on b.id = a.id
Almost all optimizers will execute them in the same way.
You could post a real execution plan, and someone here might give you a way to speed it up. It helps if you specify what database server you are using.
YMMV, but I've often found using EXISTS instead of IN makes queries run faster.
SELECT a.* FROM a WHERE EXISTS (SELECT 1 FROM b WHERE b.id = a.id)
Of course, without seeing the rest of the query and the context, this may not make the query any faster.
JOINing may be a more preferable option, but if a.id appears more than once in the id column of b, you would have to throw a DISTINCT in there, and you more than likely go backwards in terms of optimization.
I would never use a subquery like this. A join would be much faster.
select a.*
from a
join b on a.id = b.id
Of course don't use select * either (especially never use it when doing a join as at least one field is repeated) and it wastes network resources to send unnneeded data.
Have you looked at the execution plan?
How about
select a.*
from a
inner join b
on a.id = b.id
presumably the id fields are primary keys?
Select a.* from a
inner join (Select distinct id from b) c
on a.ID = c.AssetID
I tried all 3 versions and they ran about the same. The execution plan was the same (inner join, IN (with and without where clause in subquery), Exists)
Since you are not selecting any other fields from B, I prefer to use the Where IN(Select...) Anyone would look at the query and know what you are trying to do (Only show in a if in b.).
your problem is most likely in the seven tables within "a"
make the FROM table contain the "a.id"
make the next join: inner join b on a.id = b.id
then join in the other six tables.
you really need to show the entire query, list all indexes, and approximate row counts of each table if you want real help